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    Applied Mathematics Letters 19 (2006) 13611366

    www.elsevier.com/locate/aml

    Periodic solutions for discrete predatorprey systems with theBeddingtonDeAngelis functional response

    Jimin Zhang, Jing Wang

    School of Mathematics and Statistics, KLAS and KLVE, Northeast Normal University, 5268 Renmin Street, Changchun, Jilin, 130024, PR China

    Received 18 April 2005; received in revised form 22 January 2006; accepted 15 February 2006

    Abstract

    Sufficient criteria are established for the existence of positive periodic solutions of discrete nonautonomous predatorprey

    systems with the BeddingtonDeAngelis functional response using a continuation theorem.

    c 2006 Elsevier Ltd. All rights reserved.

    Keywords: Periodic solutions; Difference equations; Predatorprey; BeddingtonDeAngelis functional response; Coincidence degree

    1. Introduction

    Predatorprey interaction is one of the major forces shaping food webs. Since the great work of Lotka (in 1925)

    and Volterra (in 1926), modelling these interactions has been one of the central themes in mathematical ecology.

    One significant component of the predatorprey relationship is the predators rate of feeding upon prey, i.e., the so-called predators functional response. In general, the functional responses can be either prey dependent or predator

    dependent. Functional response equations that are strictly prey dependent, such as the Holling family ones, arepredominant in the literature.

    However, the prey-dependent ones fail to model the interference among predators, and have been facing challenges

    from the biology and physiology communities. The predator-dependent functional responses can provide better

    descriptions of predator feeding over a range of predatorprey abundances, as is supported by much significantlaboratory and field evidence (see [5] and references therein). The BeddingtonDeAngelis functional response,

    first proposed by Beddington [3] and DeAngelis [2], performed even better. So, predatorprey systems with theBeddingtonDeAngelis response have been studied extensively in the literature [1,6,7,9,10].

    It is well known that the discrete time models governed by difference equations are more appropriate than the

    continuous ones when the populations have nonoverlapping generations. In addition, discrete time models can also

    provide efficient computational models of continuous for numerical simulations. However, no such work has beendone for predatorprey systems with the BeddingtonDeAngelis functional response.

    Corresponding author.E-mail address: [email protected] (J. Zhang).

    0893-9659/$ - see front matter c 2006 Elsevier Ltd. All rights reserved.

    doi:10.1016/j.aml.2006.02.004

    http://www.elsevier.com/locate/amlmailto:[email protected]://dx.doi.org/10.1016/j.aml.2006.02.004http://dx.doi.org/10.1016/j.aml.2006.02.004mailto:[email protected]://www.elsevier.com/locate/aml
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    1362 J. Zhang, J. Wang / Applied Mathematics Letters 19 (2006) 13611366

    In this work, we will study the existence of positive periodic solutions of the discrete analogue of the predatorprey

    system with BeddingtonDeAngelis functional response explored by Fan and Kuang [ 5]. Following the clues in [4],

    with the help of differential equations with piecewise constant arguments, one can reach its discrete analogue

    x (k+ 1) = x (k) exp

    a(k) b(k)x (k)

    c(k)y(k)

    (k) + (k)x (k) + (k)y(k)y(k + 1) = y(k) exp

    d(k) +

    f(k)y(k)

    (k) + (k)x(k) + (k)y(k)

    , k Z (1.1)

    where Z denotes the set of integers. In the following, we will focus our attention on system (1.1). Considering the

    biological significance, we consider (1.1) with positive initial values and assume that the parameters in system (1.1)

    are nonnegative and -periodic with Z and > 1.

    2. Existence of positive periodic solutions

    Let Z+, R+ and R2 denote the set of nonnegative integers, nonnegative real numbers, and two-dimensional

    Euclidean vector space, respectively, and let

    Iw = {0, 1, 2, . . . , w 1} g = 1w

    w1k=0

    g(k) gu = maxkIw

    g(k) gl = minkIw

    g(k)

    where g(k) is a w-periodic sequence of nonnegative real numbers defined for k Z.Let X, Y be normed vector spaces, L : Dom L X Y be a linear mapping, N : X Y be a continuous

    mapping. The mapping L will be called a Fredholm mapping of index zero if dim Ker L = codim Im L < + and

    Im L is closed in Y. If L is a Fredholm mapping of index zero and there exist continuous projections P : X X andQ : Y Y such that Im P = Ker L , Im L = Ker Q = Im(I Q), it follows that L|Dom L Ker P : (I P)X

    Im L is invertible. We denote the inverse of that map by KP . If is an open bounded subset ofX, the mapping N will

    be called L-compact on ifQN() is bounded and KP (I Q)N : X is compact. Since Im Q is isomorphic

    to Ker L, there exists an isomorphism J : Im Q Ker L.

    Lemma 2.1 (Continuation Theorem [8]). Let L be a Fredholm mapping of index zero and N be L-compact on .Suppose:

    (a) for each (0, 1), every solution x of Lx = Nx is such that x ;(b) QNx = 0 for each x Ker L and the Brouwer degree deg{JQN, Ker L , 0} = 0.

    Then the operator equation Lx = Nx has at least one solution lying in Dom L .

    Lemma 2.2 ([4, Lemma 3.2]). Let g : Z R be w periodic, i.e., g(k + w) = g(k). Then for any fixed k1, k2 Iw,

    and any k Z, one has

    g(k) g(k1) +

    w1

    s=0

    |g(s + 1) g(s)| g(k) g(k2) w1

    s=0

    |g(s + 1) g(s)|.

    Define l2 = {u = u(k) : u(k) R2, k Z+}. Let lw l2 denote the subspace of all w periodic sequences with

    the usual supremum norm , i.e.,

    u = maxkIw

    |u1(k)| + maxkIw

    |u2(k)|, for any u = {u(k) : k Z+} lw.

    It is not difficult to show lw is a finite-dimensional Banach space. Let

    lw0 =

    u = {u(k)} lw :

    w1k=0

    u(k) = 0, k Z+

    lwc = {u = {u(k)} l

    w : u(k) = h R2, k Z+};

    then it follows that lw0 and lwc are both closed linear subspaces ofl

    w and lw = lw0 lwc , dim lwc = 2, so we reach ourmain result as follows:

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    J. Zhang, J. Wang / Applied Mathematics Letters 19 (2006) 13611366 1363

    Theorem 2.1. If a > (c/ ) and( f du )(a (c/))b1 exp{2a} du > 0, then system (1.1) has at least one

    positive periodic solution.

    Proof. First, let x(k) = exp{u1(k)}, y(k) = exp{u2(k)}, so that (1.1) becomes

    u1(k + 1) u1(k) = a(k) b(k) exp{u1(k)} c(k) exp{u2(k)}

    (k) + (k) exp{u1(k)} + (k) exp{u2(k)}

    u2(k + 1) u2(k) = d(k) +f(k) exp{u1(k)}

    (k) + (k) exp{u1(k)} + (k) exp{u2(k)}.

    (2.1)

    Define X = Y = lw, (Lu )(k) = u(k + 1) u(k), and

    N u = N

    u1u2

    (k) =

    a(k) b(k) exp{u1(k)} c(k) exp{u2(k)}

    (k) + (k) exp{u1(k)} + (k) exp{u2(k)}

    d(k) +f(k) exp{u1(k)}

    (k) + (k) exp{u1(k)} + (k) exp{u2(k)}

    for any u X and k Z+. It is trivially easy to see that L is a bounded linear operator and Ker L = lwc , Im L = lw0 ,

    as well as that dim Ker L = 2 = codim Im L. Since Im L is closed in Y, it follows that L is a Fredholm mapping ofindex zero. Define

    Pu =1

    w

    w1s=0

    u(s), u X, Qz =1

    w

    w1s=0

    z(s), z Y.

    It is easy to show that P and Q are continuous projections such that Im P = Ker L and Im L = Ker Q = Im(I Q).Then, the generalized inverse (to L) KP : Im L Ker P

    Dom L exists and is given by

    KP (z) =

    w1s=0

    z(s) 1

    w

    w1s=0

    (w s)z(s).

    Obviously, Q N and KP

    (I Q)N are continuous. Since X is a finite-dimensional Banach space, on the basis of the

    ArzelaAscoli theorem, it is not difficult to show that KP (I Q)N() is compact for any open bounded set X.

    Furthermore, Q N() is bounded, so N is L-compact on with any open bounded set X.

    For the application of the continuation theorem, we must search for an appropriate open, bounded subset .

    Corresponding to the operator equation Lu = N u, (0, 1), we have

    u1(k + 1) u1(k) =

    a(k) b(k) exp{u1(k)}

    c(k) exp{u2(k)}

    (k) + (k) exp{u1(k)} + (k) exp{u2(k)}

    u2(k + 1) u2(k) =

    d(k) +

    f(k) exp{u1(k)}

    (k) + (k) exp{u1(k)} + (k) exp{u2(k)}

    .

    (2.2)

    Assume that u(k) = {(u1(k), u2(k))T} X is an arbitrary solution of system (2.2) from 0 to w 1 with respect to k;

    we reach

    aw =

    w1k=0

    b(k) exp{u1(k)} +

    c(k) exp{u2(k)}

    (k) + (k) exp{u1(k)} + (k) exp{u2(k)}

    dw =

    w1k=0

    f(k) exp{u1(k)}

    (k) + (k) exp{u1(k)} + (k) exp{u2(k)}

    (2.3)

    From (2.2) and (2.3), we obtain

    w1

    k=0|u1(k + 1) u1(k)|

    w1

    k=0

    a(k) + b(k) exp{u1(k)} +c(k) exp{u2(k)}

    (k) + (k) exp{u1(k)} + (k) exp{u2(k)}

    = 2aw

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    1364 J. Zhang, J. Wang / Applied Mathematics Letters 19 (2006) 13611366

    w1k=0

    |u2(k+ 1) u2(k)| w1k=0

    d(k) +

    f(k) exp{u1(k)}

    (k) + (k) exp{u1(k)} + (k) exp{u2(k)}

    = 2 dw.

    Since (u1(k), u2(k)) X, there exist i , i Iw , such that

    ui (i ) = minkIw

    {ui (k)} ui (i ) = maxkIw

    {ui (k)}, i = 1, 2. (2.4)

    It follows from (2.3) and (2.4) that

    aw

    w1k=0

    b(k) exp{u1(k)} w1k=0

    b(k) exp{u1(1)} = exp{u1(1)}bw

    which reduces to u1(1) ln(a/b) := L1, and hence

    u1(k) u1(1) +

    w1

    s=0|u1(s + 1) u1(s)| ln{a/b} + 2aw := H1. (2.5)

    On the other hand, from (2.3) and (2.4), we also have

    aw

    w1k=0

    b(k) exp{u1(1)} +

    c(k)

    (k)

    = (c/)w + bw exp{u1(1)}

    which reduces to u1(1) ln{a(c/ )

    b} := l1, and hence

    u1(k) u1(1)

    w1s=0

    |u1(s + 1) u1(s)| ln

    a (c/ )

    b

    2aw := H2

    which, together with (2.5), leads to maxkIw |u(k)| max{|H1|, |H2|} := B1.From (2.3) and (2.4), we obtain

    dw

    w1k=0

    f(k) exp{u1(k)}

    l exp{u1(k)} + l exp{u2(k)}

    w1k=0

    f(k)(a/b) exp{2aw}

    l (a/b) exp{2aw} + l exp{u2(2)}.

    Then u2(2) ln{( fdl )a exp{2aw}

    b dl} := L2; we have

    u2(k) u2(2) +

    w1s=0

    |u2(s + 1) u2(s)| ln

    ( f dl )a exp{2aw}

    b dl

    + 2 dw := H3. (2.6)

    We also can obtain from (2.3) that

    dw

    w1k=0

    f(k) exp{u1(k)}

    u + u exp{u1(k)} + u exp{u2(2)}

    w1k=0

    f(k)(a (c/))b1 exp{2aw}

    u + ua(c/ )

    bexp{2aw} + u exp{u2(2)}

    .

    Then u2(2) ln{( fdu )(ac/ )b1 exp{2aw}du

    du} := l2; it follows that

    u2(k) u2(2)

    w1s=0

    |u2(s + 1) u2(s)| ln

    ( f du )(a c/ )b1 exp{2aw} du

    du

    2 dw := H4

    so maxkIw |u2(k)| max{|H3|, |H4|} = B2. Obviously, B1 and B2 are independent of. Take B = B1 + B2 + B0

    where B0 is taken sufficiently large that B0 > |l1| + |L1| + |l2| + |L2|.

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    J. Zhang, J. Wang / Applied Mathematics Letters 19 (2006) 13611366 1365

    Fig. 1. A solution (1.1) with a(k) = 1 + 0.2 sin( k2

    ), b(k) = 0.002(2 + sin( k2

    )), c(k) = 0.5 + 0.2 cos( k2

    ), d(k) = 0.6 + 0.1 sin( k2

    ), f(k) =

    0.8(0.5 + 0.2cos( k2

    )),(k) = 0.2 + 0.1 cos( k2 ),(k) = 0.2 + 0.1 sin( k2

    ) , (k) = 1 and initial conditions x(0) = 20, y(0) = 5. The solution

    tends to the 4-periodic solution (x(k), y(k)).

    Considering the algebraic equations

    a b exp{u1}

    1

    w1

    k=0

    vc(k) exp{u2}

    (k) + (k) exp{u1} + (k) exp{u2}

    d +1

    w1k=0

    f(k) exp{u1}

    (k) + (k) exp{u1} + (k) exp{u2}

    =

    00

    (2.7)

    where v [0, 1] is a parameter and (u1, u2) R2. Similarly, one can easily show that any solution (u1, u

    2) of(2.7)

    with v [0, 1] satisfies

    l1 u1 L1 l2 u

    2 L2. (2.8)

    Let = {(u1, u2)T X|(u1, u2) < B}; then is an open, bounded set in X and verifies requirement (a)

    of Lemma 2.1. When (u1, u2)

    Ker L =

    R2, (u1, u2) is a constant vector in R

    2 with (u1, u2) =

    |u1| + |u2| = B . Then we have Q N[(u1, u2)T] = 0; that is, the first part of(b) of Lemma (2.1) is valid.

    Consider the homotopy for computing the Brouwer degree

    A((u1, u2)T) = Q N((u1, u2)

    T) + (1 )F((u1, u2)T), [0, 1],

    where

    F((u1, u2)T) =

    a b exp{u1}

    d 1

    w1k=0

    f(k) exp{u1}

    (k) + (k) exp{u1} + (k) exp{u2}

    .

    By the invariance property of homotopy, direct calculation produces

    degJQN,Ker L, 0 = degQN,Ker L, 0 = degF, Ker L , 0 = 0,where deg(, , ) is the Brouwer degree and J is the identity mapping since Im Q = Ker L. We have proved that

    verifies all requirements ofLemma 2.1; then Lx = Nx has at least one solution in Dom L

    , so system (2.1) has at

    least one periodic solution in Dom L

    , say (u1(k), u2(k))

    T. Let x (k) = exp{u1(k)}, y(k) = exp{u2(k)}, so

    (x (k), y(k))T is an periodic solution of system (1.1) with strictly positive components. The proof is complete.

    Remark 2.1. In (1.1), we have assumed that > 1. In fact, if = 1, then the parameters in (1.1) are all constants

    and (1.1) is autonomous. The 1-periodic solutions of(1.1) must be constant solutions, i.e., the equilibria of (1.1).

    Finally, in order to illustrate some features of our main results, let

    a(k) = 1 + 0.2sink

    2

    , b(k) = 0.002

    2 + sin k

    2

    , c(k) = 0.5 + 0.2cos k

    2

    ,

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    1366 J. Zhang, J. Wang / Applied Mathematics Letters 19 (2006) 13611366

    d(k) = 0.6 + 0.1sin

    k

    2

    , f(k) = 0.8

    0.5 + 0.2cos

    k

    2

    ,

    (k) = 0.2 + 0.1cos

    k

    2

    , (k) = 0.2 + 0.1sin

    k

    2

    , (k) = 1.

    It is trivial to show that the conditions in Theorem 2.1 are verified. Therefore, (1.1) admits at least one -periodic

    solution. Our numerical simulation supports our theoretical findings (see Fig. 1).

    Acknowledgements

    The authors would like express their gratitude to Prof. Meng Fan for helpful discussion and suggestions, and to

    the referees for their excellent comments, which greatly improved the presentation of the work. The first author was

    supported by the NSFC.

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