Smith Chart 2.0
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Transcript of Smith Chart 2.0
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SMITH CHART EXAMPLES
Dragica Vasileska
ASU
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Smith Chart for the Impedance Plot
jxrZZzo
+==
It will be easier if we normalize the load impedance to thecharacteristic impedance of the transmission line attached to the
load.
+=
1
1z
Since the impedance is a complex number, the reflection coefficientwill be a complex number
jvu +=
( ) 22
22
vu1
vu1r
+
=
( ) 22 vu1
v2x
+
=
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Real Circles
1 0.5 0 0.5 1
1
0.5
0.5
1
{ }Re
{ }Im
r=0r=1/3
r=1
r=2.5
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Imaginary Circles
1 0.5 0 0.5 1
1
0.5
0.5
1
{ }Re
{ }Im
x=1/3 x=1 x=2.5
x=-1/3 x=-1 x=-2.5
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Normalized AdmittancejbgYZ
Y
Yy o
o
+===
+
=1
1y
( ) 22
22
vu1vu1g++
=
( ) 22 vu1
v2b
++
=
( )22
2
g11v
g1gu
+=+
++
( ) 2
2
2
b1
b1v1u =
+++
These are equations forcircles on the (u,v) plane
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Real admittance
1 0.5 0 0.5 1
1
0.5
0.5
1
{ }Re
{ }Im
g=1/3g=1g=2.5
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Complex Admittance
1 0.5 0 0.5 1
1
0.5
0.5
1
b=-1 b=-1/3
b=2.5 b=1/3
b=1
b=-2.5
{ }Im
{ }Re
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Matching
For a matching network that contains elements
connected in series and parallel, we will need twotypes of Smith chartsimpedance Smith chartadmittance Smith Chart
The admittance Smith chart is the impedanceSmith chart rotated 180 degrees.We could use one Smith chart and flip the reflection
coefficient vector 180 degrees when switchingbetween a series configuration to a parallelconfiguration.
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TowardGenerator
Away FromGenerator
Constant
ReflectionCoefficient Circle
Full Circle is One HalfWavelength SinceEverything Repeats
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Matching Example
0=
100s
P =50Z0 M
Match 100 load to a 50 system at 100MHz
A 100 resistor in parallel would do the trick but of
the power would be dissipated in the matching network.We want to use only lossless elements such as inductorsand capacitors so we dont dissipate any power in thematching network
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Matching Example We need to go from
z=2+j0 to z=1+j0 onthe Smith chart
We wont get anycloser by addingseries impedance sowe will need to addsomething in parallel.
We need to flip overto the admittancechart
ImpedanceChart
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Matching Example y=0.5+j0
Before we add the
admittance, add amirror of the r=1circle as a guide.
AdmittanceChart
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Matching Example y=0.5+j0
Before we add theadmittance, add amirror of the r=1circle as a guide
Now add positiveimaginaryadmittance.
Admittance
Chart
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Matching Example y=0.5+j0
Before we add the
admittance, add amirror of the r=1circle as a guide
Now add positive
imaginaryadmittance jb = j0.5
AdmittanceChart
( )
pF16C
CMHz1002j50
5.0j
5.0jjb
=
=
=
pF16 100
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Matching Example We will now add
series impedance
Flip to theimpedance SmithChart
We land at on ther=1 circle at x=-1
ImpedanceChart
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Matching Example Add positive
imaginary
admittance to get toz=1+j0
ImpedanceChart
pF16
100
( ) ( )
nH80L
LMHz1002j500.1j
0.1jjx
=
=
=
nH80
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Matching Example
This solution wouldhave also worked
ImpedanceChart
pF32
100
nH160
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Mainstream vs. RF Electronics
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Substrate
Buffer
Drain
n-type active layerL
n+ cap
Gate
n+ cap
Source
Substrate
Barrier / buffer
Channel layer
Drain
BarrierL
n+ cap
Gate
n+ cap
2DEG channel
Source
MESFETMetal-Semiconductor FET
HEMTHigh Electron Mobility TransistorChannel: twodimensional electrongas (2DEG) at the inter-
face channel layer - barrier
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E. Simulation Examples Example #1
This Example gives comparison of the device output characte-
ristics of a single quantum-well structure when using drift-dif-fusion and energy balance models
Example #2
Simulation results of a pseudomorphic HEMT structure: devicetransfer and output characteristics with extraction of some
significant device parameters, such as threshold voltage,
maximum saturation current, etc.
Example #3
This is a follow-up of Example #2, in which AC analysis isperformed and the device S-parameters calculated.
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Example 1
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Example 1 (contd)
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Example 1 (contd)
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Example 2
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Example 3
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Example 3 (contd)