Ecmock5 Que
description
Transcript of Ecmock5 Que
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ACE/12/EC/MG1
EC 1/24
ACEEngineering Academy
MOCK GATE (2012) 1EC : ELECTRONICS & COMMUNICATION ENGINEERING
Time : 3 hours Maximum Marks : 100Read the following instructions carefully.
1. This question paper contains 24 printed pages including pages for rough work.Please check all pages and report discrepancy, if any.
2. Candidates have to answer in the Optical Response Sheet(ORS) by darkening the bubbles using ablack ink ballpoint pen only.
3. Write your registration number, name and other details at the specified locations on theORS using Black ink ballpoint pen only.
4. All the questions in this question paper are of objective type.5. Questions must be answered on Objective Response Sheet (ORS) by darkening the
appropriate bubble (marked A, B, C, D) using Black ink ballpoint pen against thequestion number on the ORS. Each question has only one correct answer. Since bubblesdarkened by the black ink ball point pen cannot be erased, candidates should darken the bubblesin the ORS very carefully.
6. Questions 01 through 25 (25 questions) are 1-mark questions and questions 26 through 55 (30questions) are 2-mark questions.
7. The question pairs (48, 49) and (50, 51) are the common data questions. The questionpairs (52, 53) and (54, 55) are questions with linked answers. The answer to the secondquestion of the linked question pairs will depend on the answer to the first question of thepair. If the first question in the linked pair is wrongly answered or is un attempted, thenthe answer to the second question in the pair will not be evaluated.
8. Questions 56 through 60 (5 questions) are 1-mark questions and questions 61 through 65(5 questions) are 2-mark questions.
9. Un-attempted questions will result in zero mark and wrong answers will result in NegativeMarks. For Q1 to Q25 and Q56 to Q60, 0.33 mark will be deducted for each wrong answer. ForQ26 to Q51, Q61 to Q65, 0.66 mark will be deducted for each wrong answer. The question pairs(Q.52, Q.53), and (Q.54, Q55) are questions with linked answers. There will be negative marksonly for wrong answer to the first question of the linked answer question pair, i.e. for Q.52 andQ.54, 0.66 mark will be deducted for each wrong answer. There is no negative marking for Q.53and Q.55.
10. Calculator is allowed whereas charts, graph sheets or tables are NOT allowed in the examinationhall.
11. Cell / Mobile phones or any other electronic gadgets are prohibited in the examination hall.12. Rough work can be done on the question paper itself. Additional blank pages are given at the end
of the question paper for rough work.NameRegistration Number EC
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ACE/12/EC/MG1
EC MG1 2/24
Q. 1 Q. 25 carry one mark each.
Q01. The value of k such that the rank of the matrix
011201311001310
kis three, is
(A) 2 (B) 2 (C) 3 (D) -3
Q02. The solution of y3 ex4dxdy with y(1) = 0 is
(A) y = x2 (B) ey = x4 (C) log y = x3 (D) y = logx
Q03. The divergence of the vector function kxsinhz2jyeieF xx is(A) x xe e 2sinhx (B) x xe e 2sinhx .(C) x xe e 2sinhx (D) xe 2sinhx
Q04. The probability that student passes maths exam is 0.9, given that he studied. Theprobability that he passes the exam without studying is 0.2. Assume that theprobability that the student studies for all exams is 0.75. The probability that he passesthe maths exam is(A) 0.675 (B) 0.05(C) 0.725 (D) 0.275
Q05. The Laplace Transform of unit impulse function (ta) is
(A)ases
(B) 1(C) eas (D) None
Q06. A current of 3 A flows through a resistance of 20 . The energy dissipated in theresistor per minute is(A) 5.4 KJ (B) 10.8 KJ(C) 21.6 KJ (D) 43.2 KJ
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Q07. Time constant of a capacitance circuit may be defined as the time during whichvoltage across the capacitor(A) rises to 63.2% of its final steady value(B) rises to 38.6% of its final steady value(C) falls to 38.6% of its final steady value(D) 50 % of its final steady value
Q08. The driving point impedance of an RC network is 1s3s3s7s2)s(Z 2
2
.
Its canonical realization will have(A) 6 elements (B) 5 elements (C) 4 elements (D) 3 elements
Q09. Consider the system shown in Fig. 1 with time constant, . For an input x(t) = 8 u(t),the response, y(t) is shown in Fig. 2. Then is
(A) 0.535 msec (B) 0.32 msec (C) 0.09 msec (D) 11.25 msec
Q10. A speed control system is represented by the signal flow graph shown in figure.The nominal value of the parameter K is 10. Sensitivity of M(s) = c(s)/ r(s) tochanges in K is(A) 11s
0.1s
(B) 0.2s0.1s
(C) 0.2s0.1
(D) None
1s10K c(s)r(s)
1 1
0.1
y(t)x(t)1s
1
Fig. 1 t(msec)0.32
3.60
y(t)
Fig. 2
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Q11. Consider the block diagram shown in figure. The transfer function R(s)Y(s) is
(A)
CE2ACE1
ACE
(B)
1CE2ACE1ACE
(C)
1CEACE1ACE
(D)
CEACE1
2ACE
Q12. Which of the following statements is/are valid for a PIN diode ?1) In forward bias it can be used as current controlled resistance2) Electric energy is converted into light energy3) Photo carries are generated internally4) In reverse bias it can be used as capacitor
(A) 1, 3, 4 (B) 3(C) 1,3 (D) 3, 4
Q13. DE, DB, DC are Dopings of emitter, base & collector. WE, WB, WC are widthsof emitter, base & collector. , , are current gains in CB, CE, CC configurations.Which of the following statements are false ?1) DB < DC < DE 4) = (1)2) WB< WC < WE 5) =
1
3) < > 6) approximately 1
(A) 2, 3, 4, 5 (B) 1, 4, 6(C) 2, 3, 5 (D) 3 only
Y(s)R(s) A
A
E
EC ++
_ __
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-+
Vi-+
+-
10 K1K
10 K1K
V2
V1 1K
1Kb
a
10 K
V0
10 K
RL Amplifier
Feedbacknetwork = 4.9%
VS A, Ri , R0
Q14. Gain
i0
VV of the OP-amp circuit shown below, is
(A) 220 (B) 198(C) 22 (D) 0
Q15. For the negative feedback amplifier circuit shown, gain A = 1000, input resistance,Ri = 2 K and output resistance, R0 = 50 K.
The input and output resistances of the feedback amplifier are(A) 40 , 1K (B) 100 K, 1 K(C) 40 , 2.5 M (D) 100 K, 2.5 M
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Q16. For the diode circuit shown, the graphical representation of the input-output relation is
(A) (B)
(C) (D)
Q17. What is the execution time of the following 8085 program segment if the frequency ofoperation is 2 MHz ?LXI H, 2070HMVI A, 00HSTA X HXRA A(A) 28 sec, (B) 14 sec(C) 30 sec (D) 32 sec
1.3V
2.7
2.71.3V
Vi
V0
2.7V
2.7V
2.7
2.7V
Vi
V0
2.7V
1.3V
2.7V
1.3V
Vi
V0
1.3V
1.3V
1.3V
1.3V
Vi
V0
D1
D2
V0
2V
1kVi
2V
For D1 and D2 ,V = 0.7 V
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Q18. Consider the logic circuit shown in figure.The functions f1, f2 and f4 aref1 (w, x, y, z) = m(8, 9, 10)f2 (w, x, y, z) = m(7, 8, 12, 13, 14, 15)f4 (w, x, y, z) = m (8,9)Then f3 (w, x, y, z) is
(A) m(9, 10) (B) m(9)(C) m(1, 8, 9) (D) m(8, 10, 15)
Q19. The relation between input and output of a system is y(t) =
0)t(xif00)t(xif)t(x
This system is
(A) Causal, Memory less & Nonlinear(B) Causal, Dynamic & linear(C) Non-casual, Memory less & linear(D) Non-casual, Dynamic & Non linear
Q20. Consider the signal x(n) =
elsewhere;01Nn0;bn Then ROC of Z.T of x(n) is
(A)| z | > | b | (B) | z | < | b |(C) | z | > 0 (D) 0 < | z | <
Q21. In a CD Player, the sampling rate is 44.1 KHz and the samples are quantized using a16 bit/sample Quantizer. The resulting number of bits for a piece of music with aduration of 50 min is(A) 2.116 M bits (B) 1.1178 G bits(C) 2.1168 G bits (D) 1.92 G bits
f1f2
f3
f4
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Q22. Consider two random variables X and YY = Cos (X), where the pdf of X is given byf(x) = 1 , 2
1X21
= 0 , otherwiseThe variance of Y is(A) 0.76 (B) 0.96 (C) 0.56 (D) 0.26
Q23. The message input to a delta modulator is m (t) = 6 Sin (2103t) + 4 Sin (4103t).The step size is 0.314V. The minimum pulse rate that will prevent slope overload is(A) 120 103 pulses/sec (B) 2800 pules/sec(C) 280 103 pulses/sec (D) 12,000 pulses /sec
Q24. An elliptical polarized wave has an electric field of yox a)75zt(sin2aztsinE V/m.
The power per unit area conveyed by the wave in free space is(A) 6.63 mW/m2 (B) 8.63 mW/m2(C) 3.315 mW/m2 (D) 66.3 mW/m2
Q25. A potential function V = x2yz + Ay3z volts , satisfies the Laplaces equation.The value of A is(A) 3
1 (B) 32 (C) 3
1 (D) 32
Q. 26 to Q. 55 carry two marks each.
Q26. The residue of
z1sinzf is
(A) 2 (B) 0 (C) 1 (D) 1
Q27. If the initial approximation is x0 = 2.5 then the first approximation of 31)18 usingNewtons Method, is(A) 2.1 (B) 2.43 (C) 2.63 (D) 3
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Q28. The differential equation 0y4dxdyx5dx
ydx 22
2 under the transformation z = log x istransformed to an ordinary differential equation with constant coefficients. It is givenby
(A) 0y4dzyd2
2 (B) 0y2dz
dydzyd2
(C) 0y4dzdy4dz
yd2
2 (D) 0ydz
dy4dzyd2
2
Q29. The mean and standard deviation of marks of a certain group of 1000 high schoolstudents are Normally distributed with 79% and 11% respectively. Find how manystudents are above 90% [Area under curve between Z = 0 and Z = 1 is 0.3413)]?(A) 159 (B) 500
(C) 250 (D) 143
Q30. Consider the following network
The power associated with 1A source is
(A) 3 W (delivery) (B) 6 W (absorption)(C) 9 W (absorption) (D) 12 W (delivery)
6
10 15 8 A 3
1 A
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Q31. Consider the following networkThe power associated with 24 V source is
(A) 60 W (delivery) (B) 120 W (absorption)
(C) 180 W (delivery) (D) 240 W (absorption)
Q32. A control system with a P D controller is shown in figure. Find the values of KC andKD so that the velocity error constant KV is 1000 and damping ratio is 0.5.
(A) KC = 1, KD = 1(B) KC = 100, KD = 0.9(C) KC = 10, KD = 0.09(D) None
+ 8 A
3 1
24 V
2 A
4
R(s) _ KC + KD s 10)(ss1000
+ C(s)
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s 1 s 1 s 1
- 2
YU 11
1
211
11
1
Q33. The state model to the given state diagram is
(A)
3
2
1
3
2
1
3
2
1
xxx
xxx
xxx
122Y,U100
212120010
(B)
3
2
1
3
2
1
3
2
1
xxx
xxx
xxx
001Y,U100
212100010
(C)
3
2
1
3
2
1
3
2
1
xxx
xxx
xxx
100Y,U001
212120010
(D) None
Q34. The characteristic equation of a control system is given by
s6 + 2 s5 + 8 s4 + 12 s3 + 20 s2 + 16 s + 16 = 0
The number of roots of the equation, which lie on the imaginary axis of s-plane is
(A) Zero (B) 2(C) 4 (D) 6
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+ 0.5K 0.5K
5K
5K
VS
V0
D1
D2
Q35. For the given circuit assuming identical diodes which of the following is valid forI and V ?(A) I = I0 T T
v vv ve e (B) I = I0 T
v ve
(C) I = I0 Tv ve
(D) I = I0 T Tv vv ve e
Q36. For a BJT, IC = | IE | + ICBO , IE = IB + IC . If so which of the following relationsis valid ?(A) 1 CB
C CBO C CBO
III I I I
(B) IC (1+) = IB + ICBO
(C) CBOBC III 1 1 (D) IB ICBO = IC + IC
Q37. In NMOS circuit, the drain current, ID = 6 mA and process transconductanceKn = n Cox . .V
A110LW
2 The transconductance of the circuit is
(A) 8.83 VmA (B) 2.54 V
mA
(C) 1.15 VmA (D) 7.64 V
mA
Q38. Each diode has V = 0.6 V. The diodes D1 and D2 will be ON if
(A) VS > 6.3 V
(B) VS > 5.3 V
(C) VS > 4.9 V
(D) VS > 3.9 V
I1 NP
I
+V
I2 N P
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20 k
V0
200 200 0.5 mA
Ri
Vi
v(t) y(t)x(t) )t(x)t(v)t(v )t(v)t(y)t(y
Fig.
Q39. For the transistor circuit shown, assume that = 99, VT = 25 mV.The voltage gain of the amplifier is
(A) 23
(B) 33
(C) 43
(D) 53
Q40. In the circuit shown below, assume Q0 = Q1 = 0. Then the states of Q0 and Q1,immediately after the 333rd pulse are
(A) 1, 1 (B) 1, 0 (C) 0, 1 (D) 0, 0
Q41. For the interconnected system shown in figure, the combined Casual impulse responseis(A) e-t u(t)(B) t e-t u(t)(C) (t)(D) u(t)
J0 Q0
K0 0Q 1Q
J1 Q1
K1
Q0 Q1
1
Clock
> >
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2 1 1 2
1
1
X()
Fig.
0
Q42. For the spectrum, X() shown in the figure, which one of the following statements iscorrect ?
(A) x(0) = 1, x(t) is real and odd
(B) x(0) = 0, x(t) is complex and even
(C) x(0) = 0, x(t) is imaginary and odd
(D) x(0) = 2, x(t) is real and even
Q43. The message input to a Frequency modulator is m(t) = 2mA Sin2 (2fmt). Let fc bethe carrier frequency of the modulator when m(t) = 0. The carrier frequency at theoutput of the modulator is
(A) fc (B) fc+ 2AK 2mf
(C) fc + 2AK mf (D) fc+ 2
AK 2m2f
Q44. The input to the matched filter is shown in the fig.The output of the filter is sampled at t = T. The sampled value is(A) 4
(B) 4T
(C) T2
(D) 2T
Q45. In a rectangular wave guide, a = 1.5 cm, b = 0.8 cm, = 0, = 0, = 40 and
zt10sinby3cosaxsin2H 11x A/mThe cutoff frequency is(A) 28.57 GHz (B) 2.857 GHz (C) 38.57 GHz (D) 18.57 GHz
2
0 T/2 T
s(t)
t
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Q46. An electric field strength of 10 V/m is to be measured at an observation point 2 ,
500 km from a half-wave dipole antenna operating at 50 MHz . The current that mustbe fed to the antenna is(A) 8.33 mA (B) 83.33 mA (C) 0.833 mA (D) 833 mA
Q47. A 30 m long lossless transmission line with Z0 = 50 operating at 2 MHz isterminated with a load, ZL = (60 + j 40) . If phase velocity on the line is 0.6 timesthe velocity of light, the input impedance is(A) 23.97 + j 1.35 (B) 46.00 + j 2.7 (C) (1.35 + j 23.97) (D) (23.97 j 1.35)
Common Data Questions
Common Data for Questions 48 and 49:
Consider the following memory interfacing diagram.
Q48. If A12 to A15 all are connected to zero, then the address range of chip 2 is(A) 0400H to 07FFH (B) 0000H to 03FFH(C) 0800H to 0BFFH (D) 0C00H to 0FFFH
1K 8
1K 8
A0 A9 Chip 1
Chip 2not used
A12 A15A0 A9
A10
A11
CS
CS
11A10A
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2 k
VS 1 k
CC57 k
16 V
Q49. If A12 to A15 are not used, what memory address range is not represented by neitherchip 1 nor chip 2 ?(A) F800H to FBFF (B) C400H to C7FF(C) F400H to F7FF (D) FC00 to FFFF
Common Data for Questions 50 and 51:
In the transistor amplifier circuit shown in the figure below, the transistor has = 80, VBE = 0.7 V. The capacitance can be assumed to be very large.
Q50. Under the DC conditions, the operating voltage VCE is(A) 3.2 V (B) 3.61 V(C) 3.76 V (D) 4.2 V
Q51. If the value of is increased by 15% then the operating voltage is(A) Increased by more than 10%(B) Increased by less than or equal to 10%(C) Decreased by more than 10%(D) Decreased by less than or equal to 10%
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Linked Answer Questions :
Statement for Linked Answer Questions 52 and 53 :
The modulating signal into an FM modulator ism(t) = 10 cos (20t)
The output of the FM modulator iss(t) = 10 cos [4000 t + 2Kf m(t) dt] ,
where Kf = 5 Hz/Volt. The output of the FM modulator is passed through an idealBPF centered at fc = 2000 Hz with a bandwidth of 80 HzJ0(5) = 0.178 , J1(5) = 0.328 , J2(5) = 0.047 , J3(5) = 0.365 , J4(5) = 0.391J0 (10) = 0.246 , J1(10) = 0.043 , J2 (10) = 0.255 , J3 (10) = 0.058 , J4(10) = 0.22
Q52. The power of the frequency components at the output of the filter is(A) 21.39W (B) 82.2W (C) 41.17W (D) 88.19W
Q53. The percentage of the total power which appears at the output of the BPF is(A) 62.85% (B) 42.75% (C) 99.9% (D) 82.35%
Statement for Linked Answer Questions 54 and 55 :Consider the following network.
Q54. The value of current ix is(A) A25
6 (B) A1225 (C) A6
25 (D) A2512
0.4 ix30
+
20
10
4 A
60 V
ix
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Q55. Power associated with the dependent source is(A) 34.75 W (absorption) (B) 68.75 W (delivery)(C) 72.75 W (delivery) (D) 96.75 W (absorption)
General Aptitude (GA) Questions:
Q. 56 to Q. 60 carry one mark each.Q.56. Manu and Tanu are playing mathematical puzzles. Manu asks Tanu : Which whole
numbers, greater than one, divide evenly all the nine numbers, i,e., 111, 222, 333,444, 555, 666, 777, 888, 999, ? Tanu immediately gave the desired answer. It was :(A) 7, 37, 111 (B) 3, 37, 111 (C) 9, 37, 111 (D) 9, 13, 111
Q57. Choose the most appropriate word from the options given below to complete thefollowing sentenceThe puzzles that physicists solve are usually those lying about in plain sight,often things so _______ that they are overlooked by all but the keenestobservers.(A) hidden (B) vital (C) ordinary (D) vague
Q58. The question below consists of pair of related words followed by four pairs of words.Select, the pair that best expresses the relation in the original pair.
Elegy : Poetry ::(A) parable : story (B) dirge : music(C) harp : string (D) rhyme : sound
Q59. Choose the word from the options given below that is most nearly opposite inmeaning to the given word:Abdicate :(A) condone (B) affiliate(C) attack (D) usurp
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Q60. Choose the most appropriate word from the options given below to complete thefollowing sentence:The visitor was of an______ age; white-haired but baby-faced, he might havebeen twenty-five or fifty.(A) assiduous(B) unalterable(C) indecorous(D) indeterminate
Q. 61 to Q. 65 carry two marks each.
Q61. The traffic lights at three different road crossings change after every 48 s, 72 s and108 s, respectively. If they all change simultaneously at 8 : 20 : 00, then they willagain change simultaneously at :(A) 8 : 27 : 12h (B) 8 : 27 : 24h(C) 8 : 27 : 36h (D) 8 : 27 : 48h
Q62. A recipe give directions to mix 4 parts of substance A with 7 parts of substance B.These substances are to be taken by weight, but by mistake they were taken byvolume. Find the error in the percentage of the weight of A in the mixture, if 117 cm3of the substance A weighs as much as 151 cm3 of the substance B.(A) 5.05% (B) 6.00%(C) 7.05% (D) None of these
Q63. A tank with capacity T litres is empty. If water flows into the tank from pipe X at therate of X litres per minute and water is pumped out by pipe Y at the rate of Y litresper minute and X > Y, then in how many minutes will the tank be filled ?
(A) XYT (B) YX
T
(C) (T X) Y (D) (X Y) 60T
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123Literate
Illiterate
30o120o
FM
123
105o 120oF M
Literate
Illiterate
20102000
Q64. Cricket is the most popular sport in India. However its popularity has adverselyaffected the prospects of other sports like hockey and football. In order to correct theimbalance, the Ministry of sports should stop funding cricket and allot those resourcesto other sports. Which of the following, if true, would most weaken the aboveargument ?(A) The popularity of a sport is determined to a large extent by the investments made
in promoting it.(B) Ministry of sports funding is used mainly to coach budding cricketers and is
seldom used for promotional activities.(C) Crickets popularity will be very difficult to challenge as it has a longer history in
India than most other sports.(D) The nature and format of a sport is the only fact (or) that determines its popularity
Q65. The given pie charts show the proportion of literates and illiterates in a country, in theyear 2000 and 2010 and also the proportion of males (M) and females (F) among theliterates. Which one of the following statements can be said to be beyond any doubt ?
(A) In 2000 half of the illiterates were women (females).(B) The population of literate males to the total population of males remained the
same over the years.(C) Male literacy did not improve over this period.(D) The ratio of female literates to male literates improved significantly over this
period.
END OF THE QUESTION PAPER
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SPACE FOR ROUGH WORK
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Head Office : Abids, Hyderabad, AP.Summer Crash Batches for GATE + PSUs
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For (EC, EE, ME & CSIT)Summer Crash :May 12th Long -term (Morning): July 8th, 15th Long -term (Evening) :July 29th
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Sundays & Public Holidays extraclasses.
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May 10th (starts at 10 AM on the first day) Duration : 55 to 65 days Timings: 6-8 Hrs per day
Long-term Evening Batches for GATE + PSUs for EC, EE & IN June 17th & July 1st (starts at 10 AM on the first day) Duration : 6 to 7 months Timings : 6 AM to 7.45 AM on working days. Sundays & Public Holidays extra classes.
Weekend Batches for GATE + PSUs for EC, EE, IN, CSIT, ME & CIVIL June 17th & July 1st Duration : Upto end of January Timings : Saturdays, Sundays & Public Holidays full day classes.
There is no separate batch for employees. They have to follow the schedule ofcollege goer batches.
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ACE/12/EC/MG1
EC MG1 24/24
NEW DELHI, INDIA
Long-term Day Batches for GATE + IES + PSUs for EC, EE, & ME March 25th, May 1st, 16th, 31st , June 24th, Evening Batches : 6.00 PM to 9.00 PM July 1st Extra classes on public holidays
Weekend Batches for GATE +IES + PSUs for EC, EE, IN, CSIT & ME March 25th & May 1st
NOTE : The common syllabus for GATE & IES will be covered in the beginning. The
additional syllabus for IES will be covered after completion of the commonsyllabus.
Reserve your seat in advance to avoid last minute disappointment. Additional batches will be arranged depending upon response.
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