electrical machines -1 lab

5/28/2018 electrical machines -1 lab

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Electrical Machines-I Lab

EEE Department,GIST-Jaggayyapet Page 1

S.No. Name of the Experiment Page.No

1 MAGNETIZATION CHARACTERISTICS OF A DC

SHUNT GENERATOR

2

2 LOAD TEST ON DC SHUNT GENERATOR 6

3 LOAD TEST ON DC COMPOUND GENERATOR 10

4 BRAKE TEST ON DC SHUNT MOTOR 14

5 SWINBURNES TEST ON A DC SHUNT MACHINE 18

6 LOAD TEST ON DC SERIES GENERATOR 22

7 HOPKINSONS TEST ON DC SHUNT MACHINE 26

8 FIELDS TEST ON DC SERIES MACHINES 31

9 SPEED CONTROL OF DC SHUNT MOTOR 36

10 SEPERATION OF LOSSES IN DC SHUNT MOTOR 41

11 BRAKE TEST ON DC COMPOUND MOTOR 45

12 RETARDATION TEST ON DC SHUNT MOTOR 50


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1.MAGNETISATION CHARACTERISTICS OF AD.C SHUNTGENERATOR.

AIM:

To find the magnetization characteristics of a D.C shunt generator.

To find the critical field resistance and critical speed.

NAMEPLATE DETAILS:

MOTOR GENERATOR

Power3.7kw 3.7kw

Wound Shunt ShuntArmature voltage 220V. 220V.

Armature current 20 A 17A

Excitation 220V, 0.9A 220V, 0.9A

Speed 1500. 1500.

APPARATUS:

Name Type Range QtyVoltmeter M.C 0-300V 2

Ammeter M.C 0-1A 1

Rheostat___

0-300 , 1.7A 1

0-1500 , 1A 1

Tachometer --- 1


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CIRCUIT DIAGRAM:

THEORY:The magnetization characteristics of D.C. shunt generator shows the relationship

between the no-load generated emf in armature (E0) and field current (If) at any constantspeed. Due to residual magnetism in the poles, some emf is produced initially. The current

while passing through the field coils will strengthen the magnetism of the poles. This willincrease the pole flux with further increase the generated emf. Increased emf means morecurrent which further increase the flux so on. If field resistance is increased the slope ofthe resistance line increased and hence maximum voltage will build up at the generator ata given speed. If the resistance line just lies along the slope then with that value of thefield resistance, the machine will just excite. the value of the resistance represented by thetangent to the curve is known as critical resistance for a given speed.

PROCEDURE:1. Connect the circuit as per the circuit diagram.2. Keep the motor field rheostat at minimum position and generator field

rheostat at maximum position.3. Start the motor with the help of 3- point starter and adjust the motor field

rheostat till the motor reaches to its rated speed.4. Gradually increases the field current of generator by minimize the generator

field rheostat resistance.5. Note the terminal voltage (V) of generator at various field currents (If). Till

the generator attains its rated voltage.


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6. The relationship between no load voltage (V) and field current (If) gives theopen circuit characteristics (OCC).

7. Draw the graph (OCC) between terminal voltage (V) and field current (I f) tofind out the critical field resistance and critical sped.

TABULATION:

S.noField current

If(A)Voltage

(V)

MODEL GRAPH:

V

Voltage

Field current If


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PRECAUTIONS:1. Loose connection should be avoided.2. Operate the 3- point starter carefully.3. Proper rating meters should be used.4.

Run the motor rated speed.5. Check the connections before giving supply.

RESULT:Magnetization characteristics of D.C shunt generator is observed and plotted

VIVA QUESTIONS:

1. What is the purpose of plotting the magnetization curve?2. What is meant by the term critical field resistance related to DC shunt generator?3. What are the conditions to be fulfilled for the shunt generator to build up voltage?4. Why does saturation curve starts from some value higher than zero?5. What is the type of voltage induced in the armature of a DC generator?


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2. LOAD TEST ON D.C SHUNT GENERATOR

AIM:To determine the internal and external load characteristics of a D.C shunt

Generator.

NAMEPLATE DETAILS:MOTOR GENERATOR

Power5hp 5hp

Wound Shunt Shunt

Armature voltage 220V. 220V.

Armature current 20A 13.6A

Excitation 220V, 0.75A 220V,Speed 1500. 1500.

APPARATUS:

Name Type Range Qty

Voltmeter M.C 0-300V1

Ammeter M.C 0-10A,0-1A 2

Rheostat___

0-300 , 1.7A 1

0-570, 1.2A 1

Tachometer ---1

Load Resistive 5kw1


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CIRCUITDIAGRAM:

THEORY:For a generator the induced emf is equal to the terminal voltage when the generator

is not loaded. When the generator is loaded there is a fall in terminal voltage. The fall in

terminal voltage of dc shunt generator is due to IaRa drop in the armature, the effect ofarmature reaction and brush contact resistance these causes reduce the voltage across thefield terminals of the dc generator. Thus the field current and hence the induced emf isreduced which results in further reduction of the terminal voltage. The externalcharacteristics of a dc shunt generator are more drooping.

PROCEDURE:1. Connect the circuit as per the circuit diagram.2. Keep the motor field rheostat at minimum position and generator field rheostat

at maximum position.3. Start the motor with the help of 3- point starter and adjust the motor field rheostat

till the motor reaches to its rated speed. Now close the generator switch and adjustthe field rheostat of the generator till it reaches to its rated voltage.

4. Connect the load in step-by-step and each step note the load current andterminal voltage of the generator.

5. Maintain load current will note exceed rated current.6. After note the readings first switch off the generator load and than switch off themotor supply.


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TABULAR FORM:

S.NO Voltage(V)

Loadcurrent

IL(A)

Fieldcurrent

If(A)

ArmatureCurrent

Ia(A)

ArmatureVoltage

Eg(v)

GeneratorTerminal

Voltage V

PRECAUTIONS:1. Loose connection should be avoided.2. Operate the 3- point starter carefully.3. Loads should not be exceeding beyond their ratio

MODEL GRAPHInternal characteristics:

Eg

IaARMATURE CURRENT

ARMATU

REVOLVOLTAGE


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External characteristics:

Vt

ILLOAD CURRENTRESULT:

Hence the internal and external load characteristics of a D.C shunt Generator areobtained and plotted.

VIVA QUESTIONS:

1. What are the reasons for the drop in terminal voltage of a shunt generator when it isloaded?

2. What is internal or total characteristic of a DC generator?3. What should be done if the DC shunt generator fails to build up? 4. What is armature reaction?

TERMINALVOLTAGE


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3.LOAD TEST ON D.C COMPOUND GENERATOR

AIM:To determine the internal and external load characteristics of a D.C compound

Generator.


Power5hp 5hp

Wound Shunt Compound



Excitation 220V, 0.75A 220V,

Speed 1500. 1500.

APPARATUS:

Name Type Range Qty


Ammeter M.C0-15A 1

Rheostat___

0-300 , 1.7A 1

0-570, 1.2A 1

Tachometer ---1

Load Resistive 5kw1


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CIRCUITDIAGRAM:

THEORY:In a dc compound machine both the series, and the shunt field coils are present.

While shunt field is the main field, series field either it or opposes. The first type is knownas cumulative compounding whiles the other as differential compounding .Cumulatively compounded D.C. generator:

The voltage drop in armature resistance and the drop due to armature reactiontake place in this case also, but they are compensated by the increase in the flux due tothe mmf established by series winding carrying the load current, depending on the degreeof compensation.Differentially compounded D.C. generator:

The terminal voltage drops due to the following reasons in this case: (1)armature resistance drop; (2) armature reaction effect (3) reduction in flux per pole due tothe series winding m.m.f opposing the shunt winding mmf.(4) reduction in shunt fieldcurrent due to reduction inarmature voltage.

PROCEDURE:1. Connect the circuit as per the circuit diagram.2. Keep the motor field rheostat at minimum position and generator field rheostat at

maximum position.3. Start the rheostat till the motor reaches to its rated speed. Motor with the help of 3-

point starter and adjust the motor field4. Now adjust the field rheostat of the generator till it reaches to its rated voltage.5. Connect the load in step-by-step and each step note the load current (IL), field current

(If) and terminal voltage (V) of the shunt generator.6. Maintain load current will note exceed rated current.


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7.After note the readings first switch off the generator load and then switch off themotor supply.

TABULATION:

S.NO Voltage (V) Load

current,

IL(A)

Field

current

If(A)

Armature

current

Ia=IL+If(A)

Armature

Voltage

Eg=V+IaRa

MODEL GRAPH:

Internal characteristics:

Eg

IaARMATURE CURRENT

ARMATURE

VOLVOLTAGE


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Vt

PRECAUTIONS:1. Loose connection should be avoided.2. Operate the 3- point starter carefully.3. Loads should not be exceeding beyond their rating.

RESULT:

Hence the internal and external load characteristics of a D.C compoundGenerator are obtained and plotted.

VIVA QUESTIONS:1. What is external characteristic of dc generator?2. What is the function of commutator in a DC generator?3. Mention the difference between cumulative and differential compound DC

generators?4. Can you measure the induced voltage under load condition for a DC generator?

Why?5. Do you require a starter for a DC motor under the running condition, why?

TERMINALVOLTAGE


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4.BRAKE TEST ON D.C SHUNT MOTOR

AIM:To find the efficiency of D.C shunt motor by a direct load test.

NAMEPLATE DETAILS:D.C SHUNT MOTOR

Power5hp

Wound Shunt

Armature voltage 220V.

Armature current 20A

Excitation 220V, 0.75A

Speed 1500.APPARATUS:

NameType Range Qty


Ammeter M.C0-20A 1

Rheostat___

0-300 , 1.7A1

Tachometer ---1

CIRCUIT DIAGRAM:


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THEORY:It is a direct method and consists of applying a brake to a water cooled pulley

mounted on the shaft of motor. The brake band is fixed with the help of wooden blocksgripping the pulley one end of the band is fixed to earth a spring balance and other is

connected to a suspended weight. The motor is running and the load on the motor isadjusted till it carries its full load current. The simple brake test described above can beused for small motors only. Because, in the case of large motors, it is difficult to dissipatethe large amount of heat generated at the brake.

PROCEDURE:1.Connect the circuit as per the circuit diagram.2.Keep the motor field rheostat at minimum position.3.Start the motor with the help of 3- point starter and Adjust the motor field

rheostat till the motor reaches To its rated speed.

4.Now gradually apply the mechanical load by tightening the Belt over the shaft.5.Note the corresponding spring balance readings, line current, Voltage and speed at

particular load.6.Repent the above process at different load condition.7.Before the motor going to be switched off the motor must be in no load condition.8.Using the above data determine the efficiency of the compound motor.

CALCULATIONS:

Shaft torque = (S1-S2) x rx 9.81 (r = 0.1 m)= (2N) /60.

Shaft O/P = Shaft Torque X

Efficiency= = X100

TABULAR FORM:

S.NOVoltage

(V)Line

current(A)S1(kg) S2(kg) Speed(rpm) INPUT

VI(W)ShaftTorque

(N-M)

rad/sec

Shaft

Output

(W)

Efficie

%

Shaft O/PPower I/P


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GRAPHS:Graphs are plotted between1. Speed and output2. Speed and torque3. Current and torque

4. Efficiency and out put

MODEL GRAPH:

N N IL % O/PVs %

TVSIL

TVSN

ILVSN

Output(W)

Torque(N-m)

Torque(N-m)IL(A)

PRECAUTIONS:1. Loose connection should be avoided.2. Operate the 3- point starter carefully.3. Cool the shaft pulley with water.4. Proper rating meters should be used.5. Check the connections before giving supply.


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RESULT:Hence the efficiency of the D.C shunt motor at various load conditions

are calculated and plotted.

VIVA QUESTIONS:1. What is back EMF?2. How can the direction of rotation be reversed in a DC motor?3. Do you require a starter for a DC motor under the running condition, why?4. Why does the speed fall slightly when the DC shunt motor is loaded?5. What happens if the field circuit of a DC motor is opened under running condition?


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5.SWINBURNES TEST ON D.C SHUNT MACHINE

AIM:To predetermine the efficiency of D.C shunt machine by conducting No load test.


Power5hp

Wound Shunt




Speed 1500.

APPARATUS:

Name Type Range Qty


Ammeter M.C0-5A

1

0-1A 1

Rheostat___

0-300 , 1.7A1

Tachometer ---1

CIRCUITDIAGRAM:


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THEORY:The most obvious method of determining the efficiency of any machine at any

load would be to measure the output and input when the machine is running at that load.For machines of higher rating, loads of the required size may not be available. Moreover,

even if it was possible to provide such loads, large power would be consumed, making it anexpensive method. All big electrical machines are tested indirectly by measuring the losses.The machine is run as a motor on no-load at its rated voltage and the input powermeasured. In this, the motor is running at no load at the rated speed, with the help ofshunt regulator. No load power input to armature supplies iron losses, friction losses,windage losses and armature copper losses.

PROCEDURE:1. Connect the circuit as per the circuit diagram.2. Keep the motor field rheostat at minimum position.3. Start the motor with the help of 3- point starter.

4. Adjust the motor field rheostat till the motor reaches to its rated speed.5. Note the armature current, field current and voltage.6. using the above data determine the efficiency of the D.C shunt machine.

TABULAR FORM:

Voltage(V)

Armature current(Ia)

Field current(If)

Load current(IL0= Ia+ If)

CALCULATIONS:MOTOR:

Ia=IL-IshIL0=Ia0+IshConstant losses Wc=VIL0-Ia0

2RaArmature cupper losses Wcu=Ia

2 Ra

Total losses in the motor Wt=(Wc+ Ia2 Ra)

Efficiency =output/input=input-losses/input

GENERATOR:Ia=IL+IshIL0=Ia0+IshConstant losses Wc=VIL0-Ia0

2RaArmature cupper losses Wcu=Ia

2 Ra

Total losses in the motor Wt=(Wc+ Ia2 Ra)

Efficiency =output/input


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=output/output+losses

MODEL GRAPH:

Motor:

A graph is plot output of Motor Vs efficiency.

M

EFFICIENCY

OUTPUT OF MOTOR

Generator:A graph is plot output of Generator Vs efficiency.

G

EFFICIENCY

OUTPUT OF GENERATOR


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PRECAUTIONS:1. Loose connection should be avoided.2. Operate the 3- point starter carefully.3.

Dont run the motor above safe speed.4. Check the connections before givingsupply.

RESULT:Hence the efficiency of the D.C shunt machine at various load conditions aredetermined and plotted.

VIVA QUESTIONS:

1.

What are the losses in a DC machine?

2. What is the purpose of the commutator in a DC machine?3. What is the power O/P during Swinburnes test?4. What is the efficiency of a DC machine during Swinburnes test?5. Why Swinburnes test cannot be performed on DC series machine?


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6.LOAD TEST ON D.C SERIES GENERATOR

AIM:To determine the internal and external load characteristics of a D.C series

Generator.


Power5hp 5hp

Wound Shunt Series



Excitation 220V, 0.75A --------

Speed 1500. 1500.

APPARATUS

Name Type Range Qty


Ammeter M.C0-10A 1

Rheostat___

0-300 , 1.7A 1

Tachometer ---1

Load Resistive 5kw1


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CIRCUIT DIAGRAM:

THEORY:In a series generator, there is only one field winding so that connected in

series with armature winding so that whole current flows through winding as well as load,series field winding carries full load current. Therefore series field winding is designed witha fewer turns of thick wire. The resistance of series winding is very low. These generatorscan be used for few applications and employed as constant current source. By making useof drooping portion of voltage-current characteristics. The best application is for supplyingfield current for regenerative braking in DC locomotives.

PROCEDURE:1. Connect the circuit as per the circuit diagram.2. Keep the motor field rheostat at minimum position and make sure all the load

switches are in off position3. Start the motor with the help of 3- point starter and adjust the motor field rheostat

till the motor reaches to its rated speed.4. Connect the load in step-by-step and each step note the load current and terminal

voltage of the generator.

5. Maintain load current will note exceed rated current.6. After note the readings first switch off the generator load and than switch off themotor supply.


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TABULAR FORM:

S NoVoltage

V(V)

Current

Ia(A) Eg=V+Ia (Ra+Rse)

MODEL GRAPH:

Internal characteristics:

Vt

CURRENT I

TERMINA

LVOLTAGE


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Eg

ICURRENT

PRECAUTIONS:1. Loose connection should be avoided.2. Operate the 3- point starter carefully.3. Loads should not be exceeding beyond their rating

RESULT:

Hence the internal and external load characteristics of a D.C series Generator areobtained and plotted.

VIVA QUESTIONS:

1. Can a DC series generator excite on no-load, why?2. What is meant by critical resistance of a DC series generator?3. What are the reasons for the failure of a DC series generator to build up voltage? 4. What are the advantages of a DC series motor?5. Why is the starting torque of the series motor high?

EFFICIENCY

ARMATUREVOLVOLTAG

E


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7.HOPKINSONS TEST ON DC SHUNT MACHINES

AIM:

To perform Hopkinsons test on two DC shunt machines and hence obtain Theirefficiencies at various loads.


Power3.7kw 3.7kw

Wound Shunt Shunt


Armature current 20.5A 17A

Excitation 220V, 0.9A 220V, 0.9ASpeed 1500. 1500.

APPARATUS:

Name Type Range Qty

Voltmeter M.C 0-300V 2

Ammeter M.C

0-10A 2

0-2A 2

Rheostat___

0-300 , 1.7A 1

0-570 , 1.2A 1

Tachometer --- 1


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CIRCUITDIAGRAM:

THEORY:This method load test can be carried out on two shunt machines, preferably

identical ones without wasting their outputs. The two machines are mechanically coupledand are so adjusted electrically that one of them runs as a motor and other as a generator.The mechanical output of the motor drives the generator and output of the generator is

used as greater part of input to motor. If there are no losses, they would run without anyexternal power supply but due to losses generator output is not sufficient to drive motorand vice versa. The two shunt machines are connected in parallel they are to begin withstarter as unloaded motors. Then field of one is weakened and that of other isstrengthened. So former it acts as motor and later acts asgenerator.

PROCEDURE:1. Connect the circuit as per the circuit diagram.2. Keep the switch S in open position3. Keep the motor field rheostat at minimum position and generator field rheostat at

maximum position.

4. Start the motor with the help of 3- point starter and adjust the motor field rheostattill the motor reaches to its rated speed

5.Adjust the field rheostat of the generator till the voltmeter Now close the switch Scarefully.

6. Decrees the excitation of the motor.Or Increase the excitation of the generator7. That means the M.G set is loaded.8. Take the all meters readings at various conditions.9.After taking the readings open the switch s and then Switch of the motor supply.


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TABULAR FORM 1:

s.no Linevoltage

V2(V)

LineCurrent

I1(A)

Generatorcurrent

I2(A)

Motorfield

currentI3(A)

Generatorfield

currentI4(A)

Motorarmature

currentIaM(A)I1+I2-I3

Generatorarmature

currentIaG(A)I2+I4

TABULAR FORM 2:

Totalstraylosses

(W)

Straylossesper each

machine(W/2)

Totalmotorlosses

(WM)

Totalgeneratorlosses

(WG)

Inputof motor

V(I1+I2)

Output ofMotor

V(I1+I2)-

WM

Output ofgenerator(VI2+WG)

Input ofgenerator(VI2+WG)

m

CALCULATIONS:

Total stray losses for the Motor Generator set is W

W=VI1- [(I2+I4)2 Ra+ (I1+I2-I3)

2 Ra+VI4+ VI3] Watts

Stray losses per each machine = W/2 Watts


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MOTOR:Motor total losses WM= ((I1+I2-I3)

2 Ra+VI3+ W/2 ) Watts

Motor Input = (V (I1+ I2) ) watts

Motor Output = (V (I1+ I2) - WM ) watts

Motor efficiency M = [V (I1+ I2) - WM] / [V (I1+ I2)]

GENERATOR:Generator total losses WG= ((I2+I4)

2 Ra +VI4+ W/2)

Generator output = (VI2 ) watts

Generator Input = ( VI2+ WG ) watts

Generator efficiency G= VI2/ (VI2+ WG)

MODEL GRAPH:

Motor:

A graph is plot output of Motor Vs efficiency.

M

EFFICIENCY

OUTPUT OF MOTOR


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Generator:A graph is plot output of Generator Vs efficiency.

G

EFFICIENCY

OUTPUT OF GENERATOR

PRECAUTIONS:1. Loose connection should be avoided.2. Operate the 3- point starter carefully.3. Loads should not be exceeding beyond their rating.4. Proper rating meters should be used.5. Check the connections before giving supply.

RESULT:Hence the efficiency of the two machines at various load conditions are calculated

and plotted.

VIVA QUESTIONS:1. Which loss is obtained from the Hopkinsons test?2. Why Hopkinsons test is also called the regenerative or back-to-back test?3. Is the stray loss obtained from the Hopkinsons test really same for both the

machines? Why?4. What is the difference between the Swinburnes test and Hopkinsons test?5. Stray loss in a DC machine depends on what quantities?


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8.FIELDS TEST ON D.C SERIES MACHINES

AIM:To conduct fields test on two D.C series machines and find out the efficiency of

Motor and Generator at different loads.


Power3.7kw 3.7kw

Wound Series Series


Armature current 21A 17A

Speed 1500. 1500.

APPARATUS:

Name Type Range Qty

Voltmeter M.C0-300V 2

0-250V 1

Ammeter M.C 0-20A 2

Tachometer --- 1

Load Resistive 5kw 1

CIRCUIT DIAGRAM:


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THEORY:This test is applicable to two similar series machines which are mainly used for

traction work easily available in pairs. The two machines are coupled mechanically. Onemachine runs normally as a motor and drives generator whose output is wasted in a

variable load. Iron and friction losses of two machines are made equal by joining the seriesfield winding of generator in the motor armature circuit so that both machines are equallyexcited. By running them at equal speed load resistance is varied till the motor currentreaches its full load value.

PROCEDURE:1. Connect the circuit as per the circuit diagram.2. Initially put some sufficient load on the series generator.3. Start the motor with the help of 2- point starter.4.Add the loads till the armature current reaches rated value and note down the

voltages and currents.

5. Reduce the loads step by step and each step note down the voltages and currentstill the motor speed doesnt exceed safe value.

6. Keep again sufficient load on the series generator and switch off the motor supply.

TABULARFORM1:

S.No TerminalvoltageV1(V)

MotorVoltageV2(V)

LineCurrent

I1(A)

GeneratorVoltageV2(V)

LoadCurrentI2(A)

SpeedN(rpm)


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TABULARFORM2:

Totalstraylosses(W)

Straylossespereachmachine(W/2)

Totalmotorlosses(WM)

Totalgeneratorlosses(WG)

Inputofmotor

V2I1

OutputofMotor

V2I1-WM

Output ofgeneratorV3I2

Input ofgenerator(V3I2+WG)

m

CALCULATIONS:

Input of the Motor Generator set is = V1I1 Watts

Output of the Motor Generator set is = V3I2 Watts

Total losses of Motor Generator set is W t= (VI1- V3I2) Watts

Armature and field losses of the M.G. set

Wcu= ((Ra+2Rse) I12+ I2

2 Ra) Watts

Total stray losses for the Motor Generator set is W = W t-Wcu

Stray losses per each machine Ws= W/2 Watts

MOTOR:Motor total losses WM= ((Ra+Rse) I1

2+ Ws) Watts

Motor Input = V2I1watts

Motor Output = ( V2I1- WM) watts

Motor efficiency M = [V2I1- WM] / [V2I1]


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GENERATOR:

Generator total losses WG= ( I22 Ra +I1

2Rse+ Ws) Watts

Generator output = V3I2watts

Generator Input = ( V3I2+ WG) watts

Generator efficiency G = V3I2/ (V3I2+ WG)

MODEL GRAPH:

MOTOR:A graph is plot output of Motor Vs efficiency.

M

EFFICIENCY

OUTPUT OF MOTOR


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GENERATOR:A graph is plot output of Generator Vs efficiency.

G

EFFICIENCY

OUTPUT OF GENERATOR

PRECAUTIONS:1. Loose connection should be avoided.2. Operate the 2- point starter carefully.3. Loads should not be exceeding beyond their rating.4. Dont run the motor above safe speed.5. Check the connections before giving supply.

RESULT:

Hence the efficiency of the two series machines at various loadConditions are calculated and plotted.

VIVA QUESTIONS:

1. What is the usual range of field winding resistance in case of a DC series machine?2. What is field test and on what type of DC machines it is performed?3. How are large series machines tested?4. How to minimize the eddy current & hysteresis losses in case of a DC machine?5. How a DC series motor can be used as DC shunt motor?


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9.SPEED CONTROL OF D.C SHUNT MOTOR

AIM:To determine the speed control characteristics of D.C shunt motor by

1.Armature control.2. Field control.


Power5hp

Wound Shunt

Armature voltage 220V.Armature current 20A


Speed 1500.

APPARATUS:

Name Type Range Qty

Voltmeter

M.C

0-300V1

Ammeter M.C0-2A 1

Rheostat___

0-300 , 1.7A1

0-36 , 12A1

Tachometer ---1


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CIRCUITDIAGRAM:

THEORY:

The speed of the DC shunt motor can be controlled by two methods they are:Flux control:

The speed equation of DC motor is N1/. By decreasing the flux, speed isincreases. The flux of DC motor can be changed by shunt field current with the help ofshunt field rheostat. Shunt field current is small which means I2R loss is small. In thismethod speed control above rated speed is possible.Armature control:

In this method the supply voltage is normally constant. The voltage across thearmature is varied by inserting a variable rheostat in series with the armature circuit. Ascontroller resistance is increases potential difference across the armature decreases. Sospeed control below rated speed is possible.

PROCEDURE:

1. Connect the circuit as per the circuit diagram.2. Keep the all rheostat at minimum resistance position.3. Start the motor with the help of 3- point starter and

initially maintain the field current at some constant value.4. Now slowly increases the armature resistance by adjust the rheostat and note the

corresponding voltage V and speed N.5.Again set the fields current If at some other constant value and done the above

process.


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6. Now set the armature voltage at some constant value and increase the fieldresistance by adjusting the rheostat and note the corresponding field current I fandspeed N.

7. Again set the armatures voltage at some other constant value and done the aboveprocess.8. Draw the relating graphs.

Observation Table:Field Control current control method:

Eb= Eb=

Armature voltage control method:

If= If=

S.noField current

(If)Speed

(N)

S.noField current

(If)Speed

(N)S.noField current

(If)Speed

(N)

S.no Field current(If)

Speed(N)


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MODEL GRAPH:Armature voltage control method:

A graph is drawn between Armature voltage V and speed N.

N

VArmature voltage

Field Control current control method:

A graph is drawn between field current Ifand speed N.

N

If

S

PEED

SPE

ED


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PRECAUTIONS:1. Loose connection should be avoided.2. Operate the 3- point starter carefully.3. Dont run the motor above safe speed.

RESULT:

Hence the speed control of D.C shunt motor by armature control and field controlare obtained.

VIVA QUESTIONS:

1. On what factors does the speed of a DC motor depend?2. How can the speed of a DC shunt motor be controlled by field control method?3. What will be the effect on the speed of a DC shunt motor if an additional resistance

is introduced in the field circuit?4. Do the motors run faster in series combination or parallel combination? 5. Why is it not possible to obtain speed of a DC shunt motor above normal by

armature resistance control?


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10.SEPARATION OF LOSSES IN DC SHUNT MOTOR

AIM:

To separate the losses in a D.C shunt Motor.


Power5hp

Wound Shunt




Speed 1500.

APPARATUS:

Name Type Range Qty


Ammeter M.C0-2A 1

0-5A 1

Rheostat___

0-300 , 1.7A1

0-150 , 5A1

Tachometer---

1


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CIRCUITDIAGRAM:

THEORY:It is the simplest indirect method of testing dc machines in which the losses are

measured separately and efficiency at any desired load is predetermined. In this testvarious losses in a dc machine can be found into their components. The dc machine is runat no-load by varying the speed and keeping the excitation constant. If N is the speed ofthe shunt motor at any given time, then the frictional losses are found to be proportional to

N.similarly the windage losses are found to be proportional to N2.

PROCEDURE:1. Connect the circuit as per the circuit diagram.2. Keep the all rheostat at minimum resistance position.3. Start the motor with the help of 3- point starter.4.Adjust the speed of the motor to rated speed by adjusting the field rheostat.5. Note down the speed, voltage across armature and armature current.6. Keeping the field excitation constant. The speed of the motor can be varied by

controlling the armature voltage by varying the armature resistance.

7. The experiment is repeated at of the field current


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TABULAR FORM 1:

S.No Speed

N(rpm)

Armature

Voltage V

(volts)

Armature

Current I

(Amp)

Cu losses

Ia2Ra

(Watts)

Input

VIa(Watts)

Constant

losses W

(Watts)

W/N

Field current If=

S.No.Speed(rpm)

ArmatureVoltage

(V)

ArmatureCurrent

(A)

ArmatureCupperlosses

IaRa (W)

InputVIa(W)

ConstantLosses

= VIa-IaRa (W)WN


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MODEL GRAPH:

W

N

P - - - - - -- - - -- - - - - - - - - - - - - - - - - - - - - -

R - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Speed (N) (rpm)

PRECAUTIONS:1. Loose connection should be avoided.2. Operate the 3- point starter carefully.3. Dontrun the motor above safe speed.

RESULT:Hence the separation of losses in a DC shunt motor was obtained.

VIVA QUESTIONS:

1. On what factors do hysteresis and eddy current losses depend?2. Why mechanical losses occur in a DC machine?3. What are the magnetic losses in a DC machine?4. Why do iron losses occur in a DC machine?5. Does core loss occur in armature or in the poles of a DC machine?


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11.BRAKE TEST ON DC COMPOUND MOTOR

AIM:To find the efficiency of D.C compound motor by a direct load test.

NAMEPLATE DETAILS:D.C COMPOUND MOTOR

Power3.7kw

Wound Compound


Armature current 20.5A


Speed 1500rpm.

APPARATUS:

Name Type Range Qty


Ammeter M.C0-20A 1

Rheostat___

0-300 , 1.7A1

Tachometer ---1


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CIRCUIT DIAGRAM:

THEORY:

It is a direct method and consists of applying a brake to a water cooled pulleymounted on the shaft of motor. The brake band is fixed with the help of wooden blocksgripping the pulley one end of the band is fixed to earth a spring balance and other isconnected to a suspended weight. The motor is running and the load on the motor isadjusted till it carries its full load current. The simple brake test described above can beused for small motors only. Because, in the case of large motors, it is difficult to dissipatethe large amount of heat generated at the brake.

PROCEDURE:1. Connect the circuit as per the circuit diagram.2.

Keep the motor field rheostat at minimum position.3. Start the motor with the help of 3- point starter and adjust the motorfield rheostat till the motor reaches to its rated speed.

4. Now gradually apply the mechanical load by tightening the belt over theshaft.

5. Note the corresponding spring balance readings, line current, Voltageand speed at particular load.

6. Repent the above process at different load condition.


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7. Before the motor going to be switched off the motor must be in no loadcondition.

8. Using the above data deter mine the efficiency of the Compound motor.

CALCULATIONS:

Shaft torque = (S1-S2) x rx 9.81 (r = 0.146 m)= (2N) /60.Shaft O/P = Shaft Torque X

Efficiency= X100

TABULAR FORM:

S.No Voltage

(V)

Current

(A) S1(kg) S2(kg) Speed(rpm) InputPower(W) ShaftTorque(N-M)

rad/sec Efficien%

GRAPHS:Graphs are plotted between1. Speed and output2. Speed and torque3. Current and torque

4. Efficiency and out put

Shaft O/PPower I/P


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MODEL GRAPH:

N N IL % O/PVs %

TVSIL

TVSN

ILVSN

Output(W)

Torque(N-m)

Torque(N-m)

IL(A)

PRECAUTIONS:

1. Loose connection should be avoided.2. Operate the 4- point starter carefully.3. Cool the shaft pulley with water.4. Proper rating meters should be used.5. Check the connections before giving supply.

RESULT:Hence the efficiency of the D.C compound motor at various load

Conditions are calculated and plotted.


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VIVA QUESTIONS:

1. What is brake test?2. What is the main drawback of brake test?3. Why brake test is performed with the small machines only?4. What is the condition for maximum output in a DC motor?5. What are the possible causes of sparking at brushes?


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12.RETARDATION TEST ON DC SHUNT MOTOR

AIM:To conduct retardation test on a given DC machine


Power5hp

Wound Shunt


Armature current 20AExcitation 220V, 0.9A

Speed 1500.

APPARATUS:

Name Type Range Qty


Ammeter M.C0-5A 1

Rheostat___

0-300 , 1.7A1

0-1500 , 15A0-500,5A 2

Tachometer ---1


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CIRCUITDIAGRAM:

THEORY:This test is also known as running down test. It is used for finding out the stray

power losses of shunt wound DC machines. In this method of testing dc machines,machine under test is speeded up slightly above its normal speed and supply to the

armature is cut off. Consequently the armature slows down and its kinetic energy is utilizedto meet the rotational losses. The voltmeter connected across the armature shows theinstantaneous back emf of the motor. Since back emf of the motor is directly proportionalto speed, therefore, the voltmeter can be suitably calibrated to indicate speed. When thesupply to armature is cut off, the speed of the motor decreases.

PROCEDURE:1. Connect the circuit as per the circuit diagram.2. Run the motor at a speed slightly higher than rated speed by

adjusting field external rheostat..

3. Disconnect the armature circuit from supply by opening switch S.4. Note down the time taken for the machine to come down to zero

speed.5. Now, once again start the motor and run at a speed slightly higher

than rated speed.6. Disconnect the armature circuit from supply and connect it across

the rheostat by throwing switch S into the position 1& 2.7. Note down the readings of voltmeter and ammeter for two speeds

and time taken for the machine to come down to zero speed.


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OBSERVATIONS

Without load: With load:

Time taken = seconds (with load)

CALCULATIONS:

Rotational losses W=W

(dt2)(dt1-dt2)Where W

=average load power=VavgIavgwatts

dt2is the time taken for the speed to come down from N1to N2with load.

dt1is the time taken for the speed to come down from N1to N2under no-load.

S .no Speed

(rpm)

Time

(sec) S .no Speed

(rpm)

Time

(sec)

Speed (rpm) V IL Vav IavN1=

N2=


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MODEL GRAPH:speed (rpm)

N1 No-load

N2

With load

Time (sec)

PRECAUTIONS:

1. Loose connection should be avoided.2. Operate the 3- point starter carefully.3. Dont run the motor above safe speed.

RESULT:Hence the separation of losses in a DC shunt motor was obtained.

VIVA QUESTIONS:

1. What is retardation test and on what type of dc machines it is performed?2. What are the stray losses in a DC machine? 3. The lost torque in a DC motor is proportional to which loss?

electrical machines -1 lab

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