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The Mathematics of Entanglement - Summer 2013 30 May, 2013 Three Qubit Entanglement Polytopes Lecturer: Michael Walter Lecture 10 Last time we talked about SLOCC (stochastic LOCC), where we can post-select on particular outcomes Given a class of states that can be interconverted by SLOCC into |ψi other by SLOCC, C ψ = {|φi : |φi↔|ψi}, a result by Dur-Vidal-Cirac says that C ψ := {(A B C )|ψi/k ... k : A,B,C SL(d)} (1) For three qubits there is a simple classification of all possible types of entanglement. Apart from product states, and states with only bipartite entanglement, the two classes have the following representative states: |GHZ i = 1 2 (|000i + |111i) (2) and |W i = 1 2 (|001i + |010i + |100i) (3) The class of SLOCC operations forms a group: G = {A B C : A,B,C SL(d)}. (4) A easy to check fact is that SL(d)= {e X : tr(X )=0}. Therefore G = {e A e B e C = e AI I +I BI +I I C : tr(A) = tr(B) = tr(C )=0}. (5) We denote C ψ ABC by G.|ψi ABC . 1 Quantum Marginal Problem for Three Parties What are the possible ρ A , ρ B , ρ C compatible with a pure state |φi ABC C ψ ABC ? We say before that this only depends on the spectra λ A , λ B and λ C , as one can always apply local unitaries and change the basis. For example, for the W class the set of compatible spectra is given by the equation λ A max + λ B max + λ C max 2. Let us start with a simpler problem, namely given a state |ψi ABC , does there exist a state in G.|ψi ABC with ρ A = ρ B = ρ C = I/d? This is equivalent to tr(ρ A A) = tr(ρ B B) = tr(ρ C C )=0, (6) for all Hermitian traceless matrices A,B,C , which in turn is equivalent to tr(ρ A A) + tr(ρ B B) + tr(ρ C C )=0, (7) for all Hermitian traceless matrices A,B,C . We can write it as hψ ABC |A I I + I B I + I I C |ψ ABC i =0. (8) 10-1

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Transcript of 30may_2

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The Mathematics of Entanglement - Summer 2013 30 May, 2013

Three Qubit Entanglement Polytopes

Lecturer: Michael Walter Lecture 10

Last time we talked about SLOCC (stochastic LOCC), where we can post-select on particularoutcomes

Given a class of states that can be interconverted by SLOCC into |ψ〉 other by SLOCC, Cψ ={|φ〉 : |φ〉 ↔ |ψ〉}, a result by Dur-Vidal-Cirac says that

Cψ := {(A⊗B ⊗ C)|ψ〉/‖ . . . ‖ : A,B,C ∈ SL(d)} (1)

For three qubits there is a simple classification of all possible types of entanglement. Apartfrom product states, and states with only bipartite entanglement, the two classes have the followingrepresentative states:

|GHZ〉 =1

2(|000〉+ |111〉) (2)

and

|W 〉 =1

2(|001〉+ |010〉+ |100〉) (3)

The class of SLOCC operations forms a group:

G = {A⊗B ⊗ C : A,B,C ∈ SL(d)}. (4)

A easy to check fact is that SL(d) = {eX : tr(X) = 0}. Therefore

G = {eA ⊗ eB ⊗ eC = eA⊗I⊗I+I⊗B⊗I+I⊗I⊗C : tr(A) = tr(B) = tr(C) = 0}. (5)

We denote CψABCby G.|ψ〉ABC .

1 Quantum Marginal Problem for Three Parties

What are the possible ρA, ρB, ρC compatible with a pure state |φ〉ABC ∈ CψABC? We say before

that this only depends on the spectra λA, λB and λC , as one can always apply local unitaries andchange the basis.

For example, for the W class the set of compatible spectra is given by the equation λAmax +λBmax + λCmax ≥ 2.

Let us start with a simpler problem, namely given a state |ψ〉ABC , does there exist a state inG.|ψ〉ABC with ρA = ρB = ρC = I/d? This is equivalent to

tr(ρAA) = tr(ρBB) = tr(ρCC) = 0, (6)

for all Hermitian traceless matrices A,B,C, which in turn is equivalent to

tr(ρAA) + tr(ρBB) + tr(ρCC) = 0, (7)

for all Hermitian traceless matrices A,B,C. We can write it as

〈ψABC |A⊗ I ⊗ I + I ⊗B ⊗ I + I ⊗ I ⊗ C|ψABC〉 = 0. (8)

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Thus the norm of the state |ψABC〉 should not change (to 1st order) when we apply an infinitesimalSLOCC operation.

Let us look at

∂t‖etA ⊗ etB ⊗ etC |ψABC〉‖ =

∂t〈ψABC |etA ⊗ etB ⊗ etC |ψABC〉

= 2〈ψABC |A⊗ I ⊗ I + I ⊗B ⊗ I + I ⊗ I ⊗ C|ψABC〉. (9)

So from Eq. (??), if |ψABC〉 is the closest point to the origin in G.|φABC〉, then ρA = ρB =ρC = I/d.

What happens when there is no point in the class with ρA = ρB = ρC = I/d. That seemsstrange, as it implies by the above that there is no closest point to the origin. But indeed this isthe case for the |W 〉 class, for example. Consider

(ε0; 01/ε)⊗ (ε0′01/ε)⊗ (ε0′01/ε)|W 〉 = ε|W 〉 (10)

and when ε goes to zero, one approaches the origin. However the limit is not in G.|W 〉.

Theorem 1. The following are equivalent:

• There exists a closest point to 0 in G.|φABC〉.

• There exists a quantum state in G.|φABC〉 with ρA = ρB = ρC = I/d.

• G.|φABC〉 is closed.

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