Control of Chemical Reactions

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Control of Chemical Reactions

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Control of Chemical Reactions. Entropy Randomness Reactions that increase random- ness are favored. Forming gases favors reactions. Thermodynamic Control of Reactions. Enthalpy Bond Energies Forming stronger bonds favors reactions. - PowerPoint PPT Presentation

Transcript of Control of Chemical Reactions

Page 1: Control of Chemical Reactions

Control of Chemical Reactions

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Thermodynamic Control of Reactions

Enthalpy

Bond Energies– Forming stronger bonds favors reactions.– Molecules with strong bonds are more stable.

Entropy

Randomness– Reactions that

increase random- ness are favored.

– Forming gases favors reactions.

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Remember Enthalpy?

Enthalpy of formation for elements in their natural states = 0.

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H2O(g) Gaseous water -242

ΔH , kJ/molof

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The Laws of Thermodynamics

1st Law: Energy is Conserved

2nd Law: Any “spontaneous” process leads to an increase in entropy of the universe.

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Entropy

A measure of randomness. Units of J/K.

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Trends in entropy

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Entropy Change

• First define:

System Surroundings

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Entropy ChangeFor the System

If the system gets more random, DS is positive. (Favors the reaction)

If the system gets more ordered, DS is negative. (Disfavors the reaction)

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Calculating SChemical Reactions

C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(l)

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Calculating SSpecial Case: Phase Changes

T

HS

T

qS changephaserev

Heat of fusion (melting) of ice is 6000 J/mol. What is the entropy change for melting ice at 0 oC?

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Calculate entropy change for formation of rain:

H2O(g) H2O(l)

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What types of reactions lead to increased entropy?

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Entropy vs. Enthalpy Control of Reactions

Second law of thermodynamics:

Suniverse = Ssystem + Ssurroundings

systemuniverse system

-ΔHΔS = ΔS +

T

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Question: How can rain form?

H2O(g) H2O(l)

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Calculate Suniverse for H2O(l) H2O(g) at:

90 oC

110 oC

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Putting S, H and Temperature Together

Gibb’s Free Energy: G = H - TS

When G is negative, reaction is favored.

When G is positive, reaction is disfavored.

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2 Fe2O3(s) + 3 C(s) 4 Fe(s) + 3 CO2(g)

H = +468 kJS = +561 J/K G = H - TS

What is G at 25 oC and at 1000 oC?

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Enthalpy vs. Entropy Control of Reactions

G = H - TS

At high temperatures:

At low temperatures:

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Temperature Domains and Reaction Favorability

H + - +S -

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2 Fe2O3(s) + 3 C(s) 4 Fe(s) + 3 CO2(g)

H = +468 kJS = +561 J/K

In what temperature range will this reaction be favored?

High or low?

What temperature?

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Free Energy vs. Temperature Curves

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Catalytic Converters

Nitrogen oxides cause smog.

N2(g) + O2(g) 2 NO(g) H = +180 kJ S = +25 J/K

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Free Energy of Formation: Only used at 25 oC

2 BaO(s) + C(s) 2 Ba(s) + CO2(g)