Psych Solutions
-
Upload
ganesh-ayer -
Category
Documents
-
view
226 -
download
0
Transcript of Psych Solutions
-
7/29/2019 Psych Solutions
1/22
File:Psych1HeatCoil.EES 10/21/2003 3:41:38 PM Page 1
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
"AREN 3010
In-Class Psychrometric Problem #1"
"
Moist air enters a heating coil at 40F dry-bulb temperature
and 36F wet-bulb temperature at a rate of 2000 cfm.
Barometric pressure is 14.696 psia. The air leaves the
coil at a dry-bulb temperature of 140F. "
"Given information"
P_atm = 14.696
T_sa = 140
T_ma = 40
TWB_ma = 36CFM_ma = 2000
TW_ent = 180
TW_lvg = 160
T_steam = 250
"Calculate properties of mixed air"
W_ma = HUMRAT(AIRH2O,t=T_ma, b=TWB_ma,p=P_atm)
h_ma = ENTHALPY(AIRH2O,t=T_ma, w=W_ma,p=P_atm)
v_ma = VOLUME(AIRH2O,t=T_ma, w=W_ma,p=P_atm)
c_p = SPECHEAT(AIRH2O,t=T_ma,w=W_ma,p=P_atm)
"a) How much heat is added to the air?"
m_sa = CFM_ma/v_ma*CONVERT(hr,min)
h_sa = ENTHALPY(AIRH2O,t=T_sa, w=W_ma,p=P_atm)
Q_air = m_sa*(h_sa-h_ma)
Q_airT = m_sa*c_p*(T_sa-T_ma)
"b) If the heat is provided by hot water that enters the coil at 180F
and leaves at 160F, what is the water flow rate?"
c_WATER = SPECHEAT(WATER,t=TW_ent,p=P_atm)
m_w = Q_air/(c_WATER*(TW_ent-TW_lvg))
"c) If the heat is provided by a steam coil with saturated steam at 250F,
what steam flow rate is required?
-
7/29/2019 Psych Solutions
2/22
File:Psych1HeatCoil.EES 10/21/2003 3:41:39 PM Page 2
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
Assume that the steam leaves the coil as a saturated liquid?"
hfg_steam = ENTHALPY(STEAM,t=T_steam,x=1)-ENTHALPY(STEAM,t=T_steam,x=0)
m_steam = Q_air/hfg_steam
AREN 3010
In-Class Psychrometric Problem #1
Moist air enters a heating coil at 40F dry-bulb temperature
and 36F wet-bulb temperature at a rate of 2000 cfm.
Barometric pressure is 14.696 psia. The air leaves the
coil at a dry-bulb temperature of 140F.
Given information
Patm = 14.696
Tsa = 140
Tma = 40
TWBma = 36
CFMma = 2000
TWent = 180
TW lvg = 160
Tsteam = 250
Calculate properties of mixed air
Wma = 'AirH2O' , T = Tma , B = TWBma , P = Patm
hma = h 'AirH2O' , T = Tma , w = W ma , P = Patm
vma = v 'AirH2O' , T = Tma , w = W ma , P = Patm
cp = Cp 'AirH2O' , T = Tma , w = Wma , P = Patm
a) How much heat is added to the air?
msa =CFMma
vma 60
min
hr
hsa = h 'AirH2O' , T = Tsa , w = W ma , P = Patm
Qair = msa hsa hma
QairT = msa cp Tsa Tma
b) If the heat is provided by hot water that enters the coil at 180F
and leaves at 160F, what is the water flow rate?
cWATER = Cp 'Water' , T = TWent , P = Patm
-
7/29/2019 Psych Solutions
3/22
File:Psych1HeatCoil.EES 10/21/2003 3:41:39 PM Page 3
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
mw =Qair
cWATER TW ent TW lvg
c) If the heat is provided by a steam coil with saturated steam at 250F,
what steam flow rate is required?
Assume that the steam leaves the coil as a saturated liquid?
hfgsteam = h 'Steam' , T = Tsteam , x = 1 h 'Steam' , T = Tsteam , x = 0
msteam =Qair
hfgsteam
Unit Settings: [F]/[psia]/[lbm]/[degrees]
CFMma = 2000 [cfm] cp = 0.2419 [Btu/lbm-R] cWATER = 1.002 [Btu/lbm-R]
hfgsteam = 945.5 [Btu/lbm] hma = 13.42 [Btu/lbm] hsa = 37.62 [Btu/lbm]
msa = 9473 [lbm
/hr] msteam = 242.4 [lbm
/hr] mw = 11435 [lbm
/hr]
Patm = 14.7 [psia] Qair = 229218 [Btu/hr] QairT = 229162 [Btu/hr]
TWBma = 36 [F] TWent = 180 [F] TWlvg = 160 [F]
Tma = 40 [F] Tsa = 140 [F] Tsteam = 250 [F]
vma = 12.67 [ft3/lbm] Wma = 0.003532
No unit consistency or conversion problems were detected.
-
7/29/2019 Psych Solutions
4/22
File:Psych2ZoneHeat.EES 10/21/2003 3:50:04 PM Page 1
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
"AREN 3010
In-Class Psychrometric Problem #2"
"A building space is to be maintained at 70F dry-bulb and 30% RH
when the barometric pressure is 14.696 psia. The total heating load
on the space has been calculated to be 60,000 Btu/hr.
Supply air is delivered to the space at a temperature of 120F "
"Given information"
P_atm = 14.696
T_sa = 120T_ra = 70
RH_ra = .3
Q_heat = 60000
Q_fan = 400*CONVERT(W,Btu/hr)
"Calculate properties of outdoor and return air"
W_ra = HUMRAT(AIRH2O,t=T_ra, r=RH_ra,p=P_atm)
v_ra = VOLUME(AIRH2O,t=T_ra, w=W_ra,p=P_atm)
v_sa = VOLUME(AIRH2O,t=T_sa, w=W_ra,p=P_atm)
c_p = SPECHEAT(AIRH2O,t=T_ra,w=W_ra,p=P_atm)
"a) What is the volumetric airf low required for the space?"
m_sa=Q_heat /(c_p*(T_sa-T_ra))
CFM_sa = m_sa*v_sa/CONVERT(hr,min)
CFM_ra = m_sa*v_ra/CONVERT(hr,min)
"b) What is the discharge air temperature?"
T_da = T_sa-Q_fan/(m_sa*c_p)
AREN 3010
In-Class Psychrometric Problem #2
A building space is to be maintained at 70F dry-bulb and 30% RH
when the barometric pressure is 14.696 psia. The total heating load
on the space has been calculated to be 60,000 Btu/hr.Supply air is delivered to the space at a temperature of 120F
-
7/29/2019 Psych Solutions
5/22
File:Psych2ZoneHeat.EES 10/21/2003 3:50:05 PM Page 2
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
Given information
Patm = 14.696
Tsa = 120
Tra = 70
RH ra = 0.3
Qheat = 60000
Q fan = 400 3.41214 Btu/hr
W
Calculate properties of outdoor and return air
W ra = 'AirH2O' , T = Tra , R =RH ra , P = Patm
v ra = v 'AirH2O' , T = Tra , w = W ra , P = Patm
vsa = v 'AirH2O' , T = Tsa , w = W ra , P = Patm
cp = Cp 'AirH2O' , T = Tra , w = W ra , P = Patm
a) What is the volumetric airflow required for the space?
msa =Qheat
cp Tsa Tra
CFMsa = msa vsa
60 min
hr
CFMra = msa v ra
60 min
hr
b) What is the discharge air temperature?
Tda = Tsa Q fan
msa cp
Unit Settings: [F]/[psia]/[lbm]/[degrees]
CFMra = 1110 [cfm] CFMsa = 1214 [cfm] cp = 0.2425 [Btu/lbm-R]
msa = 4949 [lbm/hr] Patm = 14.7 [psia] Qfan = 1365 [Btu/hr]
Qheat = 60000 [Btu/hr] RHra = 0.3 Tda = 118.9 [F]
Tra = 70 [F] Tsa = 120 [F] vra = 13.45 [ft3/lbm]
vsa = 14.72 [ft3/lbm] Wra = 0.004648
No unit consistency or conversion problems were detected.
-
7/29/2019 Psych Solutions
6/22
-
7/29/2019 Psych Solutions
7/22
File:Psych3CoolCoil.EES 10/21/2003 12:01:00 PM Page 1
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
"AREN 3010
In-Class Psychrometric Problem #3"
"
Moist air enters a cooling coil at 78F dry-bulb temperature and
50% RH at a rate of 2400 cfm. Barometric pressure is 14.696 psia.
The air leaves the coil at a dry-bulb temperature of 55F and a
dew-point temperature of 53F. The condensate leaves at a
temperature of 52F. "
"Given information"
P_atm = 14.696
T_da = 55
TDP_da = 53
T_ma = 78
RH_ma = .5
CFM_ma = 2400T_cond = 52
"Calculate properties of mixed and supply air"
W_ma = HUMRAT(AIRH2O,t=T_ma, r=RH_ma,p=P_atm)
h_ma = ENTHALPY(AIRH2O,t=T_ma, w=W_ma,p=P_atm)
v_ma = VOLUME(AIRH2O,t=T_ma, w=W_ma,p=P_atm)
W_da = HUMRAT(AIRH2O,t=T_da, d=TDP_da,p=P_atm)
h_da = ENTHALPY(AIRH2O,t=T_da, w=W_da,p=P_atm)
c_p = SPECHEAT(AIRH2O,t=T_ma,w=W_ma,p=P_atm)
"a) What is the total load on the coil?"
m_sa = CFM_ma/v_ma*CONVERT(hr,min)
h_cond = ENTHALPY(WATER,t=T_cond,p=P_atm)
m_cond = m_sa*(W_ma-W_da)
Q_totExact = m_sa*(h_ma-h_da)-m_cond*h_cond
Q_tot=m_sa*(h_ma-h_da)
Error_Q = (Q_tot-Q_totExact)/Q_totExact
"b) What is the sensible heat ratio?"
Q_sen = m_sa*c_p*(T_ma-T_da)
SHR = Q_sen/Q_tot
"c) What are the supply air conditions?"
Q_fan = 1200*CONVERT(W,Btu/hr)
-
7/29/2019 Psych Solutions
8/22
File:Psych3CoolCoil.EES 10/21/2003 12:01:00 PM Page 2
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
T_sa = T_da+Q_fan/(m_sa*c_p)
W_sa = W_da
AREN 3010
In-Class Psychrometric Problem #3
Moist air enters a cooling coil at 78F dry-bulb temperature and
50% RH at a rate of 2400 cfm. Barometric pressure is 14.696 psia.
The air leaves the coil at a dry-bulb temperature of 55F and a
dew-point temperature of 53F. The condensate leaves at a
temperature of 52F.
Given information
Patm = 14.696
Tda = 55
TDPda = 53
Tma = 78
RHma = 0.5
CFMma = 2400
Tcond = 52
Calculate properties of mixed and supply air
Wma = 'AirH2O' , T = Tma , R = RHma , P = Patm
hma = h 'AirH2O' , T = Tma , w = W ma , P = Patm
vma = v 'AirH2O' , T = Tma , w = W ma , P = Patm
W da = 'AirH2O' , T = Tda , D =TDPda , P = Patm
hda = h 'AirH2O' , T = Tda , w = W da , P = Patm
cp = Cp 'AirH2O' , T = Tma , w = Wma , P = Patm
a) What is the total load on the coil?
msa =CFMma
vma 60
min
hr
hcond = h 'Water' , T = Tcond , P = Patm
mcond = msa W ma W da
Q totExact = msa hma hda mcond hcond
Q tot = msa hma hda
-
7/29/2019 Psych Solutions
9/22
File:Psych3CoolCoil.EES 10/21/2003 12:01:00 PM Page 3
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
ErrorQ =Q tot Q totExact
Q totExact
b) What is the sensible heat ratio?
Qsen = msa cp Tma Tda
SHR =Qsen
Q tot
c) What are the supply air conditions?
Q fan = 1200 3.41214 Btu/hr
W
Tsa = Tda +Q fan
msa cp
W sa = W da
Unit Settings: [F]/[psia]/[lbm]/[degrees]
CFMma = 2400 [cfm] cp = 0.2449 [Btu/lbm-R] Error Q = 0.004553
hcond = 20.09 [Btu/lbm] hda = 22.48 [Btu/lbm] hma = 29.94 [Btu/lbm]
mcond = 17.58 [lbm/hr] msa = 10452 [lbm/hr] Patm = 14.7 [psia]
Qfan = 4095 [Btu/hr] Qsen = 58866 [Btu/hr] Qtot = 77949 [Btu/hr]
QtotExact = 77596 [Btu/hr] RHma = 0.5 SHR = 0.7552
TDPda = 53 [F] Tcond = 52 Tda = 55 [F]
Tma = 78 [F] Tsa = 56.6 [F] vma = 13.78 [ft3/lbm]
Wda = 0.008539 Wma = 0.01022 Wsa = 0.008539
No unit consistency or conversion problems were detected.
-
7/29/2019 Psych Solutions
10/22
-
7/29/2019 Psych Solutions
11/22
File:Psych4Mix.EES 10/21/2003 9:26:57 AM Page 1
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
"AREN 3010
In-Class Psychrometric Problem #4"
"
Outdoor air is mixed with building return air in a mixing chamber
prior to conditioning. The outdoor air is at 90F and 40% RH with
an airflow of 1000 cfm. The return air is 80F and 67F wet-bulb with
an airflow rate of 3000 cfm. "
"Given information"
P_atm = 14.696
T_ra = 80
TWB_ra = 65
cfm_ra = 3000T_oa = 90
RH_oa = .4
cfm_oa = 1000
"Calculate properties of outdoor and return air"
h_ra = ENTHALPY(AIRH2O,t=T_ra, b=TWB_ra,p=P_atm)
W_ra = HUMRAT(AIRH2O,t=T_ra, b=TWB_ra,p=P_atm)
v_ra = VOLUME(AIRH2O,t=T_ra, b=TWB_ra,p=P_atm)
h_oa = ENTHALPY(AIRH2O,t=T_oa, r=RH_oa,p=P_atm)
W_oa = HUMRAT(AIRH2O,t=T_oa, r=RH_oa,p=P_atm)
v_oa = VOLUME(AIRH2O,t=T_oa, r=RH_oa,p=P_atm)
"What is the mixed air condition?"
m_oa = cfm_oa/v_oa*CONVERT(hr,min)
m_ra = cfm_ra/v_ra*CONVERT(hr,min)
m_ma = m_oa+m_ra
OA_frac = m_oa/m_ma
h_ma = OA_frac*h_oa + (1-OA_frac)*h_ra
W_ma = OA_frac*W_oa + (1-OA_frac)*W_ra
T_ma = TEMPERATURE(AIRH2O,h=h_ma,w=W_ma,p=P_atm)
v_ma = VOLUME(AIRH2O,T=T_ma,w=W_ma,p=P_atm)
cfm_ma = m_ma*v_ma/CONVERT(hr,min)
AREN 3010
In-Class Psychrometric Problem #4
-
7/29/2019 Psych Solutions
12/22
File:Psych4Mix.EES 10/21/2003 9:26:57 AM Page 2
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
Outdoor air is mixed with building return air in a mixing chamber
prior to conditioning. The outdoor air is at 90F and 40% RH with
an airflow of 1000 cfm. The return air is 80F and 67F wet-bulb with
an airflow rate of 3000 cfm.
Given information
Patm = 14.696
Tra = 80
TWB ra = 65
cfmra = 3000
Toa = 90
RHoa = 0.4
cfmoa = 1000
Calculate properties of outdoor and return air
h ra = h 'AirH2O' , T = Tra , B = TWBra , P = Patm
W ra = 'AirH2O' , T = Tra , B =TWBra , P = Patm
v ra = v 'AirH2O' , T = Tra , B = TWBra , P = Patm
hoa = h 'AirH2O' , T = Toa , R =RHoa , P = Patm
W oa = 'AirH2O' , T = Toa , R =RHoa , P = Patm
voa = v 'AirH2O' , T = Toa , R = RHoa , P = Patm
What is the mixed air condition?
moa =cfmoa
voa 60
min
hr
m ra =
cfmra
v ra 60
min
hr
mma = moa + m ra
OA frac =moa
mma
hma = OA frac hoa + 1 OA frac h ra
Wma = OA frac W oa + 1 OA frac W ra
Tma = T 'AirH2O' , h = hma , w = W ma , P = Patm
-
7/29/2019 Psych Solutions
13/22
File:Psych4Mix.EES 10/21/2003 9:26:57 AM Page 3
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
vma = v 'AirH2O' , T = Tma , w = W ma , P = Patm
cfmma = mma vma
60 min
hr
Unit Settings: [F]/[psia]/[lbm]/[degrees]
cfmma = 4000.005 [cfm] cfmoa = 1000 [cfm] cfmra = 3000 [cfm]
hma = 31.14 [Btu/lbm] hoa = 34.91 [Btu/lbm] hra = 29.91 [Btu/lbm]
mma = 17274 [lbm/hr] moa = 4248 [lbm/hr] mra = 13027 [lbm/hr]
OAfrac = 0.2459 Patm = 14.7 [psia] RHoa = 0.4
TWBra = 65 [F] Tma = 82.47 [F] Toa = 90 [F]
Tra = 80 [F] vma = 13.89 [ft3/lbm] voa = 14.13 [ft
3/lbm]
vra = 13.82 [ft3/lbm] Wma = 0.01031 Woa = 0.01206
Wra = 0.009743
No unit consistency or conversion problems were detected.
-
7/29/2019 Psych Solutions
14/22
-
7/29/2019 Psych Solutions
15/22
File:Psych5OneZone.EES 10/21/2003 9:28:52 AM Page 1
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
"AREN 3010
In-Class Psychrometric Problem #5"
"
A building space is to be maintained at 78F dry-bulb and 65F wet-bulb.
The total cooling load on the space has been calculated to be 60,000 Btu/hr
of which 42,000 Btu/hr is sensible heat gain. Supply air is delivered to the
space at a temperature of 58F. For acceptable air quality, 500 cfm of
outside air is required. Outdoor conditions are 90F and 50% RH. "
"Given information"P_atm = 14.696
T_sa = 58
T_ra = 78
TWB_ra = 65
T_oa = 90
RH_oa = .5
cfm_oa = 500
Q_sen = 42000
Q_tot = 60000
"Calculate properties of outdoor and return air"
h_ra = ENTHALPY(AIRH2O,t=T_ra, b=TWB_ra,p=P_atm)
W_ra = HUMRAT(AIRH2O,t=T_ra, b=TWB_ra,p=P_atm)
h_oa = ENTHALPY(AIRH2O,t=T_oa, r=RH_oa,p=P_atm)
W_oa = HUMRAT(AIRH2O,t=T_oa, r=RH_oa,p=P_atm)
v_oa = VOLUME(AIRH2O,t=T_oa, r=RH_oa,p=P_atm)
c_p = SPECHEAT(AIRH2O,t=T_ra,b=TWB_ra,p=P_atm)
"a) What is the airflow required for the space?"
m_sa=Q_sen /(c_p*(T_ra-T_sa))
"b)What is the supply air humidity ratio?"
h_sa = h_ra - Q_tot / m_sa
W_sa = HUMRAT(AIRH2O,t=T_sa, h=h_sa,p=P_atm)
-
7/29/2019 Psych Solutions
16/22
File:Psych5OneZone.EES 10/21/2003 9:28:53 AM Page 2
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
"c) What is the capacity of the cooling coil?"
m_oa = cfm_oa/v_oa*CONVERT(hr,min)
OA_frac = m_oa/m_sa
h_ma = OA_frac*h_oa + (1-OA_frac)*h_ra
W_ma = OA_frac*W_oa + (1-OA_frac)*W_ra
Q_coil = m_sa*(h_ma - h_sa)
"d) What is the sensible heat ratio of the cooling coil?"
T_ma = TEMPERATURE(AIRH2O,h=h_ma,w=W_ma,p=P_atm)
Q_scoil = m_sa*c_p*(T_ma - T_sa)
SHR_coil = Q_scoil/Q_coil
AREN 3010
In-Class Psychrometric Problem #5
A building space is to be maintained at 78F dry-bulb and 65F wet-bulb.
The total cooling load on the space has been calculated to be 60,000 Btu/hr
of which 42,000 Btu/hr is sensible heat gain. Supply air is delivered to the
space at a temperature of 58F. For acceptable air quality, 500 cfm of
outside air is required. Outdoor conditions are 90F and 50% RH.
Given information
Patm = 14.696
Tsa = 58
Tra = 78
TWB ra = 65
Toa = 90
RHoa = 0.5
cfmoa = 500
Qsen = 42000
Q tot = 60000
Calculate properties of outdoor and return air
h ra = h 'AirH2O' , T = Tra , B = TWBra , P = Patm
W ra = 'AirH2O' , T = Tra , B =TWBra , P = Patm
hoa = h 'AirH2O' , T = Toa , R =RHoa , P = Patm
W oa = 'AirH2O' , T = Toa , R =RHoa , P = Patm
voa = v 'AirH2O' , T = Toa , R = RHoa , P = Patm
cp = Cp 'AirH2O' , T = Tra , B = TWBra , P = Patm
-
7/29/2019 Psych Solutions
17/22
File:Psych5OneZone.EES 10/21/2003 9:28:53 AM Page 3
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
a) What is the airflow required for the space?
msa =Qsen
cp Tra Tsa
b)What is the supply air humidity ratio?
hsa = h ra Q tot
msa
W sa = 'AirH2O' , T = Tsa , h = hsa , P = Patm
c) What is the capacity of the cooling coil?
moa =cfmoa
voa 60
min
hr
OA frac =moa
msa
hma = OA frac hoa + 1 OA frac h ra
Wma = OA frac W oa + 1 OA frac W ra
Qcoil = msa hma hsa
d) What is the sensible heat ratio of the cooling coil?
Tma = T 'AirH2O' , h = hma , w = W ma , P = Patm
Qscoil = msa cp Tma Tsa
SHRcoil =Qscoil
Qcoil
Unit Settings: [F]/[psia]/[lbm]/[degrees]
cfmoa = 500 [cfm] cp = 0.2449 [Btu/lbm-R] hma = 31.99 [Btu/lbm]
hoa = 38.31 [Btu/lbm] hra = 29.92 [Btu/lbm] hsa = 22.93 [Btu/lbm]
moa = 2114 [lbm/hr] msa = 8576 [lbm/hr] OAfrac = 0.2464
Patm = 14.7 [psia] Qcoil = 77720 [Btu/hr] Qscoil = 48251 [Btu/hr]
Qsen
= 42000 [Btu/hr] Qtot
= 60000 [Btu/hr] RHoa
= 0.5
SHRcoil = 0.6208 TWBra = 65 [F] Tma = 80.98 [F]
Toa = 90 [F] Tra = 78 [F] Tsa = 58 [F]
voa = 14.19 [ft3/lbm] Wma = 0.01142 Woa = 0.01515
Wra = 0.0102 Wsa = 0.008272
No unit consistency or conversion problems were detected.
-
7/29/2019 Psych Solutions
18/22
-
7/29/2019 Psych Solutions
19/22
File:Psych6OneZoneOffDesign.EES 10/21/2003 9:29:37 AM Page 1
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
"AREN 3010
In-Class Psychrometric Problem #6"
"
A building space is to be maintained at 78F dry-bulb temperature.
The total cooling load on the space has been calculated to be 30,000 Btu/hr
of which 27,000 Btu/hr is sensible heat gain. Supply air is delivered to the
space at 58F and 90% RH. The outdoor air mass flow rate is 25% of the total
supply mass flow rate. Outdoor conditions are 80F and 55% RH. "
"Given information"P_atm = 14.696
T_sa = 58
RH_sa = .90
T_ra = 78
T_oa = 80
RH_oa = .55
OA_frac = .25
Q_sen = 27000
Q_tot = 30000
"Calculate properties of outdoor and return air"
W_sa = HUMRAT(AIRH2O,t=T_sa, r=RH_sa,p=P_atm)
h_sa = ENTHALPY(AIRH2O,t=T_sa, w=W_sa,p=P_atm)
h_oa = ENTHALPY(AIRH2O,t=T_oa, r=RH_oa,p=P_atm)
W_oa = HUMRAT(AIRH2O,t=T_oa, r=RH_oa,p=P_atm)
v_oa = VOLUME(AIRH2O,t=T_oa, r=RH_oa,p=P_atm)
c_p = SPECHEAT(AIRH2O,t=T_ra,r=.5,p=P_atm)
"a) What is the airflow required for the space?"
m_sa=Q_sen /(c_p*(T_ra-T_sa))
"b)What is the zone air humidity ratio?"
h_sa = h_ra - Q_tot / m_sa
W_ra = HUMRAT(AIRH2O,t=T_ra, h=h_ra,p=P_atm)
-
7/29/2019 Psych Solutions
20/22
File:Psych6OneZoneOffDesign.EES 10/21/2003 9:29:37 AM Page 2
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
"c) What is the capacity of the cooling coil?"
OA_frac = m_oa/m_sa
h_ma = OA_frac*h_oa + (1-OA_frac)*h_ra
W_ma = OA_frac*W_oa + (1-OA_frac)*W_ra
Q_coil = m_sa*(h_ma - h_sa)
"d) What is the sensible heat ratio of the cooling coil?"
T_ma = TEMPERATURE(AIRH2O,h=h_ma,w=W_ma,p=P_atm)
Q_scoil = m_sa*c_p*(T_ma - T_sa)
SHR_coil = Q_scoil/Q_coil
AREN 3010
In-Class Psychrometric Problem #6
A building space is to be maintained at 78F dry-bulb temperature.
The total cooling load on the space has been calculated to be 30,000 Btu/hr
of which 27,000 Btu/hr is sensible heat gain. Supply air is delivered to the
space at 58F and 90% RH. The outdoor air mass flow rate is 25% of the total
supply mass flow rate. Outdoor conditions are 80F and 55% RH.
Given information
Patm = 14.696
Tsa = 58
RHsa = 0.9
Tra = 78
Toa = 80
RHoa = 0.55
OA frac = 0.25
Qsen = 27000
Q tot = 30000
Calculate properties of outdoor and return air
W sa = 'AirH2O' , T = Tsa , R =RHsa , P = Patm
hsa = h 'AirH2O' , T = Tsa , w = W sa , P = Patm
hoa = h 'AirH2O' , T = Toa , R =RHoa , P = Patm
W oa = 'AirH2O' , T = Toa , R =RHoa , P = Patm
voa = v 'AirH2O' , T = Toa , R = RHoa , P = Patm
cp = Cp 'AirH2O' , T = Tra , R = 0.5 , P = Patm
a) What is the airflow required for the space?
-
7/29/2019 Psych Solutions
21/22
File:Psych6OneZoneOffDesign.EES 10/21/2003 9:29:38 AM Page 3
EES Ver. 6.867: #317: CEAE University of Colorado, Boulder
msa =Qsen
cp Tra Tsa
b)What is the zone air humidity ratio?
hsa = h ra Q tot
msa
W ra = 'AirH2O' , T = Tra , h = h ra , P = Patm
c) What is the capacity of the cooling coil?
OA frac =moa
msa
hma = OA frac hoa + 1 OA frac h ra
Wma = OA frac W oa + 1 OA frac W ra
Qcoil = msa hma hsa
d) What is the sensible heat ratio of the cooling coil?
Tma = T 'AirH2O' , h = hma , w = W ma , P = Patm
Qscoil = msa cp Tma Tsa
SHRcoil =Qscoil
Qcoil
Unit Settings: [F]/[psia]/[lbm]/[degrees]
cp = 0.2449 [Btu/lbm-R] hma = 30.16 [Btu/lbm] hoa = 32.42 [Btu/lbm]
hra = 29.4 [Btu/lbm] hsa = 23.96 [Btu/lbm] moa = 1378 [lbm/hr]
msa = 5513 [lbm/hr] OAfrac = 0.25 Patm = 14.7 [psia]
Qcoil = 34165 [Btu/hr] Qscoil = 27677 [Btu/hr] Qsen = 27000 [Btu/hr]
Qtot = 30000 [Btu/hr] RHoa = 0.55 RHsa = 0.9
SHRcoil = 0.8101 Tma = 78.5 [F] Toa = 80 [F]
Tra = 78 [F] Tsa = 58 [F] voa = 13.87 [ft3/lbm]
Wma = 0.01031 Woa = 0.01204 Wra = 0.009731
Wsa
= 0.009226
No unit consistency or conversion problems were detected.
-
7/29/2019 Psych Solutions
22/22