Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

14
By Kacey Olver, Tom Jubon, and Laine Murphy

Transcript of Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Page 1: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

By Kacey Olver, Tom Jubon, and Laine Murphy

Page 2: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Section 2.4

Page 3: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Section 2.4

Page 4: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Section 2.4

Page 5: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Section 2.4

Page 6: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Statements Reasons

1. <BAE is a rt <

1.

2. 2.

3. <DEA is a rt <

3.

4. 4.

5. <CAE <CEA

5.

6. <BAC <DEC

6.

Given: <BAE is a rt < <DEA is a rt < <CAE <CEAProve: <BAC <DEC

A E

DB C

Page 7: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Given: <BAE is a rt < <DEA is a rt < <CAE <CEAProve: <BAC <DEC

A E

DB C

Statements Reasons

1. <BAE is a rt <

1. Given

2. Line FK is perpendicular to line KJ

2. If 2 lines form a rt <, then they’re perpendicular.

3. <DEA is a rt <

3. Given

4. Line JH is perpendicular to line KJ

4. Same as 2

5. <CAE <CEA

5. Given

6. <BAC <DEC

6. Compl of <‘s are

Page 8: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Given: <A is compl to <C

<DBC is compl to <C

Conclusion: __?_

A

B C

D

Page 9: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Given: <A is compl to <C

<DBC is compl to <C

Conclusion: __?_

A

B C

D

Page 10: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Statements Reasons

1. Seg KM is perp to seg MO

1.

2. <KMO is a rt < 2.

3. <RMO is compl to <KMR

3.

4. <ROM is compl to <POR

4.

5. <KMR <POR 5.

6. <ROM <RMO 6.

Given: Seg KM is perp to seg MO

Seg PO is perp to seg MO

<KMR <POR

Prove: <ROM <RMO

RK P

M O

Page 11: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Statements Reasons

1. Seg KM is perp to seg MO

1. Given

2. <KMO is a rt < 2. If segs are perp, they form rt <‘s.

3. <RMO is compl to <KMR

3. If 2 <‘s form a rt <, they are compl.

4. <ROM is compl to <POR

4. Reasons 1-3

5. <KMR <POR 5. Given

6. <ROM <RMO 6. Compl’s of <‘s are

Given: Seg KM is perp to seg MO

Seg PO is perp to seg MO

<KMR <POR

Prove: <ROM <RMO

M O

RK P

Page 12: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Given: <1 is compl to <4 <2 is compl to <3 Ray RT bisects <SRVProve: Ray TR bisects <STV

R T

S

V

1

2

3

4

Page 13: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

*Solution Provided by www.darienps.org

Statements Reasons

1. Ray RT bisects <SRV 1. Given

2. <3 <4 2. If a ray bisects an angle, then it divides the angle into 2 halves

3. <1 is compl to <4 3. Given

4. <2 is compl to <3 4. Given

5. <1 <2 5. If 2 <‘s are compl to <‘s, then they are

6. Ray TR bisects <STV 6. If a ray divides an , into 2 <‘s, then it bisects the <

Page 14: Section 2.4 Theorems By Kacey Olver, Tom Jubon, and Laine Murphy.

Rhoad, Richard, George Milauskas, and Robert Whipple. Geometry For Your Enjoyment and Challenge. MA: McDougal, Littell and Company, 1991.

Honors Geometry, Chapter 2, Packet #1, Sections 2.1-2.4

Messman, Bonita. “2.4 Congruent Supplements and Compliments.” Darien High School. 17 January 2010 < http://www.darienps.org/ teachers/bmessman/AccGeo1stQ/Ch2/Wk

4_Lesson Solutions.pdf>. Web.