AA Section 3-1

53
CHAPTER 3 LINEAR FUNCTIONS Created at http://wordle.net

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Constant-Increase and Constant-Decrease Situations

Transcript of AA Section 3-1

Page 1: AA Section 3-1

CHAPTER 3LINEAR FUNCTIONS

Created at http://wordle.net

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SECTION 3-1Constant-Increase and Constant-Decrease Situations

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WARM-UP

Look at the four graphs on page 139 as such:a. Constant Increase

b. Linear Combinationc. Point-Slope

d. Step Function

1. Name at least two points on each graph.

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WARM-UP

2. Give the domain and range of each function

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WARM-UP

2. Give the domain and range of each function

a. D = Set of whole numbers; R = {n: n = 3, 3.2, 3.4, ...}

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WARM-UP

2. Give the domain and range of each function

a. D = Set of whole numbers; R = {n: n = 3, 3.2, 3.4, ...}

b. D = {A: A = 0, 3, 6}; R = {S: S = 0, 7, 14}

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WARM-UP

2. Give the domain and range of each function

a. D = Set of whole numbers; R = {n: n = 3, 3.2, 3.4, ...}

b. D = {A: A = 0, 3, 6}; R = {S: S = 0, 7, 14}

c. D = {W: W ≥ 0}; R = {L: L ≥ 7}

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WARM-UP

2. Give the domain and range of each function

a. D = Set of whole numbers; R = {n: n = 3, 3.2, 3.4, ...}

b. D = {A: A = 0, 3, 6}; R = {S: S = 0, 7, 14}

c. D = {W: W ≥ 0}; R = {L: L ≥ 7}

d. D = {w: w > 0}; R = {C: C = .33, .55, .77, ...}

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Linear Equation:

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Linear Equation: Equation that gives a graph of a line

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EXAMPLE 1

Matt Mitarnowski sells sports cars. He gets a base salary of $30,000 per year plus 2% of his sales. If Matt’s sales for the

year totaled D dollars, what is his salary S?

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EXAMPLE 1

Matt Mitarnowski sells sports cars. He gets a base salary of $30,000 per year plus 2% of his sales. If Matt’s sales for the

year totaled D dollars, what is his salary S?

S = 30,000 + .02D

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EXAMPLE 1

Matt Mitarnowski sells sports cars. He gets a base salary of $30,000 per year plus 2% of his sales. If Matt’s sales for the

year totaled D dollars, what is his salary S?

S = 30,000 + .02D

Let’s look at the table and graph

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EXPLORE

Calculate the slope for the situation in Example 1.

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EXPLORE

Calculate the slope for the situation in Example 1.

(0, 30,000), (1,000,000, 50,000)

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EXPLORE

Calculate the slope for the situation in Example 1.

(0, 30,000), (1,000,000, 50,000)

m =

50, 000 − 30, 0001, 000, 000 − 0

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EXPLORE

Calculate the slope for the situation in Example 1.

(0, 30,000), (1,000,000, 50,000)

m =

50, 000 − 30, 0001, 000, 000 − 0

=

20, 0001, 000, 000

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EXPLORE

Calculate the slope for the situation in Example 1.

(0, 30,000), (1,000,000, 50,000)

m =

50, 000 − 30, 0001, 000, 000 − 0

=

20, 0001, 000, 000

=

2100

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EXPLORE

Calculate the slope for the situation in Example 1.

(0, 30,000), (1,000,000, 50,000)

m =

50, 000 − 30, 0001, 000, 000 − 0

=

20, 0001, 000, 000

=

2100

=150

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EXPLORE

Calculate the slope for the situation in Example 1.

(0, 30,000), (1,000,000, 50,000)

m =

50, 000 − 30, 0001, 000, 000 − 0

=

20, 0001, 000, 000

=

2100

= .02 =

150

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Slope-intercept Form:

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Slope-intercept Form: y = mx + b, where m = slope and b = the y-coordinate of the y-intercept

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Slope-intercept Form: y = mx + b, where m = slope and b = the y-coordinate of the y-intercept

*In this form, the slope will ALWAYS be with the independent variable, and the y-coordinate of the y-

intercept will ALWAYS be by itself

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Slope-intercept Form: y = mx + b, where m = slope and b = the y-coordinate of the y-intercept

*In this form, the slope will ALWAYS be with the independent variable, and the y-coordinate of the y-

intercept will ALWAYS be by itself

Linear Function:

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Slope-intercept Form: y = mx + b, where m = slope and b = the y-coordinate of the y-intercept

*In this form, the slope will ALWAYS be with the independent variable, and the y-coordinate of the y-

intercept will ALWAYS be by itself

Linear Function: A function of the form y = mx + b

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Slope-intercept Form: y = mx + b, where m = slope and b = the y-coordinate of the y-intercept

*In this form, the slope will ALWAYS be with the independent variable, and the y-coordinate of the y-

intercept will ALWAYS be by itself

Linear Function: A function of the form y = mx + bEuler notation:

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Slope-intercept Form: y = mx + b, where m = slope and b = the y-coordinate of the y-intercept

*In this form, the slope will ALWAYS be with the independent variable, and the y-coordinate of the y-

intercept will ALWAYS be by itself

Linear Function: A function of the form y = mx + bEuler notation: f(x) = mx + b

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Slope-intercept Form: y = mx + b, where m = slope and b = the y-coordinate of the y-intercept

*In this form, the slope will ALWAYS be with the independent variable, and the y-coordinate of the y-

intercept will ALWAYS be by itself

Linear Function: A function of the form y = mx + bEuler notation: f(x) = mx + b

Mapping notation:

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Slope-intercept Form: y = mx + b, where m = slope and b = the y-coordinate of the y-intercept

*In this form, the slope will ALWAYS be with the independent variable, and the y-coordinate of the y-

intercept will ALWAYS be by itself

Linear Function: A function of the form y = mx + bEuler notation: f(x) = mx + b

Mapping notation: f:x mx + b

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EXAMPLE 2

Fuzzy Jeff gets an allowance of $15 per week. Whenever his parents pick up a dirty dish he left out, Jeff losts $.30.

a. Write an equation modeling this situation

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EXAMPLE 2

Fuzzy Jeff gets an allowance of $15 per week. Whenever his parents pick up a dirty dish he left out, Jeff losts $.30.

a. Write an equation modeling this situation

A = Allowance; d = Dirty Dishes

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EXAMPLE 2

Fuzzy Jeff gets an allowance of $15 per week. Whenever his parents pick up a dirty dish he left out, Jeff losts $.30.

a. Write an equation modeling this situation

A = Allowance; d = Dirty Dishes

A = 15 - .3d

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EXAMPLE 2

Fuzzy Jeff gets an allowance of $15 per week. Whenever his parents pick up a dirty dish he left out, Jeff losts $.30.

a. Write an equation modeling this situation

A = Allowance; d = Dirty Dishes

A = 15 - .3d

b. Graph the equation

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EXAMPLE 2

c. If Jeff gets no allowance, how many dishes did he leave out?

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EXAMPLE 2

c. If Jeff gets no allowance, how many dishes did he leave out?

A = 15 - .3d

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EXAMPLE 2

c. If Jeff gets no allowance, how many dishes did he leave out?

A = 15 - .3d

0 = 15 - .3d

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EXAMPLE 2

c. If Jeff gets no allowance, how many dishes did he leave out?

A = 15 - .3d

0 = 15 - .3d-15

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EXAMPLE 2

c. If Jeff gets no allowance, how many dishes did he leave out?

A = 15 - .3d

0 = 15 - .3d-15-15

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EXAMPLE 2

c. If Jeff gets no allowance, how many dishes did he leave out?

A = 15 - .3d

0 = 15 - .3d-15-15

-15 = -.3d

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EXAMPLE 2

c. If Jeff gets no allowance, how many dishes did he leave out?

A = 15 - .3d

0 = 15 - .3d-15-15

-15 = -.3d

d = 50

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EXAMPLE 2

c. If Jeff gets no allowance, how many dishes did he leave out?

A = 15 - .3d

0 = 15 - .3d-15-15

-15 = -.3d

d = 50 dishes

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Piecewise Linear Graph:

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Piecewise Linear Graph: When the rate of change switches from one constant value to another

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Piecewise Linear Graph: When the rate of change switches from one constant value to another

*Made up of two or more segments or rays

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EXAMPLE 3

The graph below describes Shecky’s weight over the first 16 weeks of his life. Write out an explanation of each piece

of the piecewise linear function.

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EXAMPLE 3

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EXAMPLE 3

Shecky weighed 9 pounds at birth.

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EXAMPLE 3

Shecky weighed 9 pounds at birth.

In his first week alive, he lost one pound.

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EXAMPLE 3

Shecky weighed 9 pounds at birth.

In his first week alive, he lost one pound.

Over the next four weeks, Shecky gained a pound a week.

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EXAMPLE 3

Shecky weighed 9 pounds at birth.

In his first week alive, he lost one pound.

Over the next four weeks, Shecky gained a pound a week.

In the following three weeks, Shecky’s weight stayed the same.

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EXAMPLE 3

Shecky weighed 9 pounds at birth.

In his first week alive, he lost one pound.

Over the next four weeks, Shecky gained a pound a week.

In the following three weeks, Shecky’s weight stayed the same.

Over the last 8 weeks, Shecky gained half of a pound per week.

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HOMEWORK

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HOMEWORK

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“Fortune favors the brave.” - Publius Terence