BATCH 13 Review 1 Phase 2

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    REVIEW-1PHASE II

    MODELLING, DESIGN AND ANALYSIS OF

    SELF-ANCHORED SUSPENSION BRIDGE

    DONE BY:

    MIRZA ABDUL BASIT BEIGH - 1011010112

    GRANDHI VENKATA ROHIT - 1011010072

    K. GURU KESAV KUMAR - 1011010075

    JASTHI SATHISH RAO - 1011010084

    PROJECT GUIDE:

    Mrs. B. VELVIZHI KUMARAVEL

    Assistant Professor (O.G)

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    PHASE- II

    SCHEDULE

    SNO DESCRIPTION DURATION(days)

    START END

    1.

    Analysis 2

    60

    1st

    January2014 28

    th

    February2014

    2. Design 2 30 1stMarch2013

    30thMarch

    2014TOTAL 90 1stJanuary

    201430thMarch

    2014

    2

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    SPECIFICATIONS OF THE MODEL

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    1. TOTAL SPAN = 1000 MM

    2. LENGTH OF MAIN SPAN = 545 MM

    3. LENGTH OF SIDE SPAN = 227.5 MM

    4. SAG IN MAIN CABLE = 86 MM

    5. SAG IN SIDE CABLE = 15 MM

    6. CLEARANCE OF DECK = 200MM7. HEIGHT OF PYLON FROM DECK = 90MM

    8. ANGLE BETWEEN PYLON AND

    SIDE SPAN CABLE () = 75.22

    9. ANGLE BETWEEN PYLON AND

    MAIN SPAN CABLE () = 56.55

    10.TOTAL NUMBER OF SUSPENDERS = 33

    WITH SPACING OF 30.2775 MM

    11. LENGTH OF THE MAIN CABLE = 581.18

    12. LENGTH OF THE SIDE SPAN CABLE = 230

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    DESIGN OF PROTOTYPE (SCALED DOWN MODEL)

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    Longitudinal Section of Self-Anchored Suspension Bridge

    LONGITUDINAL ELEVATION:

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    Design II

    Design of the deck slab

    Design of the truss

    Design of the Suspenders and Main Cable Design of the Pylons

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    DESIGN OF DECK SLABusing ArchiCAD Model

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    3D VIEW OF DECK SLAB

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    DIMENSIONS OF DECK SLAB

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    THE INTERNAL ANGLE OFDECKSLAB IS 34.5

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    Staad Pro Model of Deck Slab

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    Analysis of Deck Slab girder

    using Finite Element Analysis

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    Application of tensile force to checkthe deflection under self weight.

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    Deflection under self weight after pre

    tensioning.

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    Global Bending Moment of deck under

    Self weight

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    Global Bending Moment of deck after

    pre tensioning

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    CALCULATION

    Sag in the main cable

    EUDL ( Equivalent uniformly distributedload)

    Tension in the cable

    Length of the cable

    Sag in the main cableSag/Span=1/6=85/545

    f2=f1* L22/L1

    2

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    EUDL ( Equivalent uniformly distributed load) for a UDL

    (Uniformly distributed load shorter than span)

    W= 2wa/L2(L-a/2)

    Where, a= Length of UDL.L= Length of span.

    w= Total live load.

    EUDL ,

    W= 2(96)(4.2)/4.22(54.5-4.2/2)= 2395.42 KN/cm

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    2. Cable tension.

    T= VA2+H2

    1. Horizontal force component,

    H= pL2/8d.

    P= Equivalent load.d= Sag.

    L= Length of mid span.

    H= (2395.42) (54.5)2

    / 8(0.86).Horizontal component H= 1034.15 * 103 KN.

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    3. Vertical force component,

    VA= VB= pL/2.

    VA= Vertical force A.

    VB= Vertical force B.

    P= Equivalent load.L= Length of mid span.

    VA= VB= PL/2= (2395.42)(545)2/2

    So, Vertical Component VA= VB= 652.75 x 103

    KN.

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    Cable tension

    T= VA2+H2

    T= (652.75x 103

    )2

    + (1034.15 x 103

    )2

    T= ((4.260 x 1011) + (1.069 x 1012))

    T= 1222 x 106KN

    Tan = H/V= L/4d.= tan-I (L/4a).

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    4. Length of the cable.

    Length of the cable S= L+(8/3)(d2/L)

    S =545+(8/3)(862

    /545)= 581m

    So, Length of the main cable is 581m.

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    CURRENT STATUS Optimization of loads for deck slab

    Design of the deck slab girder using steelslender section

    Design of stiffening truss member underthe deck slab

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    NEXT STEPS

    Influence Line diagrams for the rollingloads

    Design of Cables, Suspenders and Pylons

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    OPTIMIZATION Verification and optimization of the

    Analysis vis--vis design of the Self

    Anchored Bridge part by part and then

    assembled as a whole manually plus

    supported by software details.

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