Chapter 2 Linear Kinematics Describing Objects in Linear Motion.
Linear Motion 2
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Transcript of Linear Motion 2
LINEAR MOTION
OBJECTIVE
1. To analyze linear motion of a moving object.2. To determine displacement, velocity and acceleration is zero and non-uniform when
acceleration is non zero.
INFERENCE
1. Linear motion is a motion along a straight line .
MALAYSIAN POLYTECHNIC
MATHEMATICS , SCIENCE AND COMPUTER DEPARTMENT
BB101 – ENGINEERING SCIENCE
LAB REPORT 2
GROUP MEMBERS
NAME MATRIX NOSYAFINAZ BT YAHYA 16DKA 11F 1150
NURUL FATTAH MAIMUNAH BT LOKMAN HAKIM 16DKA 11F 1148
NUR FARLIYANA AZIRA BT NOOR AZHAR 16DKA11F 1152
NUR FAIRUZA SYAHIRA BT MOHD ISA 16DKA11 F 1151
NOR HAZWANI BT ZOHARI 16DKA11F 1162
RIFF SHAFIQ BIN ISMAIL 16DKA11F 1149
SYED SALAHUDDEAN AYUB BIN SYED BADRUL HISHAM 16DKA11F 1147
TITLE PHYSICAL QUANTITIES AND MEASUREMENTS
LECTURER’S NAME
EN.SHARUDDIN BIN HUSSAIN
DATE OF SUBMISSION 23th AUGUST 2011
LECTURER’S COMMENTS
RUBRICITEM MARKS
4 3 2 11. Procedures
2. Participation
3. Diagrams
4. Data
5. Calculations
6. Analysis
7. Error Analysis
8. Questions
9. Conclusion
10. Submission date
TOTAL
2. Velocity is speed in a given direction
HYPOTHESIS
1. Velocity is speed in a given direction.2. Acceleration is the increase of velocity over a period of time.3. Deceleration is the decrease of velocity over a period of time.
APPARATUS
1. Ticker time 4. Jumper Wire
2. Runway and trolley 5. Ruler
3. Power supply 6. Lab Jack/ Clamp
Figure 1
PROCEDURES
1. The apparatus was set up as in figure 1.2. The runway is inclined about 1m-2m,so the trolley was roll down freely from rest without
any applied force.3. The ticker tape was attach to the trolley using cellophane tape.4. The ticker timer was switch on and the trolley was release freely.
ANALYSING DATA
1. The 10 dot was mark and number as the figure above.
2. The ticker tape was cut and paste into 10-dot strips on the graph paper.
Note :
1. Frequency of ticker – time is 50Hz. Therefore, 1 dot or 1 unit time represents 1/50 seconds or 0.02 second.
2. Time for 10 dots = 10 dots x 0.02 second = 0.2 seconds.
RESULT & CALCULATION
1 Number of 10-dot strips 9
2 Total time, t total=number of strips x 0.2 1.8s
3 Total displacementof the trolley Length of runway = 148.5cm÷100 = 1.485m
1.485m
4 Average velocity of the trolley
v=totaldisplacement
total time
0.325m/s
0 1 2 3 4 5 6 7 8 9 10
5 Acceleration of the trolley
a.Initial velocity
u=lengt hof first stripstime for10 dots
0.1115m/s
b.Final velicity
v=lengt hof last striptime for10dots
0.725m/s
c.Time for acceleration,t (number of strip-1) x(time for 10 dots)
1.6 s
d.acceleration
a=v−ut
0.3834m/s2
6 Average velocity
vaverage =v+u2
0.41825m/s
Question
1. Is there any difference in the value of average velocity between Result 4 and 6?
The different between Result 4 and 6 is result 4 is a theory while result 6 is practical. Result 4 is theory because it shows the velocity of the experiment. While result 6 shows the average velocity.
CONCLUSION
Enable to determine the linear motion of a moving object. Enable to determine displacement , velocity and acceleration.