5.6 inequalities in two triangles and indirect proof

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5.6 5.6 Inequalities in Two Triangles and Indirect Proof Bell Thinger Write the if-then form, converse, inverse, and contrapositive of the given statement. 3x – 8 = 22 because x = 10. ANSWER If x = 10, then 3x – 8 = 22. Con: If 3x – 8 = 22, then x = 10. Inv: If x ≠ 10, then 3x – 8 ≠ 22. Contra: If 3x – 8 ≠ 22, then x ≠ 10. n ABC, BC = 18, AB = 13, and AC = 16. List the ngles of the triangle from least to greatest. ANSWER C, B, A

Transcript of 5.6 inequalities in two triangles and indirect proof

Page 1: 5.6 inequalities in two triangles and indirect proof

5.65.6 Inequalities in Two Triangles and Indirect ProofBell Thinger

1. Write the if-then form, converse, inverse, and contrapositive of the given statement. 3x – 8 = 22because x = 10.

ANSWER If x = 10, then 3x – 8 = 22. Con: If 3x – 8 = 22, then x = 10. Inv: If x ≠ 10, then 3x – 8 ≠ 22. Contra: If 3x – 8 ≠ 22, then x ≠ 10.

2. In ABC, BC = 18, AB = 13, and AC = 16. List theangles of the triangle from least to greatest.

ANSWER C, B, A

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5.6Example 1

SOLUTION

You are given that ST PR and you know that PS PS by the Reflexive Property. Because 24 inches > 23 inches, PT >RS. So, two sides of STP are congruent to two sides of PRS and the third side in STP is longer.

Given that ST PR , how doesPST compare to SPR?

By the Converse of the Hinge Theorem, mPST > m SPR.

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5.6Example 2

Which group is farther from camp? Explain your reasoning.

BIKING Two groups of bikers leave the same camp heading in opposite directions. Each group goes 2 miles, then changes direction and goes 1.2 miles. Group A starts due east and then turns 45° toward north as shown. Group B starts due west and then turns 30° toward south.

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SOLUTION

Draw a diagram and mark the given measures. The distances biked and the distances back to camp form two triangles, with congruent 2 mile sides and congruent 1.2 mile sides. Add the third sides of the triangles to your diagram.

Next use linear pairs to find and mark the included angles of 150° and 135°.

Because 150° > 135°, Group B is farther from camp by the Hinge Theorem.

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Example 2

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5.6Guided Practice

1. WHAT IF? In Example 2, suppose Group C leaves camp and goes 2 miles due north. Then they turn 40° toward east and continue 1.2 miles. Compare the distances from camp for all three groups.

Group B is the farthest from camp, followed by Group C, and then Group A which is the closest.

ANSWER

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Use the diagram at the right.

2. If PR = PS and mQPR > mQPS, which is longer, SQ or RQ ?

ANSWER RQ

3. If PR = PS and RQ < SQ, which is larger, RPQ or SPQ?

ANSWER SPQ

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Guided Practice

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5.6Example 3

Write an indirect proof that an odd number is not divisible by 4.

GIVEN: x is an odd number.

PROVE: x is not divisible by 4.

SOLUTION

STEP 1 Assume temporarily that x is divisible by 4.

This means that = n for some whole

number n. So, multiplying both sides by 4 gives x = 4n.

x4

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STEP 2 If x is odd, then, by definition, x cannot be divided evenly by 2.However, x = 4n so = = 2n.

We know that 2n is a whole number because n is a whole number, so x can be divided evenly by 2. This contradicts the given statement that x is odd.

x2

4n2

STEP 3 Therefore, the assumption that x is divisible by 4 must be false, which proves that x is not divisible by 4.

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Example 3

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5.6Guided Practice

4. Suppose you wanted to prove the statement “If x + y = 14 and y = 5, then x = 9.” What temporary assumption could you make to prove the conclusion indirectly? How does that assumption lead to a contradiction?

Assume temporarily that x = 9; since x + y 14 and y = 5 are given, letting x = 9 leads to the contradiction 9 + 5 14.

ANSWER

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5.6Example 4

Write an indirect proof of Theorem 5.14.

GIVEN: AB DE

BC EF

AC > DF

PROVE: m B > m E

PROOF: Assume temporarily that m B > m E. Then, it follows that either

m B = m E or m B < m E.

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5.6Example 4

Case 1 If m B = m E, then B E. So, ABC DEF by the SAS Congruence Postulate and AC =DF.

Case 2 If m B < m E, then AC < DF by the Hinge Theorem.

Both conclusions contradict the given statement that AC > DF. So, the temporary assumption that m B > m E cannot be true. This proves that m B > m E.

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2. m 1 m 2?

Exit Slip

Complete each statement with < , > , or = .

1. KL NP ?

ANSWER < ANSWER <

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5.6Exit Slip

Assume ABC is a right triangle.ANSWER

Suppose you want to write an indirect proof of this statement: “In ABC, if m A > 90° then ABC is not a right triangle.” What temporary assumption should start your proof?

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Homework

Pg 352-355#4, 6, 14, 17, 22