number 3 AnD InDICeS

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NUMBER AND INDICES 3 Contents 3:01 Index notation Challenge 3:01 Now that’s a google 3:02 Expanded notation 3:03 Factors and multiples 3:04 Prime and composite numbers 3:05 Divisibility tests 3:06 HCF and LCM by prime factors Challenge 3:06 What are the factors? 3:07 Square and cube roots 3:08 The binary system Fun spot 3:08 Making magic squares Maths terms, Diagnostic test, Assignments Syllabus references (See pages x–xiii for details.) Number and Algebra Selections from Indices [Stage 4] Investigate index notation and represent whole numbers as products of powers of prime numbers.(ACMNA149) Investigate and use square roots of perfect square numbers.(ACMNA150) Working Mathematically Communicating Problem Solving Reasoning Understanding Fluency 12 2 1 143 11 × 13 This looks so power-ful! 6 × 8 = 48 7 2 = 49 7 × 9 = 63 8 2 = 64 8 × 10 = 80 9 2 = 81 9 × 11 = 99 10 2 = 100 11 × 13 = 143 12 2 = 144 10 × 12 = 120 11 2 = 121 Sample pages

Transcript of number 3 AnD InDICeS

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number AnD InDICeS 3

Contents3:01 Index notation

Challenge 3:01 Now that’s a google3:02 Expanded notation3:03 Factors and multiples3:04 Prime and composite numbers3:05 Divisibility tests

3:06 HCF and LCM by prime factorsChallenge 3:06 What are the factors?

3:07 Square and cube roots3:08 The binary system

Fun spot 3:08 Making magic squaresMaths terms, Diagnostic test, Assignments

Syllabus references (See pages x–xiii for details.)

Number and AlgebraSelections from Indices [Stage 4]• Investigateindexnotationandrepresentwholenumbersasproductsofpowersofprimenumbers.(ACMNA149)• Investigateandusesquarerootsofperfectsquarenumbers.(ACMNA150)

Working mathematically• Communicating • ProblemSolving • Reasoning • Understanding • Fluency

122 − 1 143

11 × 13

This looks so power-ful!

6 × 8 = 48

72 = 49

7 × 9 = 63

82 = 64

8 × 10 = 80

92 = 81

9 × 11 = 99

102 = 100

11 × 13 = 143

122 = 144

10 × 12 = 120

112 = 121

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74 Australian Signpost Mathematics New South Wales 7

3:01 Index notation

Findthevalueof: 1 3 × 3 × 3 2 5×5 3 2 × 2 × 2 × 2 × 2 4 5×5×5 5 10×10 6 10×10×10 7 10×10×10×10 8 10×10×10×10×10 9 7 ×10×10 10 4 ×10×10×10

Weuseapowerwhenanumberisinaproductmorethanonce.

52 =5×5 Thisisfivesquared,orfivetothepoweroftwo.

103 =10×10×10 Thisistencubed,ortentothepowerofthree.

1 Write53inexpandedformandwriteitsbasicnumeral.

2 Write10×10×10×10asapoweroften.

3 Whatisthebasicnumeralof7×103?

Solutions

1 53 2 10×10×10×10 3 7 ×103 =5×5×5 =104 = 7 ×(10×10×10) =25×5 = 7 ×1000 =125 =7000

Exercise 3:01

1 Writeeachinexpandedformandasabasicnumeral.a 42 b 102 c 22

d 12 e 72 f 92

g 23 h 54 i 33

j 103 k 104 l 105

2 Rewriteusingindexnotation.a 7 × 7 b 8 × 8 × 8c 10×10×10×10 d 10×10×10e 4 × 4 × 4 × 4 × 4 × 4 f 2 × 2 × 2 × 2g 10×10×10×10×10

PreP quIz 3:01

Note: Another name for power is index.

Worked exaMples53is5×5×5writtenusingindex notation.

Foundation worksheet 3:01Powers of numbers

This sureis powerful

stuff!

11 × 11= 112

eleven squared

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753 Number and indices

3 Writethebasicnumeralforeach.a 6 ×101 b 3 ×102 c 5×103

d 2 ×104 e 7 ×103 f 1×102

g 4 ×103 h 9×102 i 8 ×104

j 32 ×103 k 23 ×104 l 72 ×105

4 Rewriteeachexpressionusingindexnotation.a 2 × 2 × 2 × 3 × 3 b 5×5× 2 × 2 × 2c 4 × 4 × 3 × 3 × 3 × 3 d 6 × 6 × 6 × 7 × 7e 5×5×5× 3 × 3 × 3 × 3 f 8 × 8 × 8 ×10×10g 2 × 2 × 3 × 2 × 3 × 3 h 5× 6 ×5×5× 6i 4 × 4 ×5× 4 × 4 j 3 × 7 × 3 × 7 × 7 × 3

5 Rewriteeachinexpandedformandthenasabasicnumeral.a 22 × 32 b 52 × 32

c 42 × 23 d 33 × 22

e 32 × 25 f 53 × 23

g 43 × 32 × 22 h 23 × 32 × 41

6 Rewriteeachinexpandedform,thenasonetermwithonlyonepower.a 22 × 23 b 34 × 33

c 53 ×55 d 43 × 42 × 41

Doyouseeanypatternorrule?

7 Writeeachexpressionasabasicnumeral,thenexpressthis numeralasapowerofasinglenumber.a 22 × 32 b 22 ×52

c 42 × 22 d 53 × 23

Doyouseeanypatternorrule?

8 Evaluateeachexpression,rememberingtherulesfororderofoperations.a 2 × 2 + 3 × 3 b 22 + 32 c 32 − 22

d 2 × 2 × 2 + 3 × 3 × 3 e 23 + 33 f 33 − 23

g 2 × 32 + 3 × 23 h 4 × 23 +52 i 33 −5× 22

j 5× 22 + 2 × 62 k 42 + 22 ×52 l 5× 24 − 32 × 23

m53 × 22 − 24 × 6 n 43 ÷ 22 ×5 o 52 × 23 −102 ÷ 22

9 Useacalculatortofindthevalueofthefollowing. (Seetheexamplesatright.)a 25 b 34 c 44

d 29 e 37 f 56

g 64 h 75 i 94

j 123 k 204 l 185

m53 + 26 n 44 − 35

o 36 + 73 p 103 −54

q 83 + 25 × 6 r 65 ÷ 34 + 4s 55 − 26 × 42 t 47 ÷ 83 ×54

u 93 × 210 − 74 × 63 v 67 −56 × 48 ÷ 84

Abasicnumeralisthesimplestanswer.

3 × 3 × 3 × 3 × 5 × 5 = 34 × 52

23 × 52 = 2 × 2 × 2 × 5 × 5 = 8 × 25 = 200

202 = (2 × 10)2

= 22 × 102

To find 36usingacalculator: Enter:3 x 6 = Answer:729

For27 +54: Enter:2 x 7 )

NOTE

+ 5 x 4 =

Answer:753

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76 Australian Signpost Mathematics New South Wales 7

Almosteveryoneisfamiliarwiththeword‘google’fromtheinternet. However,thisbrandnameoriginallycomesfromthewordgoogol (withdifferentspelling),whichwasfirstusedin1938torefertotheverylargenumber10100.

So 1googol =10100. Thisnumberis1followedby100zeros:

10000000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000000000

However,agoogolplexisevenbigger—itisamuchbiggernumberthanagoogol.•Findouthowbigagoogolplexis.•Howlongwouldittakeyoutowriteagoogol,i.e.1followedby100zeros?•Howlongwouldittakeyoutowriteagoogolplex?

3:02 Expanded notation

If102 =10×10,findthesimplestnumeralfor: 1 102 2 5×102 3 8 ×102

If103 =10×10×10,findthesimplestnumeralfor:

4 103 5 2 ×103 6 9×103

Writeinsimplestform: 7 (6 ×10)+ 3 8 (2 ×102) +(5×10)+1 9 (7 ×103) +(9×102) + (3 ×10)+5 10 (8 ×103) +(1×102) + (3 ×10)+ 2

69875= (6 ×10000)+(9×1000)+ (8 ×100)+ (7 ×10)+(5×1) = (6 ×104) +(9×103) + (8 ×102) + (7 ×10)+(5×1)

Ten-thousands 10 000

Thousands 1000

Hundreds 100

Tens 10

Units 1

10×10×10×10=104

10×10×10=103

10×10=102

10=101

1=1

6 9 8 7 5

ChAllenge 3:01 noW thAt’S A google

This is a very big number!

PreP quIz 3:02

6 ten-thousands 9 thousands 8 hundreds 7 tens 5 units

6 9 8 7 5

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773 Number and indices

1 Write 6 millions +9thousands+2hundreds+5tensasasimplenumeral.

2 Write(5×104) + (7 ×102) + (2 ×101) +(1×1)asanumeralinitssimplestform.

3 Write932014inexpandednotation.

Solutions

1 6 millions +9thousands+2hundreds+5tens

Column values

100

000

0

100

000

100

00

100

0

100 10 1

6 0 0 9 2 5 0

2 (5×10000)+(0×1000)+ (7 ×100)+ (2 ×10)+(1×1) =50721

3 932014 =(9×100000)+ (3 ×10000)+ (2 ×1000)+(0×100)+(1×10)+ (4 ×1) =(9×105) + (3 ×104) + (2 ×103) +(0×102) +(1×101) + (4 ×1)

Exercise 3:02

1 Writeeachasasimplenumeral(abasicnumeral).a 6thousands+4hundreds+5tens+9unitsb 2ten-thousands+8thousands+6hundreds+ 3 tensc 9hundred-thousands+8hundreds+ 7 tens +4unitsd 4 millions +3hundred-thousands+8ten-thousandse 7ten-thousands+4thousands+5hundreds+ 8 tens +6unitsf 1million+1hundred-thousand+1thousand+1teng 5millions+6ten-thousands+8hundreds+ 4 tens +2unitsh 4ten-thousands+8thousands+3hundreds+9tens

2 Writethesenumeralsinsimplestform.a (8 ×1000)+(5×100)+ (3 ×10)+(9×1)b (7 ×100)+ (3 ×10)+ (8 ×1)c (7 ×1000)+ (3 ×100)+(0×10)+ (4 ×1)d (9×1000)+(0×100)+ (6 ×10)+ (7 ×1)e (9×1000)+(0×100)+(0×10)+ (3 ×1)f (8 ×1000)+ (2 ×100)+(1×10)+(0×1)

Worked exaMples

Zeros act as place holders, allowing the other digits to be in their correct columns.

10 = 101

100 = 102

1000 = 103

10 000 = 104

100 000 = 105

1 000 000 = 106

670 is shortfor 6 hundredsand 7 tens.

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96 Australian Signpost Mathematics New South Wales 7

Step 4 Rotatethesquareanticlockwisetogiveittheappearancebelow.

Activity

1 Usethismethodtomakemagicsquareswiththefollowingnumbers:a 3,4,5,6,7,8,9,10and11b 5,10,15,20,25,30,35,40and45c 36,33,30,27,24,21,18,15and12

2 Whatisthesumofacolumninthemagicsquaresof1(above)?

3 Usethepattern1,2,4,8,16,32,64,128,256tomakeamagicsquareusingthismethod.Whatistheproductofnumbersineachrow,columnanddiagonal?

basic numeral• thesimplestwaytowriteanumber,

e.g.Thebasicnumeralfor(4+ 8) × 2 is 24.composite number• anumberthathasmorethantwofactors,

e.g.9iscompositebecauseithasthreefactors:1,3and9

cube (number)• theanswerwhenawholenumberisa

productofitself3times, e.g.53 =5×5×5=125

cube root ( )3

• tofindthecuberootofanumber,e.g.8,findthenumberthatneedstobecubedtogive8: 23 = 8 so =8 23

expanded notation• awayofwritinganumberasthesumof

itsparts, e.g.612= (6 ×100)+(1×10)+ (2 ×1)

factor• afactorofacountingnumberdividesit

exactly,e.g.Thefactorsof6are1,2,3and6.• common factor:anumberthatisafactor

ofallnumbersbeingconsidered, e.g.7isacommonfactorof14,21and70.

• highestcommonfactor(HCF):thelargestofthecommonfactors, e.g.18and24havecommonfactors2,3and6,butthehighestcommonfactoris6.

index (plural: indices)• anumberindicatinghowmanyofabase

numberneedtobemultipliedtogether, e.g.for53,theindexis3

multiple• amultipleofacountingnumberisfound

bymultiplyingitbyanothercountingnumber, e.g.Themultiplesof5are5,10,15,20,…

• commonmultiple:anumberthatisamultipleofallnumbersbeingconsidered, e.g.50isacommonmultipleof2and5.

• lowestcommonmultiple(LCM):thesmallestofthecommonmultiples, e.g.10istheLCMof2and5.20istheLCMof2,5and10.

power• anotherwordforindex

prime number• acountingnumberthathasexactlytwo

factors,itselfand1,e.g.17,31,2square number• theresultofmultiplyingacounting

numberbyitself,e.g.1,16,25

square root ( )• thesquarerootofanumber,

e.g.Whatisthenumberthatmustbesquaredtogive64? 82 = 64 so =64 8

4 14 12

18 10 2

8 6 16

mAthS termS 3

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973 Number and indices

Eachsectionofthetesthassimilaritemsthattestacertaintypeofexample. Errorsinmorethanoneitemwillidentifyanareaofweakness. Eachweaknessshouldbetreatedbygoingbacktothesectionlisted.

1 Writeeachasapower.a 8 × 8 × 8 b 3 × 3 × 3 × 3 × 3 c 2 × 2 × 2 × 2

3:01

2 Writethebasicnumeralforeach.a 8 ×102 b 2 ×104 c 7 ×106

3:01

3 Writeeachasabasicnumeral.a (7 ×103) + (2 ×102) + (2 ×101) + (8 ×1)b (5×103) +(0×102) + (8 ×101) +(0×1)

3:02

4 Writeeachinexpandedformusingpowersoften.a 1824 b 4307 c 2415286

3:02

5 Listallthefactorsof:a 24 b 63 c 100

3:03

6 Listthefirstfivemultiplesof:a 4 b 8 c 11

3:03

7 Findthehighestcommonfactorof:a 36 and 48 b 60and75 c 70and98

3:03

8 Findthelowestcommonmultipleof:a 12and9 b 6 and 8 c 20and14

3:03

9 a Writeallprimenumbersthatarelessthan10.b Writeallcompositenumbersthatarelessthan10.c Whichcountingnumberisneitherprimenorcomposite?

3:04

10 Completethesefactortrees.a b c

3:04

11 Findthehighestcommonfactorandthelowestcommonmultipleof:a 2 × 2 × 2 × 3 and 2 × 2 ×5 b 3 × 3 × 3 ×5× 7 and 3 ×5×5× 7c 2 × 3 ×5× 7 and 3 × 3 ×5

3:06

Findthesimplestanswerfor:

12 a 25 b × × ×(7 11) (7 11) c × × × × ×2 2 3 2 2 3 3:07

13 a 273 b × ×11 11 113 c × × × × ×2 2 2 3 3 33 3:07

DIAgnoStIC teSt 3 number AnD InDICeS

4

24

6

36

7

42

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98 Australian Signpost Mathematics New South Wales 7

ASSIgnment 3A Chapter review 1 Rewriteusingindexnotation:

a 5×5×5×5b 3 × 3 × 2 × 2 × 2c 7 × 4 × 7 × 4 × 7

2 a Writeeachasabasicnumeral. i 4 ×103

ii 5×104

b Hence,findthebasicnumeralfor: i (4 ×103) +(5×104) ii (4 ×103) ×(5×104)

3 Rewriteasabasicnumeral:a (5×103) + (2 ×102) + (7 ×101) +(9×1)b (8 ×104) + (6 ×102) + (3 ×1)

4 List,inorder,thefactorsof:a 28 b 48 c 68

5 Foreachofthefollowing,findthegreatestmultiplethatislessthan100.a 3 b 7 c 15

6 ‘Primenumberpairs’arepairsofprimenumbersthatdifferonlyby2,e.g.11and13,or41and43.Findalltheotherprimenumberpairsbetween10and100.

7 a Bycompletingfactortrees,findtheprimefactorsof:

i 56 ii 84b FindtheHCFof56and84.c FindtheLCMof56and84.

8 Findthesimplestanswerfor:a 121

b × × × × ×2 2 2 2 3 3

c 643

d × × × × ×5 5 5 7 7 73

ASSIgnment 3B Working mathematically 1 Abookcasehassixshelves,with45books

oneachshelf.Howmanybooksareinthebookcase?

2 Abuscanhold58peopleseatedand35standing.Howmanyofthesebuseswouldbeneededtotakeaschoolof750childrenand30teachersonaschoolexcursion?

3 Agrocerbought50kgoftomatoesfor$30.Shesold20kgat$1.20perkgandtheremainder,whichwereoverripe,shesoldfor80cperkg.Howmuchdidshegetforsellingthetomatoes?Howmuchprofitdidshemake?

4 InRugbyUnion,ateamscores5pointsforatry,7pointsforaconvertedtryand3pointsforapenaltygoal.Inhowmanywayscouldateamscore22points?

5 Aschooloffersthefollowingsportschoices:Summer:cricket,waterpolo,basketball,

volleyball,tennisWinter: football,hockey,soccer,squash

Ifonesummersportandonewintersportareselected,howmanydifferentcombinationsareavailable?

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993 Number and indices

ASSIgnment 3C Cumulative revision 1 Writethebasicnumeralineachcase.

a 12÷ (28 − 24) b 84 −10× 8 c 100−[50−(20− 7)]d 23 +5− 2 + 3 e 6 ×5+ 6 × 3 f 3 +7(0⋅7 +1⋅3)

1:06

2 Wesellbucketsofblocks.Ineachbucketthereare157blocks.Wesold93bucketsofblocksonMondayand7onTuesday.Howmanyblocksdidwesellonthosetwodaysaltogether?

1:03

3 Giventhat12×1256=15072,whatisthevalueof:a 1256×12 b 13×1256 c 11×1256?

1:07A

4 Trueorfalse?a 2 ×3186×5=31860 b 9× 888 =8880− 888c 555×12=(555× 6) × 2 d 18158÷20=(18158÷ 2) ÷10e 4 ×186×25= (4 ×25)×186 f 16×100−1=16×99

1:07

5 Writeasabasicnumeral:a 1846×1 b 0×26040 c 8145+0d 446 −0 e 0÷186 f 4186÷1g 23 ×11− 22 ×11 h 31×98+69×98 i 98× 37 + 2 × 37

1:03

6 Trueorfalse?a 8 × 3 ≠ 3 × 8 b 563<560 c 213×0≥0d =16 8 e 16×5 /≤ 16× 4 f 5×816>0

g 816÷1 /< 816×1 h 999<100−0 i =1 13

1:08

7 Findtheanswertoeachcalculation.a 5× 4 + 3 × 2 b 5+ 4 × 3+ 2 c 5× (4 + 3) − 2d (5+ 4) ÷ 3 + 2 e 5× 4 ÷ (3 + 2) f (5− 4 + 3) ÷ 2

1:06

8 a Listthefactorsof100.b Listthefactorsof125.c Listallthecommonfactorsof100and125.

3:03

9 a Listthefirst10multiplesof8.b Listthefirst10multiplesof12.c Whatisthelowestcommonmultipleof8and12?

3:03

10 Fromtheset{2,5,7,12,15,36,41},write:a theprimenumbers b thecompositenumbers.

3:04

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