AA Section 2-2

52
Section 2-2 Inverse Variation

description

Inverse Variation

Transcript of AA Section 2-2

Page 1: AA Section 2-2

Section 2-2Inverse Variation

Page 2: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

Page 3: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2

Page 4: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2 63 = k(3)2

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Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2 63 = k(3)2 63 = 9k

Page 6: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2 63 = k(3)2 63 = 9k k = 7

Page 7: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2 63 = k(3)2 63 = 9k k = 7

y = 7x2

Page 8: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2 63 = k(3)2 63 = 9k k = 7

y = 7x2 y = 7(9)2

Page 9: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2 63 = k(3)2 63 = 9k k = 7

y = 7x2 y = 7(9)2 = 7(81)

Page 10: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2 63 = k(3)2 63 = 9k k = 7

y = 7x2 y = 7(9)2 = 7(81) = 567

Page 11: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2 63 = k(3)2 63 = 9k k = 7

y = 7x2 y = 7(9)2 = 7(81) = 567

b. Find y when x = 5

Page 12: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2 63 = k(3)2 63 = 9k k = 7

y = 7x2 y = 7(9)2 = 7(81) = 567

b. Find y when x = 5

y = 7x2

Page 13: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2 63 = k(3)2 63 = 9k k = 7

y = 7x2 y = 7(9)2 = 7(81) = 567

b. Find y when x = 5

y = 7x2 y = 7(5)2

Page 14: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2 63 = k(3)2 63 = 9k k = 7

y = 7x2 y = 7(9)2 = 7(81) = 567

b. Find y when x = 5

y = 7x2 y = 7(5)2 = 7(25)

Page 15: AA Section 2-2

Warm-upy varies directly as the square of x. If y = 63 when x = 3,

a. Find y when x = 9

y = kx2 63 = k(3)2 63 = 9k k = 7

y = 7x2 y = 7(9)2 = 7(81) = 567

b. Find y when x = 5

y = 7x2 y = 7(5)2 = 7(25) = 175

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Review: Direct Variation

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Review: Direct Variation

Wording for Direct Variation

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Review: Direct Variation

Wording for Direct Variation

General Equation

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Review: Direct Variation

Wording for Direct Variation

General Equation

Constant of Variation

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Review: Direct Variation

Wording for Direct Variation

General Equation

Constant of Variation

Steps to solve

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“t Varies Inversely as s”:

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“t Varies Inversely as s”: When t goes up, s goes down; when t goes down, s goes up

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“t Varies Inversely as s”: When t goes up, s goes down; when t goes down, s goes up

Inverse Variation Function:

Page 24: AA Section 2-2

“t Varies Inversely as s”: When t goes up, s goes down; when t goes down, s goes up

Inverse Variation Function:

A function of the form with k ≠ 0 and n > 0 y =

k

xn

Page 25: AA Section 2-2

“t Varies Inversely as s”: When t goes up, s goes down; when t goes down, s goes up

Inverse Variation Function:

A function of the form with k ≠ 0 and n > 0 y =

k

xn

Page 26: AA Section 2-2

“t Varies Inversely as s”: When t goes up, s goes down; when t goes down, s goes up

Inverse Variation Function:

A function of the form with k ≠ 0 and n > 0 y =

k

xn

“ is inversely proportional to”

Page 27: AA Section 2-2

“t Varies Inversely as s”: When t goes up, s goes down; when t goes down, s goes up

Inverse Variation Function:

A function of the form with k ≠ 0 and n > 0 y =

k

xn

“ is inversely proportional to”

***The intensity of the light varies inversely as the square of the distance from the light source

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Example 1Rewrite the statement, “The intensity of the light

varies inversely as the square of the distance from the light source.”

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Example 1Rewrite the statement, “The intensity of the light

varies inversely as the square of the distance from the light source.”

The intensity of the light is inversely proportional to the square of the distance from the light source

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Example 2In a room, the floor space F per person varies inversely

as the square of the number of people P in the room. Write an equation to represent this situation.

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Example 2In a room, the floor space F per person varies inversely

as the square of the number of people P in the room. Write an equation to represent this situation.

F =

k

p2

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Example 3The time T required to do a job varies inversely as the number of workers w. It takes 5 hours for 8 cement

workers to do a job. How long would it take 12 workers to do the same job?

Page 33: AA Section 2-2

Example 3The time T required to do a job varies inversely as the number of workers w. It takes 5 hours for 8 cement

workers to do a job. How long would it take 12 workers to do the same job?

T =

k

w

Page 34: AA Section 2-2

Example 3The time T required to do a job varies inversely as the number of workers w. It takes 5 hours for 8 cement

workers to do a job. How long would it take 12 workers to do the same job?

T =

k

w 5 =

k

8

Page 35: AA Section 2-2

Example 3The time T required to do a job varies inversely as the number of workers w. It takes 5 hours for 8 cement

workers to do a job. How long would it take 12 workers to do the same job?

T =

k

w 5 =

k

8k = 40

Page 36: AA Section 2-2

Example 3The time T required to do a job varies inversely as the number of workers w. It takes 5 hours for 8 cement

workers to do a job. How long would it take 12 workers to do the same job?

T =

k

w 5 =

k

8k = 40

T =

40

w

Page 37: AA Section 2-2

Example 3The time T required to do a job varies inversely as the number of workers w. It takes 5 hours for 8 cement

workers to do a job. How long would it take 12 workers to do the same job?

T =

k

w 5 =

k

8k = 40

T =

40

w

T =

40

12

Page 38: AA Section 2-2

Example 3The time T required to do a job varies inversely as the number of workers w. It takes 5 hours for 8 cement

workers to do a job. How long would it take 12 workers to do the same job?

T =

k

w 5 =

k

8k = 40

T =

40

w

T =

40

12 = 3 13 hours

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Steps to solving an inverse variation problem

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Steps to solving an inverse variation problem

1. Write an equation to describe the variation

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Steps to solving an inverse variation problem

1. Write an equation to describe the variation

2. Find k

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Steps to solving an inverse variation problem

1. Write an equation to describe the variation

2. Find k

3. Rewrite the function using k

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Steps to solving an inverse variation problem

1. Write an equation to describe the variation

2. Find k

3. Rewrite the function using k

4. Evaluate

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Example 4g is inversely proportional to h. If g = 3 when h = 6,

find g when h = 9.

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Example 4g is inversely proportional to h. If g = 3 when h = 6,

find g when h = 9.

g =

k

h

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Example 4g is inversely proportional to h. If g = 3 when h = 6,

find g when h = 9.

g =

k

h 3 =

k

6

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Example 4g is inversely proportional to h. If g = 3 when h = 6,

find g when h = 9.

g =

k

h 3 =

k

6k = 18

Page 48: AA Section 2-2

Example 4g is inversely proportional to h. If g = 3 when h = 6,

find g when h = 9.

g =

k

h 3 =

k

6k = 18

g =

18

h

Page 49: AA Section 2-2

Example 4g is inversely proportional to h. If g = 3 when h = 6,

find g when h = 9.

g =

k

h 3 =

k

6k = 18

g =

18

h

g =

18

9

Page 50: AA Section 2-2

Example 4g is inversely proportional to h. If g = 3 when h = 6,

find g when h = 9.

g =

k

h 3 =

k

6k = 18

g =

18

h

g =

18

9= 2

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Homework

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Homework

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