THURSDAY, 19 TH SEPTEMBER 2013 Today in Chemistry Percent Composition Assignment Read pp. 320-355.

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THURSDAY, 19 TH SEPTEMBER 2013 Today in Chemistry Percent Composition Assignment Read pp. 320-355

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KEY IDEA The law of Definite Proportions A compound is always composed of the same elements in the same proportion by mass, no matter how large or small the sample.

Transcript of THURSDAY, 19 TH SEPTEMBER 2013 Today in Chemistry Percent Composition Assignment Read pp. 320-355.

Page 1: THURSDAY, 19 TH SEPTEMBER 2013 Today in Chemistry Percent Composition Assignment Read pp. 320-355.

THURSDAY, 19TH SEPTEMBER 2013

•Today in Chemistry• Percent Composition

•Assignment•Read pp. 320-355

Page 2: THURSDAY, 19 TH SEPTEMBER 2013 Today in Chemistry Percent Composition Assignment Read pp. 320-355.

KEY IDEA

•Formula mass = The sum of the atomic masses in the formula. KNO3

K = 39.1 amuN = 14.0 amuO = 3 x 16.0 amuKNO3 101.1 amu

AMU?Atomic Mass Unit 39.1 g of K is equal to 14.0 g of N (same # of particles)

Page 3: THURSDAY, 19 TH SEPTEMBER 2013 Today in Chemistry Percent Composition Assignment Read pp. 320-355.

KEY IDEA

•The law of Definite Proportions

A compound is always composed of the same elements in the same proportion by mass, no matter how large or small the sample.

Page 4: THURSDAY, 19 TH SEPTEMBER 2013 Today in Chemistry Percent Composition Assignment Read pp. 320-355.

KEY IDEA

•Percent Composition~Remember it adds up to 100% Percent Composition by Mass% Comp. = # Atoms x Atomic Mass x

100Formula Mass

% H in H2O = 2 atoms H x 1.0 amu x 10018.0 amu H2O

% H in H2O = 11 % So…. %O = ?

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Page 5: THURSDAY, 19 TH SEPTEMBER 2013 Today in Chemistry Percent Composition Assignment Read pp. 320-355.

KEY IDEA

• The Law of Multiple ProportionsWhen different compounds are formed by the same elements, different masses combine in simple whole number ratios. Methane CH4 Ethane C2H6

FM = 16.0 FM = 30 % H = 25% % H = 20%

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