· lim ex : : — . x x : x : ex x : — lim lim ex = lim : lim ex = +00 : ne lim = +00 : : —...

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Transcript of  · lim ex : : — . x x : x : ex x : — lim lim ex = lim : lim ex = +00 : ne lim = +00 : : —...

Page 1:  · lim ex : : — . x x : x : ex x : — lim lim ex = lim : lim ex = +00 : ne lim = +00 : : — — lim x lim — lim lim = lim e = lim x x ex x
Page 2:  · lim ex : : — . x x : x : ex x : — lim lim ex = lim : lim ex = +00 : ne lim = +00 : : — — lim x lim — lim lim = lim e = lim x x ex x
Page 3:  · lim ex : : — . x x : x : ex x : — lim lim ex = lim : lim ex = +00 : ne lim = +00 : : — — lim x lim — lim lim = lim e = lim x x ex x
Page 4:  · lim ex : : — . x x : x : ex x : — lim lim ex = lim : lim ex = +00 : ne lim = +00 : : — — lim x lim — lim lim = lim e = lim x x ex x
Page 5:  · lim ex : : — . x x : x : ex x : — lim lim ex = lim : lim ex = +00 : ne lim = +00 : : — — lim x lim — lim lim = lim e = lim x x ex x
Page 6:  · lim ex : : — . x x : x : ex x : — lim lim ex = lim : lim ex = +00 : ne lim = +00 : : — — lim x lim — lim lim = lim e = lim x x ex x

ESERCIZI AGGIUNTIVI SUI LIMITIE0… · 294 lim 295 lim senn x sen x n 1 — e2x sen x tg3x senx 2] lim 2 311 012 lim lim 1 — cos2 x tgx — COS X t 76 . 313 lim 314 lim 2.x2 + I

ESERCIZI AGGIUNTIVI SUI LIMITIE0… · 294 lim 295 lim senn x sen x n 1 — e2x sen x tg3x senx 2] lim 2 311 012 lim lim 1 — cos2 x tgx — COS X t 76 . 313 lim 314 lim 2.x2 + I

fileMath I — {x I x 1} = [1, 00) B. No intercepts C. No symmetry D. lim — = lim — = lim = 0, so + + X X isaHA. E. f' (x) = < Ofor all x > 1, since x —1 < x -s

fileMath I — {x I x 1} = [1, 00) B. No intercepts C. No symmetry D. lim — = lim — = lim = 0, so + + X X isaHA. E. f' (x) = < Ofor all x > 1, since x —1 < x -s

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³ - GOOL Math A for Economics.pdf · 6 1.5 4 x x lim of §· ¨¸ ©¹ 1.1 4 x x lim o f §· ¨¸ ©¹ 1. 5x x lim of 1. 5x x lim o f. 3 2 x lim of x.12 x lnx x lim e of 2.11 2

³ - GOOL Math A for Economics.pdf · 6 1.5 4 x x lim of §· ¨¸ ©¹ 1.1 4 x x lim o f §· ¨¸ ©¹ 1. 5x x lim of 1. 5x x lim o f. 3 2 x lim of x.12 x lnx x lim e of 2.11 2

Scanned by CamScanner - ایران توشه...@clmcruzlqonlgoor x Ha ry x + rx —a aeØ f(x) a lim = +00 'l x +a f(x) = (r lim tanx lim —sin x mn Jut* lim lim tanx lim (C cosx rx

Scanned by CamScanner - ایران توشه...@clmcruzlqonlgoor x Ha ry x + rx —a aeØ f(x) a lim = +00 'l x +a f(x) = (r lim tanx lim —sin x mn Jut* lim lim tanx lim (C cosx rx

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CHAPTER 2 Differentiation answers/ODD02.pdf54 Chapter 2 Differentiation 17. lim x 0 4x x 22 x x x lim x 0 4x 2 x 1 4x 1 lim x 0 2x2 4 x2 x 2 x 1 2 2 x lim x 0 2 x 2x x x 1 2 x2 1 x

CHAPTER 2 Differentiation answers/ODD02.pdf54 Chapter 2 Differentiation 17. lim x 0 4x x 22 x x x lim x 0 4x 2 x 1 4x 1 lim x 0 2x2 4 x2 x 2 x 1 2 2 x lim x 0 2 x 2x x x 1 2 x2 1 x

MathsPhysicsmathsphysics.altervista.org/alterpages/files/Limitidifunzionialgebriche.pdf · lim (x2 lim (x — lim (2 — lim (x — an lim lim (I X2)2 ... (Uk) 3 — 23) e semplificando

MathsPhysicsmathsphysics.altervista.org/alterpages/files/Limitidifunzionialgebriche.pdf · lim (x2 lim (x — lim (2 — lim (x — an lim lim (I X2)2 ... (Uk) 3 — 23) e semplificando

MATH 140 Homework Problems - Pennsylvania …4 MATH 140 HOMEWORK PROBLEMS 30.lim x!3 2 x2+x 1 3x 3 x2 + 4x 21 31.lim x! 4 1 x+2 1 p3x+10 x2 3 17 + x 32.lim x!0 ex+1(x3 + x2) x4 + 3x2

MATH 140 Homework Problems - Pennsylvania …4 MATH 140 HOMEWORK PROBLEMS 30.lim x!3 2 x2+x 1 3x 3 x2 + 4x 21 31.lim x! 4 1 x+2 1 p3x+10 x2 3 17 + x 32.lim x!0 ex+1(x3 + x2) x4 + 3x2

 · 2016. 11. 27. · lim x e2x ex 2 lim xln lim x lim x In x lim 3 lim e x 2 lim x In = lim x lim x In In e 3 lim 3 vG1nx lim e In 3ex + 3 lim x e2x lim (f (x) 2x) -3 X D 3ex + 3

 · 2016. 11. 27. · lim x e2x ex 2 lim xln lim x lim x In x lim 3 lim e x 2 lim x In = lim x lim x In In e 3 lim 3 vG1nx lim e In 3ex + 3 lim x e2x lim (f (x) 2x) -3 X D 3ex + 3

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Límites y continuidad · Límites infinitos: asíntota vertical x 0 y x 5 lim x→0 3x2 x 2 x 5 x 1 lim x→0 3x2 x x 5 x 1 lim x→ 5 3x 2 x2 x 5 x 1 lim x→ 5 3x x2 x 5 x 1 Límites

 · 2015-09-23 · +1, x.0 lim sin3x tan2x-----+2,.1 lim cos8 9 p 2 x x-1!!!!!"3# n.* lim 8 1-9n 4 n! "4# x.0 lim log013+ x1 2x!!!!"5#.* lim2x6log0 x+2log1- x7!"6# x.0 lim esin 32

 · 2015-09-23 · +1, x.0 lim sin3x tan2x-----+2,.1 lim cos8 9 p 2 x x-1!!!!!"3# n.* lim 8 1-9n 4 n! "4# x.0 lim log013+ x1 2x!!!!"5#.* lim2x6log0 x+2log1- x7!"6# x.0 lim esin 32

2017-06-14 11:46 · The breaking points are —3 and 4. EX #2: lim EX lim EX #8: lim CONTINUITY EX #3 : EX : EX EX : EX : Continuous functions have no breaks in them. Discontinuous

2017-06-14 11:46 · The breaking points are —3 and 4. EX #2: lim EX lim EX #8: lim CONTINUITY EX #3 : EX : EX EX : EX : Continuous functions have no breaks in them. Discontinuous

 · xo = ItL(x) lim . limx x : limx x lim = lim -IttX lim limx x : lim neN; Iu(x) . lim lim lim lim xnx In (x) : lim Inx .1 ltL(x) . xo = I . lim

 · xo = ItL(x) lim . limx x : limx x lim = lim -IttX lim limx x : lim neN; Iu(x) . lim lim lim lim xnx In (x) : lim Inx .1 ltL(x) . xo = I . lim

GIỚI HẠN CỦA HÀM SỐ Giáo viên: Nguyễn Tiến Đạt file2) Giới hạn của hàm số tại vô cực: Các giới hạn x lim f x , x lim f x , x lim f x L, x lim f

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CONTINUITY Mrs. Erickson Continuity lim f(x) = f(c) at every point c in its domain. To be continuous, lim f(x) = lim f(x) = lim f(c) x c+x c+ x

CONTINUITY Mrs. Erickson Continuity lim f(x) = f(c) at every point c in its domain. To be continuous, lim f(x) = lim f(x) = lim f(c) x c+x c+ x

Differentialquotient dy/dx := lim y/ x D D D für x -> 0c) y(x) = ex => y(x)'= ex: Der Anstieg der Exponentialfunktion ist in jedem Punkt gleich dem Funktionswert (ei- ne weitere Besonderheit

Differentialquotient dy/dx := lim y/ x D D D für x -> 0c) y(x) = ex => y(x)'= ex: Der Anstieg der Exponentialfunktion ist in jedem Punkt gleich dem Funktionswert (ei- ne weitere Besonderheit

2.files.edl.io...3 1) 34. 36. 38. 42. 44. 48. -3.5 -2.999 f(x) 5. f(x) = 7. f(x) = -3.1 -2.99 -3.01 -3.001 -2.9 -2.5 f(x) = 6. f(x) = 8. sec lim lim lim lim sin x csc x x sec a-rx

2.files.edl.io...3 1) 34. 36. 38. 42. 44. 48. -3.5 -2.999 f(x) 5. f(x) = 7. f(x) = -3.1 -2.99 -3.01 -3.001 -2.9 -2.5 f(x) = 6. f(x) = 8. sec lim lim lim lim sin x csc x x sec a-rx

EJERCICIOS DE REPASO LÍMITES (SOLUCIONARIO LIBRO ......Se considera la función f (x) (Baleares. Junio 2008. Opción A. Cuestión 3) . Calcula lim f (x) y lim f (x). lim f (x) lim

EJERCICIOS DE REPASO LÍMITES (SOLUCIONARIO LIBRO ......Se considera la función f (x) (Baleares. Junio 2008. Opción A. Cuestión 3) . Calcula lim f (x) y lim f (x). lim f (x) lim