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    GEOPHYSICS, VOL. 67, NO. 2 (MARCH-APRIL 2002); P. 610617, 8 FIGS.10.1190/1.1468622

    The boundary element method for 3-D dc resistivitymodeling in layered earth

    Qinzhong Ma

    ABSTRACT

    The integral equation for dc resistivity modeling of

    3-D inhomogeneous bodies buried in a layered earth isderived by using Greens theorem. The main features ofthis method are (1) the layers above and below the 3-Dobject can be included, (2) multiple subsurface inhomo-geneous bodies can be embedded in the different layers,and (3) the boundary element method (BEM) is used tosolve the integral equation using triangular surface ele-ments. Linear variation of the electrical properties is as-sumed withineach element. The potentialon thegroundsurface is obtained by solving thelinear equation systemwith Gaussian elimination.

    Model calculations demonstrate that the results ob-tained by this method compare well with the analyti-cal solution of a sphere in a uniform half-space and theasymptotic behaviorfor thesolutionof a buriedbodybe-

    neath a surficial layer as the layer resistivity approachesthat of the half-space. A comparison of responses overelongate 3-D bodies with responses over 2-D bod-ies of identical cross-section also shows satisfactoryagreement.

    INTRODUCTION

    In the dc resistivity method, the development of numeri-cal methods and computer techniques allow forward modelingof subsurface 3-D resistivity structures. Usually the problemsrelyonly on numericalmethods, whichincludefinite-differencemethods (Dey and Morrison, 1979; Zhao and Yedlin, 1996);finite-element methods (Coggon, 1971; Fox et al., 1980; Zhouand Zhong, 1986); integral equation methods (Alfano, 1959;

    Dieter et al., 1969); and boundary element methods (BEM)(Okabe, 1981; Xu et al., 1984,1988; Schulz, 1985; Xu andZhao,1985). Generallyspeaking,BEM isa special case of theintegralmethod,wherethenumberofunknownsinthesetofsimultane-

    Manuscript received by the Editor August 10, 1998; revised manuscript received June 18, 2001.Formerly Lanzhou University, Geography Department, Lanzhou 730000, China; presently Seismological Bureau of Shanghai, No. 87 Lanxi Road,Putuo, Shanghai 200062, China. E-mail: [email protected] 2002 Society of Exploration Geophysicists. All rights reserved.

    ousequations is usually very large. In BEM, thesolutioncan bereduced to a 2-D problem, reducing the number of gridpointsdramatically. Thus, BEM is simpler in element division and ini-

    tial data preparation and requires less memoryparticularlyappropriate fordomains extendingto infinity (Adey andNiku,1985; Brebbia et al., 1985; Brebbia, 1988). BEM is especiallysuitable in the case of 3-D problems.

    Many distributions of 3-D anomalous bodies under a flatsurface have been investigated with boundary integral tech-niques. Lee (1975) presents a surface integral equation suitedfor the model of a heterogeneity embedded in a two-layeredmedium; the solutions were found using the Galerkin method.Okabe(1981) gives the generalized integral equations describ-ingthe arbitraryinhomogeneitiesproblemwith weightedresid-ualscheme,whichcan becalculated byBEM. Schulz(1985)de-rives the integral equations for a body buried in a horizontallystratified half-space according to Okabes generalized formu-las, where in the numerical treatment the unknown is assumedto be constant on every boundary element.

    This paper presents a derivation of the 3-D potential inte-gral equations in which multiple 3-D bodies can be embeddedin arbitrary layers within a layered earth. The derivation isstraightforward and comprehensive, being based on Greenstheorem. BEM (Brebbia, 1978) is used to solve the integralequation. The boundary of a 3-D body is divided into trian-gular elements. Linear variation of the potential is assumedwithin each element, and a Gaussian quadrature formula anddigital linear filtering techniques are used to calculate the in-tegral. Thus, the integral equation is converted into a set oflinear algebraic equations that can be solved by Gaussianelimination.

    The apparent resistivity curves obtained by this methodagree with that obtained with approximate analytic solutions.The agreement is quite good. I also examined the asymptotic

    behavior of the apparent resistivity curves for a buried spherebeneath a layer over a half-space; I find good agreement. Fi-nally, I compare the responses over elongate 3-D bodies withthose over 2-D bodies of identical cross-section.

    610

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    BEM for 3-D dc Modeling in Layered Earth 611

    BOUNDARY INTEGRAL EQUATION FORMULATION

    Boundary value problem

    Consider the configuration shown in Figure 1. The x- andy-axes are horizontal, and the z-axis is downward with the ori-gin on the ground surface. An I-A current source is impressed

    at point A (the originof thecoordinate system). The earthis ann-layeredhostinwhichthereisa3-Dbodyinthe mth layer. Thevalues 1, 2, . . . , n are the resistivities of the layers, and b isthe 3-D inhomogeneity. Let 1, 2, . . . , n be the boundariesof the layers and b be the boundary of the 3-D body. We drawa hemisphere with a very large radius r

    = under theground surface 1. In this way, the total volume consists of re-gions 1, . . . , m, . . . , n , b. Let H1, . . . , Hm1, Hm, . . . , Hn1represent the depth corresponding to each boundary. Also letU1, . . . , Um, . . . , Un, Ub represent the electric potentials in re-gions 1, . . . , m, . . . , n, b, respectively. The normal vectoron each boundary is n.

    The governing equations for Uj can be written as

    2Uj = 21I3(A), j = 1, . . . , m, . . . , n, b, (1a)

    where 2 is the 3-D Laplace operator and 3(A) is a 3-D Diracdelta function at point A on the ground surface. Because thecurrent does not cross the ground surface 1, we have

    U1

    n

    1

    = 0. (1b)

    From the continuity of the electric potential, we have

    Uj1|j = Uj |j; Um|b = Ub|b, j = 2, . . . , m, . . . , n.

    (1c)

    From the continuity of normal components of current density,we have

    FIG. 1. Principal view of a 3-D body in an arbitrarily lay-ered earth. Dashes outline an infinite boundary. The x- andy-axes are horizontal, and the z-axis is downward with theorigin on the ground surface. A current source of I A is im-pressed at point A on the ground surface:1, 2, . . . , m, . . . , n,and b are the resistivities of the layers and the 3-D inho-mogeneity, respectively: 1, 2, . . . , m, m+1, . . . , n, b arethe boundaries of the layers and the 3-D body, respectively.Thesubsurface consists of regions1, . . . , m, . . . , n, b.Thedepths corresponding to each boundary are represented byH1, . . . , Hm1, Hm, . . . , Hn1, respectively: n is the normal vec-tor on each boundary.

    1

    j1

    Uj1

    n

    j

    =1

    j

    Uj

    n

    j

    ;1

    m

    Um

    n

    b

    =1

    b

    Ub

    n

    b

    ,

    j = 2, . . . , m, . . . , n. (1d)

    Since is far from the anomalous body, the electric potential

    on is the same as that in a half-space excited by a pointsource of current on 1:

    Uj | =C

    r;

    Uj

    r

    =C

    r 2; j = 1, 2, . . . , n, (1e)

    where C is a constant of proportionality.

    Greens theorem and fundamental solution

    The basic idea behind BEM is to transform the partial dif-ferentialequations in thespacedomain into integral equationson the boundaries using Greens second identity:

    (U2 2U) d =

    U

    n

    U

    n

    d, (2)

    where is the boundary of the domain , n is the outsidenormal vector, U is a potential to be determined, and is thefundamental solution of the differential equation (1a).

    Suppose in a horizontally stratified medium that a pointsource of unit current is located at point p in the mth layer.Then the potential = j (p, q) at point q in the jth layersatisfies

    2j = 3(p), (3a)

    1

    n

    1

    = 0,

    j | =C

    r;

    j

    r

    =C

    r 2,

    j = 1, 2, . . . , m, . . . , n, (3b)

    j |j+ 1 = j+1|j+ 1 , (3c)

    1

    j

    j

    n

    j+ 1

    =1

    j+1

    j+1

    n

    j+ 1

    ,

    j = 1, 2, . . . , m, . . . , n 1. (3d)

    Here, = 21 when p 1 and = j when p / 1. The value3(p) is the 3-D Dirac delta function centered at p. The dif-ferential equation (3) is solved by separation into cylindricalcoordinates (e.g.,Daniels, 1978). Thecomplete solutionis givenby

    j (p, q) = Q

    0

    G j (z,zp, )J0(r) d, (4a)

    Q =

    1

    4, zp > 0

    1

    2, zp < 0

    , (4b)

    where r=

    (x xp)2 + (y yp)2; (xp, yp,zp) and (x, y,z) arethe coordinates of points p and q, respectively; and J0 is

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    the Bessel function of order zero. Function G j can be simpli-fied into the computational convenient forms shown inAppendix A.

    The normal derivatives (m/n) and therefore the par-tial spatial derivatives ofm are needed for the integral rep-resentation of the potential of buried bodies. Considering

    J0(r) = J1(r), we obtain

    m

    x= Q

    x xp

    r

    0

    Gm(z,zp, )J1(r) d,

    m

    y= Q

    y yp

    r

    0

    Gm(z,zp, )J1(r) d,

    m

    z= Q

    0

    zGm(z,zp, )J0(r) d.

    All of the integrals above andthe integral of equation (4)havethe form

    H(r) =

    0

    f()J (r) d; = 0, 1,

    the Hankel transform of order , and can be evaluated bymeans of linear digital filters (Anderson, 1982, 1984).

    Boundary integral equation

    Using Greens theorem, we can finally obtain the boundaryintegral equations as follows (see Appendix B):

    U1(ps) = U0s

    b

    mbUbm(ps, q)

    nd, (5)

    CpUb(pI) = U0I

    b

    mbUbm(pI, q)

    nd, (6)

    where U0s = I1(ps, A); U0I =I1(pI, A); ps 1; pI b;q b; and Cp is a coefficient.

    Formulas (5) and (6) are the boundary integral equationsthat U1 and Ub must satisfy. Equation (6)can besolved by BEMto find the potential Ub on the boundary b of the body. Then,substituting the result into integral equation (5), the potentialU1 on the ground surface can be calculated.

    If there exist d1 anomalous bodies with the correspondingresistivities bj (j = 1, 2, . . . , d1) in the m1th layer whose resis-tivity is m1 and d2 anomalous bodies with the correspondingresistivitiesbj (j = d1 + 1, d1 + 2, . . . , d1 + d2)inthem2thlayerwhose resistivity is m2 , the integral equations correspondingto equations (5) and (6) are

    U1(ps) = U0s d1+d2j=1

    bj

    mbjUbm(ps, q)

    nd, (7)

    1

    m

    4

    d1+d2j=1

    bjpmbj

    Ub(pI) = U0I

    d1 +d2j=1

    bj

    mbjUb m(pI, q)

    nd, (8)

    where mbj = (1/m) (1/bj); m = m1 when j d1 and m = m2when j > d1; bj p isthesolidangleofpoint pI against the region

    bj ; and bj p = 0 if pI is outside ofbj whose boundary is bj(Figure 2).

    BOUNDARY ELEMENT METHOD

    The following discussions are mainly for a single 3-D body,and the index b at the lower right corner ofUb is neglected. Wedivide b into triangular elements and approximate each ele-ment as a triangular plane. The vertices of the triangular planeare nodes. There are N nodes on b. The boundary integral,equation (6), is divided into a sumof integralson each elemente. For node i we have

    CiUi = U0i

    b

    e

    mbUm

    nd, (9)

    where Ci = (4 bi mmb)/(4) and U0i =I1(pi , A). Thenode numbers of the three vertices of an element are takenas j , k, and l with coordinates (xj , yj ,zj ), (xk, yk,zk), (xl , yl,zl)(Figure 3). We assume that U is composed of linear functionsin each element. Using Uj , Uk, Ul to represent U at j , k, and l,Ucan be written as

    FIG. 2. Principal view of multiple bodies in the different lay-ers. The valued 1, . . . , m1 , . . . , m2 , . . . , n represent the resi-stivities of the first layer, . . . , the m1th layer, . . . , the m2ndlayer, . . . , the nth layer; b1 , . . . , bd1

    , bd1+1, . . . , bd1+d2

    rep-resent the resistivities of these inhomogeneous bodies,respectively.

    FIG. 3. Boundary of a 3-D body divided into triangular ele-ments. Point i is the ith node on the boundary: n is the normalvector on each triangular element: j , k, l represent the nodenumbers of the three vectices of an element.

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    BEM for 3-D dc Modeling in Layered Earth 613

    U = jUj + kUk + lUl = [j , k, l]{Uj , Uk, Ul }T,

    where j , k, l are linear interpolation functions defined as

    x = xj j + xkk + xl l ,

    y = yj

    j

    + yk

    k

    + yl

    l,

    z = zj j + zkk + zl l .

    It is obvious that at point j, j = 1, k = l = 0; at pointk, j = l = 0, k = 1; and at point l, j = k = 0, l = 1. The in-tegral over an element can be derived as follows:

    e

    mbU m

    nd =

    e

    [j , k, l]mbm

    nd{Uj , Uk, Ul }

    T

    = [fi j , fik, fil ]{Uj , Uk, Ul }T,

    where

    fi j = mb

    e

    jm

    nd; fik = mb

    e

    k m

    nd;

    fil = mb

    el

    m

    nd. (10)

    All these integrals are evaluated using a Gaussian formula(Brebbia, 1978) and a linear digital filtertechnique(Anderson,1984) for the Hankel transform. In this paper a four-pointGaussian quadrature formula for the triangular elements isused. For example, we can calculate fi j as follows:

    fi j = mb

    e

    j m

    nd = mb

    4t=1

    (t)j

    m(pi , qt)

    nWt,

    where is thearea of thetriangular elements, Wt is theweight,

    (t)j isthevalueofj at point qt (Brebbia, 1978). Thecalculation

    of fik and fil is the same as that of fi j .The sum of all integrals over each element on b is obtained

    asb

    e

    mbUm

    nd = [Fi1, . . . , Fi j , . . . , FiN]

    {U1, . . . , Uj , . . . , UN}T = Fi u,

    (11)

    where u = {U1, . . . , Uj , . . . , UN}T is the column vector formed

    by U at each node on b, Fi j is the sum of fi j at the elementsaround node j , and Fi = [Fi1, . . . , Fi j , . . . , Fi N]. Substitutingequation (11) into equation (9), we obtain

    CiUi = U0i Fi u. (12)

    For each node we can derive an equation as above. From all

    the nodes i (1 i N) on b, we derive an equation system

    Cu = u0 Fu. (13)

    where C = diag[C1, . . . , Cj , . . . , CN], u0 = [U01, . . . , U0j , . . . ,U0N]

    T, F = [F1, . . . , Fj , . . . , FN]T.

    We can obtain a linear equation system from equation (13)as follows:

    [C + F]u = u0. (14)

    The system of linear equations (14) contains N equations withN unknowns that can be solved to obtain the values of u atnodes on b. Substituting these values into equation (5), weobtain

    U1(ps) = I1(ps, A) Fsu. (15)

    We can calculate U1 at each point on the ground surface.

    NUMERICAL EXAMPLES

    To test the theory and program for the most general case,we first compare the resultsof a sphere under a flat surface ob-tained by this method with that of approximate analytic solu-tion (solution of half-space as the double of the whole spacesolution). Second, we compute the solution of a buried spherebeneath an overburden and examine the asymptotic behavioras the layer resistivity approaches that of the half-space. Thenwe can compare computations for elongate 3-D bodies withthose for 2-D structures of identical cross-section. The pro-gram described in this paper can accommodate an arbitrarynumber of layers, but for simplicity we consider an inhomo-geneity in thelowerlayer of a two-layerearth (Figures5 and6).

    Thefour-electrodesystem is arrangedso thetwo potentialelec-trodes move in the middle segment between the two fixedcurrent electrodes. The current electrode spacing is 600 min Figures 4 and 5 and 1200 m in Figures 6 and 7, and the

    FIG. 4. Model curvesof apparent resistivity for a sphereburiedin a half-space earth. Solid curvesand dotted curvesare there-sults obtained by BEM and the approximate analytic solution,respectively; x represents the midpoint of the two potentialelectrodes. (a) When r/h0 = 1/2, the solid curve is comparedwith the dotted curve. (b) When r/h0 = 5/7, the solid curveis compared with the dotted curve. (c) The cross-section ofthe model. 1 = 1 ohm-m.b = 0.05 ohm-m. Thespheres radiusr= 5 m; h0 is the depth of a sphere center.

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    FIG. 5. Model curvesof apparent resistivity for a sphereburiedin a two-layer earth. (a) The curves are plotted for differ-ent overburden resistivities 1 (in ohm-m), while the substra-tum and the sphere have the resistivities 2 = 100ohm-m andb = 1 ohm-m, respectively. The dotted curve is obtained with

    the approximate analytic solution of a sphere in a uniformhalf-space (1 = 2 = 100 ohm-m). (b) The cross-section of themodel. Thethickness of the overburden ish = 5 m. Thespheresradius andthe depth of its center are10 and 20 m, respectively.A and B represent the two current electrodes, M and N repre-sentthe two potentialelectrodes, andx represents themidpointof the two potential electrodes.

    FIG. 6. Model used to compare the response of this elongate3-Dbody to theresults of a 2-Dbody of identicalcross-section.The L represents the strike length of the 3-D body, and h isthe depth of the 3-D body beneath the lower layer. The val-ues 1, 2, b are the intrinsic resistivities of the upper layer,lower layer, and 3-D body, respectively. A four-electrode sys-tem is arranged along the x-axis. The two current electrodesare located at A and B, and the two potential electrodes are atM and N.

    potential electrode spacing is 5 m in Figures 4 and 5 and 30 min Figures 6 and 7.

    Figure 4 shows the apparent resistivity a curves of asphere buried in a half-space medium in which the results ofBEM (solid curves) are compared with that of an approxi-mate analytic solution (dots). In Figure 4a, r/ h0 = 1/2; the

    results agree well. Here, r and h0 represent the radius of asphere and the depth of the sphere center, respectively. InFigure 4b, r/ h0 = 5/7. The maximum error appears at thepointover the sphere and can reach 10%. This error is mainlyin the approximate analytic solution. When r/h0 1/2, theapproximate analytic solution is convincing.

    Figure 5 shows the results of a sphere buried in a two-layermedium. The spherical surface is divided into triangular ele-ments with 29 nodes. The curve computed with this methodfor 1 = 2 = 100 ohm-m is compared with the dotted curveobtained by approximate analytic solution of a half-space con-taining a sphere . The results agree well. On the other hand, asthe overburden resistivity1 approaches thatof the substratum2 = 100ohm-m, the asymptotic value of apparent resistivity isclose to that of the half-space containing the sphere. For the

    calculations illustrated in Figure5, the computer time is severaltens of seconds on a Pentium II microcomputer.

    Theapparent resistivitycurves fromelongate3-D bodies arecompared with those from the corresponding 2-D structurecalculated using a boundary element routine (Qian and Ma,1992) in Figures 7 and 8. The body is a tetragonal prism.

    In Figure 6, the upper layer is 50 m thick, and the cross-section of the 3-D body in the lower layer is 100 100 m. Itsstrike length is L, and its depth beneath the lower layer is h.The resistivity of the bottom layer is 2 = 10 ohm-m.

    In Figure 7, the shape of apparent resistivity curves for the3-D body is similar to that of the 2-D body, although the 2-Dcase shows a stronger influence of the inhomogeneity. WhenL = 100 m, h = 5 m, apparent resistivity curve 2 is similar tothat of a 2-D body. The cubic surface is divided into triangular

    FIG. 7. Profile curves of apparent resistivity along thex-axis ofthe 3-D body of Figure 6 and across a 2-D body of identicalcross-section for 1 = 100 ohm-m, 2 = 10 ohm-m, b = 0.1ohm-m, and h = 5 m. Solid curves are the responses of the 3-Dbody. The dashed curve is the response of the 2-D structure.The L is the strike length of the 3-D body, and x represents themidpoint of the two potential electrodes.

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    BEM for 3-D dc Modeling in Layered Earth 615

    FIG. 8. Profile curves of apparent resistivity along the x-axisof the 3-D body of Figure 6 and across a 2-D bodyof identical cross-section for1 = 1.0 ohm-m, 2 = 10 ohm-m,b = 10 000 ohm-m, and h = 10 m. The L is the strike length.The results of the3-D body areplotted usingsolidcurves, whilethat of the 2-D structure is shown as dashed curve. The x rep-resents the midpoint of the two potential electrodes.

    elements with 98 nodes. When L = 480m, h = 5 m, apparent re-sistivitycurve 3 approaches that of the2-D body, andthe agree-ment between them is satisfactory. The surface of the elongate3-D body is divided into triangular elements with 260 nodes.The results with the high-resistivity body (Figure 8) are alsoqualitative agreement between the two models. On the otherhand, the extent of the agreement between the 2-D and 3-Dresults may be influenced by the nature of the layering (seeFigures 7 and 8). In Figures 7 and 8, L = 0 represents the caseof no body in the layered earth.

    CONCLUSIONS

    The method used in this paper can be used to model the 3-Dbodies located in earths with layer interfaces both above andbelow the body. Furthermore, it can be used to model multiplebodiesembedded withinthe differentlayers in a layered earth.The approach outlined here is straightforward and easy to im-plement. The numerical solution can be run on a microcom-puter (Pentium II) in a matter of minutes. The formulationspresented in this paper can become an applicable techniquefor simulating the dc resistivity responses of 3-D anomalousbodies buried in a layered earth.

    ACKNOWLEDGMENTS

    I express my sincere thanks to Colin Farquharson; DavidBoerner,the associateeditorof Geophysics; andan anonymous

    reviewer for their comments and suggestions. Thanks are alsoextended to Larry Liner, the editor of Geophysics, for his en-couragement. In addition, I thank Xu Shi-Zhi for his usefuladvice at an early stage.

    REFERENCES

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    Alfano, L., 1959, Introduction to the interpretation of resistivity mea-surements for complicated structural conditions: Geophys. Prosp.,7, 311366.

    Anderson, W. L., 1982, Fast Hankel transforms using related andlogged convelutions: ACM Trans. on Math. Software, 8, 344368.

    1984, Computation of Greens tensor integrals for three-dimensional electromagnetic problems using fast Hankel trans-forms: Geophysics, 49, 17541759.

    Brebbia, C. A., 1978, The boundary-element method for engineers:Pentech Press.

    Brebbia, C. A., Ed., 1988, Boundary elements X: Springer-VerlagBerlin.

    Brebbia, C. A., Umetani, S., and Trevelyan, J., 1985, Critical compari-sonof boundary element andfinite element methods forstressanal-ysis, in Brebbia, C. A., and Noye, B. J., Eds., BETECH 85: Compu-

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    Daniels, J. J., 1978, Interpretation of buried electrode resistivity datausing a layered earth model: Geophysics, 43, 9881001.

    Dey, A., and Morrison,H. F., 1979, Resistivity modeling for arbitrarilyshaped three-dimensional structure: Geophysics, 44, 753780.

    Dieter, K., Paterson, N. R., and Grant, F. S., 1969, IP and resistivitytype curves for three-dimensional bodies: Geophysics, 34, 615632.

    Fox, R. C., Hohmann, G. W., Killpack, T. J., and Rijo, L., 1980,Topographic effect in resistivity and induced-polarization surveys:Geophysics, 45, 7593.

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    APPENDIX A

    EXPLICIT EXPRESSION OF THE FUNDAMENTAL SOLUTIONS

    Potentials about a point source of current in a layered earthhave been expressed by Daniels (1978). However, for the sakeof convenience to an applicable technique, the fundamental

    solution in this paper is simplified in forms amenable to com-putation.In equation (4a), thefunctionG j canbe expressed as

    G j (z,zp, ) = Dj e|zzp| + Aj ()e

    (zzp) +Bj ()e(zzp),

    (A-1a)

    Dj =

    m, j = m

    0, j = m, (A-1b)

    in which Aj (), Bj () can be calculated by

    Am = TdTu m

    Tu + Td, (A-2a)

    Bm = TuTd m

    Tu + Td. (A-2b)

    Bk = (Dk+1 +Bk+1)Tk + k

    Tk + k+1, k= m 1, m 2, . . . , 1,

    (A-2c)

    Aj = (Dj1 +Aj1)Tj + j

    Tj + j1, j = m + 1, m + 2, . . . , n.

    (A-2d)

    The thickness of the jth layer is denoted by

    hj = Hj Hj1, j = 1, . . . , n.

    Expressions Tj , Tu , and Td are calculated by the followingrecursion formulas:

    T1 =1

    tan h(h1), (A-3a)

    Tk = kTk1 + k tan h(hk)k + Tk1 tan h(hk)

    , k = 2, 3, . . . , m 1, m,

    (A-3b)

    Tu = Tk, hk = zp Hm1, k = m, (A-3c)

    Tn = n, (A-4a)

    Tj = jTj+1 + j tan h(hj )j + Tj+1 tan h(hj )

    ,

    j = n 1, n 2, . . . , m + 1, m, (A-4b)

    Td = Tj ; hj = Hm zp, j = m. (A-4c)

    When z zp, G j , Gn are calculatedby the following formulas:

    G j (z,zp,)

    = (Dj + Aj )

    e(zzp) +

    Tj+1 j

    Tj+1 + je(2Hjzzp)

    ,

    j = n 1, n 2, . . . , m + 1, (A-6a)

    Gn(z,zp, ) = (Dn + An)e(zzp). (A-6b)

    When m = 1, formulas (A-3) are invalid for calculating Tu . Sup-pose there is the image of the horizontally stratified mediumover the ground. Then Tu can be replaced by Td. From equa-tion (A-2), we can obtain

    A1 = B1 =(T

    d

    1)

    2 , (A-7)

    were Td = T1 according to the recursion formulas (A-4).

    APPENDIX B

    DERIVATION OF THE INTEGRAL EQUATIONS

    Greens second identity is used in regions 1, 2, . . . ,m, . . . , n, b, respectively:

    j

    Uj

    2j j 2Uj

    d

    = j j+1+j

    Uj jn

    jUj

    n d,

    b

    Ub

    2m m2Ub

    d

    =

    b

    Ub

    m

    n m

    Ub

    n

    d,

    j = 1, 2, . . . , n, (B-1)

    where j represents two segments of which belong to theboundary of region j . When j = m,let j+1 = j+1 b;whenj = n, let j+1 = 0.

    In example 1, let p = ps 1, utilizing the relation of bound-ary values, equations (1), and (3). Notice

    1 U1[213(ps)] d = 1U1(ps),j

    Uj

    j

    n j

    Uj

    n

    d = 0,

    1

    1[21I3(A)] d = 1I1(ps, A).

    From equation (B-1), we can obtain

    U1(ps) = I1(ps, A)

    b

    mbUb m(ps, q)

    nd, (B-2)

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    where q is an arbitrary point on boundary b and mb =(1/m) (1/b). Hence, as b m , mb 0.

    In example 2, let p = pI b, utilizing the relation of boun-dary values, equations (1) and (3). The boundary surface ofb at each node is not smooth; therefore,

    m

    Um[m3(pI)] d = mmp

    4 Um(pI),b

    Ub[m3(pI)] d = mbp

    4Ub(pI),

    1

    1[21I3(A)] d = 1I1(pI, A).

    From equation (B-1), we finally obtain

    CpUb(pI) = I1(pI, A)

    b

    mbUbm(pI, q)

    nd,

    (B-3)where Cp = (4 bpmmb)/(4); q b;

    mp is the solid angle subtended by m at pI; and bp is thesolid angle subtended by b at pI.

    If the boundary surface at each node is smooth, thenbp = 2 . Let n = n1 = , . . . , = m . The integral equa-tions (B-2) and (B-3), turn out to be the integral equationsof surface potential in Schulz (1985).

    In equation (B-3),the surface integral,however, is impropersince {[m(pI, q)]/n} produces a singularity at q = pI. To

    avoid the singularity, noticing Okabes method of singular-ity analysis (Okabe, 1981) and utilizing equation (3a), we canchange the surface integral in equation (B-3) into anotherform:

    b

    mbUb

    m(pI, q)

    n m3(pI)

    2

    d, (B-4)

    which is now proper everywhere on b. Once the singularity isexcluded theoretically in the integral equation formulation, itis unnecessary to exclude numerically an infinitesimal bound-ary surface around the singular point. Rather, the integra-tion should be carried out as if no singularity in the integrandexisted.