LAB1 final
-
Upload
rohan-kataria -
Category
Documents
-
view
37 -
download
1
Transcript of LAB1 final
![Page 1: LAB1 final](https://reader036.fdocuments.net/reader036/viewer/2022082804/5472ac4eb4af9f6a7d8b466e/html5/thumbnails/1.jpg)
SIGNALSAND
SYSTEMS LAB
Submitted by:
Aakanksha Bansal(09103410)
Ashima Agrawal(09103408)
Batch:B1
EXPERIMENT-1
![Page 2: LAB1 final](https://reader036.fdocuments.net/reader036/viewer/2022082804/5472ac4eb4af9f6a7d8b466e/html5/thumbnails/2.jpg)
Aim: Introduction to MATLAB and its various applications.
Theory : Z = trapz(Y) computes an approximation of the integral of Y via the trapezoidal method (with unit spacing). To compute the integral for spacing other than one, multiply Z by the spacing increment. Input Y can be complex.
The linspace function generates linearly spaced vectors. It is similar to the colon operator ":", but gives direct control over the number of points.
y = linspace(a,b) generates a row vector y of 100 points linearly spaced between and including a and b.
y = linspace(a,b,n) generates a row vector y of n points linearly spaced between and including a and b. For n < 2, linspace returns b.
POST LAB - EXCERCISESQ1).Scalar variables. Make the following variablesa. a = 10b. b = 2.5 ×10 23
c. c = 2 + 3i , where i is the imaginary number
![Page 3: LAB1 final](https://reader036.fdocuments.net/reader036/viewer/2022082804/5472ac4eb4af9f6a7d8b466e/html5/thumbnails/3.jpg)
d. d = ej 2π /3 , where j is the imaginary number and e is Euler’s number (use exp, pi)Ans:a = 10;b = 2.5*10^23;c = 2+3i;d=exp(j*2*pi/3);
Q2). Vector variables.Make the following variables
Ans:aVec = [3.14 15 9 26];bVec = [2.71;8;28;182];cVec = [5 :-0.2 :-5];dVec = logspace(0,1,100);eVec = ['hello'];
Q3).Matrix variables.Make the following variables
![Page 4: LAB1 final](https://reader036.fdocuments.net/reader036/viewer/2022082804/5472ac4eb4af9f6a7d8b466e/html5/thumbnails/4.jpg)
Ans)3(a)
mat1=ones(9,9)mat1 = 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
>>amat = amat=2.*mat1amat =
2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2
![Page 5: LAB1 final](https://reader036.fdocuments.net/reader036/viewer/2022082804/5472ac4eb4af9f6a7d8b466e/html5/thumbnails/5.jpg)
2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2
3(b)v=[1,2,3,4,5,4,3,2,1]bmat=zeros(9,9)bmat=diag(v,0)
b=
1 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0 0 3 0 0 0 0 0 0 0 0 0 4 0 0 0 0 0 0 0 0 0 5 0 0 0 0 0 0 0 0 0 4 0 0 0 0 0 0 0 0 0 3 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0 0 1
3(c)incr = 1:1:100;cmat=reshape(incr,10,10)cmat = reshape(x,10,10);>>cmat = reshape(x,10,10)
cmat = 1 11 21 31 41 51 61 71 81 91 2 12 22 32 42 52 62 72 82 92 3 13 23 33 43 53 63 73 83 93 4 14 24 34 44 54 64 74 84 94 5 15 25 35 45 55 65 75 85 95 6 16 26 36 46 56 66 76 86 96 7 17 27 37 47 57 67 77 87 97 8 18 28 38 48 58 68 78 88 98 9 19 29 39 49 59 69 79 89 99 10 20 30 40 50 60 70 80 90 100
3(d)mat3=ones(3,4)dmat=mat3.*NaNdmat=
![Page 6: LAB1 final](https://reader036.fdocuments.net/reader036/viewer/2022082804/5472ac4eb4af9f6a7d8b466e/html5/thumbnails/6.jpg)
NaNNaNNaNNaNNaNNaNNaNNaNNaNNaNNaNNaN
3(e)emat = [13 -1 -5; -22 10 -87];emat =
13 -1 -5 -22 10 -87
3(f)fmat = ceil(-3 + 6.*rand(5,3));fmat =
0 0 -1 -1 2 2 -1 1 2 1 1 0 0 3 1
Q4).Common functions and indexing.
Ans)4(a)cSum =sum(cmat);
4(b)cMean =mean(cmat);
4(c)
![Page 7: LAB1 final](https://reader036.fdocuments.net/reader036/viewer/2022082804/5472ac4eb4af9f6a7d8b466e/html5/thumbnails/7.jpg)
emat(1,:) = [1 1 1];
4(d)cSub = cmat(2:9,2:9)
4(e)lin = 1:1:20;for j=1:20if(mod(lin(j),2)==0)lin(j)=-j;end;end;
4(f)r=rand(1,5)
a=find(r<0.5)r(a)=0
Q5)Plotting multiple lines and colors.Open a script and name it twoLinePlot.mTo plot a sine wave and a cosine wave over one period(a) Make a time vector t from 0 to 2ð with enough samples to get smooth lines, Plot sin t.(b) Use hold on.(c) Plot cos t using a red dashed line.(d) Add labels to the plot and create a legend to describe the two lines you have plotted byusinglegend.(e) Use xlimto set the x axis to be from 0 to 2ð and use ylimto set the y axis to be from -1.4 to 1.4.
Ans)t = linspace (0, 2*pi ,1000);plot (t,sin(t));hold on;plot (t,cos(t),'--r');p =plot (t,sin(t));q =plot (t,cos(t),'--r');
![Page 8: LAB1 final](https://reader036.fdocuments.net/reader036/viewer/2022082804/5472ac4eb4af9f6a7d8b466e/html5/thumbnails/8.jpg)
legend (p,'sinwave','location','North');legend (q,'coswave','location','South');xlim([0 2*pi]);ylim([-1.4 1.4]);
Q6)Plot a circle. Write the function [x, y] = getCircle (center,r) to get the x and ycoordinates of a circle. The circle should be centered at center (2-element vector containing the x and y values of the center) and have radius r. Return x and y such that plot(x, y) will plot the circle.
t = linspace(0,2*pi,1000); a = input('enter the x coord of the centre');b = input('enter the y coord of the centre');c= input('enter the radius of the circle');x = r*cos(t)+a; y = r*sin(t)+b; plot(x,y);
![Page 9: LAB1 final](https://reader036.fdocuments.net/reader036/viewer/2022082804/5472ac4eb4af9f6a7d8b466e/html5/thumbnails/9.jpg)
7. Loops and flow control. Make function called loopTest(N) that loops through thevalues 1 through N and for each number n it should display ‘n is divisible by 2’, ‘n isdivisible by 3’, ‘n is divisible by 2 AND 3’ or ‘n is NOT divisible by 2 or 3’. Use a forloop, the function mod or rem to figure out if a number is divisible by 2 or 3, and num2strto convert each number to a string for displaying. You can use any combination of if, else,andelseif.
Ans)
p=input('enter max no');
for j=1:p
if (mod(j,3)==0 && mod(j,2)==0)
disp('num div by both');
![Page 10: LAB1 final](https://reader036.fdocuments.net/reader036/viewer/2022082804/5472ac4eb4af9f6a7d8b466e/html5/thumbnails/10.jpg)
disp(j);
elseif(mod(j,3)==0)
disp('div by 3');
disp(j);
else if(mod(j,2)==0)
disp('div by 2');
disp(j);
else
disp('div by none');
disp(j);
end;
end;
end;
Q8)
Linear system of equations.Solve the following system of equations:
3a + 6b + 4c = 1. a + 5b = 2. 7b + 7c = 3Ans)A=[3,6,4;1,5,0;0,7,7]b=[1;2;3]x=A\bx = -0.5824 0.5165 -0.0879
Q9)Numerical integration.Use trapzor quad. What is the value of :Compute and display the difference between your numerical answer and the analytical answer: −24 e−5/3+ 9
Ans)x = 0:0.01:5;y=x.*exp(-x*1/3)
![Page 11: LAB1 final](https://reader036.fdocuments.net/reader036/viewer/2022082804/5472ac4eb4af9f6a7d8b466e/html5/thumbnails/11.jpg)
z=trapz(x,y)w=4.3736difference=w-zdiff = 0.0934
Q10)Practice with cells.Usually, cells are most useful for storing strings, because thelength of each string can be unique. a. Make a 3x3 cell where the first column contains the names: ‘Joe’, ’Sarah’, and ’Pat’, the second column contains their last names: ‘Smith’,‘Brown’, ‘Jackson’, and the third column contains their salaries: $30,000, $150,000, and $120,000. Display the cell using disp.
Ans)
z=cell(3)z(1,:)={'joe','smith','$30000'}z(2,:)={'sarah','brown','$150000'}z(3,:)={'pat','jackson','$120000'}disp(z)
LEARNING OUTCOME
1. Creating a file and saving to the directory.2. Working with matrix of size of mxn and using the dot operator.3. Using various predefined mathematical operators