Heat Engine 1

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    Thermal Science

    MECH 2003Y

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    The Heat Engine (Revision)

    Heat engine cycle

    Steam boiler & steam plant

    Positive displacement machine

    Nozzles

    Mixtures

    IC engines

    Hydraulic Machinery (?)

    Module Outline

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    Lecturer: J. Chummun

    Email: [email protected]

    Tel.: 403 7804

    Office: Rm 2.4, Textile Bldg., FoE

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    1kg of a fluid expands reversibly according to a linear lawfrom 4.2bar to 1.4 bar; the initial and final volumes are

    0.004 m3 and 0.02m3. The fluid is then cooled reversibly

    at constant pressure, and finally compressed reversiblyaccording to a law pv=const back to the initial conditions

    of 4.2 bar and 0.004m3.

    Sketch the cycle on a p-v diagram. Calculate the wor

    k

    done in each process and the net work of the cycle.

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    Conversion of energy (heat) directly to work

    can only be done by devices called HEAT

    ENGINES.

    INTRODUCTION:

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    Heat p WorkExamples of heat energy producing other types of energy:

    Air over a hot car roof is lofted, gaining kinetic energy;

    That same air also gains gravitational potential energy;

    All of ourwindis driven by temperature differences;

    Electricity generation thrives on temperature

    differences: no steam would circulate if everything was

    at the same temperature

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    Heat Engine

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    A heat engine is a very simple

    idea. It is a device thatconverts heat into another

    form of energy.

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    Heat engines convert heat

    energy into mechanical energy.

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    They receive heat from a high temperature source;They convert part of this heat to work;

    They reject the remaining heat to a low temperature

    sink;They involve a fluid to and from which heat is

    transferred while undergoing a cycle. The fluid is called

    a working fluid;

    They operate on cycles.

    Characteristics of heat engines

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    Applying1

    st law of thermodynamics to theheat engine, a closed system operating on

    a cycle where the net heat supplied is

    equal to the net work done,

    x!x WQ

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    Then,

    netoutin WQQ !

    Qin : heat received from source

    Qout : heat rejected to sink

    Wnet : net work output

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    Heat Engines can be schematically represented

    like this:

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    SOURCE isknown as a reservoir supplying

    energy as heat.

    SINK is known as a reservoir absorbing energy

    as heat.

    Examples of Sources: furnaces, nuclear reactors,

    solar energy.

    Examples of Sinks : atmosphere, lakes, rivers.

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    Heat Engines

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    Thermal efficiency, denoted by L is a measure of

    how efficiently a heat engine converts the heat

    that it receives to work. Thermal efficiency is also

    referred to as performance of a heat engine.Thermal efficiency, L can be defined as the ratio of

    desired output to the required input, as follows

    inputrequired

    outputdesired!L

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    Heat supplied to a system, Q, is positive.

    Work input to a system, W, is positive.

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    Since cyclic devices work between high

    temperature reservoirs (TH) supplying heatQ

    H

    and low temperature reservoirs (TL) receiving

    heat QL as shown below then,

    H

    L

    H

    net

    Q

    Q

    Q

    W!! 1L

    L for heat engines is always less than one.

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    A typical gasoline automobile engine operates at

    around 25% efficiency, and a large coal-fuelled

    electrical generating plant peaks at about 46%.

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    The burning of a fuel-air mixture in a piston driven

    heat engine produces 10kJ of heat of which 7kJ

    exits the engine at the exhaust manifold.

    What is the efficiency of this engine?

    Problem 1

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    Heat is transferred to a heat engine from a

    furnace at a rate of 80 MW. If the rate of waste

    heat rejection to a nearby river is 50 MW,

    determine the net power output and the thermal

    efficiency for this heat engine.

    Problem 2

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    The energy input to an engine is 3.00 times

    greater than the work it performs. What is its

    thermal efficiency?

    What fraction of the input energy is expelled to

    the cold reservoir?

    Problem 3

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    2nd Law of Thermodynamics -Kelvin Planck Statement

    IT IS IMPOSSIBLE FOR ANY DEVICE THAT

    OPERATES ON A CYCLE TO RECEIVE HEAT FROM A

    SINGLE RESERVOIR AND PRODUCE A NET AMOUNT

    OF WORK.

    No heat engine can have a thermal efficiency of 100%and QL can never be zero.

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    Refrigerator

    Heat flows in the direction of decreasing

    temperature, that is, from high temperature

    media to low temperature ones.

    The reverse process cannot occur by itself

    and the transfer of heat from a low-

    temperature medium to a high temperature

    one requires special devices called

    REFRIGERATORS.

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    Refrigerator

    Can be modeled as a closed system;

    Operates at steady state;

    Receives heat from a low temperature source;

    Requires a power source;

    Rejects heat to a high temperature area.

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    Basic components of a refrigeration system and typical operating

    conditions.

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    The objective of a

    refrigerator is to remove

    QL from the cooled space.

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    Refrigerator

    RW

    LQ

    H

    Q

    For the Refrigerator operating

    at steady state:

    (U = Q - W

    0 = QL QH W

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    Coefficient of Performance for Refrigirator

    InputRequired

    OutputDesiredePerformanc !

    Work

    SpaceColdfromRemovedHeatCOPR !

    R

    LL

    R

    COP0

    W

    Q

    W

    QCOP

    e

    !!

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    Heat Pump

    Can be modeled as a closed system.

    Operates at steady state

    Receives heat from a low temperature source.

    Requires a power source.

    Rejects heat to a high temperature area.

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    Heat Pump

    HPW

    LQ

    H

    Q

    For the Heat Pump operating at

    steady state:

    (U = Q - W

    0 = QL QH + W

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    The objective of a heat pumpis to supply heat QH into the

    warmer space.

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    Coefficient of Performance - HP

    InputRequired

    OutputDesiredePerformanc !

    Work

    SpaceWarmtoSuppliedHeatCOPHP !

    HP

    HHHP

    COP0

    W

    Q

    W

    QCOP

    e

    !!

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    Rank in order, from largest to smallest, the workWout performed by

    these four heat engines.

    1. Wb > Wa > Wc > Wd2. Wb > Wa > Wb > Wc3. W

    b> W

    a> W

    b= W

    c4. Wd > Wa = Wb > Wc5. Wd > Wa > Wb > Wc

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    What is the thermal efficiency of this heat engine?

    1. 0.10

    2. 0.25

    3. 0.504. 4

    5. Cant tell without knowing QC.

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    What, if anything, is wrong

    with this refrigerator?

    1. It violates the first law of thermodynamics.

    2. It violates the second law of thermodynamics.

    3. It violates the third law of thermodynamics.4. Nothing is wrong.