Ipaddressingandsubnettingworkbookv1 2
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- 1. 0011010100 10011000 100011111001011100101011100 101100011101001101111010001101000001010010110010100101010110011111110101010001011101001101010011 0010100101010101010101000110010 010101001011000 110101100011010 11010100001011 0010101001101001010010IP Addressing and Subnetting Workbook Version 1.21111111010010101 00011011 10000110 11010011
2. IP Address Classes Class A1 127(Network 127 is reserved for loopback and internal testing) Leading bit pattern 0 00000000.00000000.00000000.00000000Network .Host . Host . Host Class B128 191Leading bit pattern 1010000000.00000000.00000000.00000000 Network . Network .Host . HostClass C192 223Leading bit pattern 110 11000000.00000000.00000000.00000000 Network . Network . Network . HostClass D224 239(Reserved for multicast)Class E240 255(Reserved for experimental, used for research)Private Address Space Class A10.0.0.0 to 10.255.255.255Class B172.16.0.0 to 172.31.255.255Class C192.168.0.0 to 192.168.255.255 Default Subnet Masks Class A255.0.0.0Class B255.255.0.0Class C255.255.255.0 Produced by: Robb [email protected] Frederick County Career & Technology CenterCisco Networking Academy Frederick County Public Schools Frederick, Maryland, USA Special Thanks to Melvin Baker and Jim Dorschfor taking the time to check this workbook for errors. Inside Cover 3. Binary To Decimal Conversion 128 64 32 16 8 4 21 Answers Scratch Area 1 0010 0 10146128641632 0 1110 1 11119216 146 4 1 1111 1 11 2 1 1 1000 1 01 1191 1110 1 100 0010 0 111 0000 0 010 0110 0 010 1111 0 001 1110 0 000 0111 0 110 0000 1 11 00011011 10101010 01101111 11111000 00100000 01010101 00111110 00000011 11101101 110000001 4. Decimal To Binary ConversionUse all 8 bits for each problem 128 6432 168 4 21 = 255 Scratch Area1 1 101 110 _________________________________________ 238 23834-128 -320 0 100 010 _________________________________________ 34110 2 -64-2 _________________________________________ 12346 0 -32 _________________________________________ 50 14-8 _________________________________________ 255 6-4 _________________________________________ 200 2-2 _________________________________________ 100_________________________________________ 138_________________________________________ 1_________________________________________ 13_________________________________________ 250_________________________________________ 107_________________________________________ 224_________________________________________ 114_________________________________________ 192_________________________________________ 172_________________________________________ 100_________________________________________ 119_________________________________________ 57_________________________________________ 98_________________________________________ 179_________________________________________ 2 2 5. Address Class IdentificationAddressClass10.250.1.1 A _____150.10.15.0B _____192.14.2.0_____148.17.9.1_____193.42.1.1_____126.8.156.0 _____220.200.23.1_____230.230.45.58 _____177.100.18.4_____119.18.45.0 _____249.240.80.78 _____199.155.77.56 _____117.89.56.45_____215.45.45.0 _____199.200.15.0_____95.0.21.90_____33.0.0.0_____158.98.80.0 _____219.21.56.0 _____3 6. Network & Host Identification Circle the network portion Circle the host portion of of these addresses:these addresses:177.100.18.4 10.15.123.50119.18.45.0171.2.199.31209.240.80.78198.125.87.177199.155.77.56223.250.200.222117.89.56.45 17.45.222.45215.45.45.0126.201.54.231192.200.15.0 191.41.35.11295.0.21.90 155.25.169.22733.0.0.0 192.15.155.2158.98.80.0123.102.45.254217.21.56.0148.17.9.15510.250.1.1 100.25.1.1150.10.15.0195.0.21.98192.14.2.0 25.250.135.46148.17.9.1 171.102.77.77193.42.1.1 55.250.5.5126.8.156.0218.155.230.14220.200.23.1 10.250.1.14 7. Network Addresses Using the IP address and subnet mask shown write out the network address: 188.10.18.2188 . 10 . 0 . 0 _____________________________ 255.255.0.010.10.48.8010 . 10 . 48 . 0 _____________________________ 255.255.255.0192.149.24.191_____________________________ 255.255.255.0150.203.23.19 _____________________________ 255.255.0.010.10.10.10 _____________________________ 255.0.0.0186.13.23.110 _____________________________ 255.255.255.0223.69.230.250_____________________________ 255.255.0.0200.120.135.15_____________________________ 255.255.255.027.125.200.151_____________________________ 255.0.0.0199.20.150.35 _____________________________ 255.255.255.0191.55.165.135_____________________________ 255.255.255.028.212.250.254_____________________________ 255.255.0.05 8. Host Addresses Using the IP address and subnet mask shown write out the host address: 188.10.18.20 . 0 . 18 . 2 _____________________________ 255.255.0.010.10.48.800 . 0 . 0 . 80 _____________________________ 255.255.255.0222.49.49.11_____________________________ 255.255.255.0128.23.230.19 _____________________________ 255.255.0.010.10.10.10 _____________________________ 255.0.0.0200.113.123.11_____________________________ 255.255.255.0223.169.23.20 _____________________________ 255.255.0.0203.20.35.215 _____________________________ 255.255.255.0117.15.2.51 _____________________________ 255.0.0.0199.120.15.135_____________________________ 255.255.255.0191.55.165.135_____________________________ 255.255.255.048.21.25.54 _____________________________ 255.255.0.06 9. Default Subnet Masks Write the correct default subnet mask for each of the following addresses: 177.100.18.4 255 . 255 . 0 . 0 _____________________________119.18.45.0255 . 0 . 0 . 0 _____________________________191.249.234.191 _____________________________223.23.223.109_____________________________10.10.250.1 _____________________________126.123.23.1_____________________________223.69.230.250_____________________________192.12.35.105 _____________________________77.251.200.51 _____________________________189.210.50.1_____________________________88.45.65.35 _____________________________128.212.250.254 _____________________________193.100.77.83 _____________________________125.125.250.1 _____________________________1.1.10.50 _____________________________220.90.130.45 _____________________________134.125.34.9_____________________________95.250.91.99_____________________________ 7 10. ANDING WithDefault subnet masksEvery IP address must be accompanied by a subnet mask. By now you should be able to look at an IP address and tell what class it is. Unfortunately your computer doesnt think that way. For your computer to determine the network and subnet portion of an IP address it must AND the IP address with the subnet mask.Default Subnet Masks: Class A255.0.0.0 Class B255.255.0.0 Class C255.255.255.0ANDING Equations:1 AND 1 = 11 AND 0 = 00 AND 1 = 00 AND 0 = 0Sample:What you see... IP Address: 192 . 100 . 10 . 33 What you can figure out in your head... Address Class:CNetwork Portion:192 . 100 . 10 . 33Host Portion: 192 . 100 . 10 . 33In order for you computer to get the same information it must AND the IP address with the subnet mask in binary. NetworkHost IP Address: 1 1 0 0 0 0 0 0 . 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 1 0 0 0 0 1 (192 . 100 . 10 . 33)Default Subnet Mask: 1 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1 . 0 0 0 0 0 0 0 0 (255 . 255 . 255 . 0) AND: 1 1 0 0 0 0 0 0 . 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 0 0 0 0 0 0(192 . 100 . 10 . 0)ANDING with the default subnet mask allows your computer to figure out the networkportion of the address. 8 11. ANDING With Custom subnet masksWhen you take a single network such as 192.100.10.0 and divide it into five smaller networks (192.100.10.16, 192.100.10.32, 192.100.10.48, 192.100.10.64, 192.100.10.80) the outside world still sees the network as 192.100.10.0, but the internal computers and routers see five smaller subnetworks. Each independent of the other. This can only be accomplished by using a custom subnet mask. A custom subnet mask borrows bits from the host portion of the address to create a subnetwork address between the network and host portions of an IP address. In this example each range has 14 usable addresses in it. The computer must still AND the IP address against the custom subnet mask to see what the network portion is and which subnetwork it belongs to.IP Address:192 . 100 . 10 . 0 Custom Subnet Mask:255.255.255.240Address Ranges: 192.10.10.0 to 192.100.10.15(Invalid Range) 192.100.10.16 to 192.100.10.31 (1st Usable Range) 192.100.10.32 to 192.100.10.47 (Range in the sample below) 192.100.10.48 to 192.100.10.63 192.100.10.64 to 192.100.10.79 192.100.10.80 to 192.100.10.95 192.100.10.96 to 192.100.10.111 192.100.10.112 to 192.100.10.127 192.100.10.128 to 192.100.10.143 192.100.10.144 to 192.100.10.159 192.100.10.160 to 192.100.10.175 192.100.10.176 to 192.100.10.191 192.100.10.192 to 192.100.10.207 192.100.10.208 to 192.100.10.223 192.100.10.224 to 192.100.10.239 192.100.10.240 to 192.100.10.255 (Invalid Range)SubNetworkNetwork HostIP Address: 1 1 0 0 0 0 0 0 . 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 1 0 0 0 0 1(192 . 100 . 10 . 33)Custom Subnet Mask: 1 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1 . 1 1 1 1 0 0 0 0 (255 . 255 . 255 . 240)AND: 1 1 0 0 0 0 0 0 . 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 1 0 0 0 0 0(192 . 100 . 10 . 32)Four bits borrowed from the hostportion of the address for thecustom subnet mask.The ANDING process of the four borrowed bitsshows which range of IP addresses thisparticular address will fall into. In the next set of problems you will determine the necessary information to determine the correct subnet mask for a variety of IP addresses. 9 12. Custom Subnet MasksProblem 1Number of needed usable subnets 14Number of needed usable hosts 14 Network Address 192.10.10.0 CAddress class __________255 . 255 . 255 . 0 Default subnet mask _______________________________ 255 . 255 . 255 . 240 Custom subnet mask _______________________________ 16Total number of subnets ___________________14Number of usable subnets ___________________16Total number of host addresses ___________________ 14 Number of usable addresses ___________________4 Number of bits borrowed ___________________Show your work for Problem 1 in the space below.Number of256 128 64 3216 8 42 - HostsNumber of Subnets-2 4 8 1632 64 128 256128 64 32 16 84 21 - Binary values192 . 10 . 10 .00 0000 0012816 Observe the total number of Add the binary value64 hosts.numbers to the left of the line to-23214create the custom subnet mask. Subtract 2 for the number of+16 usable hosts. 24016 -2Subtract 2 for the total number ofsubnets to get the usable number of14subnets. 10 13. Custom Subnet MasksProblem 2Number of needed usable subnets 1000Number of needed usable hosts 60 Network Address 165.100.0.0B Address class __________255 . 255 . 0 . 0 Default subnet mask _______________________________255 . 255 . 255 . 192Custom subnet mask _______________________________1,024 Total number of subnets ___________________ 1,022 Number of usable subnets ___________________ 64 Total number of host addresses ___________________ 62 Number of usable addresses ___________________ 10Number of bits borrowed ___________________Show your work for Problem 2 in the space below.65,32, 16,3 4,02,01,02 8,19 512 536 768 Number of8496 48. 256 128 64 32 16 8 4 2 2 4Hosts - 65,32, 16,34,0 102 2048,19 536 512 Number of768 84 96Subnets- 2 4 816 32 64128 256. 24 8 Binary values - 128 64 3216 8 4 2 1 . 128 64 32 168 421165 . 100 . 0 00 0 0 0 00 . 00 0000 0 0 128 12864 +6432 192 64Observe the total number of16hosts. Add the binary valuenumbers to the left of the line to 8 -2 62Subtract 2 for the number ofcreate the custom subnet mask. 4usable hosts.21024+1 Subtract 2 for the total number of -2255 subnets to get the usable number of 1,022 subnets.11 14. Custom Subnet MasksProblem 3/26 indicates the total number ofbits used for the network andsubnetwork portion of the Network Address 148.75.0.0 /26 address. All bits remaining belongto the host portion of the address. B Address class __________255 . 255 . 0 . 0 Default subnet mask _______________________________255 . 255 . 255 . 192Custom subnet mask _______________________________1,024 Total number of subnets ___________________ 1,022 Number of usable subnets ___________________ 64 Total number of host addresses ___________________ 62 Number of usable addresses ___________________ 10Number of bits borrowed ___________________Show your work for Problem 3 in the space below.65,32, 16,3 4,02,01,02 8,19 512 536 768 Number of8496 48. 256 128 64 32 168 4 2 2 4Hosts -65, 32,16,34,0 102 204 8,19536 512 Number of 76884 96Subnets- 2 4 816 32 64128 256.24 8 Binary values - 128 64 3216 8 4 2 1 . 128 64 32 16 8 421 148 . 75 . 0 0 00 0 0 00 .0 00 0 0 0 00 128 12864 +6432 192 64Observe the total number of16hosts. Add the binary valuenumbers to the left of the line to 8 -2 62Subtract 2 for the number ofcreate the custom subnet mask. 4usable hosts.21024+1 Subtract 2 for the total number of -2255 subnets to get the usable number of 1,022 subnets.12 15. Custom Subnet MasksProblem 4Number of needed usable subnets 6Number of needed usable hosts 30 Network Address 210.100.56.0 Address class _______ Default subnet mask _______________________________Custom subnet mask _______________________________Total number of subnets ___________________Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________Show your work for Problem 4 in the space below.Number of 256 128 64 3216 8 4 2 - HostsNumber of Subnets -2 4 8 1632 64 128 256 128 64 32 16 84 2 1 - Binary values210 . 100 . 56 .00 0 0 00 0 0 13 16. Custom Subnet MasksProblem 5Number of needed usable subnets 6Number of needed usable hosts 30 Network Address 195.85.8.0Address class _______Default subnet mask _______________________________Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________Show your work for Problem 5 in the space below. Number of256 128 64 3216 8 4 2 - Hosts Number ofSubnets -2 4 8 1632 64 128 256128 64 32 16 84 2 1 - Binary values 195 . 85 . 8 .00 0 0 00 0 0 14 17. Custom Subnet Masks Problem 6 Number of needed usable subnets 126 Number of needed usable hosts 131,070Network Address 118.0.0.0 Address class _______ Default subnet mask _______________________________ Custom subnet mask _______________________________Total number of subnets ___________________Number of usable subnets ___________________Total number of host addresses ___________________Number of usable addresses ___________________ Number of bits borrowed ___________________Show your work for Problem 6 in the space below. 4,19 2,09 1,0452262 131 65,532,716,3 4,02,01,024,2 4,30 8,198,577,15 Number of ,07 ,144 512. 256 128 64 32 16 8 4 23696 48 84Hosts 68 - 88 222 4 461,04 2,09 4,19262 52131 65,532,7 16,3 1,022,04,04,24,30 8,19 8,577,15Number of ,07 ,144 512. 3648 96 84 68 Subnets - 2 48 16 3264 128 256 .88 2 2 2 4 4 6 Binary values -128 64 321684 21. 128 64 32168421 . 128 6432 16 84 21118. 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0 15 18. Custom Subnet Masks Problem 7Number of needed usable subnets 2000Number of needed usable hosts 15 Network Address 178.100.0.0 Address class __________Default subnet mask _______________________________Custom subnet mask _______________________________ Total number of subnets ___________________Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________Number of bits borrowed ___________________Show your work for Problem 7 in the space below.65, 32,16,34,0 2,0 1,028,19512 536768 Number of 84 9648. 256 128 64 32 16 84224Hosts -65, 32,16,34,0 102 204 8,19536 512 Number of 76884 96Subnets- 24 816 32 64128 256.24 8 Binary values - 128 64 32 16 8 4 21 . 128 64 32 168 4 2 1178 . 100 . 0 00 0 0 0 0 0 .0 00 000 00 16 19. Custom Subnet MasksProblem 8Number of needed usable subnets 1Number of needed usable hosts 45 Network Address 200.175.14.0Address class _______ Default subnet mask _______________________________Custom subnet mask _______________________________Total number of subnets ___________________Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________Show your work for Problem 8 in the space below. 17 20. Custom Subnet MasksProblem 9Number of needed usable subnets 60Number of needed usable hosts 1,000 Network Address 128.77.0.0Address class _______Default subnet mask _______________________________Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________ Show your work for Problem 9 in the space below. 18 21. Custom Subnet MasksProblem 10Number of needed usable hosts 60 Network Address 198.100.10.0Address class _______ Default subnet mask _______________________________ Custom subnet mask _______________________________ Total number of subnets ___________________Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________ Show your work for Problem 10 in the space below. 19 22. Custom Subnet MasksProblem 11Number of needed usable subnets 250 Network Address 101.0.0.0Address class _______Default subnet mask _______________________________Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________Show your work for Problem 11 in the space below. 20 23. Custom Subnet MasksProblem 12Number of needed usable subnets 5 Network Address 218.35.50.0Address class _______ Default subnet mask _______________________________ Custom subnet mask _______________________________Total number of subnets ___________________Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________ Show your work for Problem 12 in the space below. 21 24. Custom Subnet MasksProblem 13Number of needed usable hosts 25 Network Address 218.35.50.0Address class _______ Default subnet mask _______________________________Custom subnet mask _______________________________Total number of subnets ___________________Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________ Show your work for Problem 13 in the space below. 22 25. Custom Subnet MasksProblem 14Number of needed usable subnets 10 Network Address 172.59.0.0Address class _______ Default subnet mask _______________________________ Custom subnet mask _______________________________Total number of subnets ___________________Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________Show your work for Problem 14 in the space below. 23 26. Custom Subnet MasksProblem 15Number of needed usable hosts 50 Network Address 172.59.0.0Address class _______ Default subnet mask _______________________________Custom subnet mask _______________________________Total number of subnets ___________________Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________ Show your work for Problem 15 in the space below. 24 27. Custom Subnet MasksProblem 16 Number of needed usable hosts 29Network Address 23.0.0.0Address class _______ Default subnet mask _______________________________ Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________Show your work for Problem 16 in the space below. 25 28. SubnettingProblem 1Number of needed usable subnets 14Number of needed usable hosts 14 Network Address 192.10.10.0C Address class __________255 . 255 . 255 . 0 Default subnet mask _______________________________255 . 255 . 255 . 240Custom subnet mask _______________________________16 Total number of subnets ___________________ 14 Number of usable subnets ___________________16Total number of host addresses ___________________ 14 Number of usable addresses ___________________4 Number of bits borrowed ___________________ What is the 3rd usable 192.10.10.48 to 192.10.10.63subnet range? _______________________________________________What is the subnet number192 . 10 . 10 . 112 for the 7th usable subnet? ________________________What is the subnetbroadcast address for192 . 10 . 10 . 207the 12th usable subnet? ________________________ What are the assignableaddresses for the 8th192.10.10.129 to 192.10.10.142usable subnet? ______________________________________ 26 29. Show your work for Problem 1 in the space below.Number of256 128 64 32 16 8 4 2-HostsNumber of Subnets- 24 8 16 32 64 128 256128 64 32 1684 2 1 - Binary values192. 10 . 10 . 0 0 0 0 00 00(Invalid range) 0192.10.10.0 to 192.10.10.151 192.10.10.16to 192.10.10.31 10 192.10.10.32to 192.10.10.47 11 192.10.10.48to 192.10.10.63 1 00 192.10.10.64to 192.10.10.79 1 01 192.10.10.80to 192.10.10.95 1 10 192.10.10.96to 192.10.10.111 1 11 192.10.10.112 to 192.10.10.12710 00 192.10.10.128 to 192.10.10.14310 01 192.10.10.144 to 192.10.10.15910 10 192.10.10.160 to 192.10.10.17510 11 192.10.10.176 to 192.10.10.19111 00 192.10.10.192 to 192.10.10.20711 01 192.10.10.208 to 192.10.10.22311 10 192.10.10.224 to 192.10.10.239(Invalid range) 11 11 192.10.10.240 to 192.10.10.255128 64 32 16 16+16 -2 -2240 14 14Custom subnetUsable subnets Usable hostsmask The binary value of the last bit borrowed is the range. In this problem the range is 16.The first address in each subnet range is the subnet The first and last range of addresses are not usable.number.The first usable range of addresses is: 192.10.10.16 toThe last address in each subnet range is the subnet 192.10.10.31.broadcast address. 27 30. SubnettingProblem 2Number of needed usable subnets 1000Number of needed usable hosts 60 Network Address 165.100.0.0B Address class __________255 . 255 . 0 . 0 Default subnet mask _______________________________255 . 255 . 255 . 192Custom subnet mask _______________________________ 1,024Total number of subnets ___________________ 1,022 Number of usable subnets ___________________ 64 Total number of host addresses ___________________ 62 Number of usable addresses ___________________10 Number of bits borrowed ___________________ What is the 14th usable165.100.3.128 to 165.100.3.191 subnet range? _______________________________________________What is the subnet number165 . 100 . 1 . 64 for the 5th usable subnet? ________________________What is the subnetbroadcast address for165 . 100 . 1 . 127 the 5th usable subnet? ________________________ What are the assignableaddresses for the 8th165.100.2.1 to 165.100.0.62usable subnet? ______________________________________ 28 31. 65,32, 16,34,02,08,191,02 Number of 768 84 96 4845122536Hosts - . 256 128 64 32 16 842 65,32,16,34,08,19 102204 Number of 512 9684 768482536Subnets-2 48 16 32 64128 256. Binary values - 128 64 32 16 8 4 21 . 128 64 32 168 4 2 1 165 . 100 . 0 0 0 0 0 0 00 .0 00 0 000064 .(Invalid range) 0 165.100.0.0to165.100.0.63 Usable -21 165.100.0.64 to165.100.0.127128hosts 62 10 165.100.0.128to165.100.0.191 10246411 165.100.0.192to165.100.0.255Usable -232 161. 0 0 165.100.1.0to165.100.1.63 subnets 1,022 1. 0 1 165.100.1.64 to165.100.1.12781. 1 0 165.100.1.128to165.100.1.19141. 1 1 165.100.1.192to165.100.1.255 1282 Custom 1 0. 0 0 165.100.2.0to165.100.0.63 subnet mask +64 +1 192 255 1 0. 0 1 165.100.2.64 to165.100.0.127 1 0. 1 0 165.100.2.128to165.100.0.191 1 0. 1 1 165.100.2.192to165.100.0.255The binary value of the last bit borrowed isthe range. In this problem the range is 64. 1 1. 0 0 165.100.3.0to165.100.3.63The first and last range of addresses are not1 1. 0 1 165.100.3.64 to165.100.3.127usable. 1 1. 1 0 165.100.3.128to165.100.3.191The first usable range of addresses is:1 1. 1 1 165.100.3.192to165.100.3.255165.100.0.64 to 165.100.0.127Show your work for Problem 2 in the space below.The first address in each subnet range is the Down tosubnet number.165.100.255.128 to165.100.255.191The last address in each subnet range is thesubnet broadcast address. 29(Invalid range) 165.100.255.192 to165.100.255.255 32. SubnettingProblem 3Number of needed usable subnets 1 Network Address 195.223.50.0 Address class __________ Default subnet mask _______________________________Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________ What is the 2nd usable subnet range? _______________________________________________What is the subnet number for the 1st usable subnet? ________________________What is the subnetbroadcast address for the 1st usable subnet? ________________________ What are the assignable addresses for the 2ndusable subnet? ______________________________________ 30 33. Show your work for Problem 3 in the space below.Number of 256 128 64 3216 8 4 2- Hosts Number ofSubnets-2 4 8 1632 64 128 256 128 64 32 16 84 2 1 - Binary values195. 223 . 50 . 00 0 0 00 0 0 31 34. SubnettingProblem 4Number of needed usable subnets 750 Network Address 190.35.0.0Address class __________ Default subnet mask _______________________________Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________Total number of host addresses ___________________Number of usable addresses ___________________Number of bits borrowed ___________________What is the 14th usable subnet range? _______________________________________________What is the subnet number for the 12th usablesubnet? ________________________What is the subnetbroadcast address for the 9th usable subnet? ________________________ What are the assignableaddresses for the 5thusable subnet? ______________________________________32 35. Show your work for Problem 4 in the space below.33 36. SubnettingProblem 5 Number of needed usable hosts 6Network Address 126.0.0.0Address class __________Default subnet mask _______________________________ Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________Total number of host addresses ___________________Number of usable addresses ___________________Number of bits borrowed ___________________ What is the 1st usablesubnet range? _______________________________________________What is the subnet number for the 4th usable subnet? ________________________What is the subnetbroadcast address for the 6th usable subnet? ________________________ What are the assignableaddresses for the 9thusable subnet? ______________________________________ 34 37. Show your work for Problem 5 in the space below.34 38. Subnetting Problem 6Number of needed usable subnets 10 Network Address 192.70.10.0 Address class __________ Default subnet mask _______________________________ Custom subnet mask _______________________________Total number of subnets ___________________Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________ What is the 8th usable subnet range? _______________________________________________What is the subnet number for the 3rd usable subnet? ________________________What is the subnetbroadcast address forthe 11th usable subnet? ________________________ What are the assignableaddresses for the 9thusable subnet? ______________________________________ 36 39. Show your work for Problem 6 in the space below.37 40. SubnettingProblem 7 Network Address 10.0.0.0 /16Address class __________ Default subnet mask _______________________________Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________Total number of host addresses ___________________Number of usable addresses ___________________Number of bits borrowed ___________________ What is the 10th usable subnet range? _______________________________________________What is the subnet number for the 5th usable subnet? ________________________What is the subnetbroadcast address for the 1st usable subnet? ________________________ What are the assignableaddresses for the 8thusable subnet? _____________________________________ 38 41. Show your work for Problem 7 in the space below.39 42. SubnettingProblem 8Number of needed usable subnets 4 Network Address 172.50.0.0Address class __________ Default subnet mask _______________________________Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________Total number of host addresses ___________________Number of usable addresses ___________________Number of bits borrowed ___________________ What is the 3rd usable subnet range? _______________________________________________What is the subnet number for the 4th usable subnet? ________________________What is the subnetbroadcast address for the 5th usable subnet? ________________________ What are the assignable addresses for the 2ndusable subnet? ______________________________________ 40 43. Show your work for Problem 8 in the space below.41 44. SubnettingProblem 9 Number of needed usable hosts 28Network Address 172.50.0.0Address class __________Default subnet mask _______________________________Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________Total number of host addresses ___________________ Number of usable addresses ___________________Number of bits borrowed ___________________ What is the 1st usablesubnet range? _______________________________________________What is the subnet number for the 9th usable subnet? ________________________ What is the subnet broadcast address forthe 3rd usable subnet? ________________________ What are the assignableaddresses for the 5thusable subnet? ______________________________________ 42 45. Show your work for Problem 9 in the space below.43 46. SubnettingProblem 10Number of needed usable subnets 45 Network Address 220.100.100.0Address class __________Default subnet mask _______________________________Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________Total number of host addresses ___________________ Number of usable addresses ___________________Number of bits borrowed ___________________ What is the 4th usablesubnet range? _______________________________________________What is the subnet number for the 3rd usable subnet? ________________________What is the subnetbroadcast address forthe 12th usable subnet? ________________________ What are the assignable addresses for the 11thusable subnet? ______________________________________ 44 47. Show your work for Problem 10 in the space below. 45 48. SubnettingProblem 11 Number of needed usable hosts 8,000Network Address 135.70.0.0Address class __________Default subnet mask _______________________________Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________Total number of host addresses ___________________ Number of usable addresses ___________________Number of bits borrowed ___________________ What is the 5th usablesubnet range? _______________________________________________What is the subnet number for the 6th usable subnet? ________________________What is the subnetbroadcast address forthe 2nd usable subnet? ________________________ What are the assignableaddresses for the 4thusable subnet? ______________________________________ 46 49. Show your work for Problem 11 in the space below. 47 50. SubnettingProblem 12 Number of needed usable hosts 45Network Address 198.125.50.0Address class __________Default subnet mask _______________________________Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________Total number of host addresses ___________________ Number of usable addresses ___________________Number of bits borrowed ___________________ What is the 1st usablesubnet range? _______________________________________________What is the subnet number for the 1st usable subnet? ________________________What is the subnetbroadcast address forthe 2nd usable subnet? ________________________ What are the assignable addresses for the 2ndusable subnet? ______________________________________ 48 51. Show your work for Problem 12 in the space below. 49 52. SubnettingProblem 13Network Address 165.200.0.0 /26 Address class __________ Default subnet mask _______________________________ Custom subnet mask _______________________________Total number of subnets ___________________Number of usable subnets ___________________ Total number of host addresses ___________________ Number of usable addresses ___________________ Number of bits borrowed ___________________ What is the 9th usable subnet range? _______________________________________________What is the subnet number for the 10th usable ________________________subnet?What is the subnetbroadcast address for ________________________ the 1022nd usable subnet?What are the assignable ______________________________________addresses for the 1021st usable subnet? 50 53. Show your work for Problem 13 in the space below. 51 54. SubnettingProblem 14 Number of needed usable hosts 16Network Address 200.10.10.0Address class __________Default subnet mask _______________________________ Custom subnet mask _______________________________ Total number of subnets ___________________ Number of usable subnets ___________________Total number of host addresses ___________________Number of usable addresses ___________________Number of bits borrowed ___________________ What is the 6th usablesubnet range? _______________________________________________What is the subnet number for the 4th usable subnet? ________________________ What is the subnet broadcast address forthe 3rd usable subnet? ________________________ What are the assignableaddresses for the 5thusable subnet? ______________________________________ 52 55. Show your work for Problem 14 in the space below. 53 56. SubnettingProblem 15Network Address 93.0.0.0 19 Address class __________Default subnet mask ______________________________ Custom subnet mask ______________________________ Total number of subnets ___________________ Number of usable subnets ___________________Total number of host addresses ___________________Number of usable addresses ___________________Number of bits borrowed ___________________ What is the 14th usable subnet range? ______________________________________What is the subnet number for the 8th usable subnet? ________________________What is the subnetbroadcast address for the 6th usable subnet? ________________________ What are the assignable addresses for the 11thusable subnet? ______________________________________ 54 57. Show your work for Problem 15 in the space below. 55 58. Valid and Non-Valid IP Addresses Using the material in this workbook identify which of the addresses below are correct and usable. If they are not usable addresses explain why.IP Address: 0.230.190.192The network ID cannot be 0. ________________________________ Subnet Mask: 255.0.0.0________________________________IP Address: 192.10.10.1OK ________________________________ Subnet Mask: 255.255.255.0________________________________IP Address: 245.150.190.10________________________________ Subnet Mask: 255.255.255.0________________________________IP Address: 135.70.191.255________________________________ Subnet Mask: 255.255.254.0________________________________IP Address: 127.100.100.10________________________________ Subnet Mask: 255.0.0.0________________________________IP Address: 93.0.128.1________________________________ Subnet Mask: 255.255.224.0________________________________IP Address: 200.10.10.128 ________________________________ Subnet Mask: 255.255.255.224________________________________IP Address: 165.100.255.189 ________________________________ Subnet Mask: 255.255.255.192________________________________IP Address: 190.35.0.10 ________________________________ Subnet Mask: 255.255.255.192________________________________IP Address: 218.35.50.195 ________________________________ Subnet Mask: 255.255.0.0________________________________IP Address: 200.10.10.175 /22 ________________________________ ________________________________IP Address: 135.70.255.255________________________________ Subnet Mask: 255.255.224.0________________________________ 56 59. Class A Addressing Guide# of Bits SubnetTotal # of Usable # of Total # of Usable # of BorrowedMask Subnets SubnetsHosts Hosts2 255.192.0.04 2 4,194,304 4,194,3023 255.224.0.08 6 2,097,152 2,097,1504 255.240.0.0 1614 1,048,576 1,048,5745 255.248.0.0 3230524,288 524,2866 255.252.0.0 6462262,144 262,1427 255.254.0.0 128 126 131,072 131,0708 255.255.0.0 256 25465,53665,5349255.255.128.0512 51032,76832,766 10255.255.192.0 1,024 1,022 16,38416,382 11255.255.224.0 2,048 2,0468,192 8,190 12255.255.240.0 4,096 4,0944,096 4,094 13255.255.248.0 8,192 8,1902,048 2,046 14255.255.252.016,38416,3821,024 1,022 15255.255.254.032,76832,766 512 510 16255.255.255.065,53665,534 256 254 17 255.255.255.128131,072 131,070 128 126 18 255.255.255.192262,144 262,142 6462 19 255.255.255.224524,288 524,286 3230 20 255.255.255.240 1,048,576 1,048,5741614 21 255.255.255.248 2,097,152 2,097,150 8 6 22 255.255.255.252 4,194,304 4,194,302 4 2 Class B Addressing Guide# of Bits SubnetTotal # of Usable # of Total # of Usable # of BorrowedMask Subnets Subnets Hosts Hosts2255.255.192.04 2 16,38416,3823255.255.224.08 68,192 8,1904255.255.240.0 16144,096 4,0945255.255.248.0 32302,048 2,0466255.255.252.0 64621,024 1,0227255.255.254.0 128 126512 5108255.255.255.0 256 254256 2549 255.255.255.128512 510128 126 10 255.255.255.192 1,024 1,022 6462 11 255.255.255.224 2,048 2,046 3230 12 255.255.255.240 4,096 4,094 1614 13 255.255.255.248 8,192 8,1908 6 14 255.255.255.25216,38416,3824 2 Class C Addressing Guide# of Bits SubnetTotal # of Usable # of Total # of Usable # of BorrowedMask Subnets Subnets Hosts Hosts2 255.255.255.192 4264 623 255.255.255.224 8632 304 255.255.255.24016 1416 145 255.255.255.24832 30 866 255.255.255.25264 62 42 Inside Cover
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