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RIAN DWI ANGGARA PUTRA 111.120.051 JAWAB: Unit weight = 18 kN/m 3 Friction angel = 30 o Cohession = 20 o Weight of mass slide = (1/2)(18 kN/m 3 ) (5 meter) 2 {[tan(90 o -48 o )]- [tan(90 o -80 o )]} = 162.9 kN/m Lenght of slide = H/sin a = 5/sin 48 o = 6,73 Horizontal spase = 2 meter 1 st tensil permit = 18,3 kN 2 nd tensil permit = 21,8 kN 1 st shear permit = 0,133 kN 2 nd shear permit = 0,133 kN ΣT = = 20,05 kN/m ΣV = = 0,133 kN/m
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RIAN DWI ANGGARA PUTRA
111.120.051
JAWAB:
Unit weight
= 18 kN/m3Friction angel
= 30oCohession
= 20oWeight of mass slide= (1/2)(18 kN/m3) (5 meter)2 {[tan(90o-48o)]-[tan(90o-80o)]}
= 162.9 kN/m
Lenght of slide
= H/sin a = 5/sin 48o
= 6,73Horizontal spase= 2 meter1st tensil permit= 18,3 kN2nd tensil permit= 21,8 kN1st shear permit= 0,133 kN2nd shear permit= 0,133 kNT = = 20,05 kN/mV = = 0,133 kN/m
Fos = = 1,92