The E Tutor - Types of Quadrilaterals

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    WHAT AREQUADRILATERALS?

    A quadrilateral is a four-sided

    polygon.

    If sides are parallel, the distancebetween them is constant, and

    they will never cross, even if

    extended.

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    SIX TYPES OF

    QUADRILATERALS

    RECTANGLE

    SQUARE

    PARALLELOGRAM

    RHOMBUS

    KITE

    TRAPEZOID

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    A RECTANGLE IS

    A quadrilateral having two pairs of equalsides that are parallel

    Sides meet at right angles (90)

    Diagonals are equal in length

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    RECTANGLE In a rectangle the diagonals, besides being equal in length

    bisect each other.Given: ABCD is a Rectangle the diagonals are AC & BD

    Bisect each other at a Point O.

    To Prove: (i) AC = BD

    (ii) OA = OC or OB = OD

    Proof: In ABC and ABD

    AB = AB --------- (Common)

    BC = AD ---------------------(Apposite sides ABCD) A = B = 90 (angles of the rectangles)

    ABC ABD S. A. S. Rule

    So, AC = BD Proved

    A B

    CD

    O

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    RECTANGLE(ii) OA = OC or OB = OD

    Proof: In AOB and COD

    AB = CD (Sides of the ABCD)

    AB || CD and transversal AC & BD

    Then, ODC = OBA

    And OCD = OAB

    Alternate interior angles

    AOB COD --- A. S. A Rule

    So that all congruent part are equal .OA = OC

    and OB = OD

    Proved

    A B

    CD

    O

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    A SQUARE IS

    A rectangle having all sides of equallength

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    SQUARE

    The diagonals of a square are perpendicular bisectors ofeach other

    Given: ABCD is a Square, Where AC and BD is a diagonalbisect each other at a Pont O

    To Prove: AOD = COD = 90

    Proof: In AOD and COD

    OD Common & OA =OC

    AD = DC ------ Two sides of Squire

    So, (By SSS) AOB COD, AOD = COD

    Since AOD and COD are a linear pair,

    AOD = COD = 90

    A B

    CD

    O

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    PARALLELOGRAM

    A quadrilateral having two pairs of equalsides that are parallel

    Opposite angles are equal

    Diagonals are not equal in length

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    PARALLELOGRAM

    The diagonals of a parallelogram bisect each otherGiven: ABCD is a parallelogram where AC and BD is a diagonal

    bisect each other at Point O

    To Prove: AO = OC or BO= OD

    Proof: In AOB and CODAB = CD

    AB || CD

    CDO = OBA

    And DCO = OAB ------------ Alternate interior angles

    So, AOB COD, then

    AO = OC or BO =OD Proved

    A B

    CD

    O

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    A RHOMBUS IS

    A parallelogram having all sides of equallength

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    RHOMBUS The diagonals of a rhombus are perpendicular

    bisectors of one another.Given: ABCD is a rhombus. Therefore it is a parallelogram too.

    Since diagonals bisect each other,

    OA = OC and OB = OD.

    To Prove: AOD = COD = 90

    Proof: In AOD and COD

    OD Common & OA =OC --Given

    AD = DC ------ Two sides of this rhombus

    So, (By SSS) AOB COD, then AOD = COD,

    Since AOD and COD are a linear pair,

    AOD = COD = 90

    A B

    CD

    O

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    KITE A quadrilateral having two pairs of equal sides

    One pair of opposite equal angles

    One diagonal bisects the other.

    Diagonals intersect at right angles.

    http://www.mathsteacher.com.au/year7/ch08_angles/01_ang/ang.htmhttp://www.mathsteacher.com.au/year7/ch08_angles/01_ang/ang.htm
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    TRAPEZOID

    A quadrilateral with one pair of parallelsides

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