Jawab mektek.pdf
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Jawab : F Ay A F Ax 60ᵒ 75ᵒ 45ᵒ 90ᵒ 60ᵒ B 45ᵒ 15ᵒ C W Joint A F Ay F Ax B C F C x ∑M A = = F Cx . AC cos 30ᵒ = F Cx . Cx . 2W = 3 F Cx Cx F Ax = F Cx F Ay = W F AB cos 45ᵒ + F AC cos 60ᵒ = F AX F AB + F AC =F AX F AB +F AC = 2 F AX F AY = F AC - F AB
Transcript of Jawab mektek.pdf
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Jawab :
FAy
A
FAx 60 75 45
90
60 B
45 15
C W
Joint A
FAy
FAx
B
C
FC
x
MA =
= FCx . AC cos 30
= FCx .
Cx .
2W = 3 FCx
Cx
FAx = FCx
FAy = W
FAB cos 45 + FAC cos 60 = FAX
FAB +
FAC =FAX
FAB +FAC = 2 FAX
FAY =
FAC -
FAB
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Joint C A
45 B
FCX
C
FCX + FAC cos 60 = FCB cos 15
FCX +
FAC = 0.96 FCB
FAC sin 60 = FCB Sin 15
FAC = 0.26 FBC
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