5116 pressure slides ed

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Chapter 7 Pressure

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Transcript of 5116 pressure slides ed

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Chapter 7

Pressure

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At the end of this chapter,you should be able to Define pressure in terms of force

and area and recall the relationship: Pressure = Force/Area

Apply the relationship between pressure, force and area to new situations or to solve related problems.

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Quiz Time Why do camels have large flat feet? Why do eskimos wear snow shoes?

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6.1 Pressure

Pressure is defined as

Formula

force acting per unit area.

P =AF

where P = PressureF = Force (N)A = Area where the force is acting on (m2)

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6.1 Pressure

The S.I. unit of pressure is

or

Newton per square metre (N m-

2) Pascal (Pa).

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Quiz Time An elephant weighs 40 000 N

while a lady wearing high heels weighs 400 N. Who will exert a greater pressure on the ground if both were to stand on one leg?

Given:

Area of a elephant foot = 0.1 m2

Area of a heel = 0.0001 m2

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Quiz Time

Pressure exerted by elephant

= Force / Area

= 40 000 / 0.1

= 400 000 Pa

Pressure exerted by lady

= Force / Area

= 400 / 0.0001

= 4 000 000 Pa

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Quiz Time

Pressure exerted by elephant

= 400 000 Pa

Pressure exerted by lady

= 4 000 000 Pa

The lady’s heel exerts a higher pressure than the elephant foot.

So who hurts more when they step on you?

The elephant’s foot or the lady’s heel?

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Quiz When a balloon is pressed against a

single nail, it will burst. However, when the balloon is pressed against a bed of nails with the same amount of force, it will NOT. WHY??

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Quiz Applying the same amount of force, a

single nail having a smaller area of contact will exert a higher pressure to the balloon as compared to the pressure exerted by a bed of nails.

On the bed of nails, the force is distributed over all the nails, hence the area of contact is larger which result in a lower pressure acting on the balloon. Hence the balloon does not pop easily on it.

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6.1 Pressure

In conclusion,

To increase pressure, we can either

Increase the force applied.

Decrease the area of contact.

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Example 1

The atmospheric pressure is 100 kPa. What is the force exerted by the atmosphere on a rectangular surface that measures 0.5 m by 0.4 m?Pressure P = F A F = P × A = (100×103) ×(0.5×0.4)

= 20 000 N

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Example 2

The tyres of a car are in contact with the ground over a total area of 3.0 10-2 m2. The total weight of the car is 6300 N. Calculate the pressure exerted by the tyres on the ground.Pressure = F A = 6300 3.0×10-2

= 2.1 × 105 Pa

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Example 3

A standing man has a total contact area between his feet and the ground of 400 cm2. He is 60 kg. Calculate the pressure exerted on the ground by the man. Weight of the man W = mg = 60 × 10 = 600 NArea A = 400 cm2

= 400 × 10-4

= 4 × 10-2 m2

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Example 3

Pressure = W A = __600___ 4 × 10-2

= 15 000 Pa