Oct. 30, 2012AGENDA:1 – Bell Ringer2 – Kinematics

Equations3 – Exit Ticket

Today’s Goal:Students will be able to identify which kinematic equation to apply in each situationHomework1. Pages 4-6

CHAMPS for Bell RingerC – Conversation – No Talking H – Help – RAISE HAND for questionsA – Activity – Solve Bell Ringer on

binder paper. Homework out on desk

M – Materials and Movement – Pen/Pencil, Notebook or Paper

P – Participation – Be in assigned seats, work silently

S – Success – Get a stamp! I will collect!

October 30th (p. 13)Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:1. How many quantities did

we underline in each problem?

2. How many known variables are you given in each problem?

3. How many unknown variables are you asked to find in each problem?

4. How do you decide what equation to use?

5. What do the equations mean to you?

4 MINUTES REMAINING…

October 30th (p. 13)Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:1. How many quantities did

we underline in each problem?

2. How many known variables are you given in each problem?

3. How many unknown variables are you asked to find in each problem?

4. How do you decide what equation to use?

5. What do the equations mean to you?

3 MINUTES REMAINING…

October 30th (p. 13)Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:1. How many quantities did

we underline in each problem?

2. How many known variables are you given in each problem?

3. How many unknown variables are you asked to find in each problem?

4. How do you decide what equation to use?

5. What do the equations mean to you?

2 MINUTES REMAINING…

October 30th (p. 13)Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:1. How many quantities did

we underline in each problem?

2. How many known variables are you given in each problem?

3. How many unknown variables are you asked to find in each problem?

4. How do you decide what equation to use?

5. What do the equations mean to you?

1minute Remaining…

October 30th (p. 13)Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:1. How many quantities did

we underline in each problem?

2. How many known variables are you given in each problem?

3. How many unknown variables are you asked to find in each problem?

4. How do you decide what equation to use?

5. What do the equations mean to you?

30 Seconds Remaining…

October 30th (p. 13)Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:1. How many quantities did

we underline in each problem?

2. How many known variables are you given in each problem?

3. How many unknown variables are you asked to find in each problem?

4. How do you decide what equation to use?

5. What do the equations mean to you?

BELL-RINGER TIME IS

UP!

October 30th (p. 13)Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:1. How many quantities did

we underline in each problem?

2. How many known variables are you given in each problem?

3. How many unknown variables are you asked to find in each problem?

4. How do you decide what equation to use?

5. What do the equations mean to you?

Shout OutsPeriod 5 – ChrisPeriod 7 – Latifah, Shawn

Oct. 30, 2012AGENDA:1 – Bell Ringer2 – Kinematics

Equations3 – Exit Ticket

Today’s Goal:Students will be able to identify which kinematic equation to apply in each situationHomework1. Pages 4-6

Week 8Weekly AgendaMonday – Kinematic Equations ITuesday – Kinematic Equations IIWednesday – Kinematic Equations

IIIThursday – ReviewFriday – Review

Unit Test next week!

What are equations?Equations are relationships.

Equations describe our world.

Equations have changed the course of history.

CHAMPS for Problems p. 4-6C – Conversation – No Talking unless

directed to work in groupsH – Help – RAISE HAND for questionsA – Activity – Solve Problems on Page

4-6M – Materials and Movement –

Pen/Pencil, Packet Pages 4-6P – Participation – Complete Page 4-6S – Success – Understand all

Problems

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Solving Problems: THE EASY WAY (p. 4)

1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?

vi = 0 m/sa = 3 m/s2

Δt = 10 secondsvf = ?

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Solving Problems: THE EASY WAY (p. 4)

1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?

vi = 0 m/s a = 3 m/s2 Δt = 10 seconds vf = ?vf = vi + aΔt

Solving Problems: THE EASY WAY (p. 4)

1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?

vi = 0 m/s a = 3 m/s2 Δt = 10 seconds vf = ?vf = vi + aΔtvf = 0 m/s + (3 m/s2)(10 s) =

Solving Problems: THE EASY WAY (p. 4)

1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?

vi = 0 m/s a = 3 m/s2 Δt = 10 seconds vf = ?vf = vi + aΔtvf = 0 m/s + (3)(10) = 30 m/s

Solving Problems: THE EASY WAY (p. 4

2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?vi = 0 m/s a = 3 m/s2 Δt = 10 seconds Δx = ?Δx = viΔt + aΔt2

2

Solving Problems: THE EASY WAY (p. 4)

2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?vi = 0 m/s a = 3 m/s2 Δt = 10 seconds Δx = ?Δx = viΔt + aΔt2

2Δx = (0)(10) + (3)(10)2

2

Solving Problems: THE EASY WAY (p. 4)

2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?vi = 0 m/s a = 3 m/s2 Δt = 10 seconds Δx = ?Δx = viΔt + aΔt2

2Δx = (0)(10) + (3)(10)2

2Δx = 0 + 150 m = 150 m

Solving Problems: THE EASY WAY (p. 4

3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?vi = 0 m/s a = 40,000 m/s2 Δx = 0.5 m vf = ?

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Solving Problems (p. 4)3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?vi = 0 m/s a = 40,000 m/s2 Δx = 0.5 m vf = ?vf

2 = vi2 + 2aΔx

Solving Problems (p. 4)3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?vi = 0 m/s a = 40,000 m/s2 Δx = 0.5 m vf = ?vf

2 = vi2 + 2aΔx

vf2 = (0)2 + 2(40,000)(0.5)

Solving Problems (p. 4)3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?vi = 0 m/s a = 40,000 m/s2 Δx = 0.5 m vf = ?vf

2 = vi2 + 2aΔx

vf2 = (0)2 + 2(40,000)(0.5)

vf2 = 40,000

vf = 200 m/s

Solving Problems (p. 4)4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?vi = 20 m/s vf = 0 m/s Δt = 4 seconds

a = ?

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Solving Problems (p. 4)4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?vi = 20 m/s vf = 0 m/s Δt = 4 seconds

a = ?vf = vi + aΔt

Solving Problems (p. 4)4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?vi = 20 m/s vf = 0 m/s Δt = 4 seconds

a = ?vf = vi + aΔt0 = 20 + 4a

Solving Problems (p. 4)4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?vi = 20 m/s vf = 0 m/s Δt = 4 seconds

a = ?vf = vi + aΔt0 = 20 + 4a

0 = 20 + 4a

Solving Problems (p. 4)4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?vi = 20 m/s vf = 0 m/s Δt = 4 seconds

a = ?vf = vi + aΔt0 = 20 + 4a

-20 + 0 = 20 + 4a + -20-20 = 4a

Solving Problems (p. 4)4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?vi = 20 m/s vf = 0 m/s Δt = 4 seconds

a = ?vf = vi + aΔt0 = 20 + 4a

-20 + 0 = 20 + 4a + -20-20/4 = 4a/4

Solving Problems (p. 4)4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?vi = 20 m/s vf = 0 m/s Δt = 4 seconds

a = ?vf = vi + aΔt0 = 20 + 4a

-20 + 0 = 20 + 4a + -20-20/4 = 4a/4

a = -5 m/s2

Solving Problems (p. 5)5. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. How far does the car travel before coming to a stop?vi = 20 m/s vf = 0 m/s Δt = 4s Δx = ?

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Solving Problems (p. 5)5. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. How far does the car travel before coming to a stop?vi = 20 m/s vf = 0 m/s Δt = 4s Δx = ?

Δx = (vf + vi)Δt

2

Solving Problems (p. 5)5. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. How far does the car travel before coming to a stop?vi = 20 m/s vf = 0 m/s Δt = 4s Δx = ?

Δx = (vf + vi)Δt = (0 + 20)(4) = 40 m

2 2

Solving Problems (p. 5)6. The USS Enterprise accelerates from rest at 100,000 m/s2 for a time of four seconds. How far did the ship travel in that time?

Solving Problems (p. 5)6. The USS Enterprise accelerates from rest at 100,000 m/s2 for a time of four seconds. How far did the ship travel in that time?vi = 0 m/s a = 100,000 m/s2 Δt = 4s Δx = ?

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Solving Problems (p. 5)6. The USS Enterprise accelerates from rest at 100,000 m/s2 for a time of four seconds. How far did the ship travel in that time?vi = 0 m/s a = 100,000 m/s2 Δt = 4s Δx = ?

Δx = viΔt + aΔt2 =

2

Solving Problems (p. 5)6. The USS Enterprise accelerates from rest at 100,000 m/s2 for a time of four seconds. How far did the ship travel in that time?vi = 0 m/s a = 100,000 m/s2 Δt = 4s Δx = ?

Δx = viΔt + aΔt2 = (0)(4) + (100,000)(4)2

2 2

Solving Problems (p. 5)6. The USS Enterprise accelerates from rest at 100,000 m/s2 for a time of four seconds. How far did the ship travel in that time?vi = 0 m/s a = 100,000 m/s2 Δt = 4s Δx = ?

Δx = viΔt + aΔt2 = (0)(4) + (100,000)(4)2

2 2Δx = 800,000 m

Solving Problems (p. 5)7. At the scene of an accident, a police officer notices that the skid marks of a car are 10 m long. The officer knows that the typical deceleration of this car when skidding is -45 m/s2. What can the officer estimate the original speed of the car?

Solving Problems (p. 5)7. At the scene of an accident, a police officer notices that the skid marks of a car are 10 m long. The officer knows that the typical deceleration of this car when skidding is -45 m/s2. What can the officer estimate the original speed of the car?

Solving Problems (p. 5)7. At the scene of an accident, a police officer notices that the skid marks of a car are 10 m long. The officer knows that the typical deceleration of this car when skidding is -45 m/s2. What can the officer estimate the original speed of the car?Δx = 10 m a = -45 m/s2 vf = 0 m/s vi = ?