第二章 恒定电流
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Transcript of 第二章 恒定电流
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1()..
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W=qU U,I, t q=I t2:
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W I U t 3(J) (kWh).1kWh3.6106JW=IUt2:1().
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1. P IU3(W) (kW)1kW103W
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:. :. :.:.
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? 1:.
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2:(1) Q=W=IUtU=IR(2):1:.
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QIR t : Q=I2R t2:3(J) (kWh).
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1:.P I R 3(W) (kW)
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: QI2Rt WIUt=I=U/R: +WWQIUt I2RtIU/R! !
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: : + QI2Rt WIUt=I=U/R = :W=IUt = =I2RtU2t/R=P = I U = U2/R = I2R =P WW QIUt I2RtIU/RW= IUtQ=I2RtP = IUP=I2R=Q
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Q: . Q=I2Rt J QI R t W (). W=IUt J 1kWh=3.6106JPP=W/t=IU W kW PP=Q/t=I2R W kW: ==: >>
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1( )
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()()CD
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2 ( )
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30.4 220V5A?:PPP: PP+P:: P I2R : PIU: PPPIUI2R: WPt=(IUI2R)t =(5220-520.4) 60J =6.5104J
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:: IUt = I2Rt +W: W=(IU-I2R)t =(5220-520.4) 60 J =6.5104 J30.4 220V5A?
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: ==: >>
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1 .. 2,.
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1220V800W110V?200W
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2R1=2R=3R=6UP1P2P3 P1P2P3( )A236B632 C123D321A
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3R1=2R=3R=6UP1P2P3 P1P2P3( )A236B632 C123D321D
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4R1=6R2=3R3=4_________126
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5100 4W0.2A;20V
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61004W508W150 150_________ 0.2A;30V;6W
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7L1L2110V60W110V100WR220VB
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P=UI P=I2R C
8UPr( ) AP BU2/r C CP2r/U2 DP-P2r/U2
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::4 - 5
R=60.50.2A,22.5V,4.5W