January 2016 - Jerry Dwyerjerrydwyer.com/pdf/Clemson/Topic1Estimation.pdfI Clemson University from...
Transcript of January 2016 - Jerry Dwyerjerrydwyer.com/pdf/Clemson/Topic1Estimation.pdfI Clemson University from...
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Time-series EconometricsEstimation and Inference
Gerald P. Dwyer
Clemson University
January 2016
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Outline
1 About Me
2 Time-Series Econometrics – What will you learn?What is time-series econometrics?What is financial econometrics?Topics Covered
3 Inference and EstimationMinimum Variance Unbiased EstimationConsistency
4 Maximum Likelihood
5 Bayesian Inference in Econometrics
6 Summary
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Who Am I?
Professor
I Clemson University from 1989 to 1999 and 2013 to todayI Teach Financial Econometrics to MsC in Finance students at Trinity
College, Dublin
Federal Reserve Bank of Atlanta from 1997 to 2012
Research
Brief summary
http://www.jerrydwyer.com
Use [email protected] for this course
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What is Time-Series Econometrics?
Time-series econometrics is the use of time-series data to answereconomic questions using statistical procedures
What sorts of questions?
I How are money growth and inflation related over time?
F Not across countries – will not talk about panel data
I Is inflation in the United States likely to increase?
F Statistical analysis to inform an economic analysis
I How likely is it that a portfolio will lose 20 percent of its value in anygiven 12-month period?
I Does real GDP have a predictable trend? What sort of trend?Constant or time varying?
I What is the effect of a recession on stock prices?I Is the value of the euro likely to go up or down? What does it depend
on?
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What is Financial Econometrics?
Financial econometrics is the use of statistical procedures to answerfinancial questions
I Neither a subset of time-series econometrics nor a superset
F Can use cross-section dataF Some questions the same, some not
What sorts of questions?
I What factors affect stock returns and how much do they do so?I How likely is it that a portfolio will lose 20 percent of its value in any
given 12-month period?I Are stock prices mean reverting? Are stock returns mean reverting?I What is the effect of a recession on stock prices?I Is the value of the euro likely to go up or down? What does it depend
on?
Mostly time series data
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Topics covered
Estimation
Difference equations
Univariate time series (ARIMA)
Unit roots
Volatility (ARCH and GARCH)
Multivariate time series (Vector autoregressions)
Simultaneous-equation analysis
Cointegration and Error correction mechanisms
Nonlinear time series analysis
Bayesian analysis
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Purpose of inference
What are plausible and implausible values of estimates of a particularparameter?
I Point estimate
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Criteria for estimators
Classical statisticsI Minimum Variance Unbiased Estimators (MVUE)
F or Best Linear Unbiased Estimator (BLUE)
I Estimation proceduresF Ordinary Least Squares (OLS)F Maximum likelihood – Conditional on the data, pick the most likely
value
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OLS
Ordinary least squares with x fixed (nonstochastic)
Suppose that x is not stochasticI x is deterministic, fixed in repeated samplesI e.g. treatments of crops on plotsI time trendI quarterly dummy variables
yt = xtβ + εt , t = 1, ...,T
E yt = E xt = 0
E εt = 0, E ε2t = σ2, E εtεs = 0 ∀ t 6= s
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OLS with nonstochastic regressors is unbiased
Properties of equation
yt = xtβ + εt , t = 1, ...,T
E yt = E xt = 0
E εt = 0, E ε2t = σ2, E εtεs = 0 ∀ t 6= s
β̂ can be written
β̂ =∑ xy
∑ x2
=∑ xxβ
∑ x2+
∑ xε
∑ x2
=β +∑ xε
∑ x2
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OLS with nonstochastic regressors is unbiased
Properties of equation
yt = xtβ + εt , t = 1, ...,T
E yt = E xt = 0
E εt = 0, E ε2t = σ2, E εtεs = 0 ∀ t 6= s
β̂ can be written
β̂ =∑ xy
∑ x2
=∑ xxβ
∑ x2+
∑ xε
∑ x2
=β +∑ xε
∑ x2
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OLS with nonstochastic regressors is unbiased
And the expected value of β̂ is
E β̂ =E β + E∑ xε
∑ x2
=β +∑ x E ε
∑ x2
=β
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Why x nonstochastic?
Consider the term E ∑ xε∑ x2
in E β̂ = β + E ∑ xε∑ x2
If x is not random, then
E∑ xε
∑ x2=
∑ x E ε
∑ x2
If x is random, then in general
E∑ xε
∑ x26= E ∑ xε
E ∑ x26= ∑
(E
[x
∑ x2
]E ε
)
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Why unbiased if x nonstochastic?
Expectations operator is a linear operator
If a is a constant, thenE ax = aE x
If x∑ x2
is a constant, then
Exε
∑ x2=
x
∑ x2E ε
In general,
Exε
∑ x26= E (xε)
E ∑ x2and E
xε
∑ x26= E
[x
∑ x2
]E ε
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Right-hand side variable (x) stochastic and least squaresworks
The case with x stochastic in which least squares works: x and ε areindependent
Exε
∑ x2= E [f (x) ε] with f (x) =
x
∑ x2
E [f (x) ε] = E f (x)E ε if x and ε are independent
E f (x)E ε = 0 because E ε = 0
If x and ε are normally distributed and uncorrelated, then leastsquares is unbiased
I Sufficient but not necessary
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OLS is MVUE and BLUE
MVUE: Var[
β̂]
around true value is a minimum among estimators
that are unbiased
BLUE: β̂ is a linear function of the yt , is unbiased and has minimumvariance among unbiased estimators
I Estimator is a linear function of the yt because
β̂ =∑ xtyt
∑ x2t= ∑wtyt , wt =
xt
∑ x2t
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Least squares and error term
One way to see why E ∑ xε = 0 is required for unbiasedness:
What is the correlation of the error term and right-hand-side variablesin a computed regression?
It is identically zero (for any correct program)
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Least squares and error term
One way to see why E ∑ xε = 0 is required for unbiasedness:
What is the correlation of the error term and right-hand-side variablesin a computed regression?
It is identically zero (for any correct program)
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Proof that OLS error term has zero correlation withright-hand-side variables
Proof of exactly zero correlation of right-hand-side variables and errorterm
Consider the regressionyt = bxt + et
No constant term: Either means of variables zero or variables aredeviations from their means
Assertion to be proved: ∑ xe = 0
By definitione = y − bx
OLS coefficient b always is
b =∑ xy
∑ x2
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Proof that OLS error term has zero correlation withright-hand-side variables
Have
e =y − bx
b =∑ xy
∑ x2
Therefore
∑ xe = ∑ x (y − bx)
= ∑ xy − b∑ x2
= ∑ xy − ∑ xy
∑ x2 ∑ x2
= ∑ xy −∑ xy = 0
Therefore computed covariance of x and e is zero to machineprecision
And the correlation of x and e is zero as well
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Unbiasedness in a time series setting
Unbiasedness will hardly come up in this class
Why?
Time series regression with dependence on past valuesI yt = βyt−1 + εt , t = 1, ...,T
F Assume that yt−1 and εt are independentF Correlation of yt−1 and εt is zeroF Implies that E yt−1εt = 0
The data are an ordered sequence of observations from 1 to T
The equation above is called a first-order autoregressionI y0I ↓I y1 ← ε1
I ↓I y2 ← ε2I ...
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Unbiasedness in a time series setting
Unbiasedness will hardly come up in this class
Why?
Time series regression with dependence on past valuesI yt = βyt−1 + εt , t = 1, ...,T
F Assume that yt−1 and εt are independentF Correlation of yt−1 and εt is zeroF Implies that E yt−1εt = 0
The data are an ordered sequence of observations from 1 to T
The equation above is called a first-order autoregressionI y0I ↓I y1 ← ε1I ↓I y2 ← ε2I ...
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OLS an unbiased estimator?
Ordinary Least Squares (OLS) estimator for an autoregression?
β̂ =∑ ytyt−1
∑ y2t−1
=∑ βyt−1yt−1
∑ y2t−1+
∑ εtyt−1
∑ y2t−1
=β +∑ εtyt−1
∑ y2t−1
yt−1 not fixed in repeated samplesI Can’t have different εt and same set of y ’s ∀ t = 1, ...,TI For example, a different ε2 implies a different y2 and a different y2
implies a different y3, and so on
So the set of observations on the right-hand-side variable, yt−1, mustbe stochastic
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OLS an unbiased estimator?
Just because yt−1 is stochastic doesn’t mean that OLS is not unbiased
β̂ = β +∑ εtyt−1
∑ y2t−1
Seems like yt−1 and εt are independent and they areI By assumption, εt is independent of yt−1
But yt depends on εt , and so does yt+1, yt+2, etc.
E β̂ =β + E∑ εtyt−1
∑ y2t−1
=β + ∑ E
[(yt−1
∑ y2t−1
)εt
]εt and ∑T
t=1 y2t−1 cannot be independent and β̂ is not an unbiased
estimator in general
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Unbiasedness in a time series context
In general, estimators are not unbiased in a time series contextbecause they’re part of a sequence
I What happens in the future depends on what happened in the past
Will focus on consistency
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Bottom line on asymptotics and time series
Consistency is more pertinent than unbiasedness
The limiting distribution provides a way to estimate the variability ofthe estimator
I Some algebra can show that the mean yT of a normally distributedvariable has the asymptotic distribution N
(µ, σ2/T
)I This is the same as the finite-sample distribution in this case, but the
asymptotic distribution often is easier to find
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Simple problem of estimating the mean of a normallydistributed variable
In general, estimators are not unbiased in a time series contextbecause they’re part of a sequence but they can be unbiased ifdependence over time is unimportantSuppose y is normally distributed
y ∼ N(µ, σ2
)or can be written y ∼ NIND
(µ, σ2
)By definition
yT =∑ ytT
and s2T =∑ (yt − y)2
T − 1It’s shown in basic statistics that
E yT = µ and E s2T = σ2
Also
Var [yT ] =Var [∑ yt ]
T 2= T−2 ∑ Var [yt ]
=∑ σ2
T 2=
Tσ2
T 2=
σ2
T
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Definition of convergence in probability
Let θT be an estimator with sample size T and θ a parameter withsome particular value
Definition: θT converges in probability to a constant θ iflimT→∞ Pr (|θT − θ| > ε) = 0 ∀ ε > 0
I ε is “some constant value”, not an error term
Write plim θT = θ
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Example of consistent estimatorSuppose that θ = 0 and θT is an estimator that takes on the values 0and T
Pr (θT = 0) = 1− 1
Tand Pr (θT = T ) =
1
TTherefore
limT→∞
Pr (θT = T ) = 0
limT→∞
Pr (θT = 0) = 1
Because θ = 0,
limT→∞
Pr (|θT − θ| > ε) = 0 ∀ ε > 0
andlim
T→∞Pr (|θT − θ| < ε) = 1 ∀ ε > 0
and thereforeplim θT = 0 = θ
If θ equalled something other than zero, then θT is an inconsistentestimator of θ
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Consistency and convergence in mean square
An estimator θT is a consistent estimator of θ if and only ifplim θT = θ
Often a convenient way to prove consistency is to prove mean squareconvergence
Definition: θT converges in mean square to a constant θ withVar θT = σ2
T if
limT→∞
E θT = θ and limT→∞
σ2T = 0
I Convergence in mean square implies convergence in probabilityI Convergence in probability does not imply convergence in mean squareI In other words, an estimator can converge in probability even though it
does not converge in mean square
If θT converges in mean square to θ, then
plim θT = θ
This method of proof can be applied to easily show that the mean yTof a normally distributed variable is a consistent estimator of µ
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Properties of probability limits
Suppose have estimates aT of a parameter α and bT of a parameter β
Suppose that plim aT = α and plim bT = β
Then
plim (aT + bT ) = plim aT + plim bT = α + β
plim (aTbT ) = plim aT plim bT = αβ
plim (aT /bT ) = plim aT / plim bT = α/β if β 6= 0
This can be contrasted with the expectation operator for which, ingeneral,
E aTbT 6= αβ
E aT /bT 6= α/β
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Convergence in distribution
Want nondegenerate distribution of estimatorI If an estimator θT is a consistent estimator of θ, then estimator
converges to a constantI We want some measure of the variability of the estimatorI This is where the asymptotic distribution comes in
The asymptotic distribution of an estimator is a distribution that isused to approximate the finite-sample distribution of the estimator
Some function of the estimator converges to a distribution, theasymptotic distribution
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Limiting Distribution
Definition: If θT converges in distribution to the random variable θ,where F (θ) is the cumulative distribution function of θ, then F (θ) isthe limiting distribution of θT
Often writtenθT →d F (θ)
If F (θ) is a common form such as N(µ, σ2/T
), this is often written
asθT →d N
(µ, σ2/T
)I Proved by showing, for example, that
√T θT converges to N
(µ, σ2
)
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Bottom line on asymptotics and time series
Consistency is more pertinent than unbiasedness
The limiting distribution provides a way to estimate the variability ofthe estimator
I Some algebra can show that the mean yT of a normally distributedvariable has the asymptotic distribution N
(µ, σ2/T
)I This is the same as the finite-sample distribution in this case, but the
asymptotic distribution often is easier to find
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Maximum likelihood estimation is commonly invoked tojustify an estimator
Maximum likelihood often is a convenient way to obtain a consistentestimator
Maximum likelihood uses the distribution of the observations
Maximum likelihood obtains point estimates of the parameters as theones most likely to have generated the observations
Maximum likelihood provides a relatively straightforward way ofestimating the variance of parameters
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Maximum likelihood estimation of the parameters of anormal distribution
Have a sample of T observations, y1, y2, ..., yTSuppose they are generated independently from a normal distributionwith mean µ and variance σ2
Each observation has the distribution
1
σ (2π)1/2 exp
[− 1
2σ2(yt − µ)2
]The joint sample of T observations has the distribution
f(yt |µ, σ2
)=
1
σT (2π)T/2 exp
[− 1
2σ2
T
∑t=1
(yt − µ)2]
The likelihood function of these data and parameters is
L(µ, σ2|yt
)=
1
σT (2π)T/2 exp
[− 1
2σ2
T
∑t=1
(yt − µ)2]
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The log of the likelihood function
The likelihood function of the parameters for a normal distribution is
L(µ, σ2|yt
)=
1
σT (2π)T/2 exp
[− 1
2σ2
T
∑t=1
(yt − µ)2]
The log of the likelihood often is more convenient for exponentialdistributions such as the normal distribution
ln L(µ, σ2|yt ,
)= −T
22π − T ln σ− 1
2σ2
T
∑t=1
(yt − µ)2
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Illustration
Likelihood function
Figure: Likelihood function of normally distributed data with mean y of 2and variance s2ml = ∑ (y − y)2 /T of 1. The maximum likelihood estimatoris the mean of the normal distribution.
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Maximum likelihood estimation of mean and variance
The log of the likelihood function
ln L(µ, σ2|yt ,
)= −T
2ln 2π − T ln σ− 1
2σ2
T
∑t=1
(yt − µ)2
Maximize likelihood as a function of parameters conditional on thedata
I Can do all at once or sequentially
Want to estimate µ
Denote the estimator by a “hat” over it
Maximize by solving
∂ ln L
∂µ=
1
σ2
T
∑t=1
(yt − µ̂) = 0
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Maximum likelihood estimation of mean and variance
Maximize by solving
∂ ln L
∂µ=
1
σ2
T
∑t=1
(yt − µ̂) = 0
T
∑t=1
(yt − µ̂) = 0
T
∑t=1
yt = T µ̂
µ̂ =
T
∑t=1
yt
T= y
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Finish by finding estimator of variance
Estimator of σ2
Concentrate µ out of likelihood function by replacing it by y
ln L(σ2|yt
)=− T
2ln 2π − T ln σ− 1
2σ2
T
∑t=1
(yt − y)2
=− T
2ln 2π − T
2ln σ2 − 1
2σ2
T
∑t=1
(yt − y)2
Maximize the concentrated likelihood function with respect to σ2
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Finish by finding estimator of variance
Maximize likelihood function with respect to σ2
ln L(σ2|yt
)= −T
2ln 2π − T
2ln σ2 − 1
2σ2
T
∑t=1
(yt − y)2
Solve
∂ ln L
∂σ2= −T
2
1
σ̂2+
1
2
1
σ̂4
T
∑t=1
(yt − µ̂)2 = 0
− T +1
σ̂2
T
∑t=1
(yt − y)2 = 0
σ̂2 =
T
∑t=1
(yt − y)2
T
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Consistency and unbiasedness
µ̂ = y and σ̂2 =T
∑t=1
(yt − y)2 /T are consistent estimators of µ and
σ
I Not necessarily unbiased
I σ̂2 =T
∑t=1
(yt − y)2 /T is a biased estimator of σ2
I Not very important with enough observations
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Properties of maximum likelihood estimation commonlymentioned
Maximum likelihood provides a couple of natural estimators of thevariance of the estimatorLet θ be a parameter we have estimated
Var[θ̂]≥(
E [(∂ ln L (θ|y) /∂θ)]2)−1
where the expectation with respect to the distribution of y ’s isevaluated at the true parameterUnder regularity conditions
E [(∂ ln L (θ|y) /∂θ)]2 = −E
[∂2 ln L (θ|y)
∂θ2
]The term information matrix denotes
I = −E
[∂2 ln L (θ|y)
∂θ2
]Therefore, under regularity conditions,
Var[θ̂]= I−1
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Typical properties of maximum likelihood estimators
Let θ̂ML be the maximum likelihood of some parameter
I Suppose that the likelihood function has a single peak and a uniquemaximum
Fairly general properties
I plim θ̂ML = θI θ̂ML →d N
(θ, I−1
)I Asymptotic variance of θ̂ML is AVar
(θ̂ML
)= I−1
I Asymptotic standard deviation of θ̂ML is ASD(
θ̂ML
)I t-ratio is θ̂ML−θ
ASD(θ̂ML)∼ N (0, 1)
I Can do more complicated tests by likelihood ratio test
I −2 ln(
maxLikelihood RestrictedmaxLikelihood Unrestricted
)∼
χ2 (degrees of freedom = number of restrictions)
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Bayes rule
Foundation is Bayes rule
Combine likelihood function of parameters with prior information toget posterior distribution and conclusions
Prior – before the data
Posterior – after the data
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Bayesian analysis in Econometrics
Want to characterize knowledge about parameters
What do you think is a plausible value for a parameter?
Elasticity of demand for cars
qd = f (p, y , ...)
Elasticity is
ηqd ,y =dqd/qd
dy/y
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A somewhat obvious way to answer this question
What do you think is a plausible value of the elasticity of demand forcars with respect to income?
I Suppose have looked at no empirical studiesI Weighted average of all income elasticities is unity
I Suggests one is a plausible starting value
What is a plausible range?
Set up as “What is a plausible standard deviation of this estimate?”
Suppose approximately normally distributed so don’t have to worryabout skewness, etc.
I Speaking personally, ...I I probably would guess a standard deviation of about 0.4I Why?
I am not asserting that I am correctI I am just saying what I think is plausibleI Your prior distribution might be quite different
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A somewhat obvious way to answer this question
What do you think is a plausible value of the elasticity of demand forcars with respect to income?
I Suppose have looked at no empirical studiesI Weighted average of all income elasticities is unityI Suggests one is a plausible starting value
What is a plausible range?
Set up as “What is a plausible standard deviation of this estimate?”
Suppose approximately normally distributed so don’t have to worryabout skewness, etc.
I Speaking personally, ...I I probably would guess a standard deviation of about 0.4I Why?
I am not asserting that I am correctI I am just saying what I think is plausibleI Your prior distribution might be quite different
![Page 50: January 2016 - Jerry Dwyerjerrydwyer.com/pdf/Clemson/Topic1Estimation.pdfI Clemson University from 1989 to 1999 and 2013 to today I Teach Financial Econometrics to MsC in Finance students](https://reader033.fdocuments.net/reader033/viewer/2022042416/5f324bf1cb6c414eee48b524/html5/thumbnails/50.jpg)
A somewhat obvious way to answer this question
What do you think is a plausible value of the elasticity of demand forcars with respect to income?
I Suppose have looked at no empirical studiesI Weighted average of all income elasticities is unityI Suggests one is a plausible starting value
What is a plausible range?
Set up as “What is a plausible standard deviation of this estimate?”
Suppose approximately normally distributed so don’t have to worryabout skewness, etc.
I Speaking personally, ...I I probably would guess a standard deviation of about 0.4I Why?
I am not asserting that I am correctI I am just saying what I think is plausibleI Your prior distribution might be quite different
![Page 51: January 2016 - Jerry Dwyerjerrydwyer.com/pdf/Clemson/Topic1Estimation.pdfI Clemson University from 1989 to 1999 and 2013 to today I Teach Financial Econometrics to MsC in Finance students](https://reader033.fdocuments.net/reader033/viewer/2022042416/5f324bf1cb6c414eee48b524/html5/thumbnails/51.jpg)
A somewhat obvious way to answer this question
What do you think is a plausible value of the elasticity of demand forcars with respect to income?
I Suppose have looked at no empirical studiesI Weighted average of all income elasticities is unityI Suggests one is a plausible starting value
What is a plausible range?
Set up as “What is a plausible standard deviation of this estimate?”
Suppose approximately normally distributed so don’t have to worryabout skewness, etc.
I Speaking personally, ...I I probably would guess a standard deviation of about 0.4I Why?
I am not asserting that I am correctI I am just saying what I think is plausibleI Your prior distribution might be quite different
![Page 52: January 2016 - Jerry Dwyerjerrydwyer.com/pdf/Clemson/Topic1Estimation.pdfI Clemson University from 1989 to 1999 and 2013 to today I Teach Financial Econometrics to MsC in Finance students](https://reader033.fdocuments.net/reader033/viewer/2022042416/5f324bf1cb6c414eee48b524/html5/thumbnails/52.jpg)
A somewhat obvious way to answer this question
What do you think is a plausible value of the elasticity of demand forcars with respect to income?
I Suppose have looked at no empirical studiesI Weighted average of all income elasticities is unityI Suggests one is a plausible starting value
What is a plausible range?
Set up as “What is a plausible standard deviation of this estimate?”
Suppose approximately normally distributed so don’t have to worryabout skewness, etc.
I Speaking personally, ...I I probably would guess a standard deviation of about 0.4I Why?
I am not asserting that I am correctI I am just saying what I think is plausibleI Your prior distribution might be quite different
![Page 53: January 2016 - Jerry Dwyerjerrydwyer.com/pdf/Clemson/Topic1Estimation.pdfI Clemson University from 1989 to 1999 and 2013 to today I Teach Financial Econometrics to MsC in Finance students](https://reader033.fdocuments.net/reader033/viewer/2022042416/5f324bf1cb6c414eee48b524/html5/thumbnails/53.jpg)
Prior Distribution of Income Elasticity
−1 0 1 2 3
0.0
0.4
0.8
Prior for Income Elasticity of Demand for Cars
Den
sity
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Now get some data
What is a reasonable value of the estimated parameter after I getsome data?
Bayes rule gives me a way of combining my prior with the data
My prior distribution for the income elasticity is my prior distributionfor ηqd ,y
ηqd ,y ∼ N (µ, σ)
After I see some data, I have a distribution conditional on the data y
ηqd ,y ∼ p (µ, σ|y)
This might not be normally distribututed any more
How do I update conditional on the data?
Bayes rule
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Now get some data
What is a reasonable value of the estimated parameter after I getsome data?
Bayes rule gives me a way of combining my prior with the data
My prior distribution for the income elasticity is my prior distributionfor ηqd ,y
ηqd ,y ∼ N (µ, σ)
After I see some data, I have a distribution conditional on the data y
ηqd ,y ∼ p (µ, σ|y)
This might not be normally distribututed any more
How do I update conditional on the data?
Bayes rule
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Bayes Rule for updating parameter
Bayes rule for updating parameters conditional on data is
p(ηqd ,y |y
)=
L(ηqd ,y |y
)p(ηqd ,y
)p (y)
where p(ηqd ,y |y
)is the posterior probability distribution of values of
ηqd ,y conditional on the data
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Bayes rule is simple
Start from definition of conditional probability
pr (A,B) = pr (A|B) pr (B)
where pr (A,B) is the joint probability of two events A and Bpr (A|B) is the probability of the event A conditional on the event Bpr (B) is the probability of B
This equation defines conditional probability
pr (A|B) = pr (A,B) / pr (B) if pr (B) 6= 0
Also can saypr (A,B) = pr (B |A) pr (A)
Equate two definitions and get
pr (B |A) = pr (A|B) pr (B)
pr (A)
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Bayesian interpretation
pr (B |A) = pr (A|B) pr (B)
pr (A)
Want to draw an inference about probability of an event BI Observe some discrete event AI pr (B |A) is the probability of B conditional on observing AI pr (B) is prior probability of B – before seeing AI pr (A|B) is probability of observing A if the event B occursI pr (A) is the probability of observing A whether B occurs or notI Note that pr (A) is the unconditional probability of observing A
F pr (A) = pr (A|B) pr (B) + pr (A|not B) pr (not B)
pr (B |A) = pr (A|B) pr (B)
pr (A|B) pr (B) + pr (A|not B) pr (not B)
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Example of Bayesian analysis
pr (B |A) = pr (A|B) pr (B)
pr (A|B) pr (B) + pr (A|not B) pr (not B)
Example: B is the result that have illness, say flu
I A is some evaluation – this is the observable eventI Have a prior probability of having flu, pr (B) , say 50 percentI How informative is it if you go to doctor’s office and he says you have
the flu?I Suppose doctor says you have the flu
F 80 percent of time when you do pr (A|B)F 20 percent when you don’t pr (A|not B)
I Then the probability of your having the flu given the doctor says youdo is
.8 · .5.8 · .5 + .2 · .5 =
.40
.50= .80
I A lot of information in the doctor’s evaluation
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Other examples of Bayesian analysis
Could have a different prior probability
What is the probability that you have the flu after going to thedoctor’s if the prior probability is 0.8?
The doctor could be more or less informative
Suppose the doctor says you have the fluI 50 percent of time when you do pr (A|B)I 50 percent when you don’t pr (A|not B)
Do yourself
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Analysis in econometric context
Bayes rule
pr (B |A) = pr (A|B) pr (B)
pr (A)
Can write this in terms of discrete or continuous probabilitydistribution functions
I Let B be a parameter β and pr (B) ≡ p (β)F Might be a regression parameter
I Prior probability distribution of plausible values of a parameter βF Income elasticity of demand would be an example
I Let A be some data y we observe and pr (A|B) = p (y |β), theprobability of the data given β
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Bayesian analysis of parameter values
Posterior probability distribution of β is given by Bayes rule
p (β|y) = L (β|y) p (β)
p (y)
where p (β|y) is the posterior probability distribution of values of βconditional on the data
p (y) is a normalizing constant independent of β so this can beanalyzed using
p (β|y) ∝ L (β|y) p (β)
where ∝ means “proportional to”
Purpose is to make inferences about the posterior distribution ofparameter values
Very flexible
Coherent
Can be computationally demanding but computer time is cheap
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Comparison of classical and Bayesian analysis
Classical: Probability distribution of estimator β̂I True value is a number, zero in this case if the estimator is unbiased
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Comparison of classical and Bayesian analysis
Bayesian: Posterior probability distribution of various possible valuesof β
I True value is one of these possible values, with some more probablethan others
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Comparison of classical and Bayesian analysis
Bayesian: Posterior probability distribution of various possible valuesof β
I True value is one of these possible values, with some more probablethan others
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Interpretration of Estimate of Variability
Estimate of five percent confidence interval for a normal distribution
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Summary
Time series estimators generally cannot deliver unbiased estimators
Major concern is whether an estimator is consistent
Maximum likelihood is a commonly used estimation strategyI ConsistentI Estimator of variance readily availableI Variance usually the least possible for any estimator given assumptions
Bayesian inference is an alternative to classical statistics
Provides a more natural measure of uncertainty about the value ofparameters