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Chuong 5_Dinh luat ung xu cua vat lieu.pptx
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Transcript of Chuong 5_Dinh luat ung xu cua vat lieu.pptx
C HC VT RN BIN DNG
Chng 5. nh lut ng x ca vt liuI. nh lut ng x ca vt liu
Quan h gia ng sut v bin dng l tuyn tnhTrong : Cijkl cc hng s n hi vt liu. Cc hng s ny to thnh mt tenx hng 4. S hng s n hi c lp khng th ln hn 21
1Chng 5. nh lut ng x ca vt liuII. nh lut Hooke theo trc chnhng sut ti mt im:
Bin dng ti mt im:
2.1. Trng thi ng sut n:
2.1. Trng thi ng hai chiu:Xt phn t hnh ch nht c b dy mng u, chu trng thi ng sut phng
2Chng 5. nh lut ng x ca vt liu2.1. Trng thi ng sut hai chiu:
L lun tng t theo phng 2:
Bin dng di theo phng 1:V ngc li:
(2.1)(2.2)3Chng 5. nh lut ng x ca vt liu2.2. Trng thi ng sut ba chiu:L lun tng t bi ton trng thi ng sut phng, ta c:
4Chng 5. nh lut ng x ca vt liuIII. Muyn trtTrng thi trt thun ty
Tng t:
(3.1)321- m un n hi trt
(3.2)5Chng 5. nh lut ng x ca vt liuIV. nh lut Hooke tng qut
Trng thi ng sut ba chiuTrng thi ng sut hai chiu
(4.1)(4.2)6Chng 5. nh lut ng x ca vt liuIV. nh lut Hooke tng qut
Theo k hiu ch s: gin n th tch:
Hay:
(4.3)(4.4)7Chng 5. nh lut ng x ca vt liuIV. nh lut Hooke tng qut
Trong : - ng sut trung bnh
- moduyn nn khi
thay t biu thc (4.4) vo (4.3), ta c nh lut Hooke ngc:
(4.5)8Chng 5. nh lut ng x ca vt liuIV. nh lut Hooke tng qutHoc ta cn c th vit:
(4.5)Hoc ta c th thay cc hng s E, G, bng cc hng s Lam:
(4.6)9Chng 5. nh lut ng x ca vt liuIV. nh lut Hooke tng qutKhi nh lut Hooke ngc c vit di dng:
(4.7)Ta li c:
(4.8)=(4.4)
(4.9)10Chng 5. nh lut ng x ca vt liuVI. nh lut Hooke khiPhng trnh (4.8) din t s thay i th tch m khng b xon
Biu thc (4.8) th hin nh lut Hooke khi
Phng trnh (4.9) din t s thay i hnh dng m khng lm thay i th tch11Chng 5. nh lut ng x ca vt liuV. nh lut Hooke trong trng hp bin dng phng trng thi bin dng phng, ta c:
Thay z = 0 vo biu thc (4.1c), ta c
(5.1)Thay (5.1) vo (4.8a) v (4.8b)12Chng 5. nh lut ng x ca vt liuV. nh lut Hooke trong trng hp bin dng phng trng thi bin dng phng, ta c:
Thay z = 0 vo biu thc (4.1c), ta c
(5.1)Thay (5.1) vo (4.8a) v (4.8b), ta c nh lut Hooke cho trng thi ng sut phng:13Chng 5. nh lut ng x ca vt liuV. nh lut Hooke trong trng hp bin dng phngThay (5.1) vo (4.8a) v (4.8b), ta c nh lut Hooke cho trng thi ng sut phng:
(5.2)
(5.3)14Chng 5. nh lut ng x ca vt liuVI. Cc hng s n hi ca vt liu:Nu vt liu ng hng:
15Chng 5. nh lut ng x ca vt liuVI. Cc hng s n hi ca vt liu:Nu vt liu d hng:
- cc hng s vt liu
(4.13)16Chng 5. nh lut ng x ca vt liuVI. Cc hng s n hi ca vt liu:Trong trng hp tng qut ch c 21 hng s n hi c lp
17Chng 5. nh lut ng x ca vt liuVI. Cc hng s n hi ca vt liu:Vt liu c mt mt i xng
18Chng 5. nh lut ng x ca vt liuVI. Cc hng s n hi ca vt liu:Vt liu ch cn 13 hng s c lp
19Chng 5. nh lut ng x ca vt liuVI. Cc hng s n hi ca vt liu:Vt liu c 3 mt i xng
20Chng 5. nh lut ng x ca vt liuVI. Cc hng s n hi ca vt liu:Vt liu ch cn 9 hng s c lp
21Chng 5. nh lut ng x ca vt liuVII. Cc phng trnh c bn ca CHVRBD v phng php gii - Ba phng trnh cn bng
Cc phng trnh ca CHVRBD(I)22Chng 5. nh lut ng x ca vt liu - Su phng trnh Cauchy hoc 6 phng trnh tng thch bin dng:
(II)(II)23Chng 5. nh lut ng x ca vt liu - Su phng trnh nh lut Hooke:
(III)(III)24Chng 5. nh lut ng x ca vt liuiu kin bin:
- Trng ng sut tha iu kin cn bng trn bin tnh hc
- Trng chuyn v tha iu kin chuyn v trn bin ng hc 25Chng 5. nh lut ng x ca vt liu 1. Phng php chuyn v
Cc phng php gii bi ton LTHThay (II) vo (III) ri thay vo (I) sau bin di, ta c phng trnh LamTrong - ton t Laplace
26Chng 5. nh lut ng x ca vt liu* iu kin bin tnh hc
27Chng 5. nh lut ng x ca vt liu 2. Phng php lc
Thay (III) vo (II) ta c (IV) , sau thay (I) vo (IV), ta c h phng trnh Beltrami - MichellVi
28Chng 5. nh lut ng x ca vt liuVI. nh l v s duy nht nghim Mt vt th n hi chu tc ng ca lc th tch v lc b mt trn bin tnh hc v chuyn v cng bc trn bin ng hc th ch c duy nht mt trng ng sut, bin dng v chuyn v trong vt th.29