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Transcript of Mass Balance
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Process and Mass balance analysis
Gyeongsang National UniversityDepartment of Biological and chemical EngineeringEnvironmental Engineering Lab
Ngoc Thuan Le
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Discussions
• Environmental treatment reactors
• Hydraulic Detention time
• Study the hydraulic flow characteristics of reactors
• Mass Balance principles
• Modeling with tracer elements
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
• The constituents in wastewater are removed by physical, chemical, biological methods. These process occur in a variety of combination in treatment flow diagram.
• Important factors:
The type of reactor (container or tank)
The size of the treatment facilities
Temperature,
and others
• The fundamental for the basis analysis of the wastewater treatment is materials mass balance principle in which an accounting of mass is made before and after reactions.
Overview
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Reactors used for the treatment of wastewater
Batch reactorActivated sludge biological treatment, mixing of concentrated solution
Complete-Mix reactorAerated lagoons, aerated sludge digestion
Plug-Flow reactorChlorine contact basin, natural treatment systems, Activated sludge biological treatment…
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Complete Mix reactor in seriesLagoon treatment systems, used to simulate nonideal flow in plug flow reactor
Packed-bed reactorTrickling filter
Packed-bed upflow reactorAnaerobic treatment system
Fluidized-bed reactorUpflow sludge blanket reactors, air stripping…
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Detention time is the length of time water is retained in a vessel or basin or the period from the time the water enters a settling basin until it flows out the other end.
The theoretical detention time of a container is the same as the amount of time it would take to fill the container if it were empty.
Detention times are normally calculated for the following basins or tanks:
Flash mix chambers (seconds)
Flocculation basins (minutes)
Sedimentation tanks or clarifiers (hours)
Wastewater ponds (days)
Oxidation ditches (hours).
Detention time
Q
V
Where:
τ = hydraulic detention time, T
V = volume of the reactor, L3
Q = volumetric flow rate, L3T-1
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Ideal flow in complete-mix and plug-flow reactors
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Ex.
Problem
The reservoir for the community holds 110,000 gallons. The well will produce 60 gpm. What is the detention time in the reservoir in hours?
Solution
hrshr
orgal
gal6.30
min/60min1834
min1834min/60
000,110
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Nonideal flow in complete-mix and plug-flow reactors
The flow in complete-mix and plug-flow reactors is seldom ideal
a. Temperature differences, a portion of the water can travel to the outlet along the bottom of or across the top of the reactor without mixing completely.
b. Wind-driven circulation patterns.
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
c. Inadequate mixing, sometimes due to sufficient energy input.
d. Poor design, dead zone may develop within the reactor that will not mix with the incoming water.
e. Axial dispersion in plug flow reactors
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
The Mass-balance principle
• Mass is neither created nor destroyed, but the form of the mass can be altered (e.g., liquid to a gas)
• Precisely, the law of the conservation of mass: “What comes in must equal what goes out.”
• The mass balance analysis define what occurs within treatment reactors as a function of time.
The two numbers — in (influent) and out (effluent) — must be within 10 to 15% ofeach other to be considered acceptable. Larger discrepancies may indicate sampling errors or increasing solids levels in the unit or undetected solids discharge in the tank effluent.(Frank R, Spellman)
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
OutflowInflow
Q, Co Q, C
V, C
Mixer
Accumulation = inflow – outflow + generation (or disappearance)
One or more of the terms can be equal to zero.
- In a batch reactor in which there is no inflow or outflow, accumulation will be equal to zero.
- under steady-state condition, the rate of accumulation is zero
Generation term:
rc = -kC for a decrease in the reactant or,
rc = +kC for an increase in the reactant.
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Preparation of the Mass Balance
1. Prepare a simplified schematic or flow diagram of the system or process
2. Draw a system or control volume boundary to define the limit over which the mass balance is to be applied.
3. List all of the pertinent
4. List all of the rate expressions for the biological or chemical reactions that occur within the control volume.
5. Select a convenient basis on which the numerical calculations will be based.
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
• In a complete-mix reactor, it will be assumed that:
1. The vol. flowrate into and out of the control volume is constant.
2. The liquid within the control volume is not subject to evaporation (constant vol.)
3. The liquid within the control volume is mixed completely.
4. A chemical reaction involving a reactant A is occurring within the reactor.
5. The rate of change in the concentration of the reactant A that is occurring within the control volume is governed by a first-order reaction (rc = -kC)
Application of the Mass Balance analysis
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
VrQCQCVdt
dCco VkCQCQCV
dt
dCo )(or
Accumulation = inflow – outflow + generation
Where:
dC/dt = rate of change of reactant concentration within the control volume, ML-3T-1
V = volume contained within control vol., L3
Q = volumetric flow rate into and out of control volume, L3T-1
Co = conc. of reactant entering the control vol, ML-3
C = conc. of reactant leaving the control vol., ML-3
rc = first –order reaction (-kC), ML-3T-1
k = first-order reaction rate coefficient, T-1cc
Steady state simplification
CCV
Qr oc
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Modeling ideal flow in reactors
Ideal flow in complete-mix reactor
Simplified word statement:
Accumulation = inflow – outflow
QCQCVdt
dCo
CV
QV
dt
dC
tc
c
dtV
Q
C
dC
o 0
eCeCeCC ot
oVQt
o/)/(
Simplifying by noting that Co = 0 yields
The resulting expression after integration is
Where:C= conc. of the tracer in the reactor at time t, ML-3
Co = initial conc. of the tracer in the reactor, ML-3
t = time, TV = reactor volume, L3
Q = volumetric flow rate, L3T-1
τ = theoretical detention time, V/Q, Tθ = normalized detention time t/τ, unitless
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Modeling ideal flow in reactors
Ideal flow in plug flow reactor
Simplified word statement:
Accumulation = inflow – outflow
xxx QCQCVt
C
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Modeling ideal flow in reactors
Where:
∂C/∂t = constituent concentration, ML-3 (g/m3)
∆V = differential volume element, L3 (m3)
t = time T (s)
Q = volumetric flowrate, L3T-1(m3/s)
x = some point along the reactor length L, (m)
∆x = differential distance L (m)
xx
CCQQCV
t
C
A∆x = ∆V, A is the cross sectional area in the x direction
xx
CQxA
t
C
x
C
A
Q
t
C
x
Cv
x
C
A
Q
t
C
Taking the limit as ∆x approaches zero yields
Where, v =velocity of flow, LT-1(m/s)
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Need for tracer analysis
• The use of dyes and tracers for measuring the residence time distribution curves is one of the simplest and most successful methods
• Now, to assess the hydraulic performance of full scale reactors
① The assessment of short circuiting in sedimentation tanks and biological reactors
② The assessment of contact time in chlorine contact basins
③ The assessment of the hydraulic approach condition in UV reactors
④ The assessment of flow patterns in constructed wetlands and other natural treatment systems
Analysis of nonideal flow in reactors using tracers
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Properties of tracers
① The tracer should not affect the flow.
② The tracer should be conservative.
③ It must be possible to inject the tracer over a short time period.
④ Be able to be analyzed conveniently.
⑤ The molecular diffusivity of the tracer should be low.
⑥ Not be absorbed on or react with the exposed reactor surfaces.
⑦ Not be absorbed on or react with the particles in the wastewater.
Success in tracer studies: congo red, fluorescein (C20H12O5), fluorosilicic acid (H2SiF6), hexafluoride gas (HF6), lithium chloride (LiCl), potassium permanganate (KMnO4)….
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Treatment processes involving mass transfer
Table 4-9
Principal applications of mass transfer operations and processes in wastewater treatment
Type of reactor Phase equilibria Application
Absorption Gas ---> liquid Addition of gases to water (e.g., O2, O3, CO2, Cl2, SO2), NH3 scrubbing in acid
Adsorption Gas ---> solid Removal of organics with activated carbon
Liquid ---> solid Removal of organics with activated carbon, dechlorination
Desorption Solid ---> liquid Sediment scrubbing
Solid ---> gas Reactivation of spent activated carbon
Drying (evaporation) Liquid ---> gas Drying of sludge
Gas stripping (also known as desorption)
Liquid ---> gas Removal of gases (e.g.,O2,CO2, H2S, NH3, volatile organic compounds, NH3 from digester supernatant)
Ion exchange Liquid ---> solid Selective removal of chemical constituents, demineralization
Adapted from Crittenten (1999), McCabe and Smith (1976) and Montgomery (1985)
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
MASS BALANCE USING BOD REMOVAL
From: Mathematics Manual for water and wastewater treatment plant operators
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
• Step 1: BODin = influent BOD x flow x 8.34
• Step 2: BODout = effluent BOD x flow x 8.34
• Step 3: BOD pounds removed = BODin – BOD out
• Step 4: Solids generated (lb) = BOD removed (lb x factor)
• Step 5: Solids removed = sludge pumped (gpd) x % solids x 8.34
• Step 6: Effluent solids (mg/L) x flow (MGD) x 8.34
1g/m3 = 8.34 lb/Mgal
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Example
ProblemA conventional activated biosolids system with primary treatment is operating at the levels listed below. Does the mass balance for the activated biosolids system indicate a problem?
Solution
• BODin = 166 mg/L x 11.40 MGD x 8.34 = 15,783 lb/day
• BODout = 25 mg/L x 11.40 MGD x 8.34 = 2377 lb/day
• BOD removed = 15,783 lb/d – 2377 lb/d = 13,406 lb/day
• Solids produced = 13,406 lb/day x 0.7 lb solids/lb BOD = 9384 lb solids/day
• Solids removed = 6795 mg/L x 0.15 MGD x 8.34 = 8501 lb/day
• Difference = 9384 lb/day – 8501 lb/day = 883 lb/day, or 9.4% of solids produced.
These results are within the acceptable range.
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
MASS BALANCE FOR SETTLING TANKS
• Step 1: Solids in = pounds of influent suspended solids
• Step 2: Pounds of effluent suspended solids
• Step 3: Biosolids solids out = pounds of biosolids solids pumped per day
• Step 4: Solids in — (solids out effluent + biosolids solids pumped)
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Ex,
Problem
A settling tank receives a daily flow of 4.20 MGD. The influent contains 252 mg/L suspended solids, and the unit effluent contains 140 mg/L suspended solids. The biosolids pump operates 10 min/h and removes biosolids at the rate of 40 gpm. The biosolids content is 4.2% solids. Determine if the mass balance for solids removal is within the acceptable 10 to 15% range.
Solution
• Step 1: Solids in = 252 mg/L x 4.20 MGD x 8.34 = 8827 lb/d
• Step 2: Solids out = 140 mg/L x 4.20 MGD x 8.34 = 4904 lb/d
• Step 3: Biosolids solids = 10 min/hr x 24 hr/day x 40 gpm x 8.34 x 0.042 = 3363 lb/d
• Step 4: Balance = 8827 lb/day – (4904 lb/day + 3363 lb/day) = 560 lb, or 6.3%
MECALF & EDDY|Wastewater Engineering-treatment and reuse Chap.4|Introduction to Process analysis
Thank you for your attention!
(mg/l) solids suspended
1000*(ml/l) volumesludge Settled% h