Chapter 11 ORGANIC CHEMISTRY STUDYOFCARBON -CONTAINING COMPOUNDS.

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Chapter 1 1 ORGANIC CHEMISTRY STUDY OF CARBON -CONTAINING COMPOUNDS C H H H H Methane HO C om plicated organic m olecule

Transcript of Chapter 11 ORGANIC CHEMISTRY STUDYOFCARBON -CONTAINING COMPOUNDS.

Page 1: Chapter 11 ORGANIC CHEMISTRY STUDYOFCARBON -CONTAINING COMPOUNDS.

Chapter 1 1

ORGANIC CHEMISTRYSTUDY OF CARBON-CONTAINING COMPOUNDS

CH

H

H

H

MethaneHO

Complicated organic molecule

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SHORT HISTORY OF CHEMISTRY

PRE-1828 ERA

TWO MAJOR DISCIPLINES EMERGING

INORGANIC - MINERAL CHEMISTRY

ORGANIC CHEMISTRY - PLANTS AND ANIMALS

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ORGANIC COMPOUNDSCHARACTERISTIC PRODUCTS OF LIVING ORGANISMS

SUBSTANCES LIKE SUGAR AND OLIVE OILINORGANIC COMPOUNDS

PRODUCTS FROM NON-LIVING ENVIRONMENT

SUBSTANCES LIKE WATER AND IRON

BERZELIUS’ DEFINITIONS

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Vital Force Theory

INORGANIC MATERIALS COULD BE CONVERTEDTO ORGANIC MATERIALS IN THE PRESENCE OF A VITAL FORCE FOUND ONLY IN LIVING BODIES.

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In addition to Vital Force Theory

Organics hard to purify

Appeared to violate the Law of Definite Proportions

Organic Little Studied

Isomerism problem - same molecular formula butDifferent compounds

Consider ethanol and dimethyl ether

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Woehler’s urea synthesis

Ammonium isocyanate + heat ------> urea

NH4CNONH2CONH2

“I have been able to make urea without aid of kidneyof man or dog.

1828

1828

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Chapter 1 7

Deutsche Museum

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Chapter 1 8

STYLES

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Chapter 1 9

Schubert

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Chapter 1 10

Liszt - Young

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BIRTHSJULES VERNE - AROUND THE WORLD IN 80 DAYS

LEO TOLSTOY - ANNA KORNINA

HANS CHRISTIAN ANDERSON

MARRIAGESBARTHOLOMEW HEIFNER AND POLLY GRISHAM.IN SHELBY COUNTY, ENGLAND

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IMPORTANT EVENTSANDREW JACKSON ELECTED PRESIDENT OF USA DEFEATED JOHN Q. ADAMS

RUSSO-PERSIAN WAR ENDED

FATH ‘ALI SHAH’ AND RUSSIAN COUNTERPARTSIGNED TURKMANCHAI TREATY

GAVE RUSSIA - GEORGIA, ARMENIA, AND AZERBAIJAN

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Post 1828•Over 18,000 million compounds have been synthesized

•Pharmaceuticals

•Biochemicals

•Plastics

•Agrichemicals

•Paints

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Why so many organic?

H O N X P S Se

FORMS COVALENT BONDS WITH MANY METALS

Li Mg Al Cd Fe

FORMS COVALENT BONDS WITH NON-METALS

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WITH ITSELF

CC

CC

C

CHAINS

CCH

CCH

C

CHAINS WITH BRANCHES

C CC

CC

C

CC

RINGS

No limit

AND

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Allotropic Forms of Carbon

Graphite --layers of carbon atoms

Diamond -- 3-D tetrahedral

Buckmeisterfullerene (Bucky Ball) -- Soccer ball

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Atomic Structure

• protons, neutrons, and electrons

• isotopes

C12

6 6C14

=>

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Atomic Orbitals

2s orbital (spherical)

2p orbital =>

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Electronic Configurations

• Aufbau principle: Place electrons in lowest energy orbital first.

• Hund’s rule: Equal energy orbitals are half-filled, then filled.

=>

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Table 1-1

=>

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Bond Formation

• Ionic bonding: electrons are transferred.

• Covalent bonding: electron pair is shared.

=>

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Periodic table

• Here He Beneath Blue Sea ©, Not• One Frigate Near. Na Might All Sinking• Poopdecks Shot Cleanly Away,

Potassium,Sodium• H He• Li Be B C N O F Ne• Na Mg Al Si P S Cl A• K Ca

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Lewis Structures

• Bonding electrons

• Nonbonding electrons or lone pairs

Satisfy the octet rule! =>

C

H

H

H

OH

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TIPS

• Neutral atoms Carbon 4 bonds (double bonds count as 2

triple bonds count as 3) and NO lone pairs. Nitrogen 3 bonds and one lone pair

Oxygen 2 bonds and two lone pairs BORON 3 bonds BUT no lone pairsOne who writes MORE than 3 bonds about a

neutral BORON is a MORON

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C H-H+

CH- -

C+

N H-H+

N+ H+

N HH+

O

H-H+

O+H+

O

H+

H

TIPS2

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Multiple Bonding

=>

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EXAMPLES

CO2SO2 C2H3N

C3H6O isomer problem

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Electronegativity and Bond Polarity

Greater EN means greater polarity

=>

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C------Br C-------Li

C-------NBr--------Cl

EXAMPLES OF BOND POLARITY

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Calculating Formal Charge

• For each atom in a valid Lewis structure:• Count the number of valence electrons• Subtract all its nonbonding electrons• Subtract half of its bonding electrons

C

H

H

H

C

O

O P

O

OO

O

3-

=>

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EXAMPLES

C2H3O

HONH3

+

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Ionic Structures

C

H

H

H N

H

H

H

+

Cl-

Na O CH3 or O CH3Na+

_

X

=>

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Resonance - More than one Lewis Diagram

Example

C

O

C OH

H H

-1

Acetate ion

N

O

O

:

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Resonance Example

• Consider writing Lewis structure for NO3-2

• The real structure is a resonance hybrid.• All the bond lengths are the same.• Each oxygen has a -1/3 electrical charge.

=>

N

O

OO

_ _

N

O

OO

_

N

O

OO

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Must be legitimate Lewis structures

N

CH3

H3C

CH3

CH2+

-

N

CH3

H3C

CH3

CH2

NO NO Pentavalent nitrogen atom!!

Resonance Rules

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• Only electrons can be moved (usually lone pairs or pi electrons).

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Resonance structures?

N

O

O

: N

O

O

:

OK

CH

H

H

O

HCH

HOH

H

NO NO

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Nuclei positions and bond angles remain the same.

C=C-C+ +C-C=C

CAN”T SAY “if you turn one around 180o you wouldEnd up with same structure”

Doing so would violate this rule

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The number of unpaired electrons remains the same

H3C CH3..

H3C CH3

. .NO NO

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DELOCALIZATION OF CHARGE USUALLY IS

STABILIZING

Delocalization of charge results in fractional chargesat alternate atoms

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Major Resonance Form

• has as many octets as possible.

• has as many bonds as possible.

• has the negative charge on the most electronegative atom.

• has as little charge separation as possible.

Example

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Major Contributor?

CH

HN

H

H

+C

H

HN

H

H

+

major minor, carbon does

not have octet.

=>

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Other Examples

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Chemical Formulas

• Full structural formula (no lone pairs shown)

• Line-angle formula

• Condensed structural formula

• Molecular formula• Empirical formula

CH3COOH• C2H4O2

• CH2O =>

C

H

H

H

C

O

O H

OH

O

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BrØnsted-Lowry Acids and Bases

• Acids can donate a proton.

• Bases can accept a proton.

• Conjugate acid-base pairs.

CH3 C

O

OH + CH3 NH2 CH3 C

O

O-

+ CH3 NH3+

=>

acid base conjugatebase

conjugateacid

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CH3CO2H+ :NH3 CH3CO2

- + NH4+

ACID

BASE

CONJ BASE

CONJ ACID

H3C

O:

OH+ H2SO4

H3C

OH

OH

++ -HSO4

Amphoterism - ability to behave as an acid or base

EXAMPLES

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Acid and Base Strength• Acid dissociation constant, Ka

• Base dissociation constant, Kb

• For conjugate pairs, (Ka)(Kb) = Kw

• Spontaneous acid-base reactions proceed from stronger to weaker.

CH3 C

O

OH + CH3 NH2 CH3 C

O

O-

+ CH3 NH3+

pKa 4.74 pKb 3.36 pKb 9.26 pKa 10.64

=>

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EXAMPLESWill NaOH neutralize phenol (C6H5OH)?

NaOH +

C6H5OH

HOH + C6H5ONa

pKa = 10 pKa = 15.7

_-OH

C6H5OH

HOH + C6H5O-+

YES!!

Weaker acidStronger acid

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Determining Relative Acidity

• Electronegativity

• Size

• Resonance stabilization of conjugate base

=>

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ElectronegativityAs the bond to H becomes more

polarized, H becomes more positive and the bond is easier to break.

=>

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Size• As size increases, the H is more loosely

held and the bond is easier to break.• A larger size also stabilizes the anion.

=>

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Resonance

• Delocalization of the negative charge on the conjugate base will stabilize the anion, so the substance is a stronger acid.

• More resonance structures usually mean greater stabilization.

CH3CH2OH < CH3C

O

OH < CH3 S

O

O

OH

=>

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Lewis Acids and Bases• Acids accept electron pairs = electrophile

• Bases donate electron pairs = nucleophileCH2 CH2 + BF3 BF3 CH2 CH2

+_

nucleophile electrophile

=>

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End of Chapter 1