2-Heat Conduction Equation

download 2-Heat Conduction Equation

of 24

Transcript of 2-Heat Conduction Equation

  • 7/25/2019 2-Heat Conduction Equation

    1/24

    Heat transfer has direction as well as

    magnitude, and thus it is a vector quantity

  • 7/25/2019 2-Heat Conduction Equation

    2/24

    The various distances and angles involved when describing the

    .

  • 7/25/2019 2-Heat Conduction Equation

    3/24

    Fouriers law of heat conduction

    for one-dimensional heat conduction:

    )Watt(dx

    dTkAQcond =&

    If n is the normal of the isothermal surface atpoint P, the rate of heat conduction at that point

    can be expressed by Fouriers law as

    The heat transfer vector is

    )Watt(n

    TkAQn

    =&

    always normal to an isothermal

    surface and can be resolved

    into its components like any

    kQjQiQQ zyxn

    r&

    r&

    r&

    r& ++=

    P.Talukdar/Mech-IITD x

    T

    kA

    Q xx

    =&

    y

    T

    kAQ yy

    =&

    z

    T

    kAQ zz

    =&

  • 7/25/2019 2-Heat Conduction Equation

    4/24

    Steady versus Transient Heat

    Transfer

    The term stead im lies no

    change with time at any pointwithin the medium, while

    with time or time dependence.

    Therefore, the temperature orheat flux remains unchanged

    with time during steady heat

    transfer throu h a medium at

    any location, although both

    quantities may vary from one

  • 7/25/2019 2-Heat Conduction Equation

    5/24

    Multidimensional Heat

    Transfer

    Heat transfer roblems are also classified as bein one-

    dimensional, two-dimensional, or three-dimensional,depending on the relative magnitudes of heat transfer rates in

    Ex:1Dheattransfer:

    Heattransfer

    through

    the

    glass

    of

    a

    w n owcan econs ere to eone

    dimensionalsinceheattransferthrough

    theglasswilloccurpredominantlyinone

    direction(thedirectionnormaltothe

    surfaceof

    the

    glass)

    and

    heat

    transfer

    in

    otherdirections(fromoneside

    edgetotheotherandfromthetopedge

  • 7/25/2019 2-Heat Conduction Equation

    6/24

    A medium through which heat is conducted may involve the

    , ,

    (or thermal) energy. In heat conduction analysis, suchconversion processes are characterized as heat generation.

    Heat generation is a volumetric phenomenon. That is, it occurs

    throughout the body of a medium. Therefore, the rate of heat

    whose unit is W/m3

    The rate of heat generation in a

    as position within the medium.

    When the variation of heat

    generation with position is known,= dVgG && Watt

    P.Talukdar/Mech-IITD

    g p

    the total rate of heat generation in

    a medium of volume V can bedetermined from

  • 7/25/2019 2-Heat Conduction Equation

    7/24

    1 D Heat Conduction Equation

    Assume the density of the wall is , the specificheat is C, and the area of the wall normal to thedirection of heat transfer is A.

    An energy balance on this thin element during

    t

    GQQ elementelementxxx

    =+ + &&&

  • 7/25/2019 2-Heat Conduction Equation

    8/24

    )TT(x.A.C)TT(mCEEE tttttttttelement === +++

    x.A.gVgG elementelement == &&&

    E&&&

    t

    elementxxx

    =+ +

    TT &&

    Dividin b

    tx..x..gxxx

    =+ +

    &&Ax gives

    tCg

    xA

    tttxxx

    =+

    ++ &

    Taking the limit as x0 and t0 yields and since from Fouriers Law:

    =

    =+

    x

    TkA

    xx

    Q

    x

    QQ xxxlim

    &&&

    t

    Cg

    x

    kA

    xA

    =+

    &

  • 7/25/2019 2-Heat Conduction Equation

    9/24

    Plane wall: A is constant

    Variable conductivity:t

    Cgx

    kx

    =+

    &

    2&

    Constant conductivity:

    where the property k/C is the thermal

    tk

    g

    x2 =+

    diffusivity

  • 7/25/2019 2-Heat Conduction Equation

    10/24

    Heat Conduction Equation in a

    L C li dong Cylinder

    ons er a n cy n r ca s e e emen o

    thickness r in a long cylinder

    The area of the c linder normal to the

    direction of heat transfer at any location is A =

    2rL where r is the value of the radius at that

    location. Note that the heat transfer area A,

    location.

    &&&

    tGQQ e ementelementrrr

    =+ +

  • 7/25/2019 2-Heat Conduction Equation

    11/24

    )TT(r.A.C)TT(mCEEE tttttttttelement === +++

    r.A.gVgG elementelement == &&&

    t

    r.A.Cr.A.gQQ tttrrr =+ ++ &

    &&dividing by Argives t

    CgrA

    tttrrr

    =+

    ++ &

    T&&&

    == rrrrrrr

    0rm

    TT1 &

    tg

    rrA =

  • 7/25/2019 2-Heat Conduction Equation

    12/24

    TT1

    &

    tr

    ..

    rr

    =

    &Constant Conductivity:

    tkrr

    rr =+

    dTd1 &

    krdr

    drr=+

    t

    T1

    r

    Tr

    rr

    1

    =

    0rd

    dTr

    dr

    d=

  • 7/25/2019 2-Heat Conduction Equation

    13/24

    .

    A = 4r2

    Variable conductivity:

    t

    TCg

    r

    T.k.r

    rr

    1 22

    =+

    &

    Constant Conductivity:t

    T1

    k

    g

    r

    Tr

    rr

    1 22

    =+

    &

    P.Talukdar/Mech-IITD

    CombinedOneDimensional

    Heat

    Conduction

    Equation t

    TCg

    r

    T.k.r

    rr

    1 nn

    =+

    &

  • 7/25/2019 2-Heat Conduction Equation

    14/24

    General Heat Conduction

    Equation

    &&&&&&&

    tGQQQQQQ e ementelementzzyyxxzyx

    =+++ +++

  • 7/25/2019 2-Heat Conduction Equation

    15/24

    )TT.(z.y.x.C)TT(mCEEE tttttttttelement === +++

    z.y.x.gVgG elementelement == &&&

    t

    EGQQQQQQ elementelementzzyyxxzyx

    =+++ +++ &&&&&&&

    t

    TT

    z.y.x.Cz.y.x.gQQQQQQttt

    zzyyxxzyx

    =+++ +

    +++ &

    &&&&&&

    TTQQ1QQ1QQ1 tttzzzyyyxxx ++++ &&&&&&&

    tzy.xyz.xxz.y

  • 7/25/2019 2-Heat Conduction Equation

    16/24

    TT1QQ11 &&&&&&&

    tg

    zy.xyz.xxz.y =+

    &&&

    =

    =

    =

    +

    x

    k

    xx

    z.y.k

    xz.yxz.yxz.y

    lim xxxx

    0x

    =

    =

    =+ T

    kT

    z.x.k1Q1QQ1

    limyyyy

    &&&

    ...

    =

    =

    =

    +

    z

    Tk

    zz

    Ty.x.k

    zy.x

    1

    z

    Q

    y.x

    1

    z

    QQ

    y.x

    1lim zzzz

    0z

    &&&

    t

    TCg

    z

    Tk

    zy

    Tk

    yx

    Tk

    x

    =+

    +

    +

    &

    Under what condition?

    222&

    tkzyx222

    =+

    +

    +

  • 7/25/2019 2-Heat Conduction Equation

    17/24

    0gTTT 222=+

    +

    +

    &

    zyx

    T1TTT2

    2

    2

    2

    2

    2 =

    +

    +

    0z

    TT

    x

    T2

    2

    2

    2

    2

    2

    =

    +

    +

  • 7/25/2019 2-Heat Conduction Equation

    18/24

    TTT1T1

    &tz

    .z

    .rr

    .rr 2

    TT1T1T1 2 &

    t.

    sinrsinrr.

    rr 2222

  • 7/25/2019 2-Heat Conduction Equation

    19/24

    Boundary and Initial Conditions

    The temperature distribution in a medium depends on the

    conditions at the boundaries of the medium as well as the heat

    transfer mechanism inside the medium. To describe a heat

    transfer problem completely, two boundary conditions must be

    heat transfer is significant.

    T ere ore, we nee to spec y two

    boundary conditions for one-dimensional

    problems, four boundary conditions for

    - ,

    boundary conditions for three-dimensional

    problems

  • 7/25/2019 2-Heat Conduction Equation

    20/24

    con on, w c s usua y spec e a me = , s ca ethe initial condition, which is a mathematical expression for

    the temperature distribution of the medium initially.

    )z,y,x(f)0,z,y,x(T =

    Note that under steady conditions, the heat conduction

    equation does not involve any time derivatives, and thus we do

    not need to s ecif an initial condition

    The heat conduction equation is first order in time, and thus the initial

    condition cannot involve any derivatives (it is limited to a specified

    temperature).However, the heat conduction equation is second order in space

    coordinates, and thus a boundary condition may involve first

    er vat ves at t e oun ar es as we as spec e va ues o temperature

  • 7/25/2019 2-Heat Conduction Equation

    21/24

    Specified Temperature Boundary

    C di iondition

    The temperature of an exposed surface can

    usually be measured directly and easily.

    Therefore, one of the easiest ways to

    specify the thermal conditions on a surface

    is to specify the temperature. For one-

    dimensional heat transfer through a planewall of thickness L, for example, the

    specified temperature boundary conditions

    can be expressed as

    1T)t,0(T =Tt,LT =

  • 7/25/2019 2-Heat Conduction Equation

    22/24

    Specified Heat Flux Boundary

    ondition

    determined by inspection: positive ifthe heat flux is in the positive

    rec on o e coor na e ax s, an

    negative if it is in the opposite

    direction.

    Note that it is extremely important to

    have the correct si n for the s ecified

    heat flux since the wrong sign will

    invert the direction of heat transfer

    interpreted as heat loss

  • 7/25/2019 2-Heat Conduction Equation

    23/24

    2medium from both sides, for example, the specified heat flux boundary

    conditions can be expressed as

    50x

    )t,0(Tk =50

    x)t,L(Tk =

    and

    Special Case: Insulated Boundary

    0x

    )t,0(Tk =

    0x

    )t,0(T=

    or

  • 7/25/2019 2-Heat Conduction Equation

    24/24

    t,L

    T

    0x

    =