C. Y. Yeung (CHW, 2009)

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C. Y. Yeung (CHW, 2009) p.01 Energy Profile Energy Profile and and Reaction Mechanism Reaction Mechanism Energy Profile Energy Profile and and Reaction Mechanism Reaction Mechanism How does the reaction take place???

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Energy Profile and Reaction Mechanism. Energy Profile and Reaction Mechanism. How does the reaction take place???. p.01. C. Y. Yeung (CHW, 2009). +. C. A. B. +. A. B. C. p.02. How does a reaction occur?. A + B  C. K.E.  E a. Single Stage Rxn. collide in right orientation. - PowerPoint PPT Presentation

Transcript of C. Y. Yeung (CHW, 2009)

Page 1: C. Y. Yeung (CHW, 2009)

C. Y. Yeung (CHW, 2009)

p.01

Energy Profile Energy Profile and and

Reaction MechanismReaction MechanismEnergy Profile Energy Profile andand

Reaction MechanismReaction Mechanism

How does the reaction

take place???

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A + B A + B C C

How does a reaction occur?How does a reaction occur?

K.E. K.E. E Eaa

collide in right collide in right orientationorientation

A ++ B CSingle StagSingle Stag

e Rxne Rxn

Multi-Stage Multi-Stage RxnRxnA ++ B CIntermediateIntermediate

How to know that …. ?How to know that …. ?

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From theFrom the

ChemicalChemical && DifferentialDifferential Rate Eqns Rate Eqns !!

e.g. 2A + B e.g. 2A + B 3C 3C

If after Kinetics Studies, it was found that If after Kinetics Studies, it was found that …… Rate = k[A][B]Rate = k[A][B]

i.e. The reaction is a 2-step reaction!i.e. The reaction is a 2-step reaction!

Step 1:Step 1: A + B A + B Intermediate Intermediate (r.d.s.)(r.d.s.)

Step 2:Step 2: Intermediate + Intermediate + AA C C

** ** a “A” molecule and a “B” molecule are a “A” molecule and a “B” molecule are involved in the involved in the “rate-determining step”“rate-determining step”..

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e.g. 2A + B e.g. 2A + B 3C 3C

If after Kinetics Studies, it was found that If after Kinetics Studies, it was found that …… Rate = k[A]Rate = k[A]22

i.e. The reaction is a 2-step reaction!i.e. The reaction is a 2-step reaction!

Step 1:Step 1: A + A A + A Intermediate Intermediate (r.d.s.)(r.d.s.)

Step 2:Step 2: Intermediate + Intermediate + BB C C

** ** Two “A” molecules are involved in the Two “A” molecules are involved in the “rate-determining step”“rate-determining step”..

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e.g. 2A + B e.g. 2A + B 3C 3C

If after Kinetics Studies, it was found that If after Kinetics Studies, it was found that …… Rate = k[B]Rate = k[B]

i.e. The reaction is a 2-step reaction!i.e. The reaction is a 2-step reaction!

Step 1:Step 1: B B Intermediate Intermediate (r.d.s.)(r.d.s.)

Step 2:Step 2: Intermediate + Intermediate + 2A2A C C

** ** Only one “B” molecule is involved in the Only one “B” molecule is involved in the “rate-determining step”“rate-determining step”..

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e.g. 2A + B e.g. 2A + B 3C 3C

If after Kinetics Studies, it was found that If after Kinetics Studies, it was found that …… Rate = k[A]Rate = k[A]22[B][B]

i.e. The reaction is a Single-step i.e. The reaction is a Single-step reaction!reaction!

2A + B 2A + B 3C 3C

** ** ALL the molecules are involved in the ALL the molecules are involved in the “rate-determining step”“rate-determining step”..

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p.072A + B 2A + B 3C 3C Energy ProfileEnergy Profile ?? ??

Rate = k[A]Rate = k[A]22[B][B]

Rate = k[B]Rate = k[B]

Rate = k[A]Rate = k[A]22

Rate = k[A][B]Rate = k[A][B]

intermediate

Transition state

Transition state

higher Ea: r.d.s. (slower step)

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p. 79 Q.9 (1999 --- Differential Rate Eqn. p. 79 Q.9 (1999 --- Differential Rate Eqn. and Energy Profil and Energy Profil

e)e)(a)(a) Rate = k[A]Rate = k[A]

(c)(c) A + B A + B product product

i.e. i.e. Only a “A” is involved in Only a “A” is involved in r.d.s.r.d.s.

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Catalyst Catalyst changeschanges the energy profile of rxn! the energy profile of rxn!

A + B A + B C CIf no catalyst … A + B If no catalyst … A + B C, with high E C, with high Eaa..

With catalyst (X)… With catalyst (X)…

A + A + XX intermediate intermediate, with a lower E, with a lower Eaa. (r.d.s.). (r.d.s.)

intermediate + B intermediate + B C + C + XX (becomes a 2-stage rx(becomes a 2-stage rxn)n)

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Energy ProfilesEnergy Profiles with / withoutwith / without CatalystCatalyst …… (slow) [r.d.s.](slow) [r.d.s.]

(fast)(fast)

H is not affected H is not affected by catalystby catalyst

Only 1 transition stateOnly 1 transition state

2 transition states2 transition states

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p. 79 Q.11 (2001 --- Differential Rate Eqn. p. 79 Q.11 (2001 --- Differential Rate Eqn. and Energy Profil and Energy Profil

e)e)

(a)(a) Rate = k [I(g)]Rate = k [I(g)]22 [Ar] [Ar]

(c)(c) 2 I 2 I I I22

i.e. i.e. Two “I” atoms and one “Ar” aTwo “I” atoms and one “Ar” atom are involved in r.d.s.tom are involved in r.d.s.

3 possible energy profiles!!3 possible energy profiles!!

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3 Different 3 Different Stories are Stories are possible!possible!

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I(g) + I(g) + Ar I(g) + I(g) + Ar I I22(g) + Ar*(g) + Ar*

(g)(g)Role of ArRole of Ar: : acts as a third body to absorb enacts as a third body to absorb energy from the colliding I(g) atoms.ergy from the colliding I(g) atoms.

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Step 1:Step 1: I(g) + Ar(g) I(g) + Ar(g) I-Ar(g) [fast] I-Ar(g) [fast]

Step 2:Step 2: I-Ar(g) + I I-Ar(g) + I I I22 + Ar(g) [slo + Ar(g) [slo

w]w]Role of ArRole of Ar: : homogeneous catalysthomogeneous catalyst

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Step 1:Step 1: 2I(g) + Ar(g) 2I(g) + Ar(g) I I22Ar(g) [slow]Ar(g) [slow]

Step 2:Step 2: II22Ar(g) Ar(g) I I22 + Ar(g) [fast] + Ar(g) [fast]

Role of ArRole of Ar: : homogeneous catalysthomogeneous catalyst

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Expt. 9 Activation EnergyExpt. 9 Activation Energy

5 Br5 Br-- + BrO + BrO33-- + 6 H + 6 H++ 3 Br 3 Br22 + 3H + 3H22OO

formed quickly!formed quickly!

3 Br3 Br22 ++

OHOH OHOHBrBr BrBr

BrBr

++ 3 HBr3 HBr

e.g. 3 moles are form e.g. 3 moles are form in 42 sin 42 s

All the 3 moles All the 3 moles of Brof Br22 reacts reacts

with phenol. with phenol. does not does not

bleach methyl bleach methyl red indicator.red indicator.

At 42.1s, a new BrAt 42.1s, a new Br22 is formed, which will not is formed, which will not

react with phenol, but bleach methyl red!react with phenol, but bleach methyl red!

e.g. 1 mole.g. 1 mol

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The time required for bleaching Methyl Red is The time required for bleaching Methyl Red is

recorded. recorded. data treatmentdata treatment ...? ...?

Temp./0C Time/srate/mol s-1

(if 3 mol of Br2 are formed)

25 92 3/92

30 56 3/56

41 30 3/30

52 9 3/9

i.e. time required i.e. time required , , rate rate rate rate 1/t 1/t

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rate rate 1/t 1/t k k 1/t 1/t

Therefore …Therefore …

ln k = – + lnAln k = – + lnAEEaa

RR11TT

ln (1/t) = – + lnAln (1/t) = – + lnAEEaa

RR11TT

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AssignmentAssignment

p.74 p.74 Q.11, 12 [due date: 2/3(Mon)] Q.11, 12 [due date: 2/3(Mon)]

Lab Report: Expt. 9 Determination of ELab Report: Expt. 9 Determination of Eaa

[due date: 3/3(Tue)] [due date: 3/3(Tue)]

Quiz on Chemical Kinetics (Ch. 13-15)Quiz on Chemical Kinetics (Ch. 13-15)

[9/3(Mon)] [9/3(Mon)]

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Next ….Next ….

Chemical Equilibria & KChemical Equilibria & Keqeq

(p. 88-100)(p. 88-100)