CHE275 Chapter8 Slides

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  • Organic Chemistry

    CHE 275

    Chapter 8Nucleophilic Substitution

    Y :

    R X Y R+ : X

    nucleophile is a Lewis base (electron-pair donor)

    often negatively charged and used as Na+ or K+ salt

    substrate is usually an alkyl halide

    Nucleophilic Substitution

    +

    Substrate cannot be an a vinylic halide or anaryl halide, except under specific conditions tobe discussed in Chapter 12.

    XCC

    X

    Nucleophilic Substitution

    + R X

    Alkoxide ion as the nucleophile

    ..O:

    ..R'

    Examples of Nucleophilic Substitution

    gives an ether

    + : XR..O..

    R'

    (CH3)2CHCH2ONa + CH3CH2Br

    Isobutyl alcohol

    (CH3)2CHCH2OCH2CH3 + NaBr

    Ethyl isobutyl ether (66%)

    Example

    + R X

    Carboxylate ion as the nucleophile

    ..O:

    ..R'C

    O

    gives an ester

    + : XR..O..

    R'C O

    Examples of Nucleophilic Substitution

  • OK +CH3(CH2)16C CH3CH2I

    acetone, water

    O

    + KIO CH2CH3CH3(CH2)16C

    Ethyl octadecanoate (95%)

    O

    Example

    + R X

    Hydrogen sulfide ion as the nucleophile

    ..S:

    ..H

    gives a thiol

    + : XR..S..

    H

    Examples of Nucleophilic Substitution

    KSH + CH3CH(CH2)6CH3

    Br

    ethanol, water

    + KBr

    2-Nonanethiol (74%)

    CH3CH(CH2)6CH3

    SH

    Example

    + R X

    Cyanide ion as the nucleophile

    CN: :

    Examples of Nucleophilic Substitution

    gives a nitrile

    + : XR CN:

    DMSO

    BrNaCN +

    Cyclopentyl cyanide (70%)

    CN + NaBr

    Example

    Azide ion as the nucleophile

    .. ..

    N N N:: +

    + R X

    ..

    gives an alkyl azide

    + : XR ..N N N: +

    Examples of Nucleophilic Substitution

  • NaN3 + CH3CH2CH2CH2CH2I

    2-Propanol, water

    CH3CH2CH2CH2CH2N3 + NaI

    Pentyl azide (52%)

    Example

    + R X

    Iodide ion as the nucleophile..: I..:

    gives an alkyl iodide

    + : XR ..: I..

    Examples of Nucleophilic Substitution

    NaI is soluble in acetone; NaCl and NaBr are not soluble in acetone.

    acetone

    + NaICH3CHCH3

    Br

    63%

    + NaBrCH3CHCH3

    I

    Example Reactivity of Leaving Groups

    Reactivity of halide leaving groups in nucleophilic substitution is the same as for elimination.RI

    RBr

    RCl

    RF

    most reactive

    least reactive

    BrCH2CH2CH2Cl + NaCN

    A single organic product was obtained when 1-bromo-3-chloropropane was allowed to react with one molar equivalent of sodium cyanide in aqueous ethanol. What was this product?

    Br is a better leaving group than Cl

    Problem

    BrCH2CH2CH2Cl + NaCN

    A single organic product was obtained when 1-bromo-3-chloropropane was allowed to react with one molar equivalent of sodium cyanide in aqueous ethanol. What was this product?

    Problem

    CH2CH2CH2Cl + NaBrCN:

  • Many nucleophilic substitutions follow asecond-order rate law.

    CH3Br + HO CH3OH + Br rate = k[CH3Br][HO ]

    inference: rate-determining step is bimolecular

    Kinetics and the SN2 Mechanism

    HO CH3Br+ HOCH3 Br +

    one stepone step

    HO CH3 Br

    transition state

    Bimolecular Mechanism

    Nucleophilic substitutions that exhibitsecond-order kinetic behavior are stereospecific and proceed withinversion of configuration.

    Stereochemistry Inversion of Configuration

    nucleophile attacks carbonfrom side opposite bondto the leaving group

    three-dimensionalarrangement of bonds inproduct is opposite to that of reactant

    A stereospecific reaction is one in whichstereoisomeric starting materials givestereoisomeric products.

    The reaction of 2-bromooctane with NaOH (in ethanol-water) is stereospecific.

    (+)-2-Bromooctane ()-2-Octanol()-2-Bromooctane (+)-2-Octanol

    Stereospecific Reaction

    C

    H

    CH3

    Br

    CH3(CH2)5NaOH

    (S)-(+)-2-Bromooctane

    (CH2)5CH3

    C

    H

    CH3

    HO

    (R)-()-2-Octanol

    Stereospecific Reaction

  • The Fischer projection formula for (+)-2-bromooctaneis shown. Write the Fischer projection of the()-2-octanol formed from it by nucleophilic substitution with inversion of configuration.

    Problem

    H Br

    CH3

    CH2(CH2)4CH3

    H Br

    CH3

    CH2(CH2)4CH3

    The Fischer projection formula for (+)-2-bromooctaneis shown. Write the Fischer projection of the()-2-octanol formed from it by nucleophilic substitution with inversion of configuration.

    HO H

    CH3

    CH2(CH2)4CH3

    Problem

    Crowding at the carbon that bears the leaving group slows the rate ofbimolecular nucleophilic substitution.

    Steric Effects on SN2 reactions: Crowding at the Reaction Site

    The rate of nucleophilic substitutionby the SN2 mechanism is governedby steric effects.

    RBr + LiI RI + LiBrAlkyl Class Relativebromide rate

    CH3Br Methyl 221,000

    CH3CH2Br Primary 1,350

    (CH3)2CHBr Secondary 1

    (CH3)3CBr Tertiary too smallto measure

    Reactivity toward substitution by the SN2 mechanism

    CH3Br

    CH3CH2Br

    (CH3)2CHBr

    (CH3)3CBr

    Decreasing SN2 Reactivity

    CH3Br

    CH3CH2Br

    (CH3)2CHBr

    (CH3)3CBr

    Decreasing SN2 Reactivity

  • The rate of nucleophilic substitutionby the SN2 mechanism is governedby steric effects.

    Crowding at the carbon adjacentto the one that bears the leaving groupalso slows the rate of bimolecularnucleophilic substitution, but the effect is smaller.

    Crowding Adjacent to the Reaction Site

    RBr + LiI RI + LiBrAlkyl Structure Relativebromide rate

    Ethyl CH3CH2Br 1.0

    Propyl CH3CH2CH2Br 0.8

    Isobutyl (CH3)2CHCH2Br 0.036

    Neopentyl (CH3)3CCH2Br 0.00002

    Effect of chain branching on rate of SN2 substitution

    Interactive QuestionWhat is the major product of the reaction of the

    dihalide at the right with 1 equivalent ofNaSH in dimethyl sulfoxide?

    A) B)

    C) D) All nucleophiles, however, are Lewis bases.

    The nucleophiles described in the bookhave mostly been anions.

    ..

    ..HO: ..

    ..CH3O:..

    ..HS:

    CN: : etc.

    Not all nucleophiles are anions. Many are neutral.....HOH CH3OH..

    ..NH3: for example

    Nucleophiles and Nucleophicity

    ..

    ..HOH CH3OH....

    for example

    Many of the solvents in which nucleophilic substitutions are carried out are themselvesnucleophiles.

    Nucleophiles

    The term solvolysis refers to a nucleophilicsubstitution in which the nucleophile is the solvent.

    Solvolysis

  • substitution by an anionic nucleophile

    RX + :Nu RNu + :X

    +solvolysis

    RX + :NuH RNuH + :X

    step in which nucleophilicsubstitution occurs

    Solvolysis

    +

    substitution by an anionic nucleophile

    RX + :Nu RNu + :X

    solvolysis

    RX + :NuH RNuH + :X

    RNu + HXproducts of overall reaction

    Solvolysis

    RX

    Methanolysis is a nucleophilic substitution in which methanol acts as both the solvent andthe nucleophile.

    H

    O

    CH3

    : :+

    H

    O

    CH3

    :R+ H+

    The product is a methyl ether.

    O:

    CH3

    R ..

    Example: Methanolysissolvent product from RX

    water (HOH) ROHmethanol (CH3OH) ROCH3ethanol (CH3CH2OH) ROCH2CH3

    formic acid (HCOH)

    acetic acid (CH3COH) ROCCH3

    O

    ROCH

    OO

    O

    Typical solvents in solvolysis

    Rank Nucleophile Relative rate strong I-, HS-, RS- >105

    good Br-, HO-, 104

    RO-, CN-, N3-

    fair NH3, Cl-, F-, RCO2- 103

    weak H2O, ROH 1very weak RCO2H 10-2

    Nucleophilicity compare the relative rates of nucleophilic substitution of

    a variety of nucleophiles toward methyl iodide as the substrate. The standard of comparison is methanol, which is assigned a relative rate of 1.0.

    basicity

    solvation

    small negative ions are highly solvated in protic solvents

    large negative ions are less solvated

    Major factors that control nucleophilicity

  • Rank Nucleophile Relative Rate

    good HO, RO 104

    fair RCO2 103

    weak H2O, ROH 1

    When the attacking atom is the same (oxygenin this case), nucleophilicity increases with increasing basicity.

    Nucleophilicity

    basicity

    solvation

    small negative ions are highly solvated in protic solvents

    large negative ions are less solvated

    Major factors that control nucleophilicity

    Solvation of a chloride ion by ion-dipole attractiveforces with water. The negatively charged chlorideion interacts with the positively polarized hydrogensof water.

    Solvation

    Rank Nucleophile Relative Rate

    strong I- >105

    good Br- 104

    fair Cl-, F- 103

    A tight solvent shell around an ion makes itless reactive. Larger ions are less solvated thansmaller ones and are more nucleophilic.

    Nucleophilicity

    Tertiary alkyl halides are very unreactive in substitutions that proceed by the SN2 mechanism.Do they undergo nucleophilic substitution at all?

    Yes. But by a mechanism different from SN2. The most common examples are seen in solvolysis reactions.

    The SN1 MechanismHydrolysis of tert-butyl

    bromide.

    +

    +

    H Br.... :

    O: :

    H

    H

    CCH3

    CH3

    CH3

    Br

    C OH....

    ..

    .. :

    CH3CH3

    CH3

    C+

    +

    O :

    H

    H

    Br.... ::

    CH3CH3

    CH3

  • + O: :

    H

    H

    C+

    +

    O :

    H

    H

    Br.... ::

    CH3CH3

    CH3

    CCH3

    CH3

    CH3

    Br.... :

    This is the nucleophilic substitutionstage of the reaction; the one withwhich we are concerned.

    Hydrolysis of tert-butyl bromide.

    + O: :

    H

    H

    C+

    +

    O :

    H

    H

    Br.... ::

    CH3CH3

    CH3

    CCH3

    CH3

    CH3

    Br.... :

    Hydrolysis of tert-butyl bromide.

    The reaction rate is independentof the concentration of the nucleophileand follows a first-order rate law.

    rate = k[(CH3)3CBr]

    + O: :

    H

    H

    C+

    +

    O :

    H

    H

    Br.... ::

    CH3CH3

    CH3

    CCH3

    CH3

    CH3

    Br.... :

    Hydrolysis of tert-butyl bromide.

    The mechanism of this step isnot SN2. It is SN1 and begins with ionization of (CH3)3CBr.

    rate = k[alkyl halide]First-order kinetics implies a unimolecular

    rate-determining step.

    Proposed mechanism is called SN1(Substitution Nucleophilic unimolecular)

    Kinetics and Mechanism

    +....Br

    : :

    C....

    CH3CH3

    CH3

    Br:

    CH3C CH3

    CH3

    +

    unimolecular slow

    Mechanism

    CH3C CH3

    CH3

    +O: :

    H

    H

    C+O :

    H

    HCH3CH3

    CH3

    bimolecular fast

    Mechanism

  • ROH2+

    carbocation formation

    R+

    proton transfer

    ROH

    carbocation capture

    RX

    first order kinetics: rate = k[RX]unimolecular rate-determining step

    carbocation intermediaterate follows carbocation stabilityrearrangements sometimes observed

    reaction is not stereospecificSignificant racemization in reactions of optically active alkyl halides

    Characteristics of the SN1 mechanism

    The rate of nucleophilic substitutionby the SN1 mechanism is governed

    by electronic effects.

    Carbocation formation is rate-determining.The more stable the carbocation, the faster

    its rate of formation, and the greater the rate of unimolecular nucleophilic substitution.

    Electronic Effects Govern SN1 Rates

    RBr solvolysis in aqueous formic acid

    Alkyl bromide Class Relative Rate

    CH3Br Methyl 1

    CH3CH2Br Primary 2

    (CH3)2CHBr Secondary 43

    (CH3)3CBr Tertiary 100,000,000

    Reactivity toward substitution by the SN1 mechanism

    CH3Br

    CH3CH2Br

    (CH3)2CHBr

    (CH3)3CBr

    Decreasing SN1 Reactivity

    Nucleophilic substitutions that exhibitfirst-order kinetic behavior are

    not stereospecific.

    Generalization

  • Which alkyl halide will react faster with CH3OH under SN1 conditions?

    A) B)

    C) D)

    Interactive Question

    R-()-2-Bromooctane

    H

    C

    CH3

    Br

    CH3(CH2)5

    Stereochemistry of an SN1 Reaction

    (R)-()-2-Octanol (17%)

    H

    C

    CH3

    OH

    CH3(CH2)5

    C

    H CH3

    HO

    (CH2)5CH3(S)-(+)-2-Octanol (83%)

    H2O

    Ionization step gives carbocation; threebonds to chirality center become coplanar

    Leaving group shields one face of carbocation; nucleophile attacks

    faster at opposite face.

    Carbocations are intermediatesin SN1 reactions, rearrangements

    are possible.

    Carbocation Rearrangementsin SN1 Reactions Because...

    CH3 C

    H

    CHCH3

    Br

    CH3 H2OCH3 C

    OH

    CH2CH3

    CH3

    (93%)

    Example

    CH3 C

    H

    CHCH3

    CH3

    +

    H2O

    CH3 C CHCH3

    CH3

    H+

  • SN1 Reaction Rates Increase in Polar Protic Solvents

    Solvent Effects

    Solvent Dielectric Relativeconstant rate

    acetic acid 6 1methanol 33 4formic acid 58 5,000water 78 150,000

    SN1 Reactivity versus Solvent Polarity

    Most polar Fastest rate

    R+

    RX

    R X

    energy of RX not much affected by polarity of solvent

    transition state stabilized by polar solvent

    Ea

    R+

    RX

    R X

    energy of RX not much affected by polarity of solvent

    transition state stabilized by polar solvent

    activation energy decreases;

    rate increases

    Ea > Ea

    SN2 Reaction Rates Increase inPolar Aprotic Solvents

    An aprotic solvent is one that doesnot have an OH group.

    In general...

    Solvent Type Relative RateCH3OH polar protic 1H2O polar protic 7DMSO polar aprotic 1300DMF polar aprotic 2800Acetonitrile polar aprotic 5000

    CH3CH2CH2CH2Br + N3

    SN2 Reactivity vs. Type of Solvent

  • Interactive Question

    The reaction of butyl iodide with NaSCH3 will proceed at a faster rate in which solvent?A) acetoneB) acetic acidC) propanolD) water

    Mechanism SummarySN1 and SN2

    When...primary alkyl halides undergo nucleophilic substitution, they always react by the SN2 mechanismtertiary alkyl halides undergo nucleophilic substitution, they always react by the SN1 mechanismsecondary alkyl halides undergo nucleophilic substitution, they react by the

    SN1 mechanism in the presence of a weak nucleophile (solvolysis) in a protic solventSN2 mechanism in the presence of a good nucleophile in an aprotic solvent

    Interactive Question

    What combination is the best choice in order to prepare 3-chloro-1-iodobutane?A) 1-iodobutane + Cl2 (400C)B) 1,3-dichlorobutane + NaI (1 equiv) in

    acetoneC) 1,3-iodobutane + NaCl (1 equiv) in

    acetoneD) 3-bromo-1-iodobutane + NaCl (1 equiv)

    in acetone

    Interactive Question

    The best combination of reactants for preparing (CH3)3CSCH3 is:A) (CH3)3CCl + CH3SKB) (CH3)3CBr + CH3SNaC) (CH3)3CSK + CH3OHD) (CH3)3CSNa + CH3Br

    Substitution and Eliminationas Competing Reactions

  • Alkyl halides can react with Lewis bases by nucleophilic substitution and/or elimination.

    C C

    H

    X

    + Y:

    C C

    Y

    H

    X:

    +

    C C + H Y X:

    +

    -elimination

    nucleophilic substitution

    Two Reaction TypesHow can we tell which reaction pathway is followed for a particular alkyl halide?

    C C

    H

    X

    + Y:

    C C

    Y

    H

    X:

    +

    C C + H Y X:

    +

    -elimination

    nucleophilic substitution

    Two Reaction Types

    A systematic approach is to choose as a referencepoint the reaction followed by a typical alkyl halide(secondary) with a typical Lewis base (an alkoxideion).

    The major reaction of a secondary alkyl halidewith an alkoxide ion is elimination by the E2mechanism.

    Elimination versus Substitution

    CH3CHCH3

    Br

    NaOCH2CH3ethanol, 55C

    CH3CHCH3

    OCH2CH3CH3CH=CH2+

    (87%)(13%)

    Example

    Example: E2

    BrCH3CH2 O

    Example: SN2

    BrCH3CH2 O

  • Given that the major reaction of a secondaryalkyl halide with an alkoxide ion is elimination by the E2 mechanism, we can expect the proportion of substitution to increase with:

    1) decreased crowding at the carbon that bears the leaving group

    When is substitution favored?

    Decreased crowding at carbon that bears the leaving group increases substitution relative to elimination.

    primary alkyl halide

    CH3CH2CH2Br

    NaOCH2CH3ethanol, 55C

    CH3CH=CH2+CH3CH2CH2OCH2CH3(9%)(91%)

    Uncrowded Alkyl Halides

    primary alkyl halide + bulky base

    CH3(CH2)15CH2CH2Br

    KOC(CH3)3tert-butyl alcohol, 40C

    +CH3(CH2)15CH2CH2OC(CH3)3 CH3(CH2)15CH=CH2(87%)(13%)

    But a crowded alkoxide base can favor elimination even with a primary alkyl

    halide. Interactive Question

    Which one of the following alkyl halides would be expected to give the highest ratio ofsubstitution to elimination on treatment with sodium ethoxide in ethanol (50C)?A) 1-bromopentaneB) 2-bromopentaneC) 3-bromopentaneD) 2-bromo-3-methylbutane

    Given that the major reaction of a secondaryalkyl halide with an alkoxide ion is elimination by the E2 mechanism, we can expect the proportion of substitution to increase with:

    1) decreased crowding at the carbon that bears the leaving group

    2) decreased basicity of the nucleophile

    When is substitution favored? Weakly basic nucleophile increases

    substitution relative to elimination

    (70%)CH3CH(CH2)5CH3

    CN

    KCN

    CH3CH(CH2)5CH3

    ClpKa (HCN) = 9.1

    DMSO

    secondary alkyl halide + weakly basic nucleophile

    Weakly Basic Nucleophile

  • Weakly basic nucleophile increases substitution relative to elimination

    secondary alkyl halide + weakly basic nucleophile

    NaN3 pKa (HN3) = 4.6

    I

    (75%)N3

    Weakly Basic Nucleophile

    Tertiary alkyl halides are so sterically hinderedthat elimination is the major reaction with allanionic nucleophiles. Only in solvolysis reactionsdoes substitution predominate over eliminationwith tertiary alkyl halides.

    Tertiary Alkyl Halides

    (CH3)2CCH2CH3

    Br

    +CH3CCH2CH3

    OCH2CH3

    CH3

    CH2=CCH2CH3

    CH3

    CH3C=CHCH3

    CH3

    +

    ethanol, 25C64% 36%

    2M sodium ethoxide in ethanol, 25C1% 99%

    ExampleInteractive Question

    Which of the following is not a good nucleophile for an SN1 reaction?A) NaOCH3B) CH3OHC) CH3CH2OHD) H2O

    Interactive Question

    Which one of the following compounds gives the highest subtitution-to-elimination ratio(most substitution least elimination) on reaction with 2-bromobutane?A) NaOCH3B) NaNH2C) NaCND) NaCCH

    Leaving Groups

    We have seen numerous examples of nucleophilic substitution in which X in RX is a halogen

    However, halogens are not the only possible leaving groups

  • Other RX compounds

    ROSCH3

    O

    O

    ROS

    O

    O

    CH3

    Alkylmethanesulfonate

    (mesylate)

    Alkylp-toluenesulfonate

    (tosylate)

    undergo same kinds of reactions as alkyl halides

    Preparation

    (abbreviated as ROTs)

    ROH + CH3 SO2Clpyridine

    ROS

    O

    O

    CH3

    Tosylates are prepared by the reaction of alcohols with p-toluenesulfonyl chloride(usually in the presence of pyridine)

    Tosylates undergo typical nucleophilic substitution reactions

    H

    CH2OTs

    KCN

    ethanol-water

    H

    CH2CN

    (86%)

    The best leaving groups are weakly basic

    Approximate Relative Reactivity of Leaving Groups

    Leaving Relative Conjugate acid pKa ofGroup Rate of leaving group conj. acid

    F 10-5 HF 3.5Cl 1 HCl -7Br 10 HBr -9I 102 HI -10

    H2O 101 H3O+ -1.7TsO 105 TsOH -2.8

    CF3SO2O 108 CF3SO2OH -6

    Approximate Relative Reactivity of Leaving Groups

    Leaving Relative Conjugate acid pKa ofGroup Rate of leaving group conj. acid

    F 10-5 HF 3.5Cl 1 HCl -7Br 10 HBr -9I 102 HI -10

    H2O 101 H3O+ -1.7TsO 105 TsOH -2.8

    CF3SO2O 108 CF3SO2OH -6Sulfonate esters are extremely good leaving groups; sulfonate ions are very weak bases.

  • Tosylates can be converted to alkyl halides

    NaBr

    DMSO

    (82%)

    OTs

    CH3CHCH2CH3

    Br

    CH3CHCH2CH3

    Tosylate is a better leaving group than bromide.

    Tosylates allow control of stereochemistry

    Preparation of tosylate does not affect any of the bonds to the chirality center, so configuration and optical purity of tosylate is the same as the alcohol from which it was formed.

    TsCl

    pyridine

    H

    C OTs

    CH3

    CH3(CH2)5H

    C OH

    CH3

    CH3(CH2)5

    H

    C

    CH3

    Nu

    CH3(CH2)5

    C

    H CH3

    TosO

    (CH2)5CH3

    Nu

    SN2

    Having a tosylate of known optical purity and absolute configuration then allows the preparation of other compounds of known configuration by SN2 processes.

    Tosylates allow control of stereochemistry

    Secondary alcohols react with inversion

    C

    HH3C

    OH

    CH3(CH2)5

    C

    HH3C

    Br

    CH3(CH2)5

    C

    HCH3

    (CH2)5CH3

    Br

    HBr

    87%

    13%

    Secondary alcohols react with inversion

    C

    HH3C

    OH

    CH3(CH2)5

    C

    HH3C

    Br

    CH3(CH2)5

    C

    HCH3

    (CH2)5CH3

    Br

    HBr

    87%

    13%

    Most reasonable mechanism is SN1 with front side of carbocation shielded by leaving group

    Rearrangements can occur

    OH

    Br

    Br

    +

    93% 7%

    HBr

  • Rearrangements can occur

    OH

    Br

    Br

    +

    +

    +

    93%

    7%

    Br Br

    HBr

    Tosylates also undergo Elimination

    NaOCH3

    CH3OHheat

    OTs

    CH3CHCH2CH3CH2=CHCH2CH3

    CH3CH=CHCH3E and Z

    +

    Summary: Chapter 8Summary: Chapter 8

    8.1 Nucleophilic Substitution

    8.2 Relative Reactivity of Halides

    8.3 The SN2 Mechanism

    8.4 Steric Effects in SN2

    8.5 Nucleophiles and Nucleophilicity

    8.6 The SN1 Mechanism

    8.7 Carbocation Stability and SN1 Rate

    8.8 Stereochemistry of SN1 Reactions

    8.9 Carbocation Rearrangements in SN1 Reactions

    Summary: Chapter 8Summary: Chapter 88.10 Solvent Effects on Nucleophilic Substitution8.11 Substitution vs. Elimination8.12 Sulfonate Esters as Substrates in SN1 and SN2