STRUKTURE TASK Send Your answer to ikhwan_sma3smg@yahoo
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STRUKTURE TASK Send Your answer to [email protected] • 1. Find SS The equation, by Completing the square : a. X 2 -2x -15 = 0 b. 2/(x-1) – 6/ (2x+1) = 5 if x 1 > x 2 , find the value of x 1 /x 2 • 2. Determine the kinds of the roots of QE 3/(x+4) + (x-3)/x = 2 • 3. Find the value of p for px 2 - 3x+p=0, has equal real roots
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STRUKTURE TASK Send Your answer to [email protected]. 1. Find SS The equation, by Completing the square : a. X 2 -2x -15 = 0 b. 2/(x-1) – 6/ (2x+1) = 5 if x 1 > x 2 , find the value of x 1 /x 2 2. Determine the kinds of the roots of QE 3/(x+4) + (x-3)/x = 2 - PowerPoint PPT Presentation
Transcript of STRUKTURE TASK Send Your answer to ikhwan_sma3smg@yahoo
STRUKTURE TASK
Send Your answer to [email protected] • 1. Find SS The equation, by Completing the
square :
a. X2 -2x -15 = 0
b. 2/(x-1) – 6/ (2x+1) = 5
if x1> x2, find the value of x1/x2
• 2. Determine the kinds of the roots of QE
3/(x+4) + (x-3)/x = 2• 3. Find the value of p for px2 - 3x+p=0, has
equal real roots
• 4. if αand β are the roots of x2 + 3x -5 =0, find the value of :
a. ( α+β)3
b. 1/ α + 1/ β
• 5. Given QE 2x2 + x -7 =0, find The New QE if the roots 2α and 2β
Deadline : 29 oct 2009