March 18

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Today: Warm-Up Test Review Khan Academy Results/Schedule Begin Unit on Quadratic Equations March 18 th

Transcript of March 18

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Today:

Warm-UpTest Review

Khan Academy Results/ScheduleBegin Unit on Quadratic Equations

March 18th

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Khan Academy:

Saturday/Sunday -- 1409 minutes = 23.48 Hours

Topics for March 24th:Graphing Parabolas in Standard

FormSolving Quadratics by Factoring

1

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Number Sense: Space & Volume

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Number Sense: Space & Volume

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Number Sense: Space & Volume

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Number Sense: Space & Volume

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3D Sphere

Number Sense: Space & Volume

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Number Sense: Space & Volume

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Test Review:

Top 4 missed questions from Friday's test: v.14th; (44% correct) #8.

32x2 = 50 3rd; (42% correct) #10. x3 - 121x = 0 2nd; (40% correct) #4. -3x3 - 12x2 = 0

1st; (37%) #3. The product of (9 - 4t)(9 + 4t) results in:

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Today's Objectives:

1. Understand the characteristics of Quadratic Equations, (What they are, and what they aren't).

2. Recognize the Graph of a Quadratic Equation

3. Describe the Differences between Quadratic &

Linear Equations

4. Solve Quadratic Equations by factoring5. Listen Carefully, take notes, ask questions when needed.

Quadratic Equations:

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1. What is a Quadratic Equation? From the Latin 'quad', as in quaduplets, quadrilaterals, and quarters...

Quad means 4. A square has four sides. A variable in a quadratic equation can have an exponent of 2, but no higher.An exponent of 2 is a number 'squared'....

The following are all examples of quadratic equations:

x2 = 25, 4y2 + 2y - 1 = 0, y2 + 6y = 0, x2 + 2x - 4 = 0

The standard form of a quadratic is written as: ax2 + bx + c = 0, where only a cannot = 0

Quadratic Equations:

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We have been solving quadratic equations recently without actually calling them Quadratics. Let's review. Solve: x2 - 13x = 0

x( x - 13) = 0x = 0, or x = 13

One more example. Solve: y = x2 - 4x - 5. To find the x-intercepts, we set the equation to x2 - 4x - 5 = 0

( x - 5)( x + 1) = 0x = 5 or x = -1Which brings us to: What do Quadratic Equations look like and how are they different from linear equations?

Quadratic Equations:

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Y = 2x + 0 is a linear equation.Linear Equations are straight lines and cross the x and y axis only one time. For each 'y', there is only one 'x'. The greatest degree of any exponent in a linear equation is 1. The relationship between x and y is constant; the slope stays the same.

Linear Equations:

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Linear vs. Quadratic Equations

A. The graphs of quadratics are not straight lines, they are always in the shape of a Parabola.B. Parabolas can cross an axis more than once.

C. Unlike linear equations, each value of Y in a quadratic equation has more than one value of x. Because Y is 0 at the X-intercept, when we set the equation = to 0, we get the values of the x-intercepts.D. The slope of a quadratic is not constant. The

slope-intercept formula will not work with parabolas.

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Parabolas:...In Sports

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Parabolas:...In Archeticture

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Parabolas:...In Nature

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Parabolas:...Everywhere

Finally, the most importantParabola of all

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Objective 4: Solving Quadratic Equations by Factoring

There are 2 ways to factor Quadratic Equations and we have done both already. Let's review:

Method 1: Set the equation = to 0 and solve:Example A. x2 + 6x + 9

x2 + 6x + 9 = 0; (x + 3) (x + 3) = 0, x = -3.This is a perfect square trinomial, and the parabola only crosses the x axis at -3 and would be in this shape:

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Objective 4: Solving Quadratic Equations by Factoring

Example B. x2 + 16x + 48 = 0

(x + 12) (x + 4) = 0; x = -12, x = -4. This parabola is to the left of the Y axis

Method 2: Solve x2 = 64. Remember the standard form? ax2 + bx + c = 0, where only a cannot = 0 In this case, b is 0, and c is 64.

We can solve by taking the square root of both sides. The result is x = + 8; x = 8, and x = -8

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Factoring Quadratic Equations

From the warm-up exercises, we have seen the variousways to factor quadratic equations. The solutions, or roots, tell us where the graph crosses the x axis.

Given this information, we can begin to plot the graph. However, there is still more information we need to complete the graph.

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Remember, all Quadratic Equations are in the form of a Parabola. Parabolas are in one of these forms:

To solve and graph a quadratic equation, we need to know where the graph crosses the x and y axis:

Graphing Parabolas & Parabola Terminology

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Important points on a Parabola:

1.Axis of Symmetry:The axis of symmetry is the verticle or horizontal line which runs through the exact centerof the parabola.

Graphing Parabolas & Parabola Terminology

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Important points on a Parabola:2. Vertex: The vertex is the highest point (the maximum), or the lowest point (the minimum) on a parabola.

Notice that the axis of symmetry always runs through the vertex.

Graphing Parabolas & Parabola Terminology

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Finding the Axis of Symmetry and Vertex

1. Finding the Axis of Symmetry: The formula is: x = - b/2a Plug in and solve for y = x2 + 12x + 32

We get - 12/2; = -6. The center of the parabola crosses the x axis at -6. Since the axis of symmetry always runs through the vertex, the x coordinate for the vertex is -6 also.

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There is one more point left to find and that is they-coordinate of the vertex. To find this, plug in the value of the x-coordinate back into the equation and find y. y = -12 + 12(4) + 32. Y = 1 + 48 + 32. Y = 81.

The bottom of the parabola is at -1 on the x axis, and way up at 81 on the y axis.

Finding the Axis of Symmetry and Vertex

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Warm- Up Exercises

The slope is 2,

which is positive

and the Y-intercept

is -2Therefore, the correct graph is

A

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Warm- Up Exercises

The Y-intercept is:0

Write the equation for the line above

The slope is:2

The equation of the line is: Y = 2x + 0

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Warm- Up Exercises

3. Write the inequality for the graph below

The Y-intercept is:2

The slope is: -3The line is solid, not dotted. The equation is:

Y < -3x + 2

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Class Work:

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90% of 90 girls and 80% of 110 boys have shown up in the concert hall on time.

How many children are late?

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Parabolas

A parabola with -x2