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Page 1: PreCalculus 1st Semester Review (solutions)...PreCalculus 1st Semester Review (solutions) Author Paul Kidd Created Date 1/21/2016 9:31:14 PM ...

Precalculus  First  Semester  Review    

18)  Use  change  of  base  to  approximate  the  following  to  three  decimal  places    π‘Ž) log! 216         𝑏) log! 91      π₯π¨π πŸπŸπŸ”  π₯π¨π πŸ–

= 𝟐.πŸ“πŸ–πŸ“         π₯π¨π πŸ—πŸπ₯𝐨𝐠𝟐

= πŸ”.πŸ“πŸŽπŸ–    19)  Evaluate  the  following  limits    π‘Ž) lim!β†’!

!!!!!!!"!!!

            𝑏) lim!β†’!! !!! !!! !!!!

!  

 π‘) lim!β†’!

!!!! !!

            𝑑) lim!β†’!!!

!!!!!!!  

   20) A certain population (in thousands) grows according to the equation 𝑃 = 40𝑒!.!"#!

where P represents the population and t represent the number of years since 2000. a) Determine the year when the population 60 thousand will be reached. πŸ”πŸŽ = πŸ’πŸŽπ’†πŸŽ.πŸŽπŸπŸ“π’• 𝟏.πŸ“ = π’†πŸŽ.πŸŽπŸπŸ“π’• π₯𝐧 𝟏.πŸ“   = 𝟎.πŸŽπŸπŸ“π’• 𝒕 = π₯𝐧 𝟏.πŸ“

𝟎.πŸŽπŸπŸ“= πŸπŸ”.πŸπŸπŸ—  π’šπ’†π’‚𝒓𝒔

πŸπŸŽπŸπŸ• b) Determine the population in 2003 𝑷 πŸ‘ = πŸ’πŸŽπ’†πŸŽ.πŸŽπŸπŸ“(πŸ‘) = πŸ’πŸŽ.πŸπŸπŸ“      π’π’“      πŸ’πŸ,πŸπŸπŸ“ c) Determine the initial population. πŸ’πŸŽ,𝟎𝟎𝟎  21)  Given  π΄ = 1 0

3 4  and  π΅ =βˆ’3 20 3  

a)  Find  3𝐴 + 𝐡    b)  Find  AB    d)  Find  π΄!!    22)  Given  the  geometric  sequence  with  π‘Ž! = 32  and  π‘Ÿ = !

!  

a)  Write  the  formula  π‘Ž!  for  the  sequence  

𝒂𝒏 = πŸ‘πŸ 𝟏𝟐

𝒏!𝟏    

 b)  Write  the  first  five  terms  of  the  sequence    πŸ‘πŸ,πŸπŸ”,πŸ–,πŸ’,𝟐      c)  Determine  the  term  π‘Ž!"    

π’‚πŸπŸ = πŸ‘πŸ 𝟏𝟐

𝟏𝟐!𝟏= 𝟏

πŸ‘πŸ      

Page 2: PreCalculus 1st Semester Review (solutions)...PreCalculus 1st Semester Review (solutions) Author Paul Kidd Created Date 1/21/2016 9:31:14 PM ...

Precalculus  First  Semester  Review    

 23)  Given  the  arithmetic  sequence  with  π‘Ž! = 20  and  π‘‘ = βˆ’3  a)  Write  the  formula  π‘Ž!  for  the  sequence    π’‚𝒏 = βˆ’πŸ‘π’+ πŸπŸ‘      b)  Write  the  first  four  terms  of  the  sequence    πŸπŸŽ,πŸπŸ•,πŸπŸ’,𝟏𝟏      c)  Determine  the  term  π‘Ž!"    π’‚πŸπŸŽ = βˆ’πŸ‘ 𝟏𝟎 + πŸπŸ‘ = βˆ’πŸ•      24)  Determine  the  value  of  the  account  with  an  initial  balance  of  $3000  that  is  compounded  quarterly  with  an  interest  rate  of  8%  after  5  years.      

𝑨 = πŸ‘πŸŽπŸŽπŸŽ 𝟏+ .πŸŽπŸ–πŸ’

πŸ’ πŸ“= πŸ’πŸ’πŸ“πŸ•.πŸ–πŸ’      

 25)  Determine  the  value  of  an  account  with  an  initial  balance  of  $3000  that  is  compounded  continuously  with  an  interest  rate  of  8%  after  5  years.      π‘¨ = πŸ‘πŸŽπŸŽπŸŽπ’†.πŸŽπŸ–(πŸ“)   = πŸ’πŸ’πŸ•πŸ“.πŸ’πŸ•      26)  Determine  the  coefficient  of  the  following  terms  in  the  expansion  of   3π‘₯ + 6𝑦 !  a)  π‘₯!𝑦!         b)  π‘₯!𝑦      πŸ—πŸ•πŸπŸŽ           πŸπŸ’πŸ‘πŸŽ    27)  Evaluate  the  following    a)   𝐢!   !           b)   𝐢!   !         c)   𝐢!   !    28)  Write  in  a  +  bi  form:  !!!!

!!!!  

 πŸ!πŸ’π’ŠπŸ‘!πŸπ’Š

πŸ‘!πŸπ’ŠπŸ‘!πŸπ’Š

= πŸ”!πŸ’π’Š!πŸπŸπ’Š!πŸ–π’ŠπŸ

πŸ—!πŸ’π’ŠπŸ= πŸ”!πŸπŸ”π’Š!πŸ–

πŸ—!πŸ’= !𝟐!πŸπŸ”π’Š

πŸπŸ‘= βˆ’ 𝟐

πŸπŸ‘+ πŸπŸ”π’Š

πŸπŸ‘    

 29)  Graph  the  function  and  tell  whether  or  not  it  has  a  point  of  discontinuity  at  x  =  0.  If  there  is  a  discontinuity,  tell  whether  it  is  removable  or  non-­‐removable.  a)  π‘“ π‘₯ = !

!           b)  π‘” π‘₯ = !!!!

!  

 non-­‐removable           removable      

Page 3: PreCalculus 1st Semester Review (solutions)...PreCalculus 1st Semester Review (solutions) Author Paul Kidd Created Date 1/21/2016 9:31:14 PM ...

Precalculus  First  Semester  Review    

 30)  Simplify    a)  log!! 11!         b)  ln !

!         c)  log!

!!"  

 πŸ’             βˆ’πŸ         βˆ’πŸ‘    31)  Find  the  zeros  of  the  function  algebraically.  a)  π‘“ π‘₯ = 3π‘₯! + 2π‘₯ βˆ’ 5         b)  π‘“ π‘₯ = π‘₯! βˆ’ 36π‘₯  πŸ‘π’™πŸ + πŸπ’™βˆ’ πŸ“ = 𝟎             π’™πŸ‘ βˆ’ πŸ‘πŸ”π’™ = 𝟎  πŸ‘𝒙+ πŸ“ π’™βˆ’ 𝟏 = 𝟎           𝒙 π’™πŸ βˆ’ πŸ‘πŸ” = 𝟎  π’™ = βˆ’ πŸ“

πŸ‘,𝟏               𝒙 π’™βˆ’ πŸ” 𝒙+ πŸ” = 𝟎  

              𝒙 = 𝟎,βˆ’πŸ”,πŸ”    32)  Determine  whether  the  functions  are  even,  odd,  or  neither  a)  π‘“ π‘₯ = 3π‘₯! βˆ’ 2π‘₯           b)  π‘” π‘₯ = 2π‘₯! βˆ’ 3π‘₯! + 5    ODD               EVEN    33)  Do  the  following  functions  have  an  inverse?  If  so,  find  it  a)  π‘“ π‘₯ = π‘₯! + 1!           b)  π‘¦ = 2 βˆ’ π‘₯  π’™ = π’šπŸ + πŸπŸ‘               𝒙 = πŸβˆ’ π’š  π’™πŸ‘ = π’šπŸ + 𝟏               π’™πŸ = πŸβˆ’ π’š  π’™πŸ‘ βˆ’ 𝟏 = π’šπŸ               π’š = πŸβˆ’ π’™πŸ  π’š = π’™πŸ‘ βˆ’ 𝟏                  34)  Divide  !

!!!!!!!!

 with  long  division     35)  Divide   !!!!!!!!!!!!

 with  synthetic    π’™πŸ + πŸπ’™+ πŸ‘             πŸ“π’™πŸ‘ βˆ’ πŸ“π’™πŸ + πŸ‘π’™βˆ’ πŸ‘βˆ’ 𝟏

𝒙!𝟏  

 36)  Where  is  the  following  function  discontinuous?  a)  π‘¦ = !!!

!!!           b)  π‘¦ = !

!!!!!!!  

 π’™ = πŸ‘               𝒙 = βˆ’πŸ,βˆ’πŸ‘