The E Tutor - Types of Quadrilaterals
Transcript of The E Tutor - Types of Quadrilaterals
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WHAT AREQUADRILATERALS?
A quadrilateral is a four-sided
polygon.
If sides are parallel, the distancebetween them is constant, and
they will never cross, even if
extended.
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SIX TYPES OF
QUADRILATERALS
RECTANGLE
SQUARE
PARALLELOGRAM
RHOMBUS
KITE
TRAPEZOID
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A RECTANGLE IS
A quadrilateral having two pairs of equalsides that are parallel
Sides meet at right angles (90)
Diagonals are equal in length
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RECTANGLE In a rectangle the diagonals, besides being equal in length
bisect each other.Given: ABCD is a Rectangle the diagonals are AC & BD
Bisect each other at a Point O.
To Prove: (i) AC = BD
(ii) OA = OC or OB = OD
Proof: In ABC and ABD
AB = AB --------- (Common)
BC = AD ---------------------(Apposite sides ABCD) A = B = 90 (angles of the rectangles)
ABC ABD S. A. S. Rule
So, AC = BD Proved
A B
CD
O
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RECTANGLE(ii) OA = OC or OB = OD
Proof: In AOB and COD
AB = CD (Sides of the ABCD)
AB || CD and transversal AC & BD
Then, ODC = OBA
And OCD = OAB
Alternate interior angles
AOB COD --- A. S. A Rule
So that all congruent part are equal .OA = OC
and OB = OD
Proved
A B
CD
O
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A SQUARE IS
A rectangle having all sides of equallength
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SQUARE
The diagonals of a square are perpendicular bisectors ofeach other
Given: ABCD is a Square, Where AC and BD is a diagonalbisect each other at a Pont O
To Prove: AOD = COD = 90
Proof: In AOD and COD
OD Common & OA =OC
AD = DC ------ Two sides of Squire
So, (By SSS) AOB COD, AOD = COD
Since AOD and COD are a linear pair,
AOD = COD = 90
A B
CD
O
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PARALLELOGRAM
A quadrilateral having two pairs of equalsides that are parallel
Opposite angles are equal
Diagonals are not equal in length
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PARALLELOGRAM
The diagonals of a parallelogram bisect each otherGiven: ABCD is a parallelogram where AC and BD is a diagonal
bisect each other at Point O
To Prove: AO = OC or BO= OD
Proof: In AOB and CODAB = CD
AB || CD
CDO = OBA
And DCO = OAB ------------ Alternate interior angles
So, AOB COD, then
AO = OC or BO =OD Proved
A B
CD
O
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A RHOMBUS IS
A parallelogram having all sides of equallength
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RHOMBUS The diagonals of a rhombus are perpendicular
bisectors of one another.Given: ABCD is a rhombus. Therefore it is a parallelogram too.
Since diagonals bisect each other,
OA = OC and OB = OD.
To Prove: AOD = COD = 90
Proof: In AOD and COD
OD Common & OA =OC --Given
AD = DC ------ Two sides of this rhombus
So, (By SSS) AOB COD, then AOD = COD,
Since AOD and COD are a linear pair,
AOD = COD = 90
A B
CD
O
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KITE A quadrilateral having two pairs of equal sides
One pair of opposite equal angles
One diagonal bisects the other.
Diagonals intersect at right angles.
http://www.mathsteacher.com.au/year7/ch08_angles/01_ang/ang.htmhttp://www.mathsteacher.com.au/year7/ch08_angles/01_ang/ang.htm -
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TRAPEZOID
A quadrilateral with one pair of parallelsides
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