Statics Final

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Page 1 of 13 Mr. Mohammed Elkably Statics Final revision Rules = ‖ ‖ = ac + bd such that: = (a, b) , = (c, d) = 2 + 2 Note: = 0 if, = 0 , = 0 or The algebraic projection of in the direction of = x = (A B sin ) ̂ x = , x = , x = x = - , x = - , x = - x = 0 , x = 0 , x = 0 (a ̂ + b ̂ ) x ( c ̂ + d ̂ ) = (ad – bc) Area of triangle = × 2 Unit vector perpendicular to each of and = × × ( + ) × = × + ×

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statics final revision

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  • Page 1 of 13 Mr. Mohammed Elkably

    Statics Final revision

    Rules

    =

    = ac + bd

    such that: = (a, b) , = (c, d)

    = 2 + 2

    Note: = 0 if, = 0 , = 0 or

    The algebraic projection of in the direction of =

    x = (A B sin )

    x = , x = , x =

    x = - , x = - , x = -

    x = 0 , x = 0 , x = 0

    (a + b ) x ( c + d ) = (ad bc)

    Area of triangle =

    2

    Unit vector perpendicular to each of and =

    ( + ) = +

  • Page 2 of 13 Mr. Mohammed Elkably

    Statics Final revision

    The moment of acts at A about B is:

    MB = x = BA . F . sin

    Length of perpendicular ( arm) =

    1) If line of action passing through the point A, then : MA = 0

    2) The algebraic component of force in the direction of =

    3) If the force bisects , then: MA = - MB

    4) If the force is parallel to then: MA = MB

    Same Direction:

    R = F1 + F2 ( Magnitude)

    F1 . AB = F2 . BC ( Line of action)

    A B C

    F1 F2

    R

    A B C

    F2

    F1

    R

    Opposite Direction:

    R = F2 F1 ( Magnitude)

    F2 . AB = F! . AC ( Line of action)

    Two couples are equivalent, then M1 = M2 , (Same sign)

    Two couples are equilibrium, then M1 = -M2 (diff sign)

  • Page 3 of 13 Mr. Mohammed Elkably

    Statics Final revision

    If: F1, F2, and F3 are is same way round:

    Then, 1

    =

    2

    =

    3

    = m

    The set of forces is equivalent to a couple

    M= 2 m.A

    Area of triangle = 1

    2 base x height

    = 1

    2 a b sin C

    = . . .

    such that: s = 1

    2 (a + b+ c)

    A

    B C

    F1

    F2

    F3

  • Page 4 of 13 Mr. Mohammed Elkably

    Statics Final revision

    Definitions

    1) Condition of equilibrium of a group of coplanar forces.

    ( the sum of forces in the direction of x-axis = the sum of forces in the

    direction of y-axis = the sum of moments of forces about any point = 0)

    2) Angle of friction ()

    ( the angle included between the resultant reaction and the perpendicular

    reaction when the body is about to slide) ( tan = )

    3) Coefficient of friction () (The ratio between the limiting friction force and the normal reaction)

    4) Limiting friction force:

    (The force of friction on the body when it is about to move and its equal to )

    5) The couple:

    ( A couple consists of two forces equal in magnitude, parallel in opposite

    directions, there is a distance apart between them)

    6) Mention the equations of the equilibrium of a rigid body under the

    action of a set of collinear forces.

    ( the sum of forces in the direction of x-axis = the sum of forces in the

    direction of y-axis = the sum of moments of forces about any point = 0)

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    Statics Final revision

    A) Complete

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    Statics Final revision

    8)

    9)

    10) If the friction force F < the limiting friction force , then the body ..

    11) A couple is consists of two forces..

  • Page 7 of 13 Mr. Mohammed Elkably

    Statics Final revision

    B) Inclined rod

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    Statics Final revision

    C) Horizontal rod

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    Statics Final revision

    D) Lamina

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    E) Vectors

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    Statics Final revision

    F) Planes

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    Statics Final revision

    6)

    7)

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    Statics Final revision

    G) Shapes

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    Statics Final revision

    8)

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