Chon_271 Đề ÔN LUYỆN TOÁN 1.pdf

7/29/2019 Chon_271 N LUYN TON 1.pdf

1/47

Lb tp Ze` np 1 1

Z\[@F ZG ZE@ ENRGXBO B_B Zr Zdb 821?.:?8 222

0 7

:8 ) ; :2 6

62


2/47

Lb tp Ze` np 1


3/47

Lb tp Ze` np 1 ?

Z\[@F ZG ZE@ ENRGXBO B_B Zr Zdb 821?.:?8 222Lb 2= A` o 1< vb` lb. Na` o 6 vb` lb Db o dab l` o tt o lae `dbu vb`lb5

Zg tt Lb fbb

Lb 18= Fbb lb te` tdke tg tt sau=

A L

E

Lb 11= t t`d rb t`d=

;8 ) ?8

38 ) 18


4/47

Lb tp Ze` np 1 :


l" Sbt s tdod dp ve tr`f=

o" `f fdb . sab fdb s ve tr`f=

a" 68 l" 38 o" 48 j" 28

' ' ' '


5/47

Lb tp Ze` np 1 ;

Z\[@F ZG ZE@ ENRGXBO B_B Zr Zdb 821?.:?8 222l" _5

) 3 7 14 48 ' 7 ?8

Lb 14= a" b` ju 0 9 > 9 7 ve tr`f=

1: ) ; 14 48 ' ;8 68


6/47

Lb tp Ze` np 1 3

Z\[@F ZG ZE@ ENRGXBO B_B Zr Zdb 821?.:?8 22243 ?: 7

43 ;< 7

;< ) ?: 7

26 :6 7

26 ;8 7

;8 ) :6 7

34 ?: 7

?: ) ?: 7

38 :8 7

38 ) :8 7

188 :8 7

188 38 7

Lb


7/47

Lb tp Ze` np 1 6


Lb


8/47

Lb tp Ze` np 1 4


Lb ?3= Sbt oo s

' Z 8 ` 2=' Z 18 ` 12= ' Z 28 ` 22= ' O tt o s o gt od s

Lb ?6= Sbt s o dab od s td`d s odo v s ` v $ tdke gu"=

;? 7 ;8 ) ?

?; 7 ;; 7

18 7

?3 7

3? 7 ?? 7

:8 7

32 7

23 7 22 7

48 7

Lb ?4= Sbt s nb` tro v nb` sau oa s ode tro $tdke gu"=

1: 9 1; 9 13

9 629

9


9/47

Lb tp Ze` np 1 2


Lb :


10/47

Lb tp Ze` np 1 18

Z\[@F ZG ZE@ ENRGXBO B_B Zr Zdb 821?.:?8 222?< )


11/47

Lb tp Ze` np 1 11

Z\[@F ZG ZE@ ENRGXBO B_B Zr Zdb 821?.:?8 2221 tu` n 7 `fy

Lb ;:= t t`d rb t`d?; )


12/47

Lb tp Ze` np 1 1


13/47

Lb tp Ze` np 1 1?

Z\[@F ZG ZE@ ENRGXBO B_B Zr Zdb 821?.:?8 222?; ) 0 ;3 ;< ) > ;2

64 ' > 38 ' 4 7 ;8

Lb 36= A L

O bg

O e` td`fO d`d tag fbo E

O J

Lb 34= ' _ n` `dt o gt od s n=

' _ tr` odo n` `dt o dab od s n= ' Ny s tr` odo n` `dt o dab od s o`f vb s n` `dt o gt od

s o it qu n=

Lb 32 = Idb np < o :; do sb`d id v ;8 do sb`d fbb Db idb np < o

lae `dbu do sb`d id . fbb 5

Lb fbb

Lb ?= Np 1K o ?3 l` . tre`f o


14/47

Lb tp Ze` np 1 1:


Lb 6< = Fbb lb te` tdke tg tt sau=

Zg tt Lb fbb

G o = 43 ob l`d

Ode D`f = 18 ob l`d

O` nb = ob l`d 5

Lb 6? = @b tr`f vb s tdod dp

?: ) > :8

Lb 6:= Np 1L o ?3 l` do sb`d tre`f o


15/47

Lb tp Ze` np 1 1;

Z\[@F ZG ZE@ ENRGXBO B_B Zr Zdb 821?.:?8 222l. Dg `ay n td `g `fy


16/47

Lb tp Ze` np 1 13

Z\[@F ZG ZE@ ENRGXBO B_B Zr Zdb 821?.:?8 222Lb 43 = Fbb lb te` tdke tg tt sau=

A` v L`d o = ;: d` lb

L`d o = ? odo d` lb

A` o = d` lb5

Lb fbb

Lb 46= _ 5

44 ' > ;3 1< 7 6?

68 0 2 ;3 7 :1Lb 44 = a. Gt tu` n o gy `fy 5

l. Sbt t` oo `fy tre`f tu` n lt u t td dab

o. Sbt t` `d`f `fy kg id`f ` tr`f 5

Lb 42 = Dg `ay n fy 1; v n `fy td t

@fy gab n `fy v n `fy td

@fy iba n `fy v n `fy td

Dg qua n `fy v n `fy td

Lb 28 = Kg b `f no 2 fb tb Idb ibg `f` od v e s . ibg jb odve s

Lb 21 = F g p


17/47

Lb tp Ze` np 1 16

Z\[@F ZG ZE@ ENRGXBO B_B Zr Zdb 821?.:?8 222Zg tt

Gab o = ?6 vb` lb

D`f o = : odo vb` lb

Gab v D`f = vb` lb 5

Lb fbb

Lb 2? = O tag fbo

Lb 2:= @d @fa `ub 3: oe` f v vt. tre`f o : odo oe` f Db `d @fa`ub lae `dbu oe` vt5

Lb fbb

Lb 2;= O 68 l` b tdag qua` O :8 l` n` xk t td `dt Db o lae`dbu l` oda n` xk5

Lb fbb

Lb 23= Z sod oa A` o 68 quy` truy` @ay A` gua tdg 18 quy` truy`tra`d v 3 quy` le `db `f Db t sod oa A` o tt o lae `dbu quy`truy` v le5

Lb fbb


18/47

Lb tp Ze` np 1 14


Lb 26= @ag o 1? qu l`f lay gu xa`d. ; qu l`f lay gu v


19/47

Lb tp Ze` np 1 12

Z\[@F ZG ZE@ ENRGXBO B_B Zr Zdb 821?.:?8 222Lb fbb

Lb 18


20/47

Lb tp Ze` np 1


21/47

Lb tp Ze` np 1 . 0. 7

4< ' :1 ;? ' 1

Chon_271 Đề ÔN LUYỆN TOÁN 1.pdf

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