Test - solution
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Transcript of Test - solution
Name: ______________________________ ID:________________________________
FACULTY OF ENGINEERING TECHNOLOGY
TEST
COURSE : ELECTRICAL FUNDAMENTALS
COURSE CODE : BTP1523
LECTURER : Mohammed Hayyan ALSIBAI
DATE : 26 May 2015
DURATION : 30 MINUTES
SESSION/SEMESTER : SESSION 2014/2015 SEMESTER II
PROGRAM : BTP
INSTRUCTIONS TO CANDIDATES
1. Answer in the given space after each of the questions.
2. Answer ALL the questions in both parts.
EXAMINATION REQUIREMENTS
DO NOT TURN THIS PAGE UNTIL YOU ARE TOLD TO DO SO
This examination paper consists of 6 SIX printed pages including front pages
CONFIDENTIAL BTP1523
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Question 1 [CO2] (10 Marks)
Circle the correct answer:
The expression to determine the total resistance in the figure Q1 below is
a) R1+R2+R3+R4//R6+R5//R7
b) R1//R2+R3+R4//R6+R5//R7
c) R1+[(R2+R3+R4)//(R5+R6)]+R7
d) R1+[(R2+R3+R4)//(R5+R6)]//R7
Figure Q1
Question 2 [CO2] (10 Marks)
In Figure Q2 If current through the 4Ω resistor is 4 A, determine the current through the 6Ω resistor
Figure Q2
16/6 = 2.66 A
RT
CONFIDENTIAL BTP1523
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Question 3 [CO2] (30 marks)
For the Figure Q3 calculate: (30 marks)
Figure Q3
a) Total resistance RT (10 Marks)
b) Currents I1, I2 and I3 (15 Marks)
c) Voltage Vab (5 Marks)
a) RT = (10//5)+ 15 = 18.3333Ω
b) I3 = IT = E/RT = 0.545A
I2 = 0.18A
I1= 0.36A
c)Vab = 1.8V
CONFIDENTIAL BTP1523
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Question 4 [CO1] (50 marks)
For the Figure Q4 calculate: (50 marks)
Figure Q4
a) Calculate XC, XL, Z and write the answer in rectangular and polar form.
(25 Marks) b) Calculate I
(10 Marks) d) Calculate VR, VL, VC.
(15 Marks)
CONFIDENTIAL BTP1523
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I = IR = IL = IC = E/Z = (12.589 + j76.7)mA = 77.7mA∟80o
VR = I ZR = 19.4V∟80.6o or (3.14 + j 19.177) V
VL = I ZL = 19.04V∟170.68o or (-18.79.14 + j 3.08) V
VC = I ZC = 137.46V∟-9.3o or (135.65 - j 22.26) V
Remark:
END OF QUESTION PAPER