Lecture - 8 First order circuits

28
Lecture - 8 First order circuits

description

Lecture - 8 First order circuits. Outline. First order circuits. The Natural Response of an RL Circuit. The Natural Response of an RC Circuit. The Step Response of RL Circuits. The Step Response of RC Circuits. A General Solution for Step and Natural Responses. - PowerPoint PPT Presentation

Transcript of Lecture - 8 First order circuits

Page 1: Lecture - 8   First  order circuits

Lecture - 8

First order circuits 

Page 2: Lecture - 8   First  order circuits

Outline

• First order circuits.

• The Natural Response of an RL Circuit.

• The Natural Response of an RC Circuit.

• The Step Response of RL Circuits.

• The Step Response of RC Circuits.

• A General Solution for Step and Natural Responses.

Page 3: Lecture - 8   First  order circuits

First order circuits• A first-order circuit may be reduced to a Thevenin equivalent

connected to either a single equivalent inductor or capacitor.

(a) An inductor connected to a Thevenin equivalent

(c) A capacitor connected to a Thevenin equivalent

(b) An inductor connected to a Norton equivalent

(d) A capacitor connected to a Norton equivalent

Page 4: Lecture - 8   First  order circuits

The Natural Response of an RL Circuit

• We assume that the independent current source generates a constant current and that the switch has been in a closed position for a long time.

• Thus only constant, or dc, currents can exist in the circuit just prior to the switch's being opened, and therefore the inductor appears as a short circuit (Ldi/dt = 0) prior to the release of the stored energy. Therefore, all the source current appears in the inductive branch

• Finding the natural response requires finding the voltage and current at the terminals of the resistor after the switch has been opened, that is, after the source has been disconnected and the inductor begins releasing energy.

The circuit for t ≥ 0

Page 5: Lecture - 8   First  order circuits

The Natural Response of an RL Circuit

• To find i(t), we use Kirchhoff s voltage law to obtain an expression involving i, R, and L. Summing the voltages around the closed loop gives:

• which shows that the current starts from an initial value I0 and decreases exponentially toward zero as t increases.

0 RidtdiL 0,)( )/(

0 teIti tLRSolving

)1(21)(

Re)(

Re)(

)/(220

)/(220

)/(0

tLR

tLR

tLR

eLItw

Itp

Itv

Page 6: Lecture - 8   First  order circuits

The Natural Response of an RL Circuit

• The coefficient of t—namely, R/L—determines the rate at which the current or voltage approaches zero. The reciprocal of this ratio is the time constant of the circuit, denoted τ= L/R

• The time constant of an RL circuit equals the equivalent inductance divided by the Thevenin resistance as viewed from the terminals of the equivalent inductor.

• Calculating the natural response of an RL circuit can be summarized as follows:

1. Find the initial current, I0, through the inductor.2. Find the time constant of the circuit, τ= L/R.3. Use Eq. I0 e-t/τ, to generate i(t).

Page 7: Lecture - 8   First  order circuits

Example 1

Page 8: Lecture - 8   First  order circuits

Example 1

Page 9: Lecture - 8   First  order circuits

Example 1

Page 10: Lecture - 8   First  order circuits

The Natural Response of an RC Circuit • We assume that the independent current source generates a constant current and

that the switch has been in a closed position for a long time.

• Thus only constant, or dc, currents can exist in the circuit just prior to the switch's being opened, and therefore the capacitor appears as a open circuit (Cdv/dt = 0) prior to the release of the stored energy. Therefore, all the source voltage appears across the capacitor terminal.

• Finding the natural response requires finding the voltage and current at the terminals of the resistor after the switch has been opened, that is, after the source has been disconnected and the capacitor begins releasing energy.

The circuit for t ≥ 0

Page 11: Lecture - 8   First  order circuits

The Natural Response of an RC Circuit

• To find v(t), we use Kirchhoff s current law to obtain an expression involving v, R, and C. Summing the currents away from the upper junction between R and C gives gives:

• which shows that the voltage starts from an initial value V0 and decreases exponentially toward zero as t increases.

0Rv

dtdvC 0,)( /

0 teVtv RCtSolving

)1(21)(

)(

)(

/220

/22

0

/0

RCt

RCt

RCt

eCVtw

eR

Vtp

eRVti

Page 12: Lecture - 8   First  order circuits

The Natural Response of an RC Circuit

• The coefficient of t—namely, 1/RC—determines the rate at which the current or voltage approaches zero. The reciprocal of this ratio is the time constant of the circuit, denoted τ= RC

• The time constant of an RC circuit equals the equivalent capacitance times the Thevenin resistance as viewed from the terminals of the equivalent capacitor.

• Calculating the natural response of an RC circuit can be summarized as follows:

1. Find the initial voltage, V0, across the capacitor.2. Find the time constant of the circuit, τ = RC.3. Use Eq. v(t) = V0e-t/ τ, to generate v(t).

Page 13: Lecture - 8   First  order circuits

Example 2

Page 14: Lecture - 8   First  order circuits

Example 2

Page 15: Lecture - 8   First  order circuits

Example 2

Page 16: Lecture - 8   First  order circuits

The Step Response of RL Circuits• Step response: finding the currents and voltages generated in first-

order RL or RC circuits when either dc voltage or current sources are suddenly applied.

• The task is to find the expressions for the current in the circuit and for the voltage across the inductor after the switch has been closed.

• After the switch in circuit has been closed, Kirchhoff s voltage law requires that:

dtdiLRiVs

Solving 0,)( )/( teRV

RVti tLRss

Page 17: Lecture - 8   First  order circuits

The Step Response of RL Circuits• Which indicates that after the switch has been closed, the

current increases exponentially from zero to a final value of Vs/R.

• The time constant of the circuit, L/R, determines the rate of increase.

• The voltage across an inductor is Ldi/dt, so:

• If the initial current is zero, the voltage across the inductor jumps to Vs. We also expect the inductor voltage to approach zero as t increases, because the current in the circuit is approaching the constant value of Vs/R.

tLRs eRIVtv )/(

0 )()(

Page 18: Lecture - 8   First  order circuits

The Step Response of RC Circuits• The task is to find the expressions for the current in the circuit and

for the voltage across the capacitor after the switch has been closed.

• After the switch in circuit has been closed, Kirchhoff s current law requires that:

scc I

Rv

dtdvC

Solving 0,)()( / teRIVRItV RCtsosc

Page 19: Lecture - 8   First  order circuits

The Step Response of RC Circuits• Which indicates that after the switch has been closed, the voltage

increases exponentially from zero to a final value of IsR.

• The time constant of the circuit, RC, determines the rate of increase.

• The current in an capacitor is Cdv/dt, so:

• If the initial voltage is zero, the current in the capacitor jumps to Is. We also expect the capacitor current to approach zero as t increases, because the voltage in the circuit is approaching the constant value of IsR.

RCts e

RVIti /0 )()(

Page 20: Lecture - 8   First  order circuits

A General Solution for Step and Natural Responses

• The general solution for natural and step responses of RL and RC circuits is:

• Therefore, when computing the step and natural responses of circuits, it may help to follow these steps:

1. Identify the variable of interest for the circuit. For RC circuits, it is most convenient to choose the capacitive voltage; for RL circuits, it is best to choose the inductive current.

2. Determine the initial value of the variable, which is its value at t0. 3. Calculate the final value of the variable, which is its value as t ∞.

4. Calculate the time constant for the circuit.

/)(0

0])([)( ttff extxxtx

Page 21: Lecture - 8   First  order circuits

Example 3• Assume that the switch in the circuit shown has been in

position b for a long time, and at t = 0 it moves to position a. Find: (a) i(0+); (b) v(0+); (c) τ,t > 0; (d) i(t), t > 0; (e) v(t), t > 0+.

Page 22: Lecture - 8   First  order circuits

Example 3

Page 23: Lecture - 8   First  order circuits

Example 3

Page 24: Lecture - 8   First  order circuits

Example 4• The switch in the circuit shown in circuit shown has been

closed a long time before opening at t = 0. For t ≥ 0+, finda) v0(t).b) i0(t).c) i1(t).d) i2(t)e) i1(0+).

Page 25: Lecture - 8   First  order circuits

Example 4

Page 26: Lecture - 8   First  order circuits

Example 4

Page 27: Lecture - 8   First  order circuits

Summary• A first-order circuit may be reduced to a Thevenin (or Norton)

equivalent connected to either a single equivalent inductor or capacitor.

• The natural response is the currents and voltages that exist when stored energy is released to a circuit that contains no independent sources.

• The time constant of an RL circuit equals the equivalent inductance divided by the Thevenin resistance as viewed from the terminals of the equivalent inductor.

• The time constant of an RC circuit equals the equivalent capacitance times the Thevenin resistance as viewed from the terminals of the equivalent capacitor.

Page 28: Lecture - 8   First  order circuits

Summary

• The step response is the currents and voltages that result from abrupt changes in dc sources connected to a circuit. Stored energy may or may not be present at the time the abrupt changes take place.

• The solution for either the natural or step response of both RL and RC circuits involves finding the initial and final value of the current or voltage of interest and the time constant of the circuit.