Introductory maths analysis chapter 10 official
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INTRODUCTORY MATHEMATICAL INTRODUCTORY MATHEMATICAL ANALYSISANALYSISFor Business, Economics, and the Life and Social Sciences
2007 Pearson Education Asia
Chapter 10 Chapter 10 Limits and ContinuityLimits and Continuity
2007 Pearson Education Asia
INTRODUCTORY MATHEMATICAL ANALYSIS
0. Review of Algebra
1. Applications and More Algebra
2. Functions and Graphs
3. Lines, Parabolas, and Systems
4. Exponential and Logarithmic Functions
5. Mathematics of Finance
6. Matrix Algebra
7. Linear Programming
8. Introduction to Probability and Statistics
2007 Pearson Education Asia
9. Additional Topics in Probability
10. Limits and Continuity
11. Differentiation
12. Additional Differentiation Topics
13. Curve Sketching
14. Integration
15. Methods and Applications of Integration
16. Continuous Random Variables
17. Multivariable Calculus
INTRODUCTORY MATHEMATICAL ANALYSIS
2007 Pearson Education Asia
• To study limits and their basic properties.
• To study one-sided limits, infinite limits, and limits at infinity.
• To study continuity and to find points of discontinuity for a function.
• To develop techniques for solving nonlinear inequalities.
Chapter 10: Limits and Continuity
Chapter ObjectivesChapter Objectives
2007 Pearson Education Asia
Limits
Limits (Continued)
Continuity
Continuity Applied to Inequalities
10.1)
10.2)
10.3)
Chapter 10: Limits and Continuity
Chapter OutlineChapter Outline
10.4)
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.1 Limits10.1 Limits
Example 1 – Estimating a Limit from a Graph
• The limit of f(x) as x approaches a is the number L, written as
a. Estimate limx→1 f (x) from the graph.
Solution:
b. Estimate limx→1 f (x) from the graph.
Solution:
Lxfax
lim
2lim1
xfx
2lim1
xfx
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.1 Limits
Properties of Limits
1.
2. for any positive integer n
3.
4.
5.
constant a is wherelimlim cccxfaxax
nn
axax
lim
xgxfxgxfaxaxax
limlimlim
xgxfxgxfaxaxax
limlimlim
xfcxcfaxax
limlim
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.1 Limits
Example 3 – Applying Limit Properties 1 and 2
Properties of Limits
162lim c.
366lim b.
77lim ;77lim a.
44
2
22
6
52
t
x
t
x
xx
0lim if
lim
limlim 6.
xg
xg
xf
xg
xfax
ax
ax
ax
nax
n
axxfxf
limlim 7.
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.1 Limits
Example 5 – Limit of a Polynomial Function
Find an expression for the polynomial function,
Solution:
where
011
1 ... cxcxcxcxf nn
nn
af
cacacac
ccxcxc
cxcxcxcxf
nn
nn
axax
n
axn
n
axn
nn
nn
axax
011
1
011
1
011
1
...
lim lim...limlim
...limlim
afxfax
lim
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.1 Limits
Example 7 – Finding a Limit
Example 9 – Finding a Limit
Find .
Solution:
If ,find .Solution:
1
1lim
2
1
x
xx
2111lim1
1lim
1
2
1
x
x
xxx
12 xxf
h
xfhxfh
0
lim
xhxh
xhxhx
h
xfhxf
h
hh
22lim
112limlim
0
222
00
Limits and Algebraic Manipulation
• If f (x) = g(x) for all x a, then xgxf
axax limlim
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.2 Limits (Continued)10.2 Limits (Continued)
Example 1 – Infinite Limits
Infinite Limits
• Infinite limits are written as and .
Find the limit (if it exists).
Solution:
a. The results are becoming arbitrarily large. The limit
does not exist.
b. The results are becoming arbitrarily large. The limit
does not exist.
xx
1lim
0
xx
1lim
0
1
2lim a.
1 xx 4
2lim b.
22
x
xx
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.2 Limits (Continued)
Example 3 – Limits at Infinity
Find the limit (if it exists).
Solution:
a. b.
35
4lim a.
xx
0
5
4lim
3
xx
xx
4lim b.
xx
4lim
Limits at Infinity for Rational Functions
• If f (x) is a rational function,
and m
m
nn
xx xb
xaxf
limlim
mm
nn
xx xb
xaxf
limlim
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.2 Limits (Continued)
Example 5 – Limits at Infinity for Polynomial Functions
Find the limit (if it exists).
Solution:
Solution:
33 2lim92lim xxxxx
323 lim2lim xxxxxx
33 2lim92lim b. xxxxx
323 lim2lim a. xxxxxx
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.3 Continuity10.3 Continuity
Example 1 – Applying the Definition of Continuity
Definition• f(x) is continuous if three conditions are met:
a. Show that f(x) = 5 is continuous at 7.
Solution: Since , .
b. Show that g(x) = x2 − 3 is continuous at −4.
Solution:
afxf
xf
xf
ax
ax
lim 3.
exists lim 2.
exists 1.
55limlim77
xx
xf 75lim7
fxfx
43limlim 2
44
gxxg
xx
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.3 Continuity
Example 3 – Discontinuitiesa. When does a function have infinite discontinuity?
Solution: A function has infinite discontinuity at a when at least one of the one-sided limits is either ∞ or −∞ as x →a.
b. Find discontinuity for
Solution:
f is defined at x = 0 but limx→0 f (x) does not exist. f is discontinuous at 0.
0 if 1
0 if 0
0 if 1
x
x
x
xf
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.3 Continuity
Example 5 – Locating Discontinuities in Case-Defined Functions
For each of the following functions, find all points of discontinuity.
3 if
3 if 6 a.
2 xx
xxxf
2 if
2 if 2 b.
2 xx
xxxf
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.3 Continuity
Example 5 – Locating Discontinuities in Case-Defined Functions
Solution:
a. We know that f(3) = 3 + 6 = 9. Because
and , the function has no points of discontinuity.
96limlim33
xxfxx
9limlim 2
33
xxf
xx
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.3 Continuity
Example 5 – Locating Discontinuities in Case-Defined Functions
Solution:b. It is discontinuous at 2,
limx→2 f (x) exists.
xfxxxfxxxx
22
2
22lim2lim4limlim
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.4 Continuity Applied to Inequalities10.4 Continuity Applied to InequalitiesExample 1 – Solving a Quadratic Inequality
Solve .
Solution: Let .
To find the real zeros of f,
Therefore, x2 − 3x − 10 > 0 on (−∞,−2) (5,∞).
01032 xx
1032 xxxf
5 ,2
052
01032
x
xx
xx
2007 Pearson Education Asia
Chapter 10: Limits and Continuity
10.4 Continuity Applied to Inequalities
Example 3 – Solving a Rational Function Inequality
Solve .
Solution: Let .
The zeros are 1 and 5.
Consider the intervals: (−∞, 0) (0, 1) (1, 5) (5,∞)
Thus, f(x) ≥ 0 on (0, 1] and [5,∞).
0562
x
xx
x
xx
x
xxxf
51562