Arithmetic and Geometric Series (11.5) Short cuts.

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Arithmetic and Geometric Series (11.5) Short cuts

Transcript of Arithmetic and Geometric Series (11.5) Short cuts.

Page 1: Arithmetic and Geometric Series (11.5) Short cuts.

Arithmetic and Geometric Series (11.5)

Short cuts

Page 2: Arithmetic and Geometric Series (11.5) Short cuts.

POD

Consider a list of the first 100 positive integers.

What sort of sequence is it?

Add them. I’ll time how long it takes.

What do we call a sum of terms in a sequence?

Page 3: Arithmetic and Geometric Series (11.5) Short cuts.

POD

Consider a list of the first 100 positive integers.

It’s an arithmetic sequence, with d = 1.

We’re finding a series. We use sigma notation, or we can use Sn notation.

Want a short cut? It’s based off of something we did yesterday.

Page 4: Arithmetic and Geometric Series (11.5) Short cuts.

Arithmetic partial sums

To figure this out, start smaller. Add the first 10 positive integers. Remember what we did yesterday?

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 =

Page 5: Arithmetic and Geometric Series (11.5) Short cuts.

Arithmetic partial sums

To figure this out, start smaller. Add the first 10 positive integers. Remember what we did yesterday?

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 =

10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 =

What do we do next? Can you think of a pattern?

Page 6: Arithmetic and Geometric Series (11.5) Short cuts.

Arithmetic partial sums

To figure this out, start smaller. Add the first 10 positive integers. Remember what we did yesterday?

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 =

10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 =

11+11+11+11+11+11+11+11+11+11=110

We added the first and last terms.

Page 7: Arithmetic and Geometric Series (11.5) Short cuts.

Arithmetic partial sums

To figure this out, start smaller. Add the first 10 positive integers. Remember what we did yesterday?

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 =

10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 =

11+11+11+11+11+11+11+11+11+11=110

We need only half of the number of sums here.

Page 8: Arithmetic and Geometric Series (11.5) Short cuts.

Arithmetic partial sums

To figure this out, start smaller. Add the first 10 positive integers. Remember what we did yesterday?

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 =

10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 =

11+11+11+11+11+11+11+11+11+11=110

nn ttn

S 12

Page 9: Arithmetic and Geometric Series (11.5) Short cuts.

Arithmetic partial sums

Use this to answer the POD.

nn ttn

S 12

Page 10: Arithmetic and Geometric Series (11.5) Short cuts.

Arithmetic partial sums

Use this to answer the POD.

S100 = 100/2(1 + 100)

= 50(101)

= 5050

This problem was posed to Karl Friedrich Gauss (1777-1855) in third grade, and he determined the pattern.

Page 11: Arithmetic and Geometric Series (11.5) Short cuts.

Arithmetic partial sums

We have another tool, too. What is the formula for the nth term of an arithmetic sequence? How could we use it to change this formula?

nn ttn

S 12

Page 12: Arithmetic and Geometric Series (11.5) Short cuts.

Arithmetic partial sums

We have another tool, too. What is the formula for the nth term of an arithmetic sequence? How could we use it?

dntn

S

dntt

ttn

S

n

n

nn

)1(22

)1(

2

1

1

1

Page 13: Arithmetic and Geometric Series (11.5) Short cuts.

Arithmetic partial sums

We decide which tool to use based on the information given. What information would you need to either one?

dntn

S

ttn

S

n

nn

)1(22

2

1

1

Page 14: Arithmetic and Geometric Series (11.5) Short cuts.

Use them

1. Find the sum of the first 50 positive even integers. Which formula would you use?

How does this compare to the sum of the first 100 positive integers?

Page 15: Arithmetic and Geometric Series (11.5) Short cuts.

Use them

1. Find the sum of the first 50 positive even integers. Which formula would you use?

S50 = 50/2(2 + 100) = 25(102) = 2550

How does this compare to the sum of the first 100 positive integers?

Page 16: Arithmetic and Geometric Series (11.5) Short cuts.

Use them

1. Find the sum of the first 50 positive even integers.

Let’s look at it in summation notation.

2k 2 4 6 8 ...100k1

50

Page 17: Arithmetic and Geometric Series (11.5) Short cuts.

Use them

2. Find S12 for the series with t1 = 3 and d = -4

Page 18: Arithmetic and Geometric Series (11.5) Short cuts.

Use them

2. Find S12 for the series with t1 = 3 and d = -4.

S12 = 12/2(2(3) + (11)(-4))

= 6(6-44)

= 6(-38)

= -228

Page 19: Arithmetic and Geometric Series (11.5) Short cuts.

Geometric shortcut

The shortcut for a geometric series uses the first term and r.

r

rtS

n

n 1

11

Page 20: Arithmetic and Geometric Series (11.5) Short cuts.

Use it

3. Find S8 for 1 + 2 + 4 +8 +….

r

rtS

n

n 1

11

Page 21: Arithmetic and Geometric Series (11.5) Short cuts.

Use it

3. Find S8 for 1 + 2 + 4 +8 +….

r

rtS

n

n 1

11

2551

2561

21

211

8

8

S

Page 22: Arithmetic and Geometric Series (11.5) Short cuts.

Use it

4. Find S20 for the series with first term of 11 and

r = 1.3.

Page 23: Arithmetic and Geometric Series (11.5) Short cuts.

Use it

4. Find S20 for the series with first term of 11 and

r = 1.3.

820.6931)165.630(113.

050.18911

3.11

3.1111

20

20

S