Gas vapor 760 mmHg V1= 500 mL V2= 425 mL Question: P2=? 08/03/2018 Nur Istianah-KP1-gas vapor-2016...

Gas – vapor

Nur Istianah, ST.,MT.,M.Eng

08/03/2018 Nur Istianah-KP1-gas vapor-2016


Statement of gas behavior

Boyle’s Law

2211 VPVP

P

kV

Charles’s Law

1221 TVTV

kT

V

Gay Lussac’s Law

1221 TPTP

kT

P

Ideal gas Law

nRTPV



Example:

The 500 mL of Oxygen was compressed at 760

mmHg until reached the volume of 425 mL. How was

the pressure of oxygen after the compression?

Known parameters:

P1= 760 mmHg

V1= 500 mL

V2= 425 mL

Question: P2=?



Task 1:

What should we do to have 300 mL of oxygen at

20ºC if we just have 250 of oxygen ? (assumption:

constant pressure and constant mass)

Known parameters:

V1 = 300 mL

T1 = 20+273 = 293K

V2 = 250 mL

Equation used: V1/T1 = V2/T2

Question: T2?



Thus, we should to raise up the oxygen until 29°C



Task 2:

The amount of 50 L nitrogen was in a hard container at

101 kPa, 25ºC. How would the pressure of cotainer if it

was heated until 150ºC?

Known parameters:

P1= 101 kPa

T1= 25+273 = 298 K

T2= 150+273 = 423 K

Question: P2?


Exercise 1

There was 50 dm3 of oxygen at 27º C

and 35 atm. How much ? R=0.082

L.atm/mol.K


Exercise 2

The 5 mol of gas was placed in a

chamber with volume 40 L. It was in

20ºC memiliki tekanan 3 atm. Berapa

tekanan 20 mol gas tersebut jika

berada dalam tangki yang volumenya

100 lt dan suhu 87ºC?


Vapor-liquid equilibrium (VLE)

1. Phase rule and Raoult’s law

Av

AA

BA

BA

Pxp

yy

xx

1

1

x = fraksi liquid

y = fraksi vapor

pA = partial pressure A (atm)

PvA = vapor pressure pure A (atm)

P

xP

P

py

PxPxP

PxPxP

Ppp

AAv

AA

ABv

AAv

BBv

AAv

BA

)1(.

..



2. Boiling-point diagram and xy plots



Example

Calculate the vapor dan liquid compposition of

benzene(A) – toluene(B) that was in

equilibrium state at 95°C, 1atm(101.32 kPa).

Vapor pressure of benzene and toluene are

155.7 kPa dan 63.3 kPa.



Penyelesaian

PxPxP ABv

AAv )1(.

155.7 (xA) + 63.3 - 63.3(xA) = 101.32

xA = 0.411 xB = 0.589

368.0

632.0

B

AAv

A

y

P

xPy


How was the total pressure of the mix of water-

benzene for every temperature below if the

liquid fraction of benzene is 0.4?

Exercise



Solution:

Water (A), benzene (B):

xB = 0.4, xA = 1-0.4=0.6

Contoh pada suhu 35.3C:

PxPxP BB

v

AAv ..

kPaP

P

8.85

)4.0(150)6.0(43

Latihan soal


The data of hexane-octane vapor pressure was given as

below:

(a) Menggunakan Hukum Raoult, hitung komposisi liqud-

vapor dari hexane(A) dan octane(B) pada tekanan

total 101.3 kPa



For example at 68.7°C, (total pressure= 101.3 kPa)

PxPxP AB

v

AAv )1(.

0,13.101

)3.101(1

0,1

)1.163.101())(1.163.101(

3.101)1(1.16)(3.101

B

Av

AA

BA

A

AA

yP

Pxy

xx

x

xx

THANKS FOR YOUR

ATTENTION

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Gas vapor 760 mmHg V1= 500 mL V2= 425 mL Question: P2=? 08/03/2018 Nur Istianah-KP1-gas vapor-2016...

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