07-Clase 07-1

33
Designing A Concrete Arch Bridge ? V This is the famous Schwandbach bridge in Switzerland, designed by Robert Maillart in 1933. It spans 37.4 meters (122 feet) and was designed using the same graphical methods that will be demonstrated in this lesson. To proceed with this lesson, click on the Next button here or at the top of any page. When you are done with this lesson, click on the Contents button here or at the top of any page to return to the list of lessons.

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Transcript of 07-Clase 07-1

  • Designing A Concrete Arch Bridge?VThis is the famousSchwandbach bridge inSwitzerland, designed byRobert Maillart in 1933. Itspans 37.4 meters (122 feet)and was designed using thesame graphical methods thatwill be demonstrated in thislesson.

    To proceed with this lesson,click on the Next button hereor at the top of any page.When you are done with thislesson, click on the Contentsbutton here or at the top of anypage to return to the list oflessons.

  • Designing A Concrete Arch Bridge?VThe Problem: This is apartially finished form diagramof a bridge that will span99 feet. The roadway slopesat 7%. Eight walls spaced11 feet apart bring total loadsof 120 kips each from the stiffdeck to a concrete arch below.The arch is a concrete slabthat is 8 inches thick and16 feet wide throughout thespan. The allowable axialstress in the arch is 800 lb/in2.Shape the arch in such a waythat segment oe is parallel tothe bridge deck as shown.

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  • Designing A Concrete Arch Bridge?VStep 1: What is themaximum allowable axialforce in the arch?The given parameters are anarch thickness of 8 inches, anarch width of 16 feet, and anallowable stress of 800 lb/in2.

    The cross sectional area of the arch is its width times its thickness:Area = (width)(thickness) = (16 ft)(12 in./ft)(8 in.) = 1536 in2

    The allowable axial force in the arch is the area of the arch times the allowable stress:Force = (Area)(allowable stress) = (1536 in2)(800 lb/in2) = 1,228,800 lb = 1229 kips

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  • Designing A Concrete Arch Bridge?VStep 2: Construct a loadingdiagram and apply intervalnotation.Working clockwise from theupper left, place externalgravity loads on the formdiagram. The spaces orintervals between forces arelabeled with the uppercaseletters of the alphabet.In this diagram, the first120 kip load is placed overthe leftmost arch wall. LettersA and B are assigned to theintervals on either side of theload. This is load AB.

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  • Designing A Concrete Arch Bridge?VThe second load is placedover the next arch wall. LetterC is added to the diagram,and this becomes load BC.With each load, a vertical lineof action is extended downthrough the area of the formdiagram where the arch willbe constructed.

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  • Designing A Concrete Arch Bridge?VThe process continues untilall the loads on the arch havebeen constructed and labeled.This is load CD.

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  • Designing A Concrete Arch Bridge?VThis is load DE.

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  • Designing A Concrete Arch Bridge?VThis is load EF.

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  • Designing A Concrete Arch Bridge?VThis is load FG.

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  • Designing A Concrete Arch Bridge?VThis is load GH.

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  • Designing A Concrete Arch Bridge?VThis is load HI.The loading diagram is nowcomplete. All of the externalgravity loads acting on thearch have been placed on theloading diagram.Vertical lines of action havebeen drawn for each load,extending down through thearea of the form diagramwhere the arch will beconstructed.

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  • Designing A Concrete Arch Bridge?VStep 3: Construct a loadline to any convenient scale.The Load Line is a graphicalsummation of the loads actingon the structure. On the LoadLine, the magnitude of theforces from the loadingdiagram are drawn to scale.Beginning with force AB, weplot a segment of the loadline, parallel to AB, labeledab. The length of ab scales to120 kips, the magnitude of theforce.

    Loading Diagram

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  • Designing A Concrete Arch Bridge?VOnce again, we workclockwise around the FormDiagram, plotting each loadonto the Load Line in a tip-to-tail fashion.Although the Load Line iscomposed of vectors, theends of the force segmentsare marked with horizontal tickmarks rather than arrowheads. This helps to keep thediagram legible and accurate.

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    Vectors arrangedtip-to-tail

  • Designing A Concrete Arch Bridge?VSince all of the loads on ourarch are of equal magnitude,each segment of the LoadLine will be equal in length.When the loads on a structurevary in magnitude, or are notall strictly vertical in direction,the segments of the Load Linewill vary in length anddirection as well.

    Loading Diagram

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    Form Diagram dcba

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  • Designing A Concrete Arch Bridge?VWe continue across theLoading Diagram, plotting allthe loads on the arch onto theLoad Line.Notice how intervals on theLoading Diagram correspondto points on the Load Line.

    Loading Diagram

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    Form Diagramedcba

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  • Designing A Concrete Arch Bridge?VWe continue across theLoading Diagram...

    Loading Diagram

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    Form Diagram

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  • Designing A Concrete Arch Bridge?VWe continue across theLoading Diagram...

    Loading Diagram

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    Form Diagram

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  • Designing A Concrete Arch Bridge?VWe continue across theLoading Diagram...

    Loading Diagram

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  • Designing A Concrete Arch Bridge?VThe Load Line is nowcomplete.The total length of the LoadLine is equal to the total loadon the arch, in this case960 kips.

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  • Designing A Concrete Arch Bridge?VStep 4: Construct ray oe ofknown direction butunknown length.Ray oe is a vector whose lengthis equal to the magnitude of theforce in arch segment oe, andwhose direction is parallel tothat force.Construct ray oe throughpoint e on the load line, parallelto arch segment oe. Althoughwe dont yet know the locationof point o, the left end of rayoe, it must occur somewherealong this line.

    Loading Diagram

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  • Designing A Concrete Arch Bridge?VStep 5: Construct thelongest ray and find point o.Even before we know thelocation of point o, we cansketch the general layout ofthe rays of the Force Polygon.We can see from this sketchthat, for any point o that lieson ray oe, ray oa will be thelongest ray, corresponding tothe greatest force in the arch.Thus we must limit ray oa toa length of 1229 kips.

    Here is the equation we used in Step 1 to find the maximumallowable force in the arch:

    Force = (Area)(allowable stress) = (1536 in2)(800 lb/in2)= 1,228,800 lb = 1229 kips

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    Ray oa is

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  • Designing A Concrete Arch Bridge?VFrom point a, we use acompass to strike an arc ofradius 1229 kips, themaximum force allowable inthe arch. Where this arcintersects with ray oe ispoint o.The Load Line has nowbecome part of a ForcePolygon. Point o is the Pole ofthe diagram.

    Here is the equation we used in Step 1 to find the maximumallowable force in the arch:

    Force = (Area)(allowable stress) = (1536 in2)(800 lb/in2)= 1,228,800 lb = 1229 kips

    Loading Diagram

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    400 kipsForce Polygon

    Pole o

  • Designing A Concrete Arch Bridge?VBy scaling the length of rayoe on the Force Polygon, wecan now determine themagnitude of the force insegment oe of the arch.Loading Diagram

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  • Designing A Concrete Arch Bridge?VStep 6: Through the Pole o,construct the remainingrays of the Force Polygon,beginning at the center andworking toward the ends.As each ray is drawn,construct parallel to it thecorresponding segment of theconcrete arch on the FormDiagram.Scale the length of each rayto find the magnitude of theforce in the correspondingsegment of the arch.

    Loading Diagram

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  • Designing A Concrete Arch Bridge?VThis is ray oc.

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  • Designing A Concrete Arch Bridge?VThis is ray ob.

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  • Designing A Concrete Arch Bridge?VThis is ray oa.

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  • Designing A Concrete Arch Bridge?VThis is ray of.

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  • Designing A Concrete Arch Bridge?VThis is ray og.

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  • Designing A Concrete Arch Bridge?VThis is ray oh.

    Loading Diagram

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  • Designing A Concrete Arch Bridge?VThis is ray oi.

    Loading Diagram

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  • Designing A Concrete Arch Bridge?VThis is the bridge that youhave designed.The force polygon is agraphical tool that allows youto find the forces in astructure, and to findsimultaneously theappropriate form for thestructure.

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  • Designing A Concrete Arch Bridge?VUsing the same method thatwe used to find the form andforces for the arch, we canfind the form of a suspensionbridge whose cable can safelycarry a given maximum force.The pole of the Force Polygonlies to the right of the loadline, rather than to the left.The forces in the cable aretensile, rather thancompressive.

    Click on the Contents button to begin anew lesson.Click on the image of the Schwandbach Bridgeto return to the beginning of this lesson.

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    Schwandbach BridgeThe ProblemAllowable ForceLoading DiagramLoad LineRay 'oe'Point 'o'Form & ForcesThe SolutionSuspension Bridge

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