6 Mass-Energy Equivalence

download 6 Mass-Energy Equivalence

of 19

Transcript of 6 Mass-Energy Equivalence

  • 8/13/2019 6 Mass-Energy Equivalence

    1/19

    Mass-Energy

    Equivalence

  • 8/13/2019 6 Mass-Energy Equivalence

    2/19

    Work is required to remove a nucleon from

    a stable nucleus because of the strongnuclear force

    The binding energy of a nucleus is the

    energy required to separate all of its

    nucleons and move them infinitely far

    apart

  • 8/13/2019 6 Mass-Energy Equivalence

    3/19

    The maximum binding energy per nucleon is

    between A =50 and A =74 (most stable)

  • 8/13/2019 6 Mass-Energy Equivalence

    4/19

    Comparison of Atomic & Nuclear

    binding energy

  • 8/13/2019 6 Mass-Energy Equivalence

    5/19

    Mass Defect

    The mass of a nucleus is always less than

    the mass of all the separate nucleons(protons and neutrons)

    this difference in mass is called the mass

    defect

  • 8/13/2019 6 Mass-Energy Equivalence

    6/19

    the binding energy is related to the mass

    defect by the equation E = mc2

  • 8/13/2019 6 Mass-Energy Equivalence

    7/19

    Example

    Determine the mass defect and binding

    energy of an alpha particle.

  • 8/13/2019 6 Mass-Energy Equivalence

    8/19

    Solution alpha particle mass (2 protons, 2 neutrons) =

    6.65 x 10-27 kg (data sheet)

    mass of 2 protons = 2 x 1.67 x 10-27 kg =3.34 x 10-27 kg

    mass of 2 neutrons = 2 x 1.67 x 10-27 kg =3.34 x 10-27 kg

    total mass of separate nucleons = 6.68 x 10-27

    kg

  • 8/13/2019 6 Mass-Energy Equivalence

    9/19

    mass defect = proton mass + neutron

    mass - mass = 0.03 x 10-27 kg E = mc2

    E = (0.03 x 10-27

    kg)(3.00 x 108

    m/s)2

    E = 2.70 x 10-12 J

  • 8/13/2019 6 Mass-Energy Equivalence

    10/19

    in nuclear reactions, mass is converted to

    energy or energy is converted to mass

    Conservation of mass-energyprinciple

  • 8/13/2019 6 Mass-Energy Equivalence

    11/19

    Example

    Calculate the energy produced in the reaction

    2H mass = 3.34341 x 10-27 kg3H mass = 5.00661 x 10-27 kg

  • 8/13/2019 6 Mass-Energy Equivalence

    12/19

    Solution

    Total mass of reactants = 8.35002 x 10-27 kg

    The total mass of the products = 8.3212x10-27 kg

    Mass defect

    =8.35002x10-27 kg 8.3212x10-27 kg

    = 2.882 x 10-29 kg

  • 8/13/2019 6 Mass-Energy Equivalence

    13/19

    E = mc2

    E = (2.882 x 10-29 kg)(3.00 x 108 m/s)2

    E = 2.59 x 10-12 J

    in the form of kinetic energy of products

  • 8/13/2019 6 Mass-Energy Equivalence

    14/19

    STS

    In a CANDU reactor, 1 kg of fuel (natural

    uranium) produces 3.4 x 105 MJ of heatthat is converted to electricity

    in oil and coal power plants 1 kg of fuel

    produces about 4 MJ of heat

  • 8/13/2019 6 Mass-Energy Equivalence

    15/19

    Pair Production

    a very high energy photon may create

    matter

    The process must produce 2 particleswhose total charge is zero, since charge &

    momentum must be conserved.

  • 8/13/2019 6 Mass-Energy Equivalence

    16/19

    A particle and its antiparticle (antimatter) are

    often produced (i.e. an electron and antielectron)have the same mass and other properties, but

    opposite signs

  • 8/13/2019 6 Mass-Energy Equivalence

    17/19

    Bubble chamber track

    Neutral particles do not leave a

    track

  • 8/13/2019 6 Mass-Energy Equivalence

    18/19

    Example

    A 8.50 x 1020 Hz photon produces an

    electron and an anti-electron. Determinethe total kinetic energy of the particles.

    Conservation of Mass-Energy!!!

  • 8/13/2019 6 Mass-Energy Equivalence

    19/19