Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An...

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Lecture 8: A Design Example - An Electromagnet

Transcript of Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An...

Page 1: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

Lecture 8:A Design Example -An Electromagnet

Page 2: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Objective

Use a genetic algorithm to solve an engineering design example

Page 3: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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The ProblemDesign an electromagnet to lift a mass.

f

bv

br

Battery

i

M

Page 4: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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SpecificationsMass

10 kG10 cm by 10 cm areaMagnetic material should not overlap massMust lift from distance of 5 mm Gravity is on surface of Earth (G=9.8 m/s2)

Batteryvb = 12 Vrb = 0.5 ΩCurrent should not exceed 6 A

Page 5: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Specifications (Continued)Winding

Should not exceed packing factor of 0.7May use Aluminum (Al) or Copper (Cu)Aluminum

Density (ρw) = 2701 Kg/m3

Conductivity (σw) = 35.4 1 1/(μmΩ)Current Density (jmax) = 6.14 MA/m2

CopperDensity (ρw) = 8900 Kg/m3

Conductivity (σw) = 58.0 1/(μmΩ)Current Density (jmax) = 7.62 MA/m2

Page 6: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Specifications (Continued)

Magnetic MaterialMicrosil

Bsat = 1.4 T, μ = 15000 μ0 , ρm = 7064 Kg/m3

Superperm 80Bsat = 0.7 T, μ = 6000 μ0 , ρm = 8069 Kg/m3

Superperm 49Bsat = 1.2 T, μ = 3500 μ0 , ρm = 7892 Kg/m3

Page 7: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Specifications (Continued Again)

Size (Mass)Total mass of electromagnet should be as small as possible

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Electromagnet Dimensions

g

sw ewew

ww

sdwd

Depth intopage = d

iw

bw

Page 9: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Design Variables

WireMaterial Type mw

1=Cu, 2=A)Conductor Cross Section acNumber of Turns N

Magnetic MaterialMaterial Type mm

1=Microsil, 2=Superperm 80, 3=Superperm 49)

Page 10: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Design Variables (Continued)

CoreSlot width wsWire window width wwSlot depth dsWire window depth dwEnd width weI-core width wiBack width wbDepth d

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Parameter Vector

⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥

⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢

=

drrwrdrwmNam

wb

wi

e

dw

s

ww

s

m

w

w

θ

swww wrw =

sdww drd =

ewii wrw =

ewbb wrw =

Page 12: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Data Vector

⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥

⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢

maxf

max

max

max

sat

w

m

w

plJiB

gGM

,

σρρ

Page 13: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Electrical Analysis

Goal

Matlab m-file: Electrical_Analysis.m

),( Ψθelec

f

Fij

p=

⎥⎥⎥

⎢⎢⎢

Page 14: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Electrical AnalysisPacking factor

Winding volume (conductor)

Winding length

ww

cf dw

Nap =

( )( )wwbwwfw wdwddwpv 222 π++=

c

ww a

vl =

Page 15: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Electrical Analysis (Cont.)

Winding resistance

Current

Current Density

wc

ww a

lrσ

=

wb

b

rrvi+

=

caij =

Page 16: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Magnetic Analysis

Goal

Matlab m-file: Magnetic_Analysis.m

),,(

5,4

3,2

2,1

1,0

Ψθ iF

fBBBB

mag

e

=

⎥⎥⎥⎥⎥⎥

⎢⎢⎢⎢⎢⎢

Page 17: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Magnetic Equivalent Circuit

g

sw ewew

sdwd

1N

2N

3N

4N5N

6N

7N

ww

iw

bw0N

Page 18: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Magnetic Equivalent Circuit (Cont)

hlP

Ni1N

2N

3N

4N5N

6N

7N

2,1P

3,2P

4,3P

5,4P

6,5P

7,6P

vlP

0N

eP

1,0P

7,0P

3,6P

1,0Φ

2,1Φ

3,2Φ

5,4Φ

Page 19: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Review: Magnetic Equivalent Circuits

Page 20: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Magnetic Material Permeances

wb

e

dwdw

PP+

==μ2

7,02,1

2/7,63,2ws

e

dddwPP

−==

μ

es

i

wwdw

P+

5,4

es

b

wwdw

P+

1,0

g

sw ewew

sdwd

1N

2N

3N

4N5N

6N

7N

ww

iw

bw0N

Page 21: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Air Gap Permeances

g

sw ewew

sdwd

1N

2N

3N

4N5N

6N

7N

ww

iw

bw0N

⎟⎟⎠

⎞⎜⎜⎝

⎛+

−+

−=

s

ews

s

ws

wwdd

wddd

πμμ

1ln)(2)( 00

3,6

444 3444 2144444 344444 21

44 344 21321

facesbackfront

ie

faceinner

ss

faceouter

i

facemain

e

gww

gdwd

gwd

gdw

PP

/

00

006,54,3

1ln2

4),min(

1ln2

1ln

⎟⎟⎠

⎞⎜⎜⎝

⎛++⎟⎟

⎞⎜⎜⎝

⎛+

+⎟⎟⎠

⎞⎜⎜⎝

⎛++==

ππ

μππμ

ππ

μμ

Page 22: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Hor. And Vert. Leakage Permeances

g

sw ewew

sdwd

1N

2N

3N

4N5N

6N

7N

ww

iw

bw0N

gddwP

s

wvl +

= 0

61 μ

⎟⎟⎠

⎞⎜⎜⎝

⎛++=

s

ew

s

whl w

wdw

ddP ππ

μμ 1ln3

231 00

Page 23: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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End Leakage Permeance

g

sw ewew

sdwd

1N

2N

3N

4N5N

6N

7N

ww

iw

bw0N

wst ddw −=

bt

btbtww

bt

ebte

wwwwwwdw

wwwdwwP

+++

++

+=

)2(1)2(0

ww wdk 21 −=

⎪⎩

⎪⎨⎧

>=

www

www

wddwdw

k2

2

222

⎥⎥⎥⎥⎥

⎢⎢⎢⎢⎢

⎟⎟⎠

⎞⎜⎜⎝

⎛++−

+++

=

1

241

231

22

21

321

42

220

2 221ln168

2412

8)2(

kkkkk

kkkkk

dwwd

Pww

ee

μ

21 eee PPP +=

Page 24: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Nodal Equations

hlP

Ni1N

2N

3N

4N5N

6N

7N

2,1P

3,2P

4,3P

5,4P

6,5P

7,6P

vlP

0N

eP

1,0P

7,0P

3,6P

1,0Φ

2,1Φ

3,2Φ

5,4Φ

( ) ( ) 02,12111,01 =−++− PFFPFPNiF e

( ) ( ) ( ) 03,232722,112 =−+−+− PFFPFFPFF hl

( ) ( ) ( ) 03,2234,3433,663 =−+−+− PFFPFFPFF

( ) ( ) 05,4544,334 =−+− PFFPFF

( ) ( ) 06,5655,445 =−+− PFFPFF

( ) ( ) ( ) 03,6366,5567,676 =−+−+− PFFPFFPFF

( ) ( ) 07,667277,07 =−+−+ PFFPFFPF hl

Page 25: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Nodal Equations (Cont)

columnstPNiPF

11

1,0−=

⎥⎥⎥⎥⎥⎥⎥⎥⎥

⎢⎢⎢⎢⎢⎢⎢⎢⎢

++−−−++−−

−+−−+−

−−++−−−++−

−++

=

7,67,07,6

7,63,66,57,66,53,6

6,56,55,45,4

5,45,44,34,3

3,64,33,24,33,63,2

3,23,22,12,1

2,12,11,0

0000000

00000000000

00000000

PPPPPPPPPPP

PPPPPPPP

PPPPPPPPPPPP

PPPP

P

hlhl

hlhl

e

[ ] TFFFFFFFF =7654321

Page 26: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Fluxes

hlP

Ni1N

2N

3N

4N5N

6N

7N

2,1P

3,2P

4,3P

5,4P

6,5P

7,6P

vlP

0N

eP

1,0P

7,0P

3,6P

1,0Φ

2,1Φ

3,2Φ

5,4Φ

( )

7,077,0

7,6767,6

6,5656,5

5,4545,4

4,3434,3

3,232

2,1212,1

1,011,0

)()(

)()()()(

PFPFFPFFPFFPFFPFFPFFPFNi

−=Φ

−=Φ

−=Φ

−=Φ

−=Φ

−=Φ

−=Φ

2,3

Page 27: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Flux Densities

dwB

dwB

dwB

dwB

i

e

e

b

5,45,4

3,23,2

2,12,1

1,01,0

Φ=

Φ=

Φ=

Φ=

g

sw ewew

sdwd

1N

2N

3N

4N5N

6N

7N

ww

iw

bw0N

Page 28: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Force

( )( )

( )( ) ( )i

ie

ss

ss

i

ie

wggwdw

dwggdwd

wggdw

gdw

gP

gP

πμ

πμ

πμμ

+−

+−

+−−=

∂=

∂ 0,002

06,54,3 2,min44

min2

( )20

61

gddw

gP

s

wvl

+−=

∂∂ μ

Using co-energy techniques and assuming magnetic linearity it can be shown

Page 29: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Force (Cont.)

⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥

⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢

∂−

∂−

∂∂

∂−

∂−

=∂∂

0000000

00000

00000

00000

00000

00000000000000

6,56,5

6,56,5

4,34,3

4,34,3

gP

gP

gP

gP

gP

gP

gP

gP

gP

Page 30: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Force (Continued)

[ ] [ ]g

PNP

gPPPN

gL vl

∂∂

+∂∂

=∂∂ −− 2

column1st1

row1st 12

012

2

21 i

gLfe ∂

∂−=

Page 31: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Setting Up Constraints

Less than function

⎪⎪⎩

⎪⎪⎨

>

Δ−

+

=Δ maxmax

max

max xx

xxx

xx

xxxltne1

11

),,(

Page 32: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Setting Up Constraints

Greater than function

⎪⎪⎩

⎪⎪⎨

<

Δ−

+

=Δ minmin

min

min xx

xxx

xx

xxxgtne1

11

),,(

Page 33: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Geometrical Constraints

Recall, magnetic material should not overlap mass

)1.0,,2( max1 llwwltnec maxes +=

)1.0,,(2 maxmax lldltnec =

Page 34: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Electrical Constraints

Packing Factor

Current Density

Current

)1.0,,( ,,3 maxfmaxff pppltnec =

)1.0,,(4 maxmax Jjjltnec =

)1.0,,(5 maxmax iiiltnec =

Page 35: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Flux Density Constraints

Back of U-Core

Back of Legs

Front of Legs

I-Core

)01.0,,( 1,06 satsat BBBltnec =

)01.0,,( 2,17 satsat BBBltnec =

)01.0,,( 3,28 satsat BBBltnec =

)01.0,,( 5,49 satsat BBBltnec =

Page 36: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Force Constraints

We must lift mass (and I-core)

GwwdwMf mesireq ))2(( ρ++=

)01.0,,(10 reqreqe fffgtnec =

Page 37: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Performance Metrics

Total mass

( )( )( ) wwwbwwf

mibeses

wdwddwp

dwwwwdwdm

ρπ

ρ2

1

22

))(2(2

++

++++=

g

sw ewew

ww

sdwd

Depth intopage = d

iw

bw

Page 38: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Fitness Function

Combined constraint

Fitness Function

),,min( 1021 cccc L=

⎪⎪⎩

⎪⎪⎨

<−

=+=

∑=

110

11

10

1

1

cc

cm

ci

εf

Page 39: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Code Organization

Design CodesElectromagnet_Design.m

GOSETElectromagnet_Fitness.m

Electrical_Analysis.mMagnetic_Analysis.m

Page 40: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Code Organization (Cont)

Supporting RoutinesElectromagnet_Drawing1Electromagnet_Drawing2Electromagnet_Design_ReviewElectromagnet_Design_MultirunElectromagnet_Design_Multrun_Review

Page 41: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Electromagnet_Design.m (1/3)% Electromagnet Design%% Written by:% Ricky Chan for S.D. Sudhoff% School of Electrical and Computer Engineering% 1285 Electrical Engineering Building% West Lafayette, IN 47907-1285% E-mail: [email protected]

% Set Up PopulationGAP = gapdefault;GAP.fp_ngen = 2500;GAP.fp_ipop = 500;GAP.fp_npop = 500;GAP.mc_alg = 4.0;GAP.dt_alg = 3;

% Set Up MigrationsGAP.mg_nreg=5; % number of regionsGAP.mg_tmig=100; % mean time between migrationsGAP.mg_pmig=0.05; % probability of a individual migrating

% Unitsmm=1.0e-3;cm=1.0e-2;

Page 42: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Electromagnet_Design.m (2/3)% Problem Requirement Data Psi.M = 10; % Mass of object (Kg)Psi.G = 9.8; % Gravity (m/s2)Psi.g = 0.5*cm; % Gap Width (m)Psi.rhow = [ 8900; 2701]; % Wire - Kg/m3 Psi.sigmaw = [ 58.0; 35.4]*1e6; % Wire - A/OhmPsi.jmaxw = [ 7.62; 6.14]*1e6; % Wire - A/m2Psi.descw = ['Copper '; 'Aluminum']; % Wire - DescriptionPsi.bmaxm = [ 1.4; 0.7; 1.2]; % Steel - Bsat, TPsi.rhom = [7064.1; 8069.4; 7892.1]; % Steel - Density Kg/m3Psi.myum = [ 15000; 6000; 3500]; % Steel - Perm., (relative)Psi.descm = ['Microsil '; ...

'Superperm 80'; ...'Superperm 49']; % Steel - Description

Psi.imax = 6; % Maximum current, APsi.lmax = 10e-2; % Maximum lengthPsi.pfmax = 0.7; % Maximum packing factorPsi.vb = 12; % Battery VoltagePsi.rb = 0.5; % Battery Resistance

Page 43: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Electromagnet_Design.m (3/3)% Genetic Mapping% mw ac N mm ws rww ds rdw we rwi rwb dGAP.gd_min = [ 1 1e-8 10 1 1*cm 0.1 1*mm 0.1 1*mm 0.2 0.2 1*mm];GAP.gd_max = [ 2 1e-4 1e3 3 10*cm 1.0 20*cm 1.0 5*cm 2.0 2.0 10*cm];GAP.gd_type = [ 1 3 3 1 3 3 3 3 3 3 3 3 ];GAP.gd_cid = [ 1 1 1 1 1 1 1 1 1 1 1 1 ];

% Solve Problem[fP,GAS]= gaoptimize(@Electromagnet_Fitness,GAP,Psi,[],[],[]);

% Get Final Answer and Plotfinal_parameters = GAS.bestgenes(:,end);f = Electromagnet_Fitness(final_parameters,Psi,23);

% Save runs=input('Type 1 to Save Run ');if (s==1)

save samplerunend

Page 44: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Electromagnet_Fitness.m (1/7)function fitness = Electromagnet_Fitness(param,Psi,figNum)

% ELECTROMAGNET_FITNESS %% fitness = Electromagnet_Fitness(param,Psi,x)%% Inputs:% param = design parameters% Psi = data vectors% x = optional input to print out extra information%% Outputs:% fitness = fitness value%% Written by:% Ricky Chan for S.D. Sudhoff% School of Electrical and Computer Engineering% 1285 Electrical Engineering Building% West Lafayette, IN 47907-1285% E-mail: [email protected]

Page 45: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Electromagnet_Fitness.m (2/7)% Map to nicer variable namesmw = param(1);ac = param(2);N = round(param(3));mm = param(4);ws = param(5);rww = param(6);ds = param(7);rdw = param(8);we = param(9);rwi = param(10);rwb = param(11);d = param(12);

Page 46: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Electromagnet_Fitness.m (3/7)% Computing the width of winding (ww), depth of winding (dw), width of the% I core (wi), and the width of the back of the U core (wb)ww = rww*ws;dw = rdw*ds;wi = rwi*we;wb = rwb*we;

% Electrical Circuit Analysis[pf, j, i] = Electrical_Analysis(param,Psi);

% Magnetic Analysis[B01, B12, B23, B45, fe] = Magnetic_Analysis(param,Psi,i);

% Constraintslmax = Psi.lmax;pfmax = Psi.pfmax;jmaxw = Psi.jmaxw(mw);imax = Psi.imax;bmax = Psi.bmaxm(mm);rhom = Psi.rhom(mm);rhow = Psi.rhow(mw);

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Electromagnet_Fitness.m (4/7)c1 = ltne(ws+2*we,lmax,0.1*lmax);c2 = ltne(d,lmax,0.1*lmax);c3 = ltne(pf,pfmax,0.1*pfmax);c4 = ltne(j,jmaxw,0.1*jmaxw);c5 = ltne(i,imax,0.1*imax);c6 = ltne(B01,bmax,0.01*bmax);c7 = ltne(B12,bmax,0.01*bmax);c8 = ltne(B23,bmax,0.01*bmax);c9 = ltne(B45,bmax,0.01*bmax);f_req = (Psi.M + wi*d*(ws+2*we)*rhom)*Psi.G;c10 = gtne(fe,f_req,0.01*f_req);

% find the aggregrate constraintc = [c1 c2 c3 c4 c5 c6 c7 c8 c9 c10];cmin = min(c);

% design objectivem1 = (2*ds*we*d + (ws+2*we)*(wb+wi)*d)*rhom + ...

pf*(ww*dw*(2*d+2*wb)+pi*dw^2*ww)*rhow;

% compute the fitness if (cmin == 1)

fitness = 1/(m1+1e-6);else

fitness = sum(c)-length(c);end

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Electromagnet_Fitness.m (5/7)% if more than 3 arguments, plot the result% and write a reportif nargin >= 3

format short g

disp('Parameters'); disp(['Parameter 1: Wire type ',Psi.descw(mw,:)]);disp(['Parameter 2: Wire cross section is ', num2str(ac), ' m^2']);disp(['Parameter 3: Number of turns is ', num2str(N)]);disp(['Parameter 4: Magnetic material is ', Psi.descm(mm,:)]);disp(['Parameter 5: Slot width is ',num2str(ws*100),' cm']);disp(['Parameter 6: Winding width is ',num2str(rww*100),'% slot width']);disp(['Parameter 7: Slot depth is ',num2str(ds*100),' cm']);disp(['Parameter 8: Winding depth is ',num2str(rdw*100),'% slot depth']);disp(['Parameter 9: End width is ',num2str(we*100),' cm']);disp(['Parameter 10: I width is ',num2str(rwi*100),'% end width']);disp(['Parameter 11: Base width is ',num2str(rwb*100),'% end width']);disp(['Parameter 12: Depth is ',num2str(d*100),' cm']);disp(' ');

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disp('Constraints');disp(['Overall width is ',num2str(100*(ws+2*we)/lmax),'% allowed']);disp(['Overall depth is ',num2str(100*d/lmax),'% allowed']);disp(['Packing factors is ',num2str(100*pf/pfmax),'% allowed']);disp(['Current density is ',num2str(100*j/jmaxw),'% allowed']);disp(['Current is ',num2str(100*i/imax),'% allowed']);disp(['Back core flux density is ',num2str(100*B01/bmax),'% allowed']);disp(['Back end core flux density is ',num2str(100*B12/bmax),'% allowed']);disp(['Front end core flux density is ',num2str(100*B23/bmax),'% allowed']);disp(['I core flux density is ',num2str(100*B45/bmax),'% allowed']);disp(['Force required is ',num2str(f_req),' N']);disp(['Force produced is ',num2str(100*fe/f_req), '% required']);disp(' ');disp('Metrics');disp(['Mass is ',num2str(m1),' Kg']);

figure(figNum);clf;Electromagnet_Drawing1(param,Psi);figure(figNum+1)Electromagnet_Drawing2(param,Psi);

end

Electromagnet_Fitness.m (6/7)

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Electromagnet_Fitness.m (7/7)function p = ltne(x,xmax,delta)

if x <= xmaxp = 1;

elsep = 1./(1+abs((xmax-x)./delta));

end

function p = gtne(x,xmin,delta)

if x >= xminp = 1;

elsep = 1./(1+abs((xmin-x)./delta));

end

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Sample Evolution

1 2 3 4 5 6 7 8 9 10 11 120

0.5

1

Parameter Number

Nor

mal

ized

Val

ue

500 1000 1500 2000 2500-6

-4

-2

0

2

f:B(b

) Md(

g) M

n(r)

Generation

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Evolution – Best Fit Individual

(Matlab Demo)

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ParametersParameter 1: Wire type Copper Parameter 2: Wire cross section is 7.8519e-007 m^2Parameter 3: Number of turns is 585Parameter 4: Magnetic material is MicrosilParameter 5: Slot width is 7.1906 cmParameter 6: Winding width is 97.7656% slot widthParameter 7: Slot depth is 0.96031 cmParameter 8: Winding depth is 97.8117% slot depthParameter 9: End width is 1.2104 cmParameter 10: I width is 49.2545% end widthParameter 11: Base width is 52.2008% end widthParameter 12: Depth is 3.7947 cm

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ConstraintsOverall width is 96.1141% allowedOverall depth is 37.9474% allowedPacking factors is 99.3753% allowedCurrent density is 99.4713% allowedCurrent is 99.1917% allowedBack core flux density is 99.442% allowedBack end core flux density is 50.9116% allowedFront end core flux density is 49.215% allowedI core flux density is 99.6887% allowedForce required is 99.5053 NForce produced is 100.3524% required

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Metrics

Mass is 0.86127 Kg

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-0.1 -0.05 0 0.05 0.1

-0.15

-0.1

-0.05

0

0.05

0.1

0.15

-0.1 -0.05 0 0.05 0.1

-0.15

-0.1

-0.05

0

0.05

0.1

0.15Profile View

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3-D View

-0.02

0

0.02

-0.050

0.05

-0.015

-0.01

-0.005

0

0.005

0.01

0.015

0.02

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Design RepeatabilityRepeat design 25 times:

0100.00100.00mn

3.48106.1693.95N

1.46102.0595.26aw

0100.00100.00mw

Std/MnMax/MnMin/MnParameter

Page 59: Lecture 8: A Design Example - An Electromagnetsudhoff/ee630/Lecture08.pdf · A Design Example - An Electromagnet. 2 Objective Use a genetic algorithm to solve an engineering design

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Design Repeatability

1.46101.9496.46rdw

4.07105.8692.18ds

0.57100.7297.93rww

5.06110.0188.44ws

Std/MnMax/MnMin/MnParameter

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Design Repeatability

5.93109.8288.55we

1.09102.0097.55Fitness

9.02118.9183.18d

5.17108.7889.55rwb

5.06109.2690.00rwi

Std/MnMax/MnMin/MnParameter