Reflective losses quickly become significant Eugene Hecht, Optics, Addison-Wesley, Reading, MA,...
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Transcript of Reflective losses quickly become significant Eugene Hecht, Optics, Addison-Wesley, Reading, MA,...
Reflective losses quickly become significantReflective losses quickly become significant
Eugene Hecht, Eugene Hecht, OpticsOptics, Addison-Wesley, Reading, MA, 1998., Addison-Wesley, Reading, MA, 1998.
Antireflective CoatingsAntireflective Coatings
Melles Griot CatalogueMelles Griot Catalogue
= 1= 1 = 1.38= 1.38 = 1.5= 1.5
= 0.025
= 0.002
Total Total = 2.7% = 2.7%compared to compared to (() = 3.5% ) = 3.5%
without coatingwithout coating
Melles Griot CatalogueMelles Griot Catalogue
Film thickness further reduces reflectionsFilm thickness further reduces reflections
Melles Griot CatalogueMelles Griot Catalogue
Observed Observed for MgF for MgF22 coated optic coated optic
If incident beam is not at 90If incident beam is not at 90ºº use Fresnel’s use Fresnel’s complete equationcomplete equation
componentcomponent componentcomponent
Ingle and Crouch, Ingle and Crouch, Spectrochemical AnalysisSpectrochemical Analysis
For an air-glass interfaceFor an air-glass interface
Ingle and Crouch, Ingle and Crouch, Spectrochemical AnalysisSpectrochemical Analysis
For unpolarized light, For unpolarized light, increases increases as as 11 increases increases
componentcomponent componentcomponent
Eugene Hecht, Eugene Hecht, OpticsOptics, Addison-Wesley, Reading, MA, 1998., Addison-Wesley, Reading, MA, 1998.
Example of highExample of high at high at high 11
Ingle and Crouch, Ingle and Crouch, Spectrochemical AnalysisSpectrochemical Analysis
Brewster’s AngleBrewster’s Angle
11 where where of polarized light of polarized light
is zerois zero
1
21-p tan
1
21-p tan
For an air-glass transition For an air-glass transition pp
= 58= 58° ° 40’40’
Are you getting the concept?Are you getting the concept?
Suppose light in a quartz crystal (n = 1.55) strikes a boundarySuppose light in a quartz crystal (n = 1.55) strikes a boundarywith air (n = 1.00) at a 50-degree angle to the normal. At whatwith air (n = 1.00) at a 50-degree angle to the normal. At whatangle does the light emerge?angle does the light emerge?
Why?
http://www.rpi.edu/dept/phys/Dept2/APPhys1/optics/optics/node15.htmlhttp://www.rpi.edu/dept/phys/Dept2/APPhys1/optics/optics/node15.html
Total Internal ReflectionTotal Internal Reflection
11sinsin11 = = 22sinsin22
Snell’s Law:Snell’s Law:
If If 22 = 90 = 90ºº
1
21-c1 sin
1
21-c1 sin
At any At any 11 cc T( T() ) 0 0
For a glass-air transition For a glass-air transition cc = 42 = 42ºº
Eugene Hecht, Eugene Hecht, OpticsOptics, Addison-Wesley, Reading, MA, 1998., Addison-Wesley, Reading, MA, 1998.
Fiber OpticsFiber Optics
http://www.us.schott.com/fiberoptics/english/company/index.html#http://www.us.schott.com/fiberoptics/english/company/index.html#..
Defining Characteristics:
• Numerical Aperture• Spectral Transmission• Diameter
Are you getting the concept?Are you getting the concept?Light of vacuum wavelength Light of vacuum wavelength 00= 850.0 nm enters the end of an optical= 850.0 nm enters the end of an optical
fiber from air at an angle of 20.5fiber from air at an angle of 20.5oo with respect to the normal. with respect to the normal.Its wavelength inside the fiber is 574.3 nm. Its wavelength inside the fiber is 574.3 nm. A. What is the index of refraction inside the fiber? A. What is the index of refraction inside the fiber? B. What is the angle between the light ray and the normal inside the B. What is the angle between the light ray and the normal inside the fiber? fiber? C. Assuming the end of the fiber is perpendicular to its upper edge, whatC. Assuming the end of the fiber is perpendicular to its upper edge, whatis the angle between the light ray and the surface when the light reachesis the angle between the light ray and the surface when the light reachesthe upper edge? the upper edge? D. If the index of refraction outside the upper edge of the fiber is 1.44,D. If the index of refraction outside the upper edge of the fiber is 1.44,what is the angle between the light and the normal to the surface as itwhat is the angle between the light and the normal to the surface as itexits the upper edge?exits the upper edge?
Numerical Aperture (NA)Numerical Aperture (NA)
http://www.us.schott.com/fiberoptics/english/company/index.html#http://www.us.schott.com/fiberoptics/english/company/index.html#..
NA: A dimensionless number that characterizes the range ofangles over which the system can accept or emit light
offcutoutsideNA sin offcutoutsideNA sin
outside
Cut-off Angle: This maximum value for the angle of incidence onthe fiber that experiences TIR is called the cut-off angle.
Are you getting the concept?Are you getting the concept?
Consider an optical fiber having a core index of 1.46 and acladding index of 1.45. What is the critical angle for this core-
cladding interface? For what range of angles inside the fiber atthe entrance to the fiber (2) will light be totally internally reflectedat the upper edge of the fiber? To what range of incidenceangles (1) does this correspond? What is the numerical apertureof this fiber?
Evanescent Waves in Fiber OpticsEvanescent Waves in Fiber Optics
http://www.olympusmicro.com/primer/java/tirf/evaintensityhttp://www.olympusmicro.com/primer/java/tirf/evaintensity // http://www.photonics.cusat.edu/
d
z
eIzI
0)( d
z
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0)(
Evanescent Waves for TIR MicroscopyEvanescent Waves for TIR Microscopy
http://www.olympusmicro.com/primer/java/tirf/penetration/index.htmlhttp://www.olympusmicro.com/primer/java/tirf/penetration/index.html
2123
22
0
sin4 cf
p
nnd
2123
22
0
sin4 cf
p
nnd