Lecture No. 9 Chapter 3 Contemporary Engineering Economics Copyright © 2010 Contemporary...
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Transcript of Lecture No. 9 Chapter 3 Contemporary Engineering Economics Copyright © 2010 Contemporary...
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Lecture No. 9Chapter 3
Contemporary Engineering EconomicsCopyright © 2010
Contemporary Engineering Economics, 5th edition, © 2010
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Composite Cash Flows
Situation 1: If you make 4 annual deposits of $100 in your savings account which earns a 10% annual interest, what equal annual amount (A) can be withdrawn over 4 subsequent years? Situation 2: What value of A would make the two cash flow transactions equivalent if i = 10%?
Contemporary Engineering Economics, 5th edition, © 2010
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Establishing Economic Equivalence
Method 1: at n = 0 Method 2: At n = 4
Contemporary Engineering Economics, 5th edition, © 2010
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Example 3.26 Cash Flows with Subpatterns
Given: Two cash flow transactions, and i = 12%
Find: C
Strategy: First select the base period to use in calculating the equivalent value for each cash flow series (say, n = 0). You can choose any period as your base period.
Contemporary Engineering Economics, 5th edition, © 2010
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Example 3.27 Establishing a College Fund
Given: Annual college expenses = $40,000 a year for 4 years, i = 7%, and N = 18 years
Find: Required annual contribution (X) Strategy: It would be computationally efficient if you choose n = 18 (the year she goes to college) as the base period.
Contemporary Engineering Economics, 5th edition, © 2010
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Cash Flows with Missing Payments
Given: Cash flow series with a missing payment, i = 10% Find: P
Strategy: Pretend that we have the 10th missing payment so that we have a standard uniform series. This allows us to use (P/A,10%,15) to find P. Then we make an adjustment to this P by subtracting the equivalent amount added in the 10th period.
Contemporary Engineering Economics, 5th edition, © 2010
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Example 3.28 Calculating an Unknown Interest Rate
Given: Two payment options
Find: i at which the two options are equivalent
Excel Solution:
Contemporary Engineering Economics, 5th edition, © 2010
Option 1: Take a lump sum payment in the amount of $167M. Option 2: Take the 26-installment option.
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Example 3.29 Unconventional Regularity in Cash Flow Pattern Given: Payment series given, i = 10%, and N = 12 years
Find: P
Strategy: Since the cash flows occur every other year, find out the equivalent compound interest rate that covers the two-year period.
Solution:
Equivalence Calculations for a skipping cash flow pattern
Contemporary Engineering Economics, 5th edition, © 2010
Actually, $10,000 payment occurs every other year for 12 years at 10%.We can view this same cash flow seriesas having $10,000 payment occurs every periodat an interest rate of 21% over 6 years.