Section 1.2 DOMAIN, RANGE, INTERCEPTS, SYMMETRY, …...Test for Symmetry Analyze Graphically The...

DOMAIN, RANGE,

INTERCEPTS, SYMMETRY,

EVEN/ODD

Section 1.2

Vocabulary

• zeros

• roots

• line symmetry

• point symmetry

• even function

• odd function

Example 1

Estimate Function Values

A. ADVERTISING The function f (x) = –5x

2 + 50x approximates the profit at a toy company, where x represents marketing costs and f (x) represents profit. Both costs and profits are measured in tens of thousands of dollars. Use the graph to estimate the profit when marketing costs are $30,000. Confirm your estimate algebraically.

Example 1

Estimate Function Values

$30,000 is three ten thousands. The function value at x = 3 appears to be about 100 ten thousands, so the total profit was about $1,000,000. To confirm this estimate algebraically, find f(3).

f(3) = -5(3)2 + 50(3) = 105, or about $1,050,000.

The graphical estimate of about $1,000,000 is reasonable.

Example 2

Find Domain and Range

Use the graph of f to find the domain and range of the function.

Example 2

Find Domain and Range

Domain

• The dot at (3, -3) indicates that the domain of f ends at 3 and includes 3.

• The arrow on the left side indicates that the graph will continue without bound.

The domain of f is . In set-builder notation, the

domain is .

Range

The graph does not extend above y = 2, but f (x) decreases without bound for smaller and smaller values of x. So the range of f is .

Example 2

Use the graph of f to find the domain and range of the function.

A. Domain:

Range:

B. Domain:

Range:

C. Domain:

Range:

D. Domain:

Range:

Example 3

Find y-Intercepts

A. Use the graph of the function f (x) = x

2 – 4x + 4 to approximate its y-intercept. Then find the y-intercept algebraically.

Example 3

Find y-Intercepts

B. Use the graph of the function g (x) =│x + 2│– 3 to approximate its y-intercept. Then find the y-intercept algebraically.

Example 4

Find Zeros

Use the graph of f (x) = x

3 – x to approximate its zero(s). Then find its zero(s) algebraically.

Example 4

Answer: -1, 0, 1

Find Zeros

Estimate Graphically

The x-intercepts appear to be at about -1, 0, and 1.

Solve Algebraically

x

3 – x = 0 Let f (x) = 0.

x(x

2 – 1) = 0 Factor.

x(x – 1)(x + 1) = 0 Factor.

x = 0 or x – 1 = 0 or x + 1 = 0 Zero Product Property

x = 0 x = 1 x = -1 Solve for x.

The zeros of f are 0, 1, and -1.

Example 4

A. –2.5

B. –1

C. 5

D. 9

Use the graph of to approximate

its zero(s). Then find its zero(s) algebraically.

Key Concept 1

Example 5

Test for Symmetry

A. Use the graph of the equation y = x

2 + 2 to test for symmetry with respect to the x-axis, the y-axis, and the origin. Support the answer numerically. Then confirm algebraically.

Example 5

Test for Symmetry

Analyze Graphically

The graph appears to be symmetric with respect to the y-axis because for every point (x, y) on the graph, there is a point (-x, y).

Support Numerically

A table of values supports this conjecture.

Example 5

Test for Symmetry

Confirm Algebraically

Because x2 + 2 is equivalent to (-x)2 + 2, the graph is symmetric with respect to the y-axis.

Example 5

Test for Symmetry

B. Use the graph of the equation xy = –6 to test for symmetry with respect to the x-axis, the y-axis, and the origin. Support the answer numerically. Then confirm algebraically.

Example 5

Test for Symmetry

Analyze Graphically

The graph appears to be symmetric with respect to the origin because for every point (x, y) on the graph, there is a point (-x, -y).

Support Numerically

A table of values supports this conjecture.

Example 5

Test for Symmetry

Confirm Algebraically

Because (-x)( -y) = -6 is equivalent to (x)(y) = -6, the graph is symmetric with respect to the origin.

Example 5

Use the graph of the equation y = –x

3 to test for symmetry with respect to the x-axis, the y-axis, and the origin. Support the answer numerically. Then confirm algebraically.

A. symmetric with respect to the x-axis

B. symmetric with respect to the y-axis

C. symmetric with respect to the origin

D. not symmetric with respect to the x-axis, y-axis, or the origin

Key Concept 2

Example 6

A. Graph the function f (x) = x

2 – 4x + 4 using a graphing calculator. Analyze the graph to determine whether the function is even, odd, or neither. Confirm algebraically. If even or odd, describe the symmetry of the graph of the function.

Identify Even and Odd Functions

Example 6


It appears that the graph of the function is neither symmetric with respect to the y-axis nor to the origin. Test this conjecture algebraically.

f (-x) = (-x)

2 – 4(-x) + 4 Substitute -x for x.

= x

2 + 4x + 4 Simplify.

Since –f (x) = -x

2 + 4x - 4, the function is neither even nor odd because f (-x) ≠ f (x) or –f (x).

Example 6

B. Graph the function f (x) = x

2 – 4 using a graphing calculator. Analyze the graph to determine whether the function is even, odd, or neither. Confirm algebraically. If even or odd, describe the symmetry of the graph of the function.


Example 6


From the graph, it appears that the function is symmetric with respect to the y-axis. Test this conjecture algebraically.

f (-x) = (-x)2 – 4 Substitute -x for x.

= x

2 - 4 Simplify.

= f (x) Original function f (x) = x

2 – 4

The function is even because f (-x) = f (x).

Example 6

C. Graph the function f (x) = x

3 – 3x

2 – x + 3 using a graphing calculator. Analyze the graph to determine whether the function is even, odd, or neither. Confirm algebraically. If even or odd, describe the symmetry of the graph of the function.


Example 6


From the graph, it appears that the function is neither symmetric with respect to the y-axis nor to the origin. Test this conjecture algebraically.

f (–x) = (–x)

3 – 3(–x)2 – (–x) + 3 Substitute –x for x.

= –x

3 – 3x

2 + x + 3 Simplify.

Because –f (x) = –x

3 + 3x

2 + x – 3, the function is neither even nor odd because f (–x) ≠ f (x) or –f (x).

LIMITS, CONTINUITY, AND END

BEHAVIOR

Section 1.3

Vocabulary

• continuous function

• limit

• discontinuous function

• infinite discontinuity

• jump discontinuity

• removable discontinuity

• nonremovable discontinuity

• end behavior

Key Concept 1

Key Concept 2

Concept Summary 1

Example 1

Identify a Point of Continuity

Check the three conditions in the continuity test.

Determine whether is continuous at

. Justify using the continuity test.

Because , the function is defined at

1. Does exist?

Example 1


2. Does exist?

Construct a table that shows values of f(x) approaching from the left and from the right.

The pattern of outputs suggests that as the value

of x gets close to from the left and from the

right, f(x) gets closer to . So we estimate that

.

Example 1


3. Does ?

Because is estimated to be and

we conclude that f (x) is continuous at . The

graph of f (x) below supports this conclusion.

Example 1


Answer: 1.

2. exists.

3. .

f (x) is continuous at .

Example 1

Determine whether the function f (x) = x

2 + 2x – 3 is continuous at x = 1. Justify using the continuity test.

A. continuous; f (1)

B. Discontinuous; the function is undefined at x = 1

because does not exist.

Example 2

Identify a Point of Discontinuity

A. Determine whether the function is

continuous at x = 1. Justify using the continuity

test. If discontinuous, identify the type of

discontinuity as infinite, jump, or removable.

Example 2


2. Investigate function values close to f(1).

The pattern of outputs suggests that for values of x approaching 1 from the left, f (x) becomes increasingly more negative. For values of x approaching 1 from the right, f (x) becomes increasing more positive.

Therefore, does not exist.

Example 2


3. Because f (x) decreases without bound as x approaches 1 from the left and f (x) increases without bound as x approaches 1 from the right, f (x) has an infinite discontinuity at x = 1. The graph of f (x) supports this conclusion.

Example 2


B. Determine whether the function is

continuous at x = 2. Justify using the continuity



Example 2


2. Investigate function values close to f (2).

Example 2


3. Because exists, but f (2) is undefined,

f (x) has a removable discontinuity at x = 2. The

graph of f (x) supports this conclusion.

4

Example 2

A. f (x) is continuous at x = 1.

B. infinite discontinuity

C. jump discontinuity

D. removable discontinuity

Determine whether the function

is continuous at x = 1. Justify using the continuity



Key Concept 3

Example 3

Approximate Zeros

Investigate function values on the interval [-2, 2].

A. Determine between which consecutive integers

the real zeros of are located on the

interval [–2, 2].

Example 3

Approximate Zeros

Because f (-1) is positive and f (0) is negative, by the Location Principle, f (x) has a zero between -1 and 0. The value of f (x) also changes sign for [1,2]. This indicates the existence of real zeros in each of these intervals. The graph of f (x) supports this conclusion.

Example 3

A. Determine between which consecutive integers the real zeros of f (x) = x

3 + 2x

2 – x – 1 are located on the interval [–4, 4].

A. –1 < x < 0

B. –3 < x < –2 and –1 < x < 0

C. –3 < x < –2 and 0 < x < 1

D. –3 < x < –2, –1 < x < 0, and 0 < x < 1

Example 4

Graphs that Approach Infinity

Use the graph of f(x) = x

3 – x

2 – 4x + 4 to describe its end behavior. Support the conjecture numerically.

Example 4


Analyze Graphically

Support Numerically

Construct a table of values to investigate function values as |x| increases. That is, investigate the value of f (x) as the value of x becomes greater and greater or more and more negative.

In the graph of f (x), it appears that and

Example 4


The pattern of outputs suggests that as x approaches –∞, f (x) approaches –∞ and as x approaches ∞, f (x) approaches ∞.

Example 4

Use the graph of f (x) = x

3 + x

2 – 2x + 1 to describe its end behavior. Support the conjecture numerically.

A.

B.

C.

D.

Example 5

Graphs that Approach a Specific Value

Use the graph of to describe its end

behavior. Support the conjecture numerically.

Example 5

Graphs that Approach a Specific Value

Analyze Graphically

Support Numerically

In the graph of f (x), it appears that

.

As . As . This supports our conjecture.

Example 5

Use the graph of to describe its end

behavior. Support the conjecture numerically.

A.

B.

C.

D.

Example 6

Apply End Behavior

PHYSICS The symmetric energy function is

. If the y-value is held constant, what

happens to the value of symmetric energy when

the x-value approaches negative infinity?

We are asked to describe the end behavior of E (x) for

small values of x when y is held constant. That is, we

are asked to find .

EXTREMA AND AVERAGE

RATE OF CHANGE

Section 1.4

Vocabulary

• increasing

• decreasing

• constant

• maximum

• minimum

• extrema

• average rate of change

• secant line

Key Concept 1

Example 1

Analyze Increasing and Decreasing Behavior

A. Use the graph of the function f (x) = x

2 – 4 to estimate intervals to the nearest 0.5 unit on which the function is increasing, decreasing, or constant. Support the answer numerically.

Example 1


Analyze Graphically

From the graph, we can estimate that f is decreasing on and increasing on .

Support Numerically

Create a table using x-values in each interval.

The table shows that as x increases from negative values to 0, f (x) decreases; as x increases from 0 to positive values, f (x) increases. This supports the conjecture.

Example 1


B. Use the graph of the function f (x) = –x

3 + x to estimate intervals to the nearest 0.5 unit on which the function is increasing, decreasing, or constant. Support the answer numerically.

Example 1


Support Numerically

Create a table using x-values in each interval.

Analyze Graphically

From the graph, we can estimate that f is decreasing on , increasing on , and decreasing on .

Example 1


0.5 1 2 2.5 3

–6 –13.125 –24

Example 1


The table shows that as x increases to , f (x)

decreases; as x increases from , f (x) increases;

as x increases from , f (x) decreases. This supports

the conjecture.

Answer: f (x) is decreasing on and

and increasing on

Example 1

Use the graph of the function f (x) = 2x 2 + 3x – 1 to

estimate intervals to the nearest 0.5 unit on which the function is increasing, decreasing, or constant. Support the answer numerically.

A. f (x) is increasing on (–∞, –1) and (–1, ∞).

B. f (x) is increasing on (–∞, –1) and decreasing on (–1, ∞).

C. f (x) is decreasing on (–∞, –1) and increasing on (–1, ∞).

D. f (x) is decreasing on (–∞, –1) and decreasing on (–1, ∞).

Key Concept 2

Example 2

Estimate and Identify Extrema of a Function

Estimate and classify the extrema to the nearest 0.5 unit for the graph of f (x). Support the answers numerically.

Example 2


Analyze Graphically

It appears that f (x) has a relative minimum at

x = –1 and a relative maximum at x = 2. It also appears

that so we conjecture

that this function has no absolute extrema.

Example 2


Because f (–1.5) > f (–1) and f (–0.5) > f (–1), there is a

relative minimum in the interval (–1.5, –0.5) near –1. The approximate value of this relative minimum is

f (–1) or –7.0.

Support Numerically

Choose x-values in half unit intervals on either side of the estimated x-value for each extremum, as well as one very large and one very small value for x.

Example 2


f (100) < f (2) and f (–100) > f (–1), which supports our conjecture that f has no absolute extrema.

Likewise, because f (1.5) < f (2) and f (2.5) < f (2), there is a relative maximum in the interval (1.5, 2.5) near 2. The approximate value of this relative maximum is f (2) or 14.

Answer: To the nearest 0.5 unit, there is a relative minimum at x = –1 and a relative maximum at x = 2. There are no absolute extrema.

Example 2

Estimate and classify the extrema to the nearest 0.5 unit for the graph of f (x). Support the answers numerically.

A. There is a relative minimum of 2 at x = –1 and a relative maximum of 1 at x = 0. There are no absolute extrema.

B. There is a relative maximum of 2 at x = –1 and a relative minimum of 1 at x = 0. There are no absolute extrema.

C. There is a relative maximum of 2 at x = –1 and no relative minimum. There are no absolute extrema.

D. There is no relative maximum and there is a relative minimum of 1 at x = 0. There are no absolute extrema.

Example 3

Use a Graphing Calculator to Approximate

Extrema

GRAPHING CALCULATOR Approximate to the nearest hundredth the relative or absolute extrema of f (x) = x

4 – 5x

2 – 2x + 4. State the x-value(s) where they occur.

f (x) = x

4 – 5x

2 – 2x + 4

Graph the function and adjust the window as needed so that all of the graph’s behavior is visible.

Example 3


Extrema

From the graph of f, it appears that the function has

one relative minimum in the interval (–2, –1), an absolute minimum in the interval (1, 2), and one

relative maximum in the interval (–1, 0) of the domain. The end behavior of the graph suggests that this function has no absolute extrema.

Example 3


Extrema

Using the minimum and maximum selection from the CALC menu of your graphing calculator, you can estimate that f(x) has a relative minimum of 0.80 at

x = –1.47, an absolute minimum of –5.51 at x = 1.67,

and a relative maximum of 4.20 at x = –0.20.

Example 3


Extrema

Answer: relative minimum: (–1.47, 0.80); relative maximum: (–0.20, 4.20); absolute minimum: (1.67, –5.51)

Example 3

GRAPHING CALCULATOR Approximate to the nearest hundredth the relative or absolute extrema of f (x) = x

3 + 2x 2 – x – 1. State the x-value(s) where they

occur.

A. relative minimum: (0.22, –1.11); relative maximum: (–1.55, 1.63)

B. relative minimum: (–1.55, 1.63); relative maximum: (0.22, –1.11)

C. relative minimum: (0.22, –1.11); relative maximum: none

D. relative minimum: (0.22, 0); relative minimum: (–0.55, 0) relative maximum: (–1.55, 1.63)

Example 4

Use Extrema for Optimization

FUEL ECONOMY Advertisements for a new car claim that a tank of gas will take a driver and three passengers about 360 miles. After researching on the Internet, you find the function for miles per tank of gas for the car is f (x) = -0.025x

2 + 3.5x + 240, where x is the speed in miles per hour . What speed optimizes the distance the car can travel on a tank of gas? How far will the car travel at that optimum speed?

Example 4


We want to maximize the distance a car can travel on a tank of gas. Graph the function f (x) = –0.025x

2 + 3.5x + 240 using a graphing calculator. Then use the maximum selection from the CALC menu to approximate the x-value that will produce the greatest value for f (x).

Example 4

Answer: The optimal speed is about 70 miles per hour. The car will travel 362.5 miles when traveling at the optimum speed.


The graph has a maximum of 362.5 for x ≈ 70. So the speed that optimizes the distance the car can travel on a tank of gas is 70 miles per hour. The distance the car travels at that speed is 362.5 miles.

Example 4

VOLUME A square with side length x is cut from each corner of a rectangle with dimensions 8 inches by 12 inches. Then the figure is folded to form an open box, as shown in the diagram. Determine the length and width of the box that will allow the maximum volume.

A. 6.43 in. by 10.43 in.

B. 4.86 in. by 8.86 in.

C. 3 in. by 7 in.

D. 1.57 in. by 67.6 in.

Key Concept3

Example 5

Find Average Rates of Change

A. Find the average rate of change of f (x) = –2x

2 + 4x + 6 on the interval [–3, –1].

Use the Slope Formula to find the average rate of change of f on the interval [–3, –1].

Substitute –3 for x1 and –1 for x2.

Evaluate f(–1) and f(–3).

Example 5


Simplify.

Answer: 12

The average rate of change on the interval [–3, –1] is 12. The graph of the secant line supports this conclusion.

Example 5


B. Find the average rate of change of f (x) = –2x

2 + 4x + 6 on the interval [2, 5].

Example 5


Example 5

Find the average rate of change of f (x) = –3x

3+ 2x + 3 on the interval [–2, –1].

A. 27

B. 11

C.

D. –19

Example 6

A. GRAVITY The formula for the distance traveled by falling objects on the Moon is d (t) = 2.7t

2, where d (t) is the distance in feet and t is the time in seconds. Find and interpret the average speed of the object for the time interval of 1 to 2 seconds.

Find Average Speed

Example 6

PHYSICS Suppose the height of an object dropped from the roof of a 50 foot building is given by h (t) = –16t

2 + 50, where t is the time in seconds after the object is thrown. Find and interpret the average speed of the object for the time interval 0.5 to 1 second.

A. 8 feet per second

B. 12 feet per second

C. 24 feet per second

D. 132 feet per second

Section 1.2 DOMAIN, RANGE, INTERCEPTS, SYMMETRY, …...Test for Symmetry Analyze Graphically The...

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Transcript of Section 1.2 DOMAIN, RANGE, INTERCEPTS, SYMMETRY, …...Test for Symmetry Analyze Graphically The...