Mass-Energy Equivalence - Linville Mass-Energy...Mass-Energy Equivalence ... • the binding energy...
Transcript of Mass-Energy Equivalence - Linville Mass-Energy...Mass-Energy Equivalence ... • the binding energy...
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Mass-Energy Equivalence
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• Work is required to remove a nucleon from a stable nucleus because of the strong nuclear force
• The binding energy of a nucleus is the energy required to separate all of its nucleons and move them infinitely far apart
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The maximum binding energy per nucleon is between A =50 and A =74 (most stable)
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Comparison of Atomic & Nuclear binding energy
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Mass Defect
• The mass of a nucleus is always less than the mass of all the separate nucleons (protons and neutrons)
• this difference in mass is called the mass defect
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• the binding energy is related to the mass defect by the equation ΔE = Δmc2
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Example
• Determine the mass defect and binding energy of an alpha particle.
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Solution• alpha particle mass (2 protons, 2 neutrons) =
6.65 x 10-27 kg (data sheet)
• mass of 2 protons = 2 x 1.67 x 10-27 kg = 3.34 x 10-27 kg
• mass of 2 neutrons = 2 x 1.67 x 10-27 kg = 3.34 x 10-27 kg
• total mass of separate nucleons = 6.68 x 10-27
kg
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• mass defect = proton mass + neutron mass - α
mass = 0.03 x 10-27 kg
• ΔE = Δmc2
• ΔE = (0.03 x 10-27 kg)(3.00 x 108 m/s)2
• ΔE = 2.70 x 10-12 J
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• in nuclear reactions, mass is converted to energy or energy is converted to mass
• Conservation of mass-energy principle
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Example
• Calculate the energy produced in the reaction
2H mass = 3.34341 x 10-27 kg3H mass = 5.00661 x 10-27 kg
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Solution
• Total mass of reactants = 8.35002 x 10-27 kg
• The total mass of the products = 8.3212x10-27 kg
• Mass defect • =8.35002x10-27 kg – 8.3212x10-27 kg• = 2.882 x 10-29 kg
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• ΔE = Δmc2
• ΔE = (2.882 x 10-29 kg)(3.00 x 108 m/s)2
• ΔE = 2.59 x 10-12 J
• in the form of kinetic energy of products
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STS
• In a CANDU reactor, 1 kg of fuel (natural uranium) produces 3.4 x 105 MJ of heat that is converted to electricity
• in oil and coal power plants 1 kg of fuel produces about 4 MJ of heat
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Pair Production
• a very high energy photon may create matter
• The process must produce 2 particles whose total charge is zero, since charge & momentum must be conserved.
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• A particle and its antiparticle (antimatter) are often produced (i.e. an electron and antielectron) have the same mass and other properties, but opposite signs
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Bubble chamber trackNeutral particles do not leave a track
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Example
• A 8.50 x 1020 Hz photon produces an electron and an anti-electron. Determine the total kinetic energy of the particles.
• Conservation of Mass-Energy!!!
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Solution• photon energy = energy to make particles + Ek
• Ephoton = Eelectron + Eantielectron + Ek
• hf = mc2 + mc2 + Ek
• Ek =(6.63x10-34J•s)(8.50x1020) - 2(9.11x10-31kg)c2
• = 4.00 x 10-13 J